Develop Reference

Get data from database using php,ajax

I have a simple section in which I am displaying data from the database, my database looks like this.
Now I have four buttons looks like this
When a user clicks one of the above buttons it displays this
So now when user eg select construction and next select eg Egypt' in the console and clicks buttonconfirmdisplays [855,599075], user can select multiple countries, this works as expected forconstruction ,power,oil`,
Now I want if user eg clicks All available industries button in those four buttons and next select eg Egypt and click confirm it should display
the sum of egypt total projects in construction, oil, power sector 855+337+406 =1598 and the sum of total budgets in both sectors 1136173
Here is my solution
HTML
<div id="interactive-layers">
<div buttonid="43" class="video-btns">
<span class="label">Construction</span></div>
<div buttonid="44" class="video-btns">
<span class="label">Power</span></div>
<div buttonid="45" class="video-btns">
<span class="label">Oil</span></div>
<div buttonid="103" class="video-btns">
<span class="label">All available industries</span>
</div>
</div>
Here is js ajax
$("#interactive-layers").on("click", ".video-btns", function(){
if( $(e.target).find("span.label").html()=="Confirm" ) {
var selectedCountries = [];
$('.video-btns .selected').each(function () {
selectedCountries.push( $(this).parent().find("span.label").html() ) ;
});
if( selectedCountries.length>0 ) {
if(selectedCountries.indexOf("All available countries")>-1) {
selectedCountries = [];
}
} else {
return;
}
var ajaxurl = "";
if(selectedCountries.length>0) {
ajaxurl = "data.php";
} else {
ajaxurl = "dataall.php";
}
$.ajax({
url: ajaxurl,
type: 'POST',
data: {
countries: selectedCountries.join(","),
sector: selectedSector
},
success: function(result){
console.log(result);
result = JSON.parse(result);
$(".video-btns").each(function () {
var getBtn = $(this).attr('buttonid');
if (getBtn == 106) {
var totalProjects = $("<span class='totalprojects'>"+ result[0] + "</span>");
$(this).append(totalProjects)
}else if(getBtn ==107){
var resultBudget = result[1]
var totalBudgets = $("<span class='totalbudget'>"+ '&#36m' +" " + resultBudget +"</span>");
$(this).append( totalBudgets)
}
});
return;
}
});
}
});
Here is php to get all dataall.php
$selectedSectorByUser = $_POST['sector'];
$conn = mysqli_connect("localhost", "root", "", "love");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = array();
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result))
{
if($row['Sector']==$selectedSectorByUser ) {
$totalProjects+= $row['SumofNoOfProjects'];
$totalBudget+= $row['SumofTotalBudgetValue'];
}
}
echo json_encode([ $totalProjects, $totalBudget ] );
exit();
?>
Here is data.php
<?php
$selectedSectorByUser = $_POST['sector'];
$countries = explode(",", $_POST['countries']);
//var_dump($countries);
$conn = mysqli_connect("localhost", "root", "", "meedadb");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = array();
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result))
{
if($row['Sector']==$selectedSectorByUser && in_array($row['Countries'],$countries ) ) {
// array_push($data, $row);
$totalProjects+= $row['SumofNoOfProjects'];
$totalBudget+= $row['SumofTotalBudgetValue'];
}
}
// array_push($wynik, $row);
echo json_encode([ $totalProjects, $totalBudget ] );
//echo json_encode($data);
exit();
?>
Now when the user clicks All available industries btn and selects a country I get [0,0] on the console.
What do I need to change to get what I want? any help or suggestion will be appreciated,

in you dataAll.php
If you have select All available industries
you shold not check for sector because you need all sector (eventually you should check for countries )
so you should avoid the check for this condition
<?php
$conn = mysqli_connect("localhost", "root", "", "love");
$result = mysqli_query($conn, "SELECT * FROM meed");
$data = [];
$wynik = [];
$totalProjects = 0;
$totalBudget = 0;
while ($row = mysqli_fetch_array($result)) {
$totalProjects += $row['SumofNoOfProjects'];
$totalBudget += $row['SumofTotalBudgetValue'];
}
echo json_encode([$totalProjects, $totalBudget]);

You can use the SQL JOIN operator, or in this case an implicit join would be cleanest:
$result = mysqli_query($conn, "SELECT * FROM construction, power, oil_and_gas, industrial WHERE construction.Countries = power.Countries AND power.Countries = oil_and_gas.Countries AND oil_and_gas.Countries = industrial.Countries");
You need the WHERE conditions so it knows how the rows of each different table are related to each other. You can shorten it a bit with aliases for the tables:
$result = mysqli_query($conn, "SELECT * FROM construction as C, power as P, oil_and_gas as G, industrial as I WHERE C.Countries = P.Countries AND P.Countries = G.Countries AND G.Countries = I.Countries");
In this case, however, I think you may want to consider changing the structure of your database. It seems like you repeat columns quite a bit across them. Perhaps these can all be in a single table, with a "type" column that specifies whether it's power, construction, etc. Then you can query just the one table and group by country name to get all your results without the messy joins across 4 tables.

