Bootstrap set radio button checked with jquery - javascript

I have radio buttons in my html code.
I want to change their state based on my input values via jquery
Here is My Html
<div class="col-md-2 col-xs-offset-1">
<div class="radio">
<label>
<input type="radio" name="rdo_pkdrop" value="0" id="rdo_pick">
Pick-up Time
</label>
</div>
<div class="radio">
<label>
<input type="radio" name="rdo_pkdrop" id="rdo_drop" value="1">
Drop Time
</label>
</div>
</div>
An jQuery is
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_pick').prop('checked',true);
}
But This has no effect
I also tried with
$('#rdo_pick').prop('checked','checked'); and
$('#rdo_pick').attr('checked','true');
$('#rdo_pick').addClass('checked');

This is only way I could find. Although somewhat inelegant, it does work.
if(qs_trip_type == 0){
$('#rdo_pick').click();
}else{
$('#rdo_drop').click();
}

The issue with bootstrap is that you set a checked radio button by adding the active class to the corresponding label of the input. It looks like this:
<label class="btn btn-default active"> <!-- Note the class 'active' here -->
<input type="radio" name="myRadio" value="value1" checked="checked"/>Value 1
</label>
<!-- ... -->
To check a radio button using jQuery you could first select the input field with a jQuery Selector and then add the class to the parent:
var $myRadioInput = $(...);
$myRadioInput.parent('.btn').addClass('active');
Don't forget to remove the class active on the formerly selected label with jQuery removeClass('active') to first unselect them.
I also like it to set the checked property on the input itself to have the proper state on it:
$myRadioInput.prop('checked', true);
Note that the checked="checked" attribute is only the inital state for the input to be the checked input when loading the page. It does NOT change with the jQuery .prop() method, as it is an attribute and is different to the actual checked property. This is well described in jQuery Docs.

I have tried,this code is ok for bootstrap radio.
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true).click();
}else{ //not ekse
$('#rdo_pick').prop('checked',true).click();
}

there is a typo in your code replace ekse with else
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_pick').prop('checked',true);
}

if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{ //not ekse
$('#rdo_pick').prop('checked',true);
}
Here's the jsfidlle http://jsfiddle.net/urLh9qnh/

Try this
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_drop').prop('checked',true);
}

Try This:
after setting the value of the radio, please add this code
$("input[type='checkbox'], input[type='radio']").iCheck({
checkboxClass: 'icheckbox_minimal',
radioClass: 'iradio_minimal'
});

Here is a one line solution:
$('#rdo_pick').iCheck('check');

Related

Checkboxes, javascript runs 2 times through function if I click on text

I want to click on a checkbox and if I click this box it should run a function what gets an ID and saves it into an array or deletes it from the array if it still exists in the array.
That works, but if I click on the text beside the box the function runs twice. It first writes the ID into the array and then deletes it.
I hope you can help me so that I can click on the text and it just runs once
HTML
<label><input type="checkbox" value="XXX" >Active</label>
JavaScript/jQuery
function addOrRemoveBoxes(ID){
if(boxArr.indexOf(ID) != -1){
removeFromArray(ID)
}
else{
boxArr.push(ID);
}
}
$(".checkBoxes").unbind().click(function() {
event.stopPropagation();
addOrRemoveBoxes($(this).find('input').val());
});
The problem is probably that your label and your input are picking the click. Try to bind it only to input. Like this:
$(".checkBoxes input").unbind().click(function() {
event.stopPropagation();
addOrRemoveBoxes($(this).find('input').val());
});
Your HTML is structured bad. When your label is clicked it triggers a click event for the input so you have to separate the input form the label like: <input type="checkbox" name="opt1" id="opt1_1" value="ENG"> <label for="opt1_1">hello</label>. Also your jQuery makes no sense, why do you use unbind()? And we can't see what removeFromArray() does (we can guess but I prefer to see all code used or note that you use pseudo code).
I made this in 5 min: (hopes it helps you)
$(document).ready(function(){
window.boxArr = [];
$(document).on('click','[name=opt1]',function(){
addOrRemoveBoxes(this.value);
//show contents of boxArr
if(boxArr.length == 0){
$('#output').html('nothing :/');
}
else{
$('#output').html(boxArr.join(" -> "));
}
});
});
function addOrRemoveBoxes(ID){
var arrayIndex = boxArr.indexOf(ID);
if(arrayIndex > -1){
boxArr.splice(arrayIndex, 1);
}
else{
boxArr.push(ID);
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h1>Choose</h1>
<input type="checkbox" name="opt1" id="opt1_1" value="ENG"> <label for="opt1_1">hello</label> <br>
<input type="checkbox" name="opt1" id="opt1_2" value="DUT"> <label for="opt1_2">hallo</label> <br>
<input type="checkbox" name="opt1" id="opt1_3" value="SWE"> <label for="opt1_3">hej</label>
<br><br><h2>Array contains:</h2>
<div id="output">nothing :/</div>
Side note: with [name=opt1] we select all the elements with name="opt1" attribute.

