I am trying to make a stepy-form for my project. What I want to do is I want to submit all my data step by step in stepy-form so I used an AJAX request for this purpose, but When I am trying to save it it's not working. So I used noConflict Method to avoid jQuery conflicts but I still have the same problem. I am using adminEX template And Not getting any error message. So can anyone help me?
<script src="ajax/jquery.min.js"></script>
<script>
$.noConflict();
Jquery(document).ready(function(){
$('#stepy_form').click(function(){
$.ajax({
type: 'POST',
url: 'ajax/insert_all.php',
data: {
txtVehicleNo: txtVehicleNo,
SltType: SltType,
txtPANNumber: txtPANNumber,
txtManufacture: txtManufacture,
txtModel: txtModel,
txtEngineNumber: txtEngineNumber,
txtChassisNumber: txtChassisNumber,
txtOwnerName: txtOwnerName,
txtUnlaidenWt: txtUnlaidenWt,
txtGVW: txtGVW
// qid: 'form1'
},
//alert('hello');
//async: true,
//cache: false,
success: function(result) {
alert('SUCCESS');
//$('#target').html(result);
}
});
});
});
</script>
And this one is the URL ,insert_all.php
$qid = $_POST['qid'];
echo $qid;
You are not using 'no conflict' with jquery and accessing it using $. Change $ with jQuery like this
$.noConflict();
jQuery(document).ready(function(){
jQuery('#stepy_form').click(function(){
jQuery.ajax({
type: 'POST',
url: 'ajax/insert_all.php',
data: {
txtVehicleNo: txtVehicleNo,
SltType: SltType,
txtPANNumber: txtPANNumber,
txtManufacture: txtManufacture,
txtModel: txtModel,
txtEngineNumber: txtEngineNumber,
txtChassisNumber: txtChassisNumber,
txtOwnerName: txtOwnerName,
txtUnlaidenWt: txtUnlaidenWt,
txtGVW: txtGVW
},
success: function(result) {
alert('SUCCESS');
//$('#target').html(result);
}
});
});
});
Related
<script type="text/javascript">
$(function() {
$("#epdate").bind("change", function() {
$.ajax({
type: "GET",
url: "change6-emp.php",
data: "epdate="+$("#epdate").val(),
success: function(html) {
$("#output").html(html);
}
});
});
});
</script>
i have this code and i want to add another variable
inside ajax script adding another
data: "empname="+$("#empname").val(),
dopesnt work i hope someone would help me. thank you
and how can i call a postname or make a postname into session an call it into another php page?
Actually, there are multiple ways, either separate them using a & character.
<script type="text/javascript">
$(function() {
$("#epdate").bind("change", function() {
$.ajax({
type: "GET",
url: "change6-emp.php",
data: "epdate=" + $("#epdate").val() + "&empname="+$("#empname").val(),
success: function(html) {
$("#output").html(html);
}
});
});
});
</script>
Or alternatively, you can use an object which holds the name-value pair.
<script type="text/javascript">
$(function() {
$("#epdate").bind("change", function() {
$.ajax({
type: "GET",
url: "change6-emp.php",
data: { epdate : $("#epdate").val(), empname : $("#empname").val() },
success: function(html) {
$("#output").html(html);
}
});
});
});
</script>
UPDATE 1: You can also pass it as an array in the following format,
data : [{
name : 'epdate',
value : $("#epdate").val()
}, {
name : 'empname',
value : $("#empname").val()
}],
UPDATE 2: There is build in functions in jQuery to do the same, use [serialize()][] or serializeArray() method for that. You can apply it on a form element or input elements and which generates based on the input elements name attribute.
data : $('#epdate,#empname').serialize(),
// or
data : $('#epdate,#empname').serializeArray()
,
I have tried to ajax using post to jsp script my html table rows for weeks now with no success.Can anyone please guide me on this?Below is what I have done so far.
window.addEventListener("DOMContentLoaded", function () {
var form = document.getElementById("updateDealPmtForm");
document.getElementById("btn").addEventListener("click", function () {
$('#notSoCoolGrid > tr').each(function(event) {
event.preventDefault();
var postData = {
paymentId:$('#paymentId').text(),
id:$('#deald').text(),
pType:$('#pType').text(),
pAmt:$('#pAmt').text(),
currency:$('#currency').text(),
pInvDate:$('#pInvDate').text(),
pRecDate:$('#pRecDate').text(),
comments:$('#comments').text()
};
console.log(postData);
$.ajax({
async: false,
type: "POST",
cache: false,
url: "/update_deal_pmt_script.jsp",
data: postData.$('input, select').serialize() ,
success: function(msg){
alert("submitted");
}
});
});
});
If I correctly understand your need, you want to transmit the content of your rows, each in the form showed in your current postData.
