input:
"/desh/HRTY/THR/TDR/2015-01-09?passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false"
javascript:
var params = {};
var paramDelim = link.indexOf('?');
var parmeters = link.substring(paramDelim + 1, link.length);
var parts = parmeters.split('[&=]');
output of my js code:
0: "passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false"
length: 1
i want to split my url into a map with key:value like this
output:
origin:THR
destination:TDR
goDate:2015-01-09
passengers:STANDARD:1
returnDate:2015-01-10
max:0
withThac:false
My code not do exactly what i want in output, what is wrong ?
You should split with
var params = parmeters.split('&')
and then split all the values you get
for (var i = 0,len = params.length; i<len;i++){
var data = params[i].split("=", 2); // Max 2 elements
var key = data[0];
var value = data[1];
...
}
i think your wrong ' characters
var params = {};
var paramDelim = link.indexOf('?');
var parmeters = link.substring(paramDelim + 1, link.length);
/*--> i think used regexp. Clear ' Char. --> */var parts = parmeters.split(/[&=]/);
use this like..
good luck
A possible solution using ECMA5 methods and assuming that your string is always the same pattern.
var src = '/desh/HRTY/THR/TDR/2015-01-09?passengers=STANDARD:1&returnDate=2015-01-10&max=0&withThac=false',
slice = src.split(/[\/|?|&]/).slice(3),
data = slice.reduce(function (output, item) {
var split = item.split('=');
output[split.shift()] = split.shift();
return output;
}, {
origin: slice.shift(),
destination: slice.shift(),
goDate: slice.shift()
});
document.body.appendChild(document.createTextNode(JSON.stringify(data)));
Related
Hi I'm trying to split between a string that contain a number image src and store them in an array. for now i can only get 1 image src, how can I loop through and store all src images into an array?
var s = contentHtml;
//splits the first src
var arrStr = s.split('<img src="').pop().split('"').shift();
var numofimg = (s.split('<img src="').length - 1);
var myarray = [numofimg];
if (numofimg != 0) {
for (int i = 0; i < numofimg; i++) {
}
}
If you really want to do this with just strings (i.e. all of the img tags are consistently formatted, no extra attributes, etc.) you can use a regular expression to handle it.
var contentHtml = "<html>Some junk<img src=\"abc.jpg\" />Some junk<img src=\"def.jpg\" /><p>Some junk<img src=\"9000.gif\" /></p></html>";
var results = [];
var rgx = /<img src="([^"]+)"/g;
var match;
while (match = rgx.exec(contentHtml)) {
results.push(match[1]); // match[1] contains the captured group
}
console.log(results);
If it's a more complex document or not consistent, there are probably better ways to do it.
var strImages = '<img src="afoo.jpg"><img src="bar.jpg"><img src="banana.jpg">';
var rePattern = /src="(.+?)"/g;
var arSources = [];
reMatch = rePattern.exec(strImages);
while (reMatch !== null) {
arSources.push(reMatch[0]);
reMatch = rePattern.exec(strImages);
};
console.log(arSources);
Given a slash separated URL like http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3 how could I build a key/value Object with the dynamic parameters (param1/value, param2/value2...) of this URL?
Valid parameters always have this slash separated paramand value format and some/fixed/path would be a substring manually provided.
I tried to split the full URL (or whatever it could be) by the fixed substring and I managed to slice the dynamic params out of it as I wanted but I couldn't create the key/value Object as I needed:
var url = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
var uri = "some/fixed/path/";
var result = {};
url.split( uri ).forEach(function(x){
var arr = x.split('/');
arr[1] && (result[arr[0]] = arr[1]);
});
console.log( result );
But this piece of code only brings me the first pair instead of all of them and it requires the uri to obligatorily have a trailing slash. If the substring doesn't have it or has one to the left it acts all weird with a blank key and the first key as value o.O
I know it's simple, but I just can't do it. I tried to search but this must have a very specific way to refer to because I couldn't find by my own.
One last thing, if you don't mind explain instead of just give me the fish, I'd appreciate, so there won't have a next time... hopefully
You were only taking the second part after some/fixed/path/. You need to split this second part and iterates over the array. On each even index, I create a new property in the object with the name of the previous element
x is the current element
i is the current index
a is the array containing each element after splitting with /
var url = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
var uri = "some/fixed/path/";
var result = {};
var paramsToSplit = url.split(uri)[1];
paramsToSplit.split('/').forEach((x,i,a)=>{
if(i%2)
result[a[i-1]] = x;
});
console.log( result );
Try this:
var url = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
var uri = "some/fixed/path/";
var url = url.substring(url.indexOf(uri) + uri.length)
var options = url.split('/');
var results = [];
for(var i=0;i<options.length; i+=2){
results.push({[options[i]]:options[i+1]})
}
Are you looking for somethig like that?
