Develop Reference

jQuery full screen section slide left, slide right

I am playing with jquery recently and right now - trying to get animations to work.
Whole idea is basically a fullscreen slider. We have few sections with position absolute and height 100% of the document - in jquery we're playing with z-index. It's quite simply, but I can't figure out how to make a proper slide left and right animations. It's always breaking.
$(document).ready(function() {
var windowWidth = $(window).width();
var slideCount = $('.slide').length;
$('button#next').on('click', function() {
var slideActive = $('.slide.active');
var nextSlide = slideActive.next('.slide');
nextSlide.addClass('active').animate({
'z-index' : '2',
'left' : windowWidth
},500);
slideActive.removeClass('active');
});
});;
body, html {
height: 100%;
position: relative;
}
body {
font-size: 14px;
color: #fff;
}
nav {
position: absolute;
top: 2rem;
right: 2rem;
z-index: 99;
}
section {
height: 100%;
display: flex;
align-items: center;
position: absolute;
right: 0;
left: 0;
}
section#home {
background-color: #2c3e50;
}
section#aboutMe {
background-color: #e74c3c;
}
section#smthElse {
background-color: #1abc9c;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<nav>
<button id="prev">Back</button>
<button id="next">Next</button>
</nav>
<section id="home" class="slide active">
<div class="container">
<p>1</p>
</div>
</section>
<section id="aboutMe" class="slide">
<div class="container">
<p>2</p>
</div>
</section>
<section id="smthElse" class="slide">
<div class="container">
<p>3</p>
</div>
</section>
Before that I tried just by adding class with css defined in .css and animating it (jquery ui) but effect was more or less the same.
All I want to achive is a simple slide functions of my sections.
Example behaviour: http://codepen.io/jibbon/pen/BoisC
Also, I am not looking for ready solutions as I need as simple code as possible to learn and develop it in my way.
Thank you guys!

There are many things that you can improve in your code to achieve what you want.
First, active class is set to a slide but isn't applied any special CSS rule, as you set position: absolute to your divs, you must set z-index to overlap one above other, initializing your app.
Here there is a idea, how to implement what you want:
https://jsfiddle.net/nz2hL6vn/1/

How to scroll beyond fixed position elements on a page with TOC without using JS?

Any ideas how to fix this problem: On a page with TOC (table of contents) with links pointing to hashtags within the same page, when the browser scrolls down other fixed position elements hide it. The browser should scroll further down to avoid being hidden by the fixed elements.
Fiddle to demonstrate this problem: https://jsfiddle.net/fcro6mth/ Click Section One or Section Two - the browser scrolls down to it but its hidden by the fixed header
Solution with JS: https://jsfiddle.net/fcro6mth/1/
Can you think of any solution that doesn’t involve JS?
Code from JS fiddle:
HTML:
<header>
This is the fixed position header
<nav>
Section One
Section Two
Section Three
</nav>
</header>
<div class="body">
This is the body.
<section id="section1">This is section one</section>
<section id="section2">This is section two</section>
<section id="section3">This is section three</section>
</div>
CSS:
section {
background: lightgrey;
margin: 20px 0;
padding: 20px 10px;
height: 300px;
}
header {
background-color: grey;
position: fixed;
top: 0;
padding: 10px;
width: 100%;
box-sizing: border-box;
left: 0;
color: white;
}
.body {
margin: 70px 10px 0 10px;
}
JavaScript:
$("nav a").click(function (event) {
var $target = $(event.currentTarget),
$scrollToTarget = $($target.attr("href")),
$header = $("header"),
prop = {
scrollTop: $scrollToTarget.offset().top - $header.outerHeight(true)
},
speed = 1000;
$('html, body').animate(prop, speed);
});

Check this: https://stackoverflow.com/a/13555927/2112228
Nice example to make hidden anchors for offsetting your sections.

Updated version of your fiddle:
https://jsfiddle.net/fcro6mth/4/
Solution
I wrapped your sections in div-wrappers gave them the IDs, padded them down and pulled them back up with a negative margin.
This results in the exact same appearance, but the links do what you want them to do.
Example:
HTML:
<div id="section1" class="wrapper">
<section >This is section one</section>
</div>
CSS:
.wrapper {
padding-top: 50px;
margin-top: -50px;
}

I have struggled with this issue a lot in designing a webpage with a combined banner / navbar of about 300px fixed at the top of a page full of short items linked to by anchor links from the website's home page.
The problem I have found with the "margin-top: -XXpx; padding-top: XXpx" approach is that the invisible padding overlaid the preceding item, meaning that active content (ie. links) were blocked. I overcame this by applying positioning to the anchored elements and setting the z-index so that the first item was on top of the stack with each subsequent item lower in the stack - like this:
CSS
.anchored-element {
padding-top: 300px;
margin-top: -300px;
position: relative;
}
HTML
<div class="anchored-element" style="z-index: 99">FIRST ITEM</div>
<div class="anchored-element" style="z-index: 98">SECOND ITEM</div>
<div class="anchored-element" style="z-index: 97">THIRD ITEM</div>
... etc
This provided a fix that worked for me across Firefox, Safari and Chrome on my desktop, and on my iOS devices. I hope this helps others tackle this very frustrating issue in bootstrap!

