Develop Reference

Slider of images with undefined height

I'm trying to create a slider of images (previous/next) so the images slide to the left when I click "previous" and to the right when I click "next" with 0.5s of slowness, so it takes some animation. And when I reach the last image and click "next", I want images to "run backwards" to the first one, the same when I'm in the first one and click "previous", so it "run forward" until the last one.
I want the same behaviour this JSFiddle shows. (but I don't need the timer to move images automatically and don't need the "triggers" buttons, just "previous" and "next").
The problem here is that my images don't have fixed size. I define a width in percentage and can't define a height because I have responsive design, the image resizes as I resize the browser window.
The jQuery to previous/next actions is pretty easy, but I just can't find a way to add this animation when I remove/add the "active" class to my images (so they become visible or not).
I have already tried putting all images side by side and showing only the first one (setting container width equals to image width), so when I click "next" I just "move" the container to the left so it begins to display the next image, but it doesn't work because once I can't define the height of the images, they will appear underneath each other, not side by side.
JSFiddle
HTML
<div class="images">
<img class="active" src="1.jpg">
<img src="2.jpg">
<img src="3.jpg">
</div>
<div class="previous">previous</div>
<div class="next">next</div>
CSS
img {
width: 100px;
display: none;
float: left;
}
img.active {
display: block;
}
jQuery
$('.next').on('click', function() {
var active = $('img.active');
var next = active.next('img');
if (next.length) {
active.removeClass('active');
next.addClass('active');
} else {
active.removeClass('active');
$('.images img:first').addClass('active');
}
});

Well the problem is the height for sliding.
First you need to have an element which is the "picture frame" which hold all the other images. That's important.
For better imagination a picture:
Now you have several technics to show and hide images. One could be to set the opacity. When using transition: opacity .15s ease-in-out; The one Picture is fading out and the next on is fading in.
For the slideshow effect is given to the position of the visible image to its width to the left and the image previously purely new to his wide to the right and then to 0. Thus, moves the current picture on the left the frame out and the new comes out right in.
And here is the difficulty if the height is not the same. If the current image 300px high and the new 400px, so the image frame here would adjust his height immediately once the new image start to be visible.
The content below would start to jump with each slide.
Is that so desired???
If yes, I can make you an example how it works.

You can actually do this in Pure CSS!
You use an ID and a label (with a for attribute=for the targeted id)
That's basically it. All you have left is to style it! (Forked from Joshua Hibbert's Pen)
body {
background: #f7f4e2;
}
/* Slides */
.slider input {
display: none;
}
/* Buttons */
.slider label {
display: none;
cursor: pointer;
position: absolute;
top: 6em;
left: 50%;
transform: translateX(-50%);
color: #fff;
background: #000;
padding: 1.36em .5em;
opacity: .6;
font-size: 19px;
font-family: fantasy;
font-weight: bold;
transition: .25s;
}
.slider label:hover {
opacity: 1;
}
.previous {
margin-left: -188px;
}
.next {
margin-left: 188px;
}
#slide1:checked ~ .buttons .slide1 {
display: block;
}
#slide2:checked ~ .buttons .slide2 {
display: block;
}
#slide3:checked ~ .buttons .slide3 {
display: block;
}
#slide4:checked ~ .buttons .slide4 {
display: block;
}
/* Images */
.slider {
position: absolute;
top: 50%;
left: 50%;
width: 400px;
height: 300px;
margin-top: -150px;
margin-left: -200px;
white-space: nowrap;
padding: 0;
float: left;
transition: .25s;
overflow: hidden;
box-shadow: 0 0 0 3.12px #e8e8e8,
0 0 0 12.64px #eaebe4,
0 0 0 27.12px #000,
0 24px 3.824em 5.12px #000;
}
.slide {
width: 500em;
transition: .25s;
}
.slider img {
float: left;
width: 400px;
height: 300px;
}
#slide1:checked ~ .slide {
margin: 0;
}
#slide2:checked ~ .slide {
margin: 0 0 0 -400px;
}
#slide3:checked ~ .slide {
margin: 0 0 0 -800px;
}
#slide4:checked ~ .slide {
margin: 0 0 0 -1200px;
}
<div class="slider">
<input type="radio" name="slide" id="slide1" checked="true" />
<input type="radio" name="slide" id="slide2" />
<input type="radio" name="slide" id="slide3" />
<input type="radio" name="slide" id="slide4" />
<div class="buttons">
<!-- Slide 1 -->
<label for="slide4" class="slide1 previous"><</label>
<label for="slide2" class="slide1 next">></label>
<!-- Slide 2 -->
<label for="slide1" class="slide2 previous"><</label>
<label for="slide3" class="slide2 next">></label>
<!-- Slide 3 -->
<label for="slide2" class="slide3 previous"><</label>
<label for="slide4" class="slide3 next">></label>
<!-- Slide 4 -->
<label for="slide3" class="slide4 previous"><</label>
<label for="slide1" class="slide4 next">></label>
</div>
<div class="slide">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/872485/coldchase.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/980517/icehut_sm.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/943660/hq_sm.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/599584/home.jpg">
</div>
</div>
Although this method is the most compatible (except for old versions of IE) and depending on how you animate it this method can be more time consuming than a JS method, but can also be faster, it just depends on how you want the animations to go, or you could use a css library that does this for you.
Here are some css image sliders I recommend.
10 Amazing Pure CSS3 Image Sliders
http://bashooka.com/coding/pure-css3-image-sliders/
Pure CSS Image Slider Without Javascript #Codeconvey is a good solution for what you're looking for, but lots of CSS
http://codeconvey.com/pure-css-image-slider/
The downside to these along with what you're working on is that you can't touch to slide on a phone or tablet which is more common now a days with photo galleries.
I recommend checking out Fotorama it's amazing! :)