var url = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
var uri = "some/fixed/path/";
var params = [];
var values = [];
var results = {};
url.split( uri )[1].split('/').forEach(function(e,i) {
if(i%2==0){
params.push(e)
} else {
values.push(e);
}
})
console.log( params, values );
params.forEach(function(e,i) {
results[e] = values[i];
});
console.log( results );
You may do as follows;
var text = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
result = text.split("/")
.slice(6)
.reduce((r,c,i,a) => i&1 ? Object.assign(r,{[a[i-1]]: c}) : r, {});
console.log(result);
You are quite close, you basically need to make another for loop for your produced arr and step every 2 values. Like so...
var url = "http://www.example.com/some/fixed/path/param1/value1/param2/value2/param3/value3";
var uri = "some/fixed/path/";
var result = {};
url.split( uri ).forEach(function(x){
var arr = x.split('/');
var step;
for (step = 0; step <= arr.length; step += 2) {
arr[step + 1] && (result[arr[step]] = arr[step + 1]);
}
});
console.log( result );
We have a string ,
var str = "Name=XYZ;State=TX;Phone=9422323233";
Here in the above string we need to fetch only the State value i.e TX. That is 2 characters after the substring State=
Can anyone help me implement it in javascript.
.split() the string into array and then find the index of the array element having State string. Using that index get to that element and again .split() it and get the result. Try this way,
var str = "Name=XYZ;State=TX;Phone=9422323233";
var strArr = str.split(';');
var index = 0;
for(var i = 0; i < strArr.length; i++){
if(strArr[i].match("State")){
index = i;
}
}
console.log(strArr[index].split('=')[1]);
jsFiddle
I guess the easiest way out is by slicing and splitting
var str = "Name=XYZ;State=TX;Phone=9422323233";
var findme = str.split(';')[1];
var last2 = findme.slice(-2);
alert(last2);
Need more help? Let me know
indexOf returns the position of the string in the other string.
Using this index you can find the next two characters
javascript something like
var n = str.indexOf("State=");
then use slice method
like
var res = str.slice(n,n+2);
another method is :
use split function
var newstring=str.split("State=");
then
var result=newstring.substr(0, 2);
Check this:
var str1 = "Name=XYZ;State=TX;Phone=9422323233";
var n = str1.search("State");
n=n+6;
var res = str1.substr(n, 2);
The result is in the variable res, no matter where State is in the original string.
There are any number of ways to get what you're after:
var str = "Name=XYZ;State=TX;Phone=9422323233"
Using match:
var match = str.match(/State=.{2}/);
var state = match? match[0].substring(6) : '';
console.log(state);
Using replace:
var state = str.replace(/^.*State=/,'').substring(0,2);
console.log(state);
Using split:
console.log(str.split('State=')[1].substring(0,2));
There are many other ways, including constructing an object that has name/value pairs:
var obj = {};
var b = str.split(';');
var c;
for (var i=b.length; i; ) {
c = b[--i].split('=');
obj[c[0]] = c[1];
}
console.log(obj.State);
Take your pick.
Hi I have some vars like this:
var a = Base-Shirt_Stripe.jpg
var b = Closed-Flatknit-Collar_Stripe.png
How do i create two new vars like:
var c = Base-Shirt
var d = Stripe
or
var e = Closed-Flatknit-Collar
var f = Stripe
basically split at the _ remove the _ and remove the extension.
//for example, we take a
var a = 'Base-Shirt_Stripe.jpg';
//then we take the part of a before the dot
//and split between `_`
//split returns an array
var split = a.substring(0,a.indexOf('.'))
.split('_');
//split is an array, so we use indices to indicate which
console.log(split[0]); //Base-Shirt
console.log(split[1]); //Stripe
Sample here. You can do the same for your b
may be you could do like
var a = "Base-Shirt_Stripe.jpg"
var k = a.replace(/(\.\w*)$/g, "").split("_");
alert(k[0]);
alert(k[1]);
here is the fiddle
You need to make them strings to start with, then use String.split() to split the string into an array of the different parts.
jsFiddle
var a = "Base-Shirt_Stripe.jpg"
var b = "Closed-Flatknit-Collar_Stripe.png"
var aSplit = a.substr(0, a.lastIndexOf('.')).split('_');
var c = aSplit[0];
var d = aSplit[1];
var bSplit = b.substr(0, b.lastIndexOf('.')).split('_');
e = bSplit[0];
f = bSplit[1];
You could also take the removal of the extension out into its own function using String.lastIndexOf() and String.substr().
function removeExtension(file) {
return file.substr(0, file.lastIndexOf('.'));
}
//Javascript Split can divide it into parts. Javascript Split return type is array.'
//e g.
var a = Base-Shirt_Stripe.jpg
var parts = a.split('_');
console.log(parts[0]);
//output
" Base-Shirt "
//parts[0] contain base-shirt and parts[1] contain Stripe.jpg.