The single table looks OK.
(The rest of this Answer is not complete, but might be useful.)
First, let's design the URL that will request the data.
.../foo.php?industry=...&country=...
But, rather than special casing the "all" in the client, do it in the server. That is, the last button for industry will generate
?industry=all
and the PHP code will not include this in the WHERE clause:
AND industry IN (...)
Similarly for &country=all versus &country=egypt,iran,iraq
Now, let me focus briefly on the PHP:
$wheres = array();
$industry = #$_GET['industry'];
if (! isset($industry)) { ...issue error message or use some default... }
elseif ($industry != 'all') {
$inds = array();
foreach (explode(',', $industry) as $ind) {
// .. should test validity here; left to user ...
$inds[] = "'$ind'";
}
$wheres[] = "industry IN (" . implode(',', $inds) . )";
}
// ... repeat for country ...
$where_clause = '';
if (! empty($wheres)) {
$where_clause = "WHERE " . implode(' AND ', $wheres);
}
// (Note that this is a generic way to build arbitrary WHEREs from the data)
// Build the SQL:
$sql = "SELECT ... FROM ...
$where_clause
ORDER BY ...";
// then execute it via mysqli or pdo (NOT mysql_query)
Now, let's talk about using AJAX. Or not. There were 2 choices:
you could have had the call to PHP be via a GET and have that PHP display a new page. This means that PHP will be constructing the table of results.
you could have used AJAX to request the data. This means that Javascript will be constructing the data of results.
Which choice to pick probably depends on which language you are more comfortable in.

How to use javascript if statements within function to populate table

I've created a search page that sends results to a table with the ability to click on a specific record which then opens another page in the desired format.
I'd like to do is be able to open different formatted pages based on the data returned in the search query but I'm having a bit of trouble pulling it all together.
Here's the PHP used to request and retrieve the data from the database, as well as populate it in a table where each record can be selected and used to populate a planner page with all the proper formatting:
$search = $_POST['search'].'%';
$ment = $_POST['ment'];
$stmt = $link->prepare("SELECT lname, fname, rank, reserve, ment1, pkey FROM planner WHERE lname LIKE ? AND ment1 LIKE ? ORDER BY lname, fname");
$stmt->bind_param('ss', $search, $ment);
$stmt->execute();
$result = $stmt->get_result();
if ($result->num_rows > 0) {
echo "<table><tr><th>Last Name</th><th>First Name</th><th>Rank</th><th>Mentor Group</th><th></th></tr>";
while($row = $result->fetch_assoc()) {
$rsv = $row['reserve'];
$pkey = $row['pkey'];
echo "<tr><td>".$row['lname']."</td><td>".$row['fname']."</td><td>".$row['rank']."</td><td>".$row['ment1']."</td><td><button onClick=getPlanner('".$pkey."');>Get Planner</button></td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
Now the fun part. I want to open different pages based on the information contained in the record. I've got it working for the pkey variable by itself with a single javascript function. However, if I want to open a differently formatted page using the same function using if, else statements, the table only populates with the link page based on the last record compared. Here is my attempt to get the JavaScript with the if, else statements working but it only uses the format of the last record that's compared.
var pkey = <?php echo json_encode($pkey); ?>;
var rsv = <?php echo $rsv ?>;
//var check = document.write(rsv);
function getPlanner(pkey) {
if(rsv != 0){
var plan = window.open("../php/plannerR.php?pln=" + pkey);
} else {
var plan = window.open("../php/planner.php?pln=" + pkey);
}
}
How do I get the 'Get Planner' button to open the correctly formatted planner page based on the users specific information?

To make things easier I'd suggest the following:
Do the logic already in php when generating the html-table (and the link).
while($row = $result->fetch_assoc()) {
$rsv = $row['reserve'];
$pkey = $row['pkey'];
if($rsv) { // thats basicly the same as !=0
$target='../php/plannerR.php'
} else {
$target='../php/planner.php'
}
echo "<tr><td>".$row['lname']."</td><td>".$row['fname']."</td>";
echo "<td>".$row['rank']."</td><td>".$row['ment1']."</td>";
echo "<td><a class='button styleIt' href='".$target."?pkey=".$pkey."&rsv=".$rsv."'>Get Planner</a></td></tr>";
}
If you wanna stick to your js solution (which is more hassle unless you really need it) you can of course go with the solution from my comments that you already successfully implemented (and posted as answer so others can see the implementetion).