Stack of slides continuously growing

Let us say I want to design a website with four slides. I would like each slide to cover the previous one while the visitor is scrolling. Following is an attempt with stellar.js (a jquery plugin): http://jsfiddle.net/8mxugjqe/. You can see that it works for the first slide, which gets covered by the second one, but I could not have it work for the others.
HTML:
<body>
<div id="one" data-stellar-ratio=".2">
<p>This is the first div.</p>
</div>
<div id="two" data-stellar-ratio="1">
<p>This is the second one.</p>
</div>
<div id="three">
<p>Third one!</p>
</div>
<div id="four">
<p>Fourth and last.</p>
</div>
</body>
CSS:
* {
margin: 0;
padding: 0;
}
#one, #two, #three, #four {
position: absolute;
height: 100%;
width: 100%;
font-size: 5em;
}
p {
margin: 1em;
width: 60%;
}
#one {
background: red;
}
#two {
background: blue;
top: 100%;
}
#three {
background: green;
top: 200%;
}
#four {
background: yellow;
top: 300%;
}

I was able to throw something together using just jQuery and no other libraries. It relies on relative positioning. Basically, everything scrolls normally until one of the slides reaches the top of the browser window. Once it tries to scroll past the top of the browser window, I add an offset to the slide's vertical position to keep it from moving up any further. When scrolling back the other way, I simply subtract from this offset until it hits 0 at which point it begins to scroll normally again.
I'm sure the code can be cleaned up but I added a ton of comments so hopefully it's readable. If you have any questions or you would like me to modify it to better suit your needs, let me know. Here's a fiddle with the solution I came up with:
http://jsfiddle.net/jwnace/jhxfe2gg/
You can also see a full page demo of the same code here:
http://joenace.com/slides/

Grid of divs that are size of viewport

I want to make a grid of divs that are the size of the viewport. Just to set a few basic variables, lets say I want it to be 7 divs wide and 10 divs high.
Here is a code I have so far to set the div size:
function height() {
var height = $(window).height();
height = parseInt(height) + 'px';
$(".page").css('height',height);
}
$(document).ready(function() {
height();
$(window).bind('resize', height);
});
function width() {
var width = $(window).width();
width = parseInt(width) + 'px';
$(".page").css('width',width);
}
$(document).ready(function() {
width();
$(window).bind('width', width);
});
Right now I just have 2 divs that are stacked on top of each other. One is red and one is black, just so I can see them. I want to be able to put content inside the divs. I also made sure to put
body {
margin: 0px;
}
Later I am going to put some scrolling features with jQuery but for now I just want a way to make the grid.
Edit:
Each individual div is the size of the viewport
Edit:
I used this handy plugin for the scrolling that is much better then a small script at the end of the page

You won't need any javascript for this as it can be easier achieved with just CSS.
HTML
<div id="content1">
Place your content here.
</div>
<div id="content2">
Place your content here.
</div>
<div id="content3">
Place your content here.
</div>
CSS
* {
margin: 0;
}
html, body {
height: 100%;
}
#content1,#content2,#content3 {
min-height: 100%;
height: auto !important; /*min-height hack*/
height: 100%; /*min-height hack*/
}
EXAMPLE 1
All 3 divs have the size of the browser window and of course they adjust accordingly. Also you can add a anchor link to navigate from tab to tab with again just html/css
Go to Main Element
If a navigation like this is something you would like to have then you can have a look on the
EXAMPLE 2
PS: in the example i have separated the css of the boxes just to put different colors but you can have it as i posted it above.
I've also created another fiddle for you, as my first two versions were missing something...You asked for a couple of divs vertically and a couple horizontally.
EXAMPLE 3
This example has 3x2 divs (6 total) but with the same logic you can make them 7x10.
Please don't hesitate to ask if you don't understand anything in the code.
Also i've added a bit of jQuery to make the scrolling more smooth, which is optional, you can just remove it
JavaScript (don't forget to include jQuery)
var $root = $('html, body');
$('a').click(function () {
$root.animate({
scrollLeft: $($.attr(this, 'href')).offset().left,
scrollTop: $($.attr(this, 'href')).offset().top
}, 500);
return false;
});
Hope this helps you
EDIT: You need to include jQuery in your code and also wrap the javascript code with:
$(window).load(function(){
});