Hi i am trying to get each longitude and latitude that arrives in this format:
(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)
I wish to store them in these strings tmpLon1 tmpLat1 tmpLon2 tmpLat2 tmpLon3 tmpLat3 tmpLon4 tmpLat4
So far i have done this coding but it fails to work, any body have a better method and could code up an example please ?
//(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)
//Remove all the shit
longlat = (longlat.replace(/\(/g,""));
longlat = (longlat.replace(/\)/g,"|"));
longlat = (longlat.replace(/\ /g,""));
//52.99315484540412,-1.179145092694469|52.99315323095451, -1.1786797294303852|52.993042641012025, -1.1789238104507405|52.99308461678997, -1.1791705736801106|
//Now split out each long lat
tmpLon1 = longlat.split(",","1"); //ok
tmpLat1 = longlat.replace(tmpLon1 + ",","");
tmpLon2 = tmpLat1;
tmpLat1 = tmpLat1.split("|","1"); //ok
tmpLon2 = tmpLon2.split("|","2");
tmpLon2 = tmpLon2.replace(tmpLat1,"");
tmpLat2 = longlat.split(",","4");
tmpLon3 = "";
tmpLat3 = "";
tmpLon4 = "";
tmpLat4 = "";
I'd do this:
var a = "(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)",
latLngs = [],
pairs = a.replace(/^\(|\)$/g,'').split(')(');
for(var i=0,pair;pair=pairs[i];i++) {
pair = pair.split(',');
latLngs.push({lat: +pair[0], lng: +pair[1]});
}
console.log(latLngs);
you can see it live here: http://jsfiddle.net/LCYrg/
You could also simply do:
var a = "(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)",
JSON.parse(a.split(')(').join('],[').replace('(','[[').replace(')',']]'));
But this would require the JSON object to be present, which is not the case in ie7 and below. This could be fixed by including the json2.js file found here: https://github.com/douglascrockford/JSON-js
Regex to the rescue! Since you know the format of your string, you can use regex here to search for you.
var str = "(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, 1.1789238104507405)(52.99308461678997, -1.1791705736801106)";
var regex = /\((-?[0-9]+\.[0-9]+), (-?[0-9]+\.[0-9]+)\)/g;
var latlonArray = [];
var match = regex.exec(str);
while (match) {
latlonArray.push({
"lat" : match[1],
"lon" : match[2]
});
match = regex.exec(str);
}
var tmpLon1 = latlonArray[0].lon;
var tmpLat1 = latlonArray[0].lat;
var tmpLon2 = latlonArray[1].lon;
var tmpLat2 = latlonArray[1].lat;
var tmpLon3 = latlonArray[2].lon;
var tmpLat3 = latlonArray[2].lat;
var tmpLon4 = latlonArray[3].lon;
var tmpLat4 = latlonArray[3].lat;
Example: http://jsfiddle.net/jonathon/57rE4/
The latlonArray is an array of objects with lat and lon properties, containing the ones found in your string.
Note: the regex I used here is just something I came up with. It works with your example input but might not necessarily be the best.
Also note: this isn't meant to be 'pull out and use' JavaScript. It's merely showing you another way to do it. I'd recommend optimising it by various means (e.g. moving all vars to the top, etc).
i guesy u can do something like:
(assuming input is your input string)
input = input.replace(/\s/,''); //remove spaces
var pairs_strings = input.substring(1,-1).split(")("); //remove braket of start and end and then split into pairs
var pairs = new Array();
for(var i=0; i<paris_strings.length; i++){
lon = pairs_strings[i].split(",").shift();
lat = pairs_strings[i].split(",").pop();
pairs[i] = new Array(lon, lat);
}
var tmpLon1 = pairs[0][0];
var tmpLan1 = pairs[0][1];
....
but be aware it's not tested and i don't know what will happend with the negative values
If your input format is not changing you could do it in 3 lines:
var str = "(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)";
var pattern = /([\d\.-]+),\s([\d\.-]+)\)\(([\d\.-]+),\s([\d\.-]+)\)\(([\d\.-]+),\s([\d\.-]+)\)\(([\d\.-]+),\s([\d\.-]+)/;
var result = str.match(pattern);
To get the results use:
tmpLon1=result[1];
tmpLon2=result[3];
tmpLon3=result[5];
tmpLon4=result[7];
tmpLat1=result[2];
tmpLat2=result[4];
tmpLat3=result[6];
tmpLat4=result[8];
var str = "(52.99315484540412, -1.179145092694469)(52.99315323095451, -1.1786797294303852)(52.993042641012025, -1.1789238104507405)(52.99308461678997, -1.1791705736801106)";
var str = str.replace(/\)\(/g,', ').replace(/\(|\)/g,'').split(", ");
To get the results:
tmpLon1=result[0];
tmpLon2=result[2];
tmpLon3=result[4];
tmpLon4=result[6];
tmpLat1=result[1];
tmpLat2=result[3];
tmpLat3=result[5];
tmpLat4=result[7];