Check to see if none of the checkboxes was checked in jquery

I have two checkboxes and one of the checkboxes must be checked. I can see that it's right, no syntax errors. What should be made to my code to check if none of the checkboxes were checked?
HTML :
<input type="checkbox" value="aa" class="first" name="a"> Yes<br/>
<input type="checkbox" value="bb" class="second" name="b"> No <br/>
<button type="submit">Go!</button>
<p class="error"></p>
JavaScript:
$('button').on('click',function(){
if( $(".first:not(:checked)") && $(".second:not(:checked)") ){
$('.error').text('You must select atleast one!');
}else
$('.error').hide();
});
Example : http://jsfiddle.net/ptbTq/
Check this fiddle: http://jsfiddle.net/692Dx/
Checking code:
if($('input[type="checkbox"]:checked').length == 0) {
alert('none checked');
}
You are using selectors which do not return boolean values which is what you need when writing an if condition. Here's what you could do:
$('button').on('click',function() {
if(!$(".first").is(":checked") && !$(".second").is(":checked")) {
$('.error').text('You must select atleast one!').show();
} else {
$('.error').hide();
}
});
or if you prefer and think it could be more readable you could invert the condiciton:
$('button').on('click',function() {
if($(".first").is(":checked") || $(".second").is(":checked")) {
$('.error').hide();
} else {
$('.error').text('You must select atleast one!').show();
}
});
Also notice that you need to .show() the error message in the first case as you are hiding it in the second.
And here's a live demo.
Short:
$("input[type=checkbox]").is(":checked")
returns true if:
one of your checkboxes - from the selector ("input[type=checkbox]") - is checked.
else return false
and in your case:
$(".first, .second").is(":checked")
Do something at least one of your checkboxes is checked
Put the same class on both checkboxes and you can do something like
if ($(':checkbox.the_class:checked').length > 0) {
// at least one checkbox is checked
// ...
}
The best would be to put your checkboxes inside a div with an unique ID so you can verify all the checkboxes in there, so your code will work in all cases. Even when adding new checkboxes to the div later on.
<div id="cb">
<input type="checkbox" value="aa" class="first" name="a" /> Yes<br/>
<input type="checkbox" value="bb" class="second" name="b" /> No <br/>
<button type="submit">Go!</button>
<p class="error"></p>
</div>
Your JQuery:
$('button').click(function() {
var checked_one = $('div#cb input[type="checkbox"]').is(':checked');
if (!checked_one )
$('.error').text('You must select atleast one!');
else
$('.error').hide();
});
Live demo can be seen here: http://jsfiddle.net/ptbTq/15/

