I want to renumber the integers inside a string, that has this format (letters and int numbers): "e1b2xx4d3".
In this example, I want to get: "e1b2xx3d4";
I have written the following JS code:
var count = 0;
var matches;
var transcript = "e1b2xx4d3";
var transcript1 = transcript;
regex = /\d+/g;
while ((matches = regex.exec(transcript)) !== null) {
transcript1 = transcript1.replace(matches[0], ++count);
}
console.log(transcript1);
The idea is to replace each number in the string by its sequence number (count), but it does not work because of destructive replaces (here, we get "e1b2xx4d3", because "xx4" is replaced with "xx3", but at the next iteration by "xx4" back).
I need to do this with regex because the case that I deal with is more complex than the one shown and requires using regex.
I think that I have to do it in two passes (iterations): 1. compiling replacements and 2. applying replacements simultaneously.
By curiousity, can someone find a way to do this in one pass ?
Fiddle: http://jsfiddle.net/0frru6fr/
This is usually done with a replacing function:
n = 0
result = "e1b2xx4d3".replace(/\d+/g, function() { return ++n })
alert(result)
See docs for more info.
Related
I am using extendscript to build some invoices from downloaded plaintext emails (.txt)
At points in the file there are lines of text that look like "Order Number: 123456" and then the line ends. I have a script made from parts I found on this site that finds the end of "Order Number:" in order to get a starting position of a substring. I want to use where the return key was hit to go to the next line as the second index number to finish the substring. To do this, I have another piece of script from the helpful people of this site that makes an array out of the indexes of every instance of a character. I will then use whichever array object is a higher number than the first number for the substring.
It's a bit convoluted, but I'm not great with Javascript yet, and if there is an easier way, I don't know it.
What is the character I need to use to emulate a return key in a txt file in javascript for extendscript for indesign?
Thank you.
I have tried things like \n and \r\n and ^p both with and without quotes around them but none of those seem to show up in the array when I try them.
//Load Email as String
var b = new File("~/Desktop/Test/email.txt");
b.open('r');
var str = "";
while (!b.eof)
str += b.readln();
b.close();
var orderNumberLocation = str.search("Order Number: ") + 14;
var orderNumber = str.substring(orderNumberLocation, ARRAY NUMBER GOES HERE)
var loc = orderNumberLocation.lineNumber
function indexes(source, find) {
var result = [];
for (i = 0; i < source.length; ++i) {
// If you want to search case insensitive use
// if (source.substring(i, i + find.length).toLowerCase() == find) {
if (source.substring(i, i + find.length) == find) {
result.push(i);
}
}
alert(result)
}
indexes(str, NEW PARAGRAPH CHARACTER GOES HERE)
I want all my line breaks to show up as an array of indexes in the variable "result".
Edit: My method of importing stripped all line breaks from the document. Using the code below instead works better. Now \n works.
var file = File("~/Desktop/Test/email.txt", "utf-8");
file.open("r");
var str = file.read();
file.close();
You need to use Regular Expressions. Depending on the fields do you need to search, you'l need to tweek the regular expressions, but I can give you a point. If the fields on the email are separated by new lines, something like that will work:
var str; //your string
var fields = {}
var lookFor = /(Order Number:|Adress:).*?\n/g;
str.replace(lookFor, function(match){
var order = match.split(':');
var field = order[0].replace(/\s/g, '');//remove all spaces
var value = order[1];
fields[field]= value;
})
With (Order Number:|Adress:) you are looking for the fields, you can add more fields separated the by the or character | ,inside the parenthessis. The .*?\n operators matches any character till the first break line appears. The g flag indicates that you want to look for all matches. Then you call str.replace, beacause it allows you to perfom a single task on each match. So, if the separator of the field and the value is a colon ':', then you split the match into an array of two values: ['Order number', 12345], and then, store that matches into an object. That code wil produce:
fields = {
OrderNumber: 12345,
Adresss: "my fake adress 000"
}
Please try \n and \r
Example: indexes(str, "\r");
If i've understood well, wat you need is to str.split():
function indexes(source, find) {
var order;
var result = [];
var orders = source.split('\n'); //returns an array of strings: ["order: 12345", "order:54321", ...]
for (var i = 0, l = orders.length; i < l; i++)
{
order = orders[i];
if (order.match(/find/) != null){
result.push(i)
}
}
return result;
}
Regular expressions are most powerful. However, the result they return is sometimes useless:
For example:
I want to manage a CSV string using semicolons.