Perhaps not the ideal situation but at least it will give you an idea. you can use the animation function of jQuery and I also changed your code a bit. See demo here
Within your HTML I would say this:
<div id="images">
<div class="images-wrapper">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/02/In-the-spotlight.jpg">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/02/Bath-time-with-ducky.jpg">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/03/FB_IMG_1452981788903.jpg">
<img src="http://www.pictures-of-cats.org/images/Pixiebob-cat-list-of-cat-breeds-pictures-of-cats.jpg" />
</div>
</div>
<div class="previous">
previous
</div>
<div class="next">
next
</div>
and within your jQuery code you can animate the width:
$('.images-wrapper img:gt(0)').hide();
$('.next').click(function() {
$('.images-wrapper img:first-child').animate({width:'toggle'},350).next().fadeIn().end().appendTo('.images-wrapper');
});
$('.previous').click(function() {
$('.images-wrapper img:first-child').animate({width:'toggle'},350);
$('.images-wrapper img:last-child').prependTo('.images-wrapper').fadeOut();
$('.images-wrapper img:first-child').fadeIn();
});
With this implementation the whole process of changing and adding the active class to the image is removed and replaced by animation functions

Simplest solution (I think) is to force the items to be of the same size, by placing them in a div. You can even have the div show the image without the use of an img tag, by using the background-image CSS feature (see http://www.w3schools.com/css/css3_backgrounds.asp for more details).
The item CSS could look like:
.item {
background-size: contain;
background-position: center;
}
and in each item in the HTML:
<div class='item' style='background-image: url(img1.jpg)' />
<div class='item' style='background-image: url(img2.jpg)' />
<div class='item' style='background-image: url(img3.jpg)' />

I finally got there.
HERE is the fiddle with the solution I developed.
The main problem in the implementation of this image slider was that images, althought were all the same size, have dynamic width (defined in % on CSS) and dynamic height (not defined on CSS).
The solution was basically put an "fake" image (with opacity: 0) inside my container so the container get the actual size of images I will use in the slider; put a div to "hold" the real images with position: absolute and give it a width calculted by number of images * 100%; and for last, give each image in my slider a width of x%, based on number of images.
In the jQuery, I "move" the "images holder div" always by %, never by static values, once the width of everything can change if I resize the window.
If you start to slide the images to the left and right and then resize the window, you will see that it continues to work perfectly.

I have implemented using css3 animations. However this will require manipulating animation values in css every time a slide gets added or removed.
#keyframes slideAnim {
0% {
transform: translateX(0)
}
12.5% {
transform: translateX(0%);
}
25% {
transform: translateX(-25%);
}
37.5% {
transform: translateX(-25%)
}
50% {
transform: translateX(-50%)
}
62.5% {
transform: translateX(-50%)
}
75% {
transform: translateX(00%);
}
89.5% {
transform: translateX(00%)
}
100% {
transform: translateX(00%)
}
}
Here the animation values are set such that there is a pause between slide transitions. I have added a parent frame to show only one slide at a time.
Please refer this fiddle.

CSS move element when hovering on previous div [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 7 years ago.
Improve this question
I'm trying to make a site that uses a "grid" that looks just like the one on www.uve.info/en/ (middle of the page, under "Services") and has the same effect while hovering.
I've made divs with classes "black-cell", "grey-cell" and "white-cell" and ordered them the same way they did. White cells have a negative z-index and are moved left (odd rows) or right (even rows) by 33%. That way, they stay invisible under grey or black cells.
It's easy to get the desired result on odd rows:
.grey-cell:hover + .odd
visibility: visible
right: 0
, but the problem arises when I try to do the same thing with white cells in even rows because the HTML structure is different (white cell - black cell - grey cell) and I can't target the previous div.
Unfortunately, I can't use flexbox to change the order of elements due to some reasons that are not important for this topic. I've tried using jquery function "insertBefore", but it changes the HTML structure and doesn't help here.
So, is there a way to change the order of the elements without flexbox, OR to target the previous div with CSS/SASS?