How to display diffrence divs according to radio selection

I have 2 radio buttons no one of them checked by default and I want if any one of them checked a Div appear according to what radio button was checked.
( Divs have different content )
and if the selection changed the one which appeared now disappear and the other appear.
and when one of them appear there are another 2 radio to do the same thing for another one div ( one to show and one to hide )
Here what I tried to do
JavaScript
function haitham()
{
if(document.getElementById('s').checked == true)
{
document.getElementById('StudentData').style.display = "block";
document.getElementById('GraduateData').style.display = "none";
}
else if(document.getElementById('g').checked == true)
{
document.getElementById('GraduateData').style.display = "block";
document.getElementById('StudentData').style.display = "none";
}
}
function info()
{
if(document.getElementById('y').checked == true)
{
document.getElementById('MoreInfo').style.display = "block";
}
else if(document.getElementById('n').checked == true)
{
document.getElementById('MoreInfo').style.display = "none";
}
}
HTML
<input class="margin2" id="s" type="radio" name="kind" value="student" onchange="haitham()"
required="required" />Student
<input class="margin2" id="g" type="radio" name="kind" value="graduate" onchange="haitham()"
required="required" />Graduate
<div id="StudentData">
content 1
<input class="margin2" id="y" type="radio" name="info" value="yes" onchange="info()"
required="required" />Student
<input class="margin2" id="n" type="radio" name="info" value="no" onchange="info()"
required="required" />Graduate
</div>
<div id="GraduateData">
content 2
</div>
<div id="MoreInfo">
content 3
</div>
the first work good but the other 2 radio did not work although it should be the same
Thank you ...
Your problem wasn't a javascript or html one, it was actually a CSS issue. Your code was fine, aside from the fact that the values for display are "none" and "block" not "" and "hidden". I modified your code and updated the fiddle.
Here's the link:
http://jsfiddle.net/8JpSQ/4/
Just add a clicked event to the radio buttons, and through a Javascript function change the attribute of the respective DIV to hidden when required. To show it instead, remove the attribute 'hidden'. Also, we'd probably be able to help more if you can post some code showing what you tried/what went wrong. But what I suggested should be the general approach to make what you want happen.
I have no idea what your HTML is, so here's what I have:
$('input[type="checkbox"]').click(function() {
$('.divWrapper > div').eq($(this).index()).fadeOut().siblings().fadeIn();
});
I'm assuming this is your structure:
<form>
<checkbox>
<checkbox>
...
</form>
<div class="divWrapper">
<div>
<div>
...
</div>

jquery missing ) after argument list on radiobutton form

I copied a pice of jquery code from a tutorial for working with radio buttons. It is not working for me but from the comments on the tutorial it seems to work for other people. I get this "missing ) after argument list" } else {
So here is the relevant portion of my code. I have two radio buttons above two forms. I want to show the form with the checked radio button and hide the other form.
<script type="text/javascript">
$(document).ready(function() {
$('#existing-login').show();
$('#new-customer').hide();
});
$("input[#name='customer']").change(function(){
if ($("input[#name='customer']:checked").val() == "new")
$("#new-customer").show();
$("#existing-login").hide();
} else {
$("#existing-login").show();
$("#new-customer").hide();
}
});
</script>
<input type="radio" name="customer" value="existing" checked="checked"/>
<input type="radio" name="customer" value="new"/>
<div id="existing-login">
<!-- form for existing customer login -->
</div>
<div id="new-customer">
<!-- form for new customers -->
</div>
Missing { after your if statement:
if ($("input[#name='customer']:checked").val() == "new") {
$("#new-customer").show();
$("#existing-login").hide();
} else {
$("#existing-login").show();
$("#new-customer").hide();
}
Also the # syntax for selecting attributes isn't supported anymore in current versions of jQuery, so remove that too:
if ($("input[name='customer']:checked").val() == "new") {

How to check a radio button with jQuery?