Thanks to Jeff I played around a bit with bringing both variables into the function and got it to work. Final code below.
$search = $_POST['search'].'%';
$ment = $_POST['ment'];
$stmt = $link->prepare("SELECT lname, fname, rank, reserve, ment1, pkey FROM planner WHERE lname LIKE ? AND ment1 LIKE ? ORDER BY lname, fname");
$stmt->bind_param('ss', $search, $ment);
$stmt->execute();
$result = $stmt->get_result();
if ($result->num_rows > 0) {
echo "<table><tr><th>Last Name</th><th>First Name</th><th>Rank</th><th>Mentor Group</th><th></th></tr>";
while($row = $result->fetch_assoc()) {
$rsv = $row['reserve'];
$pkey = $row['pkey'];
echo "<tr><td>".$row['lname']."</td><td>".$row['fname']."</td><td>".$row['rank']."</td><td>".$row['ment1']."</td><td><button onClick=getPlanner('".$pkey."','".$rsv."');>Get Planner</button></td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
var pkey = <?php echo json_encode($pkey); ?>;
var rsv = <?php echo $rsv ?>;
//var check = document.write(rsv);
function getPlanner(pkey, rsv) {
if(rsv != 0){
var plan = window.open("../php/plannerR.php?pln=" + pkey);
}
else{
var plan = window.open("../php/planner.php?pln=" + pkey);
}
}

bring data from a JSON and show in a popup

I have a leaderboard where if you click on a name a popup is displayed : https://jsfiddle.net/pvwvdgLn/1/
In practice, I will pull the list of the leaderboard from a DB.What you see here in the list are static names of employees,just for reference. So,how do I assign names using data attributes and search for that name in the JSON?
There are various fields in the popup like: Name,Email,Date of birth etc which I want to display for the respective person whose name is clicked by the user.
I have below JSON which is fetching me the array which contains all these data of all the people in the list :
<?php
session_start();
$servername = "xxxxx";
$connectioninfo = array(
'Database' => 'xxxxxxxxxxxxx'
);
$conn = sqlsrv_connect($servername, $connectioninfo);
if (!$conn) {
echo 'connection failure';
die(print_r(sqlsrv_errors() , TRUE));
}
$q1 = "select top 10 *
from pointsBadgeTable
WHERE WeekNumber ='week51'
order by pointsRewarded desc";
$stmt = sqlsrv_query($conn, $q1);
if ($stmt == false) {
echo 'error to retrieve info !! <br/>';
die(print_r(sqlsrv_errors() , TRUE));
}
do {
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
}
while (sqlsrv_next_result($stmt));
sqlsrv_free_stmt($stmt);
sqlsrv_close($conn); //Close the connnectiokn first
//Set content type to json
header('Content-Type: application/json');
//Echo a json object to the browser
echo json_encode($result);
?>
As can be seen in the query,it fetches JSON for all the top10 ,whose names can be seen in the list.
the html and JS related to the popup is here : https://jsfiddle.net/woef5mn6/
How can I display the respective data in the popup from the JSON only for the person whose name is clicked ?
please help me.

I have edited your fiddle to show how your problem can be solved. This is just a simple solution. It needs to modified according to your requirement.
Here is the fiddle
I am creating the employee list from your JSON and populating the ordered list
function employeeList() {
$("#myOL").empty();
$.each(employee, function(i,o) {
$("#myOL").append("<li><mark>" + o.EmployeeName + "</mark><small>" + o.score + "</small></li>");
});
}
Then onclick of the individual employee, i am getting his details from JSON by his name and then populating the popup details (as a best practice here - you should get the employee details by calling a service through ajax using a unique identifier [employeeId] ):
function getEmployeeByName(name) {
var index = -1;
var filteredObj = employee.find(function(item, i) {
if(item.EmployeeName === name){
index = i;
}
});
return employee[index];
}
Hope this helps!

Multiple AJAX functions on one functions page

I'd like to find a way of having a single page in the root of each of my web sections to hold all of the databae queries I'm calling.
I'm using a little script .....
<script type="text/javascript">
$(function() {
var availableTags = <?php include('fn-search-em.php'); ?>;
$("#quick-add").autocomplete({
source: availableTags,
autoFocus:true
});
});
</script>
.... to do SQL searches that appear as the user is typing. Similar to this ....
$sql = "SELECT * FROM stock_c_colours WHERE current_c_status = 'current' AND deleted = 'no'";
$result = mysqli_query($conn, $sql);
$results_list = array();
while($row = mysqli_fetch_array($result))
{
$colour_id = $row['id'];
$range_name = $row['range_name'];
$range_colour = $row['colour'];
$colour_code = $row['code'];
$p1 = $row['piece_size_1'];
$p2 = $row['piece_size_2'];
if($p1 > 1){
$p_mark = 'x';
}
else {
$p_mark = '';
}
$results_list[] = $range_name.' ('.$range_colour.' '.$colour_code.' '.$p1.$p_mark.$p2.') ID:'.$colour_id;
}
echo json_encode($results_list);
Echos a list in the form of a JSON array back to the text box and voila, a list. However, the site I'm working on at the moment has about 20 search boxes for various reasons scattered around (user request), does this mean I have to have 20 separate php function pages, each with their own query on, or can a single page be used?
I suspect the java needs modifying a little to call a specific function on a page of multiple queries, but I'm not good with Java, so some help would be greatly appreciated.
I did initially try adding ?action= to the end of the PHP address in the Java script, hoping a GET on the other end would be able to separate the PHP end into sections, but had no luck.