I define a string like:
var data = "John;Paul;Pete;Stuart;George";
If I use the instruction:
var tab = data.match(/;/g)
after what, "tab" contains an array of 4 ";" :
tab[0]=";", tab[1]=";", tab[2]=";", tab[3]=";"
This array is not useful in the present case, because I knew it even before using the regular expression.
Indeed, what I want to do is 2 things:
1stly: Suppress the 4th element (not "Stuart" as "Stuart", but "Stuart" as 4th element)
2ndly: Replace the 3rd element by "Ringo" so as to get back (to where you once belonged!) the following result:
data == "John;Paul;Ringo;George";
In this case, I would greatly prefer to obtain an array giving the positions of semicolons:
tab[0]=4, tab[1]=9, tab[2]=14 tab[3]=21
instead of the useless (in this specific case)
tab[0]=";", tab[1]=";", tab[2]=";", tab[3]=";"
So, here's my question: Is there a way to obtain this numeric array using regular expressions?
To get tab[0]=4, tab[1]=9, tab[2]=14 tab[3]=21, you can do
var tab = [];
var startPos = 0;
var data = "John;Paul;Pete;Stuart;George";
while (true) {
var currentIndex = data.indexOf(";", startPos);
if (currentIndex == -1) {
break;
}
tab.push(currentIndex);
startPos = currentIndex;
}
But if the result wanted is "John;Paul;Ringo;George", you can do
var tab = data.split(';'); // Split the string into an array of strings
tab.splice(3, 1); // Suppress the 4th element
tab[2] = "Ringo"; // Replace the 3rd element by "Ringo"
var str = tab.join(';'); // Join the elements of the array into a string
The second approach is maybe better in your case.
String.split
Array.splice
Array.join
You should try a different approach, using split.
tab = data.split(';') will return an array of the form
tab[0]="John", tab[1]="Paul", tab[2]="Pete", tab[3]="Stuart", tab[4]="George"
You should be able to achieve your goal with this array.
Why use a regex to perform this operation? You have a built-in function split, which can split your string based on the delimiter you pass.
var data = "John;Paul;Pete;Stuart;George";
var temp=data.split(';');
temp[0],temp[1]...
I have a text which goes like this...
var string = '~a=123~b=234~c=345~b=456'
I need to extract the string such that it splits into
['~a=123~b=234~c=345','']
That is, I need to split the string with /b=.*/ pattern but it should match the last found pattern. How to achieve this using RegEx?
Note: The numbers present after the equal is randomly generated.
Edit:
The above one was just an example. I did not make the question clear I guess.
Generalized String being...
<word1>=<random_alphanumeric_word>~<word2>=<random_alphanumeric_word>..~..~..<word2>=<random_alphanumeric_word>
All have random length and all wordi are alphabets, the whole string length is not fixed. the only text known would be <word2>. Hence I needed RegEx for it and pattern being /<word2>=.*/
This doesn't sound like a job for regexen considering that you want to extract a specific piece. Instead, you can just use lastIndexOf to split the string in two:
var lio = str.lastIndexOf('b=');
var arr = [];
var arr[0] = str.substr(0, lio);
var arr[1] = str.substr(lio);
http://jsfiddle.net/NJn6j/
I don't think I'd personally use a regex for this type of problem, but you can extract the last option pair with a regex like this:
var str = '~a=123~b=234~c=345~b=456';
var matches = str.match(/^(.*)~([^=]+=[^=]+)$/);
// matches[1] = "~a=123~b=234~c=345"
// matches[2] = "b=456"
Demo: http://jsfiddle.net/jfriend00/SGMRC/
Assuming the format is (~, alphanumeric name, =, and numbers) repeated arbitrary number of times. The most important assumption here is that ~ appear once for each name-value pair, and it doesn't appear in the name.