In the site you're refering to, the structure seems to be the same for the two types of effects (move to the left & move to the right).
<div class="item [...]">
<div class="col [...]">[...]</div>
<div class="col [...]">[...]</div>
<div class="col-hover">[...]</div>
</div>
Actually, you can see that for the "Cycle hire" effect (2nd one), there is another "indent" class for the main container of the row (class "item").
<div class="item indent [...]">[same structure as above]</div>
It looks like this class is driving the animation to the left when it's written.
Then, if you take the element having class "col-hover", it's displayed "absolute" and positioned at left:50% inside the class "item".
.item .col-hover {
left: 50%;
}
But, for "item" and "indent", it's overwritten to be at left: 0.
That way, the element is positioned under the central block, which is the second for a transition to the right, and the first for moving to the left.
So when "item" is hovered, "col-hover" goes to the right :
.item:hover col-hover {
left: 100%;
}
But if the element which has the "item" class also has "indent" class, then the "col-hover" goes to left:-50% (to the left)
.item:hover.indent .col-hover {
left: -50%;
}
So you can keep the same structure and play with absolute position for the element you want to move.
I suppose you have noted the transition on "col-hover" for the animation, changing the left property making the element moving.
Hope this helps !

Please mind the code its a little dirty clean it but it works like you want.
<html>
<head>
<style type="text/css">
.box
{
width:200px;
height:200px;
background:rgba(0,0,0,120);
margin:0 auto;
color:White;
}
.big-box
{
height:200px;
width:600px;
color:White;
position:absolute;
border:1px solid black;
z-index:-1;
-webkit-transition:all 0.3s;
}
.big-box1
{
top:0px;
left:-200px;
text-align:right;
}
.big-box2
{
top:200px;
left:200px;
text-align:left;
}
.big-box > .box
{
display:inline-block;
}
.par
{
position:relative;
height:400px;
width:600px;
margin:0 auto;
border:1px solid black;
overflow:visible;
}
.b1:hover~.big-box1
{
left:0px;
}
.b2:hover~.big-box2
{
left:0px;
}
</style>
</head>
<body>
<div class="par">
<div class="box b1">One</div>
<div class="box b2">Two</div>
<div class="big-box big-box1">
<div class="box">OneC</div>
</div>
<div class="big-box big-box2">
<div class="box">TwoC</div>
</div>
</div>
</body>
</html>

Was messing around with this question for a warm up, it's not fully thought through but I'll post in case some of it helps.
fiddle
https://jsfiddle.net/Hastig/7Lb427m4/2/
css
.blocks-wrapper {
font-size: 0;
margin-bottom: 10px;
position: relative;
text-align: center;
}
.block {
display: inline-block;
height: 200px; width: 200px;
}
.hidey {
font-size: 15px;
z-index: -1;
color: red;
position: absolute;
left: 50%;
top: 50%; bottom: 50%;
transition: all 1s ease;
}
.blocks-wrapper:nth-child(odd) .block:nth-child(1) { }
.blocks-wrapper:nth-child(odd) .block:nth-child(2) { background-color: #222; }
.blocks-wrapper:nth-child(odd) .block:nth-child(3) { background-color: #111; }
.blocks-wrapper:nth-child(even) .block:nth-child(1) { background-color: #111; }
.blocks-wrapper:nth-child(even) .block:nth-child(2) { background-color: #222; }
.blocks-wrapper:nth-child(even) .block:nth-child(3) { }
.blocks-wrapper:nth-child(odd) .block:nth-child(2):hover ~ .hidey,
.blocks-wrapper:nth-child(odd) .block:nth-child(3):hover ~ .hidey {
left: 15%;
}
.blocks-wrapper:nth-child(even) .block:nth-child(1):hover ~ .hidey,
.blocks-wrapper:nth-child(even) .block:nth-child(2):hover ~ .hidey {
left: 75%;
}
html
<div class="blocks-wrapper">
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="hidey">testerer</div>
</div><!-- end blocks-wrapper -->
<div class="blocks-wrapper">
<div class="block"></div>
<div class="block"></div>
<div class="block"></div>
<div class="hidey">testerer</div>
</div><!-- end blocks-wrapper -->

Have tried using the previous sibling selector ~
.grey-cell:hover ~ .even{
visibility: visible;
left: 0;
}