You need to change <?php include('fn-search-em.php'); ?>; to <?php $action = 'mode1'; include('fn-search-em.php'); ?>;.
Then in your fn-search-em.php file, use the $action variable to determine what kind of MySQL query you make.
For example:
if ($action == 'mode1')
$sql = "SELECT * FROM stock_c_colours WHERE current_c_status = 'current' AND deleted = 'no'";
else
$sql = "SELECT * FROM stock_c_colours WHERE current_c_status = 'mode1' AND deleted = 'no'";

You can do this with by creating a php file with a switch statement to control what code is executed during your Ajax call:
JS:
$.ajax({url: 'ajax.php', method: 'POST', async:true, data: 'ari=1&'+formData,complete: function(xhr){ var availableTags = JSON.parse(xhr.responseText);}});
PHP:
<?php
switch($_REQUEST['ari']){
case 1:
$sql = "SELECT * FROM stock_c_colours WHERE current_c_status = 'current' AND deleted = 'no'";
$result = mysqli_query($conn, $sql);
$results_list = array();
while($row = mysqli_fetch_array($result)){
$colour_id = $row['id'];
$range_name = $row['range_name'];
$range_colour = $row['colour'];
$colour_code = $row['code'];
$p1 = $row['piece_size_1'];
$p2 = $row['piece_size_2'];
if($p1 > 1){$p_mark = 'x';}
else { $p_mark = ''; }
$results_list[] = $range_name.' ('.$range_colour.' '.$colour_code.' '.$p1.$p_mark.$p2.') ID:'.$colour_id;
}
echo json_encode($results_list);
break;
case 2:
// another SQL Query can go here and will only get run if ARI == 2
break;
}
?>
This allows you to keep multiple AJAX handlers in the same file, you just need to pass the index for the desired handler when you make calls to the PHP file or nothing will happen.

Check if user exists with AJAX and PHP

I am trying to create a signup form that checks if the user exists in the database, I inserted a sample user and when I tried signing up with that user it didn't say its already been taken. What have I done wrong?
The JavaScript:
function formSubmit()
{
document.getElementById('email_valid').innerHTML = '';
var temail=document.forms["signup_form"]["temail"].value.replace(/^\s+|\s+$/g, '');
var atpos=temail.indexOf("#");
var dotpos=temail.lastIndexOf(".");
if (atpos<1 || dotpos<atpos+2 || dotpos+2>=temail.length)
{
//alert("Not a valid e-mail address");
setTimeout(function(){document.getElementById('email_valid').innerHTML = '<br/>Email must be valid...';},1000);
var temailsub=0;
}
else
{
$.post('/resources/forms/signup/email.php',{email: temail}, function(data){
document.getElementById('email_valid').innetHTML = data;
if(data.exists){
document.getElementById('email_valid').innetHTML = '<br/>The email address you entered is already in use.';
var temailsub=0;
}else{
var temailsub=1;
}
}, 'JSON');
}
if(temailsub==1e)
{
setTimeout(function(){document.getElementById("signup_form").submit();},1000);
}
else
{
return false;
}
}
The PHP file (email.php):
<?php
header('content-type: text/json');
require_once $_SERVER['DOCUMENT_ROOT']."/resources/settings.php";
$query = $pdo->prepare("SELECT * FROM users WHERE email=:email");
$query->execute(array(
":email"=> $_POST['email']
));
echo json_encode(array('exists' => $query->rowCount() > 0));
?>
I have checked and double checked the code, I still cannot see why its not detecting that the email has already been used... what do i need to do to fix this and avoid this in the future?

The problem is that PDOStatement::rowCount() returns the number of rows affected by the last SQL statement. You are performing a SELECT so this value will always be 0. SELECT does not affect any rows. Instead you need to count the number of rows:
$query = $pdo->prepare("SELECT COUNT(*) FROM users WHERE email=:email");
$query->execute(array(
":email"=> $_POST['email']
));
$rows = $query->fetchColumn();
echo json_encode(array('exists' => $rows);
Also from jtheman's comment above, you should replace innetHTML with innerHTML in your JavaScript.