I have a textbox with input value of 20,466,000.00 . I want to return only the value of 20466000 without a comma and a decimal point. I tried the following :
// Get value
var nca_balance = $("#nca-balance").text();
var nca_amount = parseInt(nca_balance.replace(",", ""),10);
alert(nca_amount);
But it only returns the value of 20466 ? Why ? My expected result must be 20466000. Please help with my code. Thanks
How about this one:
parseInt("20,466,000.00".replace(/,/g, ""), 10)
Because replace is replacing the first comma by default use g as global option in replace regular expression /,/g like,
var nca_balance = $("#nca-balance").text();
var nca_amount = parseInt(nca_balance.replace(/,/g, ""),10);
alert(nca_amount);
var nca_balance = $("#nca-balance").text();
var nca_amount = parseInt(nca_balance.replace(/,/g, ""), 10);
alert(nca_amount);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<span id="nca-balance">20,466,000.00<span>
You have to use regular expression instead of replace function because replace function will replace only first matching character.
nca_balance = "20,466,000.00";
var nca_amount = parseInt(nca_balance.replace(/,/g, ''));
alert(nca_amount);
Regular expression /,/g will replace all comma with your provided character globally.
Related
I have the below input
var input = (a-d){12-16},(M-Z){5-8},[#$%!^,12+-,23^!]
I need to remove the comma within the square brackets such that the final output will be
var output = (a-d){12-16},(M-Z){5-8},[#$%!^12+-23^!]
By solution
function test()
{
var input = '(a-d){12-16},(M-Z){5-8},[#$%!^,12+-,23^!]'; //input string
var splitByFirstBracket = input.split("["); //split the input by [ character
//merge the arrays where the second array is replaced by '' for ','
var output = splitByFirstBracket[0] + '[' + splitByFirstBracket[1].replace(/,/g,'');
alert(output);
}
It is providing the output correctly. Is there any better way - I am open both for JavaScript and JQuery.
Thanks in advance
You can use a regular expression replacement. The replacement can be a function, which receives the part of the input that was matched by the regexp, and then it can calculate the replacement. In this case, it would use another replace call to remove the commas.
var input = '(a-d){12-16},(M-Z){5-8},[#$%!^,12+-,23^!]'; //input string
var output = input.replace(/\[.*?\]/g, function(match) {
return match.replace(/,/g, '');
});
console.log(output);
A string representing a currency is to be converted to a number.
For example:
Input : "125.632.454.454.403,51"
Output expected : 125632454454403.51
Currently I am trying:
Trial 1)
a = "125.632.454.454.403,51";
a.replace(/./, '');
Result = "25.632.454.454.403,51"
Trial 2)
a = "125.632.454.454.403,51";
a.replace(/./g, '');
Result = ""
But I expect the replace function to find all the occurrences of "." and replace by "".
Trial 3)
a = "125.632.454.454.403,51";
a.replace(/,/, '');
Result = "125.632.454.454.40351"
I would be glad if I find a fix for this.
You need to use \. instead of .. The dot (.) matches a single character, without caring what that character is. Also you can do it with single replace() with callback .
var str = "125.632.454.454.403,51";
str = str.replace(/\.|,/g, function(m) {
return m == '.' ? '' : '.'
});
document.write(str);
try:
var str = "125.632.454.454.403,51" ;
var result = str.replace(/\./g,'').replace(/\,/g,'.');
console.log(Number(result))
replace returns the changed string, it does not change it in-place!
You can find this out, by refering to the documentation.
Use
var Result = a.split('.').join("");
console.log(Result);
. has specific meaning in a regex. It matches any character. You need to escape the dot if you are actually looking for the character itself
var a = "125.632.454.454.403,51";
var result = a.replace(/\./g,"");
You can also do (parseFloat(a.replace(/[^0-9]+/g,""))/100)
And if you have to do this for multiple currencies, I would recommend looking into autonumeric.js. It handles all this for you.
I have the next code that was given to me to split up a string into an array.
var chk = str.split(/[^a-z']+/i);
The problem I'm having with this solution is that if the string has a period in the end, it's being replaced with ","
For example:
If I have the next string: "hi,all-I'm-glad."
The solution above results: "hi,all,I'm,glad," (notice the "," in the end).
I need that the new string will be: "hi,all,I'm,glad"
How can I acheive it ?
Check for a . being the last character and remove it first
var str = "hi,all-I'm-glad. that you, can help,me. that-doesn't make any-sense, I know.";
if(str.charAt( str.length-1 ) == ".") {
str = str.substring(0,str.length-1);
}
var chk = str.split(/[^a-z']+/i);
console.log(chk);
var chk = str.match(/[a-z']+/gi);
console.log(chk);
You could check to see if the last element of your string array returns an empty string and remove that element
if (chk[chk.length-1] == "")
{
chk.pop();
}
var chk="to.to.".split(/[^a-z']+/i); if(chk[chk.length-1].length==0){chk.pop()}; console.log(chk);
To remove the last value of your array using pop if this one is empty.
You can utilize the pure regex power:
"hi,all-I'm-glad. that you, can help,me. that-doesn't make any-sense, I know.".replace(/[\-\.\s]/g, ',').replace(/,{2,}/g, ',').replace(/,$/,'')
i want to select a sting from the long para. it has number of dot('.')s. i want to trim the word from the second one, is it any way to do this?
example
var name = "one.two.three";
name.substring(0,name.indexOf('.'))
name.substring(0,name.lastIndexOf('.'))
from above trimming in case if i use indexOf it gives first word (one), if i use lastIndex of it gives the word (three), but i need to select the second one, to get value as 'second'
how can i trim this using indexOf method? or to select multicombination strings like one.three or one.two, or two.three?
thanks in advance!
use string.split.
e.g.
name.split(".")[1]
var name="one.two.three";
var result=name.split(".").slice(0,2).join(".");
Example:
"".split(".").slice(0,2).join(".") // return ""
"one".split(".").slice(0,2).join(".") // return "one"
"one.two".split(".").slice(0,2).join(".") // return "one.two"
"one.two.three".split(".").slice(0,2).join(".") // return "one.two"
"one.two.three.four.five".split(".").slice(0,2).join(".") // return "one.two"
Is that work for you ?
var name = "one.two.three";
var params = name.split('.');
console.log(params[1]);
use Split
var name = "one.two.three";
var output = name.split('.');
alert(output[1]);
example here
I have a string like foobar1, foobaz2, barbar23, nobar100 I want only foobar, foobaz, barbar, nobar and ignoring the number part.
If you want to strip out things that are digits, a regex can do that for you:
var s = "foobar1";
s = s.replace(/\d/g, "");
alert(s);
// "foobar"
(\d is the regex class for "digit". We're replacing them with nothing.)
Note that as given, it will remove any digit anywhere in the string.
This can be done in JavaScript:
/^[^\d]+/.exec("foobar1")[0]
This will return all characters from the beginning of string until a number is found.
var str = 'foobar1, foobaz2, barbar23, nobar100';
console.log(str.replace(/\d/g, ''));
Find some more information about regular expressions in javascript...
This should do what you want:
var re = /[0-9]*/g;
var newvalue= oldvalue.replace(re,"");
This replaces al numbers in the entire string. If you only want to remove at the end then use this:
var re = /[0-9]*$/g;
I don't know how to do that in JQuery, but in JavaScript you can just use a regular expression string replace.
var yourString = "foobar1, foobaz2, barbar23, nobar100";
var yourStringMinusDigits = yourString.replace(/\d/g,"");