Positioning DIVs after resizable()

I'm using jQuery's resizable(). I want to center an image to the resized div after it's resized. I'm using the stop: function() but no success.
This what I've tried.
But it does not center the div to the resized div. How do I center #smlD to #mainD when resized?
$('#mainD').resizable({
stop: function (){
var gpa = ($('#mainD').width() - $('#smlD').width()) / 2;
$('#smlD').css({ left: gpa });
}
});
EDIT
css:
.inW3{
position:relative;
background-color: #000;
width: 100px;
height: 100px;
left:0;
right:0;
margin-left:auto;
margin-right:auto;
}
.innerWrp .inW1 .inW2{
position: relative;
}
.outerWrp{
position: absolute;
}
html:
<div class ="outerWrp">
<div class ="innerWrp">
<div class ="inW1">
<div class ="inW2" id="mainD">
<div class ="inW3" id ="smlD">
</div>
</div>
</div>
</div>
</div>

Let the css do the work for you. With margin-left: auto and margin-right: auto you shouldn't be worried about centering on stop resizable().
Check out your code here CodePen working with centering on resize:
$('#mainD').resizable();

How to arrange floating elements vertically

I have 3 fieldsets.
What I would like to make is this layout:
I want the bottom right fieldset to be bottom aligned, so it's bottom would be aligned with the left fieldset.
It should work in different resolutions.
Is there an easy way? or I will have to use javascript to add to it a margin-top dynamically?
code:
<div class="fieldSetsContainer">
<fieldset class="leftFieldSet">test
<br/>test
<br/>test
<br/>test
<br/>test
<br/>test
<br/>
</fieldset>
<div class="rightFieldSets">
<fieldset>test2</fieldset>
<fieldset class="bottomRightFieldSet">test3</fieldset>
</div>
css:
.rightFieldSets {
float:left;
width:34%;
}
.rightFieldSets fieldset {
clear:left;
width:89%;
}
.leftFieldSet {
width:62%;
float:left;
margin-right:1px;
}
.bottomRightFieldSet {
margin-top:6px;
}
here is the a link:
http://jsfiddle.net/bbryK/

My solution assumes two things:
The right column has a fixed width.
The left column must always be the highest.
See http://jsfiddle.net/c3AFP/2/
Html structure:
<div class="container">
<div class="right">
<fieldset class="top"></fieldset>
<fieldset class="bottom"></fieldset>
</div>
<fieldset class="left"></fieldset>
</div>
Css styles:
.container {
position: relative;
}
.top, .bottom {
width: 300px;
}
.left {
margin-right: 300px;
}
.right {
float: right;
margin-left: 10px;
}
.bottom {
position: absolute;
bottom: 0;
}
EDIT:
Here is a solution with the right column sized by percentage: http://jsfiddle.net/c3AFP/5/
EDIT 2:
Here is a table based solution which removes the requirement of the left column being the tallest. Using vertical-align you can adjust where the smaller elements should align in relation to the tallest one: http://jsfiddle.net/c3AFP/7/

I'm giving you a start point on fiddle. Please play around, make some code and do share the same.
http://jsfiddle.net/vY462/
#one{width:200px;height:70px;border:2px solid black;float:left;}
#two,#three{width:200px;height:25px;border:2px solid black;float:right;margin-top:5px;}
<div id="one">1</div>
<div id="two">2</div>
<div id="three">3</div>

Two photos positioned on each other. Show one on hover. Possible with css or only javascript?

What I want to do is to show the top photo (which is set to visibility: hidden) on hover. I have two photos positioned on each other like this:
<div class="frame">
<img src="./img/portfolio/default1.jpg" width="300" height="178" alt="Title Here"></a>
<div class="boxwrapper" style="visibility: hidden;"></div>
</div>
Added the second photo through css:
.boxwrapper {
background: url("../img/boxPlus.gif");
position: relative;
width: 300px;
height: 178px;
left: -6px;
top: -184px;
z-index: 1000;
}
Is it possible to do with css? Tried (and several more options):
#frame img:hover .boxwrapper {
visibility: visible;
}
But it is not working. Or this is only possible with javascript? If yes, please give some tips as I am not too much of javascript guy. Thanks!

You could set the photo as background of the boxwrapper
.boxwrapper{
background: url("../img/boxPlus.gif");
}
.boxwrapper:hover{
background: url("../img/portfolio/default1.jpg");
}
if this is not possible you could add it as background trough a style attribute inside your html
<div class="boxwrapper" style="background: url('../img/boxPlus.gif');" ></div>

You'd have to put the :hover class on a parent container. CSS does not allow such things to trickle "up" the tree, only down.
.boxwrapper {
display: none;
}
.frame:hover .boxwrapper {
display: block;
}