So this can be made at once for all rows (instead of ajaxing successively each of them).
It might be something like this:
window.addEventListener("DOMContentLoaded", function () {
var form = document.getElementById("updateDealPmtForm");
document.getElementById("btn").addEventListener("click", function () {
event.preventDefault();
var postData = [];
$('#notSoCoolGrid > tr').each(function(event) {
postData.push(
paymentId:$('#paymentId').text(),
id:$('#deald').text(),
pType:$('#pType').text(),
pAmt:$('#pAmt').text(),
currency:$('#currency').text(),
pInvDate:$('#pInvDate').text(),
pRecDate:$('#pRecDate').text(),
comments:$('#comments').text()
);
});
console.log(postData);
$.ajax({
async: false,
type: "POST",
cache: false,
url: "/update_deal_pmt_script.jsp",
data: postData,
success: function(msg){
alert("submitted");
}
});
});
});
Note that I choosed (the simplest way, IMO) to make a simple array of rows, where each one is an object like you already structured them.
Last point: I notice you specified async: false.
I don't know why you did that, and so I kept it unchanged.
But note that it's not recommended, and is being on the road to become deprecated.
I finally was able to solve this issue,for that I want to post my answer it might be helpful for someone out there.My previous code was submitting a form before even ajax call being triggered and I have to use Classes instead of IDs to identify my rows.I had to change the code completely to be able to submit the form
$('#btn').click(function(e) {
e.preventDefault();
$('#notSoCoolGrid tr').each(function(i, tr) {
var postData = {
paymentId : $('.paymentId', tr).val(),
id : $('.deald', tr).val(),
pType:$('.pType', tr).val(),
pAmt:$('.pAmt',tr).val(),
currency:$('.currency',tr).val(),
pInvDate:$('.pInvDate',tr).val(),
pRecDate:$('.pRecDate',tr).val(),
comments:$('.comments',tr).val()
}
$.ajax({
async: false,
type: "post",
url: "/update_deal_pmt_script.jsp",
data: postData
})
.done(function(response) {
console.log(response);
})
.fail(function(x, status, error) {
alert("Error: " + error);
});
});
});
I am a beginner in JavaScript means and programming, and I encountered a problem for a personal project. I made an anime fight website getting some information from MySQL Database each anime has ten videos and photos, through a random button it randomly takes one link for a video and photo. The problem is that it only work only one time if I random again nothing happens. I know that in order to make that work I have to rewrite the code again after the success of the first random for getting a second random but this will create an infinite loop. Can somebody help me solve this issue.
This is the code used:
<script>
$(document).ready(function () {
$('.imgResponsive').click(function(){
$('#hiddenPage').hide();
$('#hiddenPage').html('<center><img src="img/loading.gif"></center>');
$('#hiddenPage').show();
$.ajax({
type: 'POST',
url: 'php/handler.php',
data: {
anime: $(this).prev().val()
},
success: function(response){
$('#hiddenPage').html(response);
$('#random').click(function(){
$('#hiddenPage').hide();
$('#hiddenPage').html('<center><img src="img/loading.gif"></center>');
$('#hiddenPage').show();
$.ajax({
type: 'POST',
url: 'php/handler.php',
data: {
anime: $(this).prev().val()
},
success: function(response){
$('#hiddenPage').html(response);
}
});
})
}
});
})
});
</script>
I understand that $.ajax request overwrites initial .imgResponsive element, am I right? Along with overwritten .imgResponsive you permanently lose click event attached to this element.
In that case you need to attach event to element container, eg.
$(document).on('click', '.imgResponsive', function() {....
...
}
instead of
$('.imgResponsive').click(function(){ ....
You have to register EventListener in order to proceed.
Try this:
<script>
var showImage = function(e){
e.preventDefault();
$('#hiddenPage').hide();
$('#hiddenPage').html('<center><img src="img/loading.gif"></center>');
$('#hiddenPage').show();
$.ajax({
type: 'POST',
url: 'php/handler.php',
data: {
anime: $(this).prev().val()
},
success: function(response){
$('#hiddenPage').html(response);
}
});
};
$(document).ready(function () {
$('document').on('click', '.imgResponsive', showImage);
$('document').on('click','#random', showImage);
});
</script>
The way your code is written, you're handling only a single AJAX response (aside from the first one) with no way to handle more AJAX requests triggered by clicking the #random button. You need to write functions for handling button clicks and the AJAX responses instead of using anonymous functions; that way it's modular enough that you can listen for and handle more button clicks in the future.
