Develop Reference

How do I stop an image at the bottom of the window?

$(".raindrop1").clone().removeClass("raindrop1").addClass("raindropDelete").appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
}).animate({
top: "+=1000"
}, function() {
$(".raindropDelete").remove();
});
body {
background: rgb(0, 0, 0);
}
.shape {
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="shape" onclick="curse()"></div>
<img src='http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width="15px" class="raindrop1">
I got this bit of code but I just can't seem to get it to work the way I want to. I want to make an image fall down to the bottom of the screen but to delete itself just before a scrollbar appears.
JS:
$(".raindrop1").clone().removeClass("raindrop1").addClass("raindropDelete").appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
}).animate({top :"+=1000"}, function() {
$(".raindropDelete").remove();
});
HTML:
<div class = "shape" onclick = "curse()"></div>
<img src = 'http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width = "15px" class = "raindrop1">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
and CSS:
body{
background: rgb(0, 0, 0);
}
.shape{
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
Am I doing anything wrong?
JSFiddle

You are trying to remove your droplet in the function that is used to do something when animation is completed. So droplet animation is still going until it will reach +1000px from the top.
To remove before it falls below the window it's possible to use step option for animate method. What it does is looking what happens during animation and you can remove the droplet if when it falls below the edge.
Step Function
The second version of .animate() provides a step option — a callback
function that is fired at each step of the animation. This function is
useful for enabling custom animation types or altering the animation
as it is occurring. It accepts two arguments (now and fx), and this is
set to the DOM element being animated.
now: the numeric value of the property being animated at each step
fx: a reference to the jQuery.fx prototype object, which contains a number
of properties such as elem for the animated element, start and end for
the first and last value of the animated property, respectively, and
prop for the property being animated.
So what I've done is created a step function that each step looks if droplet is reached the edge of the window. If condition is met - just remove the droplet
$(".raindrop1").clone()
.removeClass("raindrop1")
.addClass("raindropDelete")
.appendTo("body").css({
left: $(".shape").position().left - 29.50,
top: $(".shape").position().top + 1,
position: "relative"
})
.animate({top :"+=100"},
{step: function(now) {
if (now+50 >= $(window).height())
$(".raindropDelete").remove();
}
},
function() {});
body{
background: rgb(0, 0, 0);
}
.shape{
border-radius: 50px;
width: 10px;
height: 10px;
background-color: white;
position: absolute;
left: 50%;
top: 50%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class = "shape" onclick = "curse()"></div>
<img src = 'http://images.clipartpanda.com/raindrop-clipart-RTGdn5bTL.png' width = "15px" class = "raindrop1">

using this css you can stick your image to the bottom of the window in all new browsers
.fix{
position:fixed;
bottom:0px;
left:50%;
}
<img src="yourimagepath" class="fix"/>
and for IE6 you can use
position:absolute; instead of fixed. It will position the image on the bottom of the page but as you scroll up the image will scroll with the page. Unfortunately position:fixed in not supported in IE6
Using this code you can detect if the user has reached to the bottom of the page. Here you can add your code for deleting the image. If you put the code here the image will be deleted automatic if the user reaches to the bottom of the page.
window.onscroll = function(ev) {
if ((window.innerHeight + window.scrollY) >= document.body.offsetHeight) {
// you're at the bottom of the page
}
};

You can use sticky elements. They are elements on a page that will not be scrolled out of view. In other words it sticks to a visible area (viewport or scrolling box). You can create this with CSS using position: sticky;.
[Ref: http://www.hongkiat.com/blog/useful-css-tricks-you-might-have-overlooked/]
Look at the following code for an example:
https://codepen.io/rpsthecoder/pen/zGYXEX
HTML:
<h4>Scroll to see the sticky element <em>sticking</em></h4>
<div class="extra"></div>
<br />
<div id="wrapper">
<div id="sticky">
sticky
</div>
</div>
<br />
<div class="extra"></div>
CSS:
#sticky {
position: sticky;
background: #F762BC;
width: 100px;
height: 100px;
top: 70px;
left: 10px;
display: flex;
justify-content:center;
align-items:center;
box-shadow: 0 0 6px #000;
text-shadow: 0 0 4px #fff
}
#wrapper {
width: 75%;
margin: auto;
height: 400px;
background-color: #ccc;
}
.extra{
background: #ccc;
width: 75%;
margin: auto;
height: 100px;
}
body {
height: 1000px;
font-family: georgia;
}
h4{
text-align: center;
}

How to prevent get over other divs?