You can remove the last token by a simple replacement:
str.replace(/(.*)~.*/, '$1')
This works by using the greedy property of * to force it to match the last ~ in the input.
This can also be achieved with lastIndexOf, since you only need to know the index of the last ~:
str.substring(0, (str.lastIndexOf('~') + 1 || str.length() + 1) - 1)
(Well, I don't know if the code above is good JS or not... I would rather write in a few lines. The above is just for showing one-liner solution).
A RegExp that will give a result that you may could use is:
string.match(/[a-z]*?=(.*?((?=~)|$))/gi);
// ["a=123", "b=234", "c=345", "b=456"]
But in your case the simplest solution is to split the string before extract the content:
var results = string.split('~'); // ["", "a=123", "b=234", "c=345", "b=456"]
Now will be easy to extract the key and result to add to an object:
var myObj = {};
results.forEach(function (item) {
if(item) {
var r = item.split('=');
if (!myObj[r[0]]) {
myObj[r[0]] = [r[1]];
} else {
myObj[r[0]].push(r[1]);
}
}
});
console.log(myObj);
Object:
a: ["123"]
b: ["234", "456"]
c: ["345"]
(?=.*(~b=[^~]*))\1
will get it done in one match, but if there are duplicate entries it will go to the first. Performance also isn't great and if you string.replace it will destroy all duplicates. It would pass your example, but against '~a=123~b=234~c=345~b=234' it would go to the first 'b=234'.
.*(~b=[^~]*)
will run a lot faster, but it requires another step because the match comes out in a group:
var re = /.*(~b=[^~]*)/.exec(string);
var result = re[1]; //~b=234
var array = string.split(re[1]);
This method will also have the with exact duplicates. Another option is:
var regex = /.*(~b=[^~]*)/g;
var re = regex.exec(string);
var result = re[1];
// if you want an array from either side of the string:
var array = [string.slice(0, regex.lastIndex - re[1].length - 1), string.slice(regex.lastIndex, string.length)];
This actually finds the exact location of the last match and removes it regex.lastIndex - re[1].length - 1 is my guess for the index to remove the ellipsis from the leading side, but I didn't test it so it might be off by 1.
Some outside code is giving me a string value like..
null,402,2912,2909,2910,2913,2911,2914,2915,2388,2389,2390,
now i have to save this value to the data base but putting 0 in place of null in javascript. Is there any javascript string releated function to do this conversion?
You can simply use the replace function over and over again until all instances are replaced, but make sure that all your string will ever contain is the character sequence null or a number (and obviously the delimiting comma):
var str = "null,402,2912,null"
var index = str.indexOf("null");
while(index != -1) {
str = str.replace("null", "0");
index = str.indexOf("null");
}
You need to run a for loop because the function String.replace(search, rplc) will replace only the first instance of search with rplc. So we use the indexOf method to check, in each iteration, if the required term exists or not. Another alternative (and in my opinion, a better alternative would be:
var str = "null,402,2912,null"
var parts = str.split(",");
var data = []
for(var i=0; i<parts.length; i++) {
data[data.length] = parts[i]=="null"?0:parseInt(parts[i]);
}
Basically, what we are doing is that since you will anyways be converting this to an array of numbers (I presume, and sort of hope), we first split it into individual elements and then inspect each element to see if it is null and make the conversion accordingly.