I try to check a radio button with jQuery. Here's my code:
<form>
<div id='type'>
<input type='radio' id='radio_1' name='type' value='1' />
<input type='radio' id='radio_2' name='type' value='2' />
<input type='radio' id='radio_3' name='type' value='3' />
</div>
</form>
And the JavaScript:
jQuery("#radio_1").attr('checked', true);
Doesn't work:
jQuery("input[value='1']").attr('checked', true);
Doesn't work:
jQuery('input:radio[name="type"]').filter('[value="1"]').attr('checked', true);
Doesn't work:
Do you have another idea? What am I missing?
For versions of jQuery equal or above (>=) 1.6, use:
$("#radio_1").prop("checked", true);
For versions prior to (<) 1.6, use:
$("#radio_1").attr('checked', 'checked');
Tip: You may also want to call click() or change() on the radio button afterwards. See comments for more info.
Try this.
In this example, I'm targeting it with its input name and value
$("input[name=background][value='some value']").prop("checked",true);
Good to know: in case of multi-word value, it will work because of apostrophes, too.
Short and easy to read option:
$("#radio_1").is(":checked")
It returns true or false, so you can use it in "if" statement.
One more function prop() that is added in jQuery 1.6, that serves the same purpose.
$("#radio_1").prop("checked", true);
Try this.
To check Radio button using Value use this.
$('input[name=type][value=2]').attr('checked', true);
Or
$('input[name=type][value=2]').attr('checked', 'checked');
Or
$('input[name=type][value=2]').prop('checked', 'checked');
To check Radio button using ID use this.
$('#radio_1').attr('checked','checked');
Or
$('#radio_1').prop('checked','checked');
Use prop() mehtod
Source Link
<p>
<h5>Radio Selection</h5>
<label>
<input type="radio" name="myRadio" value="1"> Option 1
</label>
<label>
<input type="radio" name="myRadio" value="2"> Option 2
</label>
<label>
<input type="radio" name="myRadio" value="3"> Option 3
</label>
</p>
<p>
<button>Check Radio Option 2</button>
</p>
<script>
$(function () {
$("button").click(function () {
$("input:radio[value='2']").prop('checked',true);
});
});
</script>
The $.prop way is better:
$(document).ready(function () {
$("#radio_1").prop('checked', true);
});
and you can test it like the following:
$(document).ready(function () {
$("#radio_1, #radio_2", "#radio_3").change(function () {
if ($("#radio_1").is(":checked")) {
$('#div1').show();
}
else if ($("#radio_2").is(":checked")) {
$('#div2').show();
}
else
$('#div3').show();
});
});
Try This:
$("input[name=type]").val(['1']);
http://jsfiddle.net/nwo706xw/
Surprisingly, the most popular and accepted answer ignores triggering appropriate event despite of the comments. Make sure you invoke .change(), otherwise all the "on change" bindings will ignore this event.
$("#radio_1").prop("checked", true).change();
You have to do
jQuery("#radio_1").attr('checked', 'checked');
That's the HTML attribute
Try this
$(document).ready(function(){
$("input[name='type']:radio").change(function(){
if($(this).val() == '1')
{
// do something
}
else if($(this).val() == '2')
{
// do something
}
else if($(this).val() == '3')
{
// do something
}
});
});
If property name does not work don't forget that id still exists. This answer is for people who wants to target the id here how you do.
$('input[id=element_id][value=element_value]').prop("checked",true);
Because property name does not work for me. Make sure you don't surround id and name with double/single quotations.
Cheers!
We should want to tell it is a radio button.So please try with following code.
$("input[type='radio'][name='userRadionButtonName']").prop('checked', true);
Yes, it worked for me like a way:
$("#radio_1").attr('checked', 'checked');
This answer is thanks to Paul LeBeau in a comment. I thought I'd write it up as a proper answer since there surprisingly wasn't one.
The only thing that worked for me (jQuery 1.12.4, Chrome 86) was:
$(".js-my-radio-button").trigger("click");
This does everything I want – changes which radio button looks selected (both visually and programmatically) and triggers events such as change on the radio button.
Just setting the "checked" attribute as other answers suggest would not change which radio button was selected for me.
Try this with example
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<input type="radio" name="radio" value="first"/> 1 <br/>
<input type="radio" name="radio" value="second"/> 2 <br/>
</form>
<script>
$(document).ready(function () {
$('#myForm').on('click', function () {
var value = $("[name=radio]:checked").val();
alert(value);
})
});
</script>
$("input[name=inputname]:radio").click(function() {
if($(this).attr("value")=="yes") {
$(".inputclassname").show();
}
if($(this).attr("value")=="no") {
$(".inputclassname").hide();
}
});
Get value:
$("[name='type'][checked]").attr("value");
Set value:
$(this).attr({"checked":true}).prop({"checked":true});
Radio Button click add attr checked:
$("[name='type']").click(function(){
$("[name='type']").removeAttr("checked");
$(this).attr({"checked":true}).prop({"checked":true});
});
Just in case anyone is trying to achieve this while using jQuery UI, you will also need to refresh the UI checkbox object to reflect the updated value:
$("#option2").prop("checked", true); // Check id option2
$("input[name='radio_options']").button("refresh"); // Refresh button set
I use this code:
I'm sorry for English.
var $j = jQuery.noConflict();
$j(function() {
// add handler
$j('#radio-1, #radio-2').click(function(){
// find all checked and cancel checked
$j('input:radio:checked').prop('checked', false);
// this radio add cheked
$j(this).prop('checked', true);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset class="section">
<legend>Radio buttons</legend>
<label>
<input type="radio" id="radio-1" checked>
Option one is this and that—be sure to include why it's great
</label>
<br>
<label>
<input type="radio" id="radio-2">
Option two can be something else
</label>
</fieldset>
Try this
var isChecked = $("#radio_1")[0].checked;
I've just have a similar problem, a simple solution is to just use:
.click()
Any other solution will work if you refresh radio after calling function.
function rbcitiSelction(e) {
debugger
$('#trpersonalemail').hide();
$('#trcitiemail').show();
}
function rbpersSelction(e) {
var personalEmail = $(e).val();
$('#trpersonalemail').show();
$('#trcitiemail').hide();
}
$(function() {
$("#citiEmail").prop("checked", true)
});
$("#radio_1").attr('checked', true);
//or
$("#radio_1").attr('checked', 'checked');
I got some related example to be enhanced, how about if I want to add a new condition, lets say, if I want colour scheme to be hidden after I click on project Status value except Pavers and Paving Slabs.
Example is in here:
$(function () {
$('#CostAnalysis input[type=radio]').click(function () {
var value = $(this).val();
if (value == "Supply & Lay") {
$('#ul-suplay').empty();
$('#ul-suplay').append('<fieldset data-role="controlgroup"> \
http://jsfiddle.net/m7hg2p94/4/
attr accepts two strings.
The correct way is:
jQuery("#radio_1").attr('checked', 'true');
In addition, you can check if the element is checked or not:
if ($('.myCheckbox').attr('checked'))
{
//do others stuff
}
else
{
//do others stuff
}
You can checked for unchecked element:
$('.myCheckbox').attr('checked',true) //Standards way
You can also uncheck this way:
$('.myCheckbox').removeAttr('checked')
You can checked for radio button:
For versions of jQuery equal or above (>=) 1.6, use:
$("#radio_1").prop("checked", true);
For versions prior to (<) 1.6, use:
$("#radio_1").attr('checked', 'checked');
I used jquery-1.11.3.js
Basic Enable & disable
Tips 1: (Radio button type common Disable & Enable)
$("input[type=radio]").attr('disabled', false);
$("input[type=radio]").attr('disabled', true);
Tips 2: ( ID selector Using prop() or attr())
$("#paytmradio").prop("checked", true);
$("#sbiradio").prop("checked", false);
jQuery("#paytmradio").attr('checked', 'checked'); // or true this won't work
jQuery("#sbiradio").attr('checked', false);
Tips 3: ( Class selector Using prop() or arrt())
$(".paytm").prop("checked", true);
$(".sbi").prop("checked", false);
jQuery(".paytm").attr('checked', 'checked'); // or true
jQuery(".sbi").attr('checked', false);
OTHER TIPS
$("#paytmradio").is(":checked") // Checking is checked or not
$(':radio:not(:checked)').attr('disabled', true); // All not check radio button disabled
$('input[name=payment_type][value=1]').attr('checked', 'checked'); //input type via checked
$("input:checked", "#paytmradio").val() // get the checked value
index.html
<div class="col-md-6">
<label class="control-label" for="paymenttype">Payment Type <span style="color:red">*</span></label>
<div id="paymenttype" class="form-group" style="padding-top: inherit;">
<label class="radio-inline" class="form-control"><input type="radio" id="paytmradio" class="paytm" name="paymenttype" value="1" onclick="document.getElementById('paymentFrm').action='paytmTest.php';">PayTM</label>
<label class="radio-inline" class="form-control"><input type="radio" id="sbiradio" class="sbi" name="paymenttype" value="2" onclick="document.getElementById('paymentFrm').action='sbiTest.php';">SBI ePAY</label>
</div>
</div>
try this
$("input:checked", "#radioButton").val()
if checked returns True
if not checked returns False
jQuery v1.10.1
Some times above solutions do not work, then you can try below:
jQuery.uniform.update(jQuery("#yourElementID").attr('checked',true));
jQuery.uniform.update(jQuery("#yourElementID").attr('checked',false));
Another way you can try is:
jQuery("input:radio[name=yourElementName]:nth(0)").attr('checked',true);

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