I have a problem...In the following example i don't want that the div who is fixed get over the div with the background red.
Here is the example:
http://jsfiddle.net/HFjU6/3645/
#fixedContainer
{
background-color:#ddd;
position: fixed;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
margin-left: -100px; /*half the width*/
}

Alright, I think I get what the OP wants. He wanted a container that stays fixed on the top of the viewport, but remains confined by a parent. This behaviour is known as a conditional sticky behaviour, and is actually implemented in both Firefox (without vendor prefix) and macOS/iOS Safari (with -webkit- prefix): see position: sticky.
Therefore the easiest (but also the least cross-browser compatible) way is simply to modify your markup, such that the sticky element stays within a parent, and you declare position: sticky on it:
* {
margin: 0;
padding: 0;
}
#fixedContainer {
background-color: #ddd;
position: -webkit-sticky;
position: sticky;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
transform: translate(-50%, 0); /* Negative left margins do not work with sticky */
}
#div1 {
height: 200px;
background-color: #bbb;
}
#div1 .content {
position: relative;
top: -100px; /* Top offset must be manually calculated */
}
#div2 {
height: 500px;
background-color: red;
}
<div id="div1">
<div id="fixedContainer">I am a sticky container that stays within the sticky parent</div>
<div class="content">Sticky parent</div></div>
<div id="div2">Just another element</div>
An alternative would be to use a JS-based solution. In this case, you do not actually have to modify your markup. I have changed the IDs for easier identification of the elements, however.
The gist of the logic is this:
When the scroll position does not exceed the bottom of the parent minus the outer height of the sticky content, then we do not do anything.
When the scroll position exceeds the bottom of the parent minus the outer height of the sticky content, we dynamically calculate the top position of the sticky content so that it remains visually in the parent.
$(function() {
$(window).scroll(function() {
var $c = $('#sticky-container'),
$s = $('#sticky-content'),
$t = $(this); // Short reference to window object
if ($t.scrollTop() > $c.outerHeight() - $s.outerHeight()) {
$s.css('top', $c.offset().top + $c.outerHeight() - $t.scrollTop() - $s.outerHeight());
} else {
$s.css('top', 0);
}
});
});
* {
margin: 0;
padding: 0;
}
div {
height: 500px;
background-color: red;
}
#sticky-container {
background-color: #bbb;
height: 200px;
}
#sticky-content {
background-color: #ddd;
position: fixed;
width: 200px;
height: 100px;
margin-left: -100px;
left: 50%;
top: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="sticky-content">Sticky content that stays within the bounds of #div1</div>
<div id="sticky-container">Sticky confinement area</div>
<div>Other content</div>
Old answer before OP clarified the question appropriately:
Just give them the appropriate z-index values. In this case, you want to:
Do not use static positioning. This can be done by using position: relative for the large elements, in conjunction with the originally position: fixed element.
Assign the appropriate stacking order. The grey <div> element to have the lowest z-index, followed by the position fixed element, and then by the red element.
There are some catchalls to stacking though: the stacking context is reset when you traverse up or down the node tree. For example, the example will not work if the elements are not siblings.
Here is a proof-of-concept example, modified from your fiddle so that inline CSS is removed.
* {
margin: 0;
padding: 0;
}
#fixedContainer {
background-color: #ddd;
position: fixed;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
margin-left: -100px;
z-index: 2;
}
#div1 {
height: 200px;
background-color: #bbb;
position: relative;
z-index: 1;
}
#div2 {
height: 500px;
background-color: red;
position: relative;
z-index: 3;
}
<div id="fixedContainer">z-index: 2</div>
<div id="div1">z-index: 1</div>
<div id="div2">z-index: 3</div>

Just give the z-index.
Hope it helps...
http://jsfiddle.net/HFjU6/1/#run
#fixedContainer {
background-color:#ddd;
position: fixed;
width: 200px;
height: 100px;
left: 50%;
top: 0%;
margin-left: -100px; /*half the width*/
z-index: 2;
}
.div-red {
position: relative;
z-index: 5;
}
<div id="fixedContainer"></div>
<div style="height:200px;background-color:#bbb;"></div>
<div style="height:500px;background-color:red;" class="div-red"></div>

How to get the position of an element relative to another using jQuery?

Please have a look at this:
http://liveweave.com/5bhHAi
If you click the "Get Pos" link you will see the red div's position relative to the image.
Now say this image's size has changed at some point down the line. How can I get the new position for the red div based on the initial data?
HTML:
<div id="watermark"></div>
<img src="http://placekitten.com/g/320/270" class="small-img">
<div><br><br>Get Pos</div>
jQuery:
$(document).ready(function() {
var $watermark = $('#watermark');
$('.get-pos').on('click', function(e) {
e.preventDefault();
var watermark_position = {
top: $watermark.position().top - $('.small-img').position().top,
left: $watermark.position().left - $('.small-img').position().left
};
alert(watermark_position.top + 'px from the top');
alert(watermark_position.left + 'px from the left');
});
});
CSS:
#watermark { background: red; position: absolute; top: 215px; left: 265px; width: 50px; height: 50px; }