This should answer your needs:
var str = 'null,402,2912,2909,2910,2913,2911,2914,2915,2388,2389,2390';
str.split(",").map(function (n) { var num = Number(n); return isNaN(num) ? 0 : num; });
The simplest solution is:
var inputString = new String("null,402,2912,2909,2910,2913,2911,2914,2915,2388,2389,2390,");
var outputString = inputString.replace("null", "0");
What I understood from your question is:
You want to replace null with 0 in a string.
You may use
string = "null,402,2912,2909,2910,2913,2911,2914,2915,2388,2389,2390,"
string.replace(/null/g,0)
Hope it helps.
I'm trying to extract a substring from a file with JavaScript Regex. Here is a slice from the file :
DATE:20091201T220000
SUMMARY:Dad's birthday
the field I want to extract is "Summary". Here is the approach:
extractSummary : function(iCalContent) {
/*
input : iCal file content
return : Event summary
*/
var arr = iCalContent.match(/^SUMMARY\:(.)*$/g);
return(arr);
}
function extractSummary(iCalContent) {
var rx = /\nSUMMARY:(.*)\n/g;
var arr = rx.exec(iCalContent);
return arr[1];
}
You need these changes:
Put the * inside the parenthesis as
suggested above. Otherwise your matching
group will contain only one
character.
Get rid of the ^ and $. With the global option they match on start and end of the full string, rather than on start and end of lines. Match on explicit newlines instead.
I suppose you want the matching group (what's
inside the parenthesis) rather than
the full array? arr[0] is
the full match ("\nSUMMARY:...") and
the next indexes contain the group
matches.
String.match(regexp) is
supposed to return an array with the
matches. In my browser it doesn't (Safari on Mac returns only the full
match, not the groups), but
Regexp.exec(string) works.
You need to use the m flag:
multiline; treat beginning and end characters (^ and $) as working
over multiple lines (i.e., match the beginning or end of each line
(delimited by \n or \r), not only the very beginning or end of the
whole input string)
Also put the * in the right place:
"DATE:20091201T220000\r\nSUMMARY:Dad's birthday".match(/^SUMMARY\:(.*)$/gm);
//------------------------------------------------------------------^ ^
//-----------------------------------------------------------------------|
Your regular expression most likely wants to be
/\nSUMMARY:(.*)$/g
A helpful little trick I like to use is to default assign on match with an array.
var arr = iCalContent.match(/\nSUMMARY:(.*)$/g) || [""]; //could also use null for empty value
return arr[0];
This way you don't get annoying type errors when you go to use arr
This code works:
let str = "governance[string_i_want]";
let res = str.match(/[^governance\[](.*)[^\]]/g);
console.log(res);
res will equal "string_i_want". However, in this example res is still an array, so do not treat res like a string.
By grouping the characters I do not want, using [^string], and matching on what is between the brackets, the code extracts the string I want!
You can try it out here: https://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_match_regexp
Good luck.
(.*) instead of (.)* would be a start. The latter will only capture the last character on the line.
Also, no need to escape the :.
You should use this :
var arr = iCalContent.match(/^SUMMARY\:(.)*$/g);
return(arr[0]);
this is how you can parse iCal files with javascript
function calParse(str) {
function parse() {
var obj = {};
while(str.length) {
var p = str.shift().split(":");
var k = p.shift(), p = p.join();
switch(k) {
case "BEGIN":
obj[p] = parse();
break;
case "END":
return obj;
default:
obj[k] = p;
}
}
return obj;
}
str = str.replace(/\n /g, " ").split("\n");
return parse().VCALENDAR;
}
example =
'BEGIN:VCALENDAR\n'+
'VERSION:2.0\n'+
'PRODID:-//hacksw/handcal//NONSGML v1.0//EN\n'+
'BEGIN:VEVENT\n'+
'DTSTART:19970714T170000Z\n'+
'DTEND:19970715T035959Z\n'+
'SUMMARY:Bastille Day Party\n'+
'END:VEVENT\n'+
'END:VCALENDAR\n'
cal = calParse(example);
alert(cal.VEVENT.SUMMARY);