Something like this:
<script>
$(document).ready(function () {
$('.imgResponsive').click(function(){
$('#hiddenPage').hide();
$('#hiddenPage').html('<center><img src="img/loading.gif"></center>');
$('#hiddenPage').show();
$.ajax({
type: 'POST',
url: 'php/handler.php',
data: {
anime: $(this).prev().val()
},
success: handleResponse
});
$('#random').click(handleButtonClick);
});
function handleButtonClick(e){
$('#hiddenPage').hide();
$('#hiddenPage').html('<center><img src="img/loading.gif"></center>');
$('#hiddenPage').show();
$.ajax({
type: 'POST',
url: 'php/handler.php',
data: {
anime: $(this).prev().val()
},
success: handleResponse
});
}
function handleResponse(response){
$('#hiddenPage').html(response);
}
});
</script>
Edit: Another thing that might be happening is that your #random element is being overwritten every time you do $('#hiddenPage').html(response);. In that case you would need to attach a new event handler to the new #random element every time you handle an AJAX response:
function handleResponse(response){
$('#hiddenPage').html(response);
$('#random').click(handleButtonClick);
}
I try AJAX and JSON.
I have got this very simple scripts. Could you help me to get it work?
html file
<div class="esemeny">
<h2>Event</h2>
<p></p>
<button>click</button>
</div>
json file, I call it eventresult.json
{name: whatever,
}
and the javascript file
$(function(){
$('button').on('click', function(){
$.ajax('/javascript/eventresult.json', {
dataType: 'json',
success: function(result){
var esemeny = $('.esemeny');
esemeny.find('p').html(result.name);
}
});
});
});
Thank you
You didn't tell what did want to do exactly, anyway I think, this what you want to do:
JSON:
{
name: "whatever"
}
JS:
$(function(){
$('button').on('click', function(){
$.ajax('/javascript/eventresult.json', {
dataType: 'json',
type: 'GET' // you want to get content
success: function(result){
var esemeny = $('.esemeny');
esemeny.find('p').html(result.name);
}
});
});
});
Hope that helps a bit
I guess your JSON should look like
{
name: "whatever"
}
Mind the double quotes and the unnecessary comma.
Well,you actually didn't descripte the question clearly.You can have a debug that can be seen from your firebug console,like this:
$.ajax('/javascript/eventresult.json', {
dataType: 'json',
success: function(result){
var esemeny = $('.esemeny');
esemeny.find('p').html(result.name);
}
}).fail(function(jqXHR, textStatus, errorThrown){console.log(textStatus+':'+ errorThrown)})
Here are some suggestions that should make it work:
Make sure you include the necessary script files in your html file:
<head>
<script type='text/javascript' src='http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js'></script>
</head>
<div class="esemeny">
<h2>Event</h2>
<p></p>
<button>click</button>
</div>
<script src="javascript.js"></script>
Make sure you use valid json in the json file
{
"name": "whatever"
}
Use .click() function in your javascript:
$(function() {
$('button').click(function() {
$.ajax('/trials/eventresult.json', {
dataType: 'json',
success: function(result) {
var esemeny = $('.esemeny');
esemeny.find('p').html(result.name);
}
});
});
});
I am working with codeigniter and jquery. I am using ajax to send some info to a codeigniter function to perform a db operation , in order to update the page. After the operation is complete I am trying to refresh the page. However the refresh works inconsistently and usually I have to reload the page manually. I see no errors in firebug:
var message = $('#send_message').val()
if ((searchIDs).length>0){
alert("searchIDs "+searchIDs );
$.ajax({
type: "POST",
url: "AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
success: function(){
alert("OK");
},
complete: function() {
location.href = "pan_controller/my_detail";
}
})
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("OK");
location.href = "pan_controller/my_detail";
});
} else { alert("nothing checked") }
break;
How can I fix this?
addendum: I tried changing to ;
$.ajax({
type: "POST",
url: "AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("REFRESHING..");
location.href = "pan_controller/my_detail";
});
}
})
This is just defaulting to the website homepage. again, no errors in firebug
Add the window object on location.href like this:
window.location.href = "pan_controller/my_detail";
Try to use full path like
$.ajax({a
type: "POST",
url: "YOURBASEPATH/AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("REFRESHING..");
location.href = "YOURBASEPATH/pan_controller/my_detail";
});
}
})
BASEPATH should be like this "http://www.example.com"
Try disabling the csrf_enabled (config/config.php) and trying it. If that works, then re-enable the protection and, instead of compiling data yourself, serialize the form; or, at least include the csrf hidden field codeigniter automatically adds. You can also use GET to avoid the CSRF protection, but that's least advisable of of the solutions.