Here is a solution to what I understand you want from question/comments:
http://jsfiddle.net/tXT2d/
var imgPos = $(".image img").offset();
var wmPos_tmp = $(".watermark").offset();
var watermarkPosition = {
top: wmPos_tmp.top - imgPos.top,
left: wmPos_tmp.left - imgPos.left
}

You can accomplish your intended goal (placing the watermark at the right place even after size changes) without using javascript at all if you do just a little reworking. A working example of the following solution is here
(just change the width of the .img-container to see it function).:
.watermark {
background: red;
width: 50px;
height: 50px;
}
.img-container {
width: 295px;
height: auto;
position: relative;
}
.img-container img {
width: 100%;
}
.img-container .watermark {
position: absolute;
right: 10px;
bottom: 10px;
}
<div class="img-container">
<div class="watermark"></div>
<img src="http://placekitten.com/g/320/270" class="small-img">
</div>
Your html containing the image will look basically like this:
<div class="img-container">
<div class="watermark"></div>
<img src="http://placekitten.com/g/320/270" class="small-img">
</div>
And the css to get the placement to happen looks like this:
.watermark { background: red; width: 50px; height: 50px; }
.img-container {
width: 275px;
height: auto;
position: relative;
}
.img-container img {
width: 100%;
}
.img-container .watermark {
position: absolute;
right: 10px;
bottom: 10px;
}
Here, the image will always match the width of its container, and the watermark will always place itself ten pixels from the right and ten pixels from the bottom of the container.

Moving divs with javascript

This is my problem, I have a div and inside 2 divs, one is centered and the other one is fixed on the left, the problem is when I resize the screen the centered div overlaps the fixed one, what I wanted to do is detect when the centered div overlaps the other div and change its left value with javascript, but is not working, any ideas?
This is my design:
<div id="content-wrap">
<div id="content">
</div>
<div id="leftbar">
</div>
</div>
and the CSS:
#content-wrap
{
clear: both;
float: left;
width: 100%;
}
#content
{
text-align: left;
padding: 0;
margin: 0 auto;
height: 470px;
width: 760px;
overflow: auto;
}
#leftbar
{
background-color: transparent;
width: 200px;
height: 470px;
position: absolute;
top: 185px;
left: 50px;
}
and this is the javascript code:
window.onload = function Centrar() {
var leftBar = $get("leftbar");
if (leftBar != null) {
var content = $get("content");
var size = leftBar.offsetLeft + leftBar.offsetWidth;
if (content.offsetLeft < size) {
content.style.left = size + 20 + 'px';
}
}
}
Thanks in advance for any help.

The easiest fix would be to apply a min-width to your #content-wrap container that prevented the overlap from occurring:
#content-wrap {
clear: both;
float: left;
width: 100%;
/* #leftbar width x 2 + #content width */
min-width: 1160px;
}
However, if you want to use Javascript, you'll need to attach the code to the window load and resize events:
$(window).bind('load resize', function() {
var content = $('#content');
var leftbar = $('#leftbar');
// get the right edge of the #leftbar
var leftbarEdge = leftbar.width() + leftbar.offset().left;
// check if an overlap has occured and adjust #content left position if yes
if (leftbarEdge > content.offset().left) {
content.css({
left: leftbarEdge - content.offset().left
});
}
});
The last change you'll need to apply to get this working is to set #content to position: relative in the CSS so it respects the left property you're setting with Javascript:
#content {
position: relative;
/* remaining css */
}
You can see it in action here.

How can I create many divs on on top of the other using CSS/jQuery?

Basically, I want many(>25) divs to be displayed one on top of the other so that only one can be seen at a time. I have the jQuery UI draggable implemented, so once a div is dragged away, the next div is shown. What CSS do I need to make such a stack of divs? jQuery is also available if required.
Thanks!

Try this:
CSS
div.square {
cursor: pointer;
width: 100px;
height: 100px;
border: 2px dashed purple;
position: absolute;
top: 30px;
left: 30px;
font-size: 50px;
line-height: 100px;
text-align: center;
color: white;
}
jQuery + jQueryUI
var count = 25;
var colors = ['red','green','blue','orange','yellow'];
while(count--) {
$('<div/>',{className:'square', text:count}).draggable().css({position:'absolute','z-index':count, text:count, backgroundColor:colors[count % 5]})
.appendTo('body');
}
EDIT:
I just noticed that for some reason in IE and Safari .draggable() overrides the absolute positioning with relative, so you need to set it back to absolute after you made it draggable.
Updated the example above.
http://jsfiddle.net/p9wWA/

You mean something like this?
#relative_container { position: relative; }
#relative_container div { position: absolute; top: 0; left: 0; width: 100px; height: 100px; }
#relative_container div.item_1 { z-index: 100; } /* Higher index means its more on top */