I can't tell if you want the div to be the entire size of the screen and then have the overflow scroll - and shoot over to the next panel, or if you want your grid of divs to be the size of the viewport. If it's the second, here is my answer.
fiddle is here:
HTML
<div class="block">01</div>
<div class="block">02</div>
<div class="block">03</div>
<div class="block">04</div>
<div class="block">05</div>
<div class="block">06</div>
<div class="block">07</div>
<div class="block">etc. (to 70)</div>
CSS
* {
-moz-box-sizing: border-box;
-webkit-box-sizing: border-box;
box-sizing: border-box;
/* http://www.paulirish.com/2012/box-sizing-border-box-ftw/ */
margin: 0;
}
html {
height: 100%;
background-color: orange;
}
body {
height: 100%;
border: 1px solid blue;
}
.block {
width: 14.285714%%; /* 100/7 */
float: left;
height: 10%; /* 100/10 */
border: 1px solid rgba(255,255,255,.5);
}
Now, If that's not what you wanted, maybe this is.
fiddle is here:
HTML
<div id="content1" class="block">
<h2>block 01</h2>
</div>
<div id="content2" class="block">
<h2>block 02</h2>
</div>
<div id="content3" class="block">
<h2>block 03</h2>
</div>
<div id="content4" class="block">
<h2>block 04</h2>
</div>
<div id="content5" class="block">
<h2>block 05</h2>
</div>
<div id="content6" class="block">
<h2>block 06</h2>
</div>
<div id="content7" class="block">
<h2>block 07</h2>
</div>
<div id="content8" class="block">
<h2>block 08</h2>
</div>
<!-- you'll need 70... ? -->
<nav class="global-nav">
01
02
03
04
05
06
07
08
</nav>
CSS ( a little SASS in here for quickness )
* {
-moz-box-sizing: border-box;
-webkit-box-sizing: border-box;
box-sizing: border-box;
margin: 0;
}
html, body {
height: 100%;
}
html {
width: 700%;
/* overflow: hidden; */
/*This would hide the scroll bars but I'm leaving them for you to see */
}
.block {
min-height: 100%;
height: auto !important; /*min-height hack*/
height: 100%; /*min-height hack*/
width: 100%/7; /* SASS division to be quick*/
float: left;
border: 1px solid red;
}
.global-nav {
position: fixed;
bottom: 0;
left: 0;
}
.global-nav a {
display: block;
color: black;
}

Position badge over corner of image automatically

I have a layout where images "float" within a certain area. The layout looks like this:
The source like this:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<!-- EDIT: I am aware that I can put the badge here. See the edit notes and image below. -->
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
The CSS looks like this (in SCSS):
div.free_tile { width: 176px; height: 206px; float: left; margin: 0 20px 20px 0; position: relative;
&.last { margin: 0 0 20px 0; }
a.img_container { display: block; width: 176px; height: 158px; text-align: center; line-height: 156px; margin-bottom: 10px; }
img { margin: 0; border: 1px solid $dark3; display: inline-block; vertical-align: middle; #include boxShadow;
&.canonical { border: 1px solid $transect; }
}
.location, .taxonomy { width: 176px; }
.location { font-weight: 700; }
.taxonomy { line-height: 10px; font-size: 10px; text-transform: uppercase; height: 20px; overflow: hidden; }
}
div.transect_badge { height: 20px; width: 20px; background: url('/images/transect-badge.png'); }
So, basically the images are sitting vertically-aligned middle and text-aligned center, and they have a maximum width of 176 and max height of 158, but they're cropped to maintain the original aspect ratio so the actual top corner of each image falls differently depending on which image it is.
I have a badge that I'd like to put in the top corner of certain images (when the image is "canonical"). You see the style for this above (div.transect_badge).
The problem, of course, is I don't know where the top corner of the image will be so I can't hardcode the position via CSS.
I assume that I'll need to do this via jQuery or something. So, I started with a jQuery method to automatically append the badge div to any canonical images. That works fine, but I can't figure out how to position it over the top left corner.
How can this be done? (ideally using just HTML and CSS, but realistically using JS/jQuery)
--EDIT--
Here's the problem: The image is floating inside a container, so the corner of the image might fall anywhere inside the outer limits of the container. Here's an example of what happens if I try to use position:absolute; top:0; left:0 inside the same container the image is bound by:

It took some tryouts, but here it is: the size independent image badge positioner.
HTML:
<div class="tile">
<span class="photo">
<img src="/photos/10.jpg" alt="10" /><ins></ins>
</span>
<p class="location">Houston</p>
<p class="taxonomy">T6 | Conduit | Infrastructure</p>
</div>
CSS:
.tile {
float: left;
width: 176px;
height: 206px;
margin: 0 20px 20px 0;
}
.photo {
display: block;
width: 176px;
height: 158px;
text-align: center;
line-height: 158px;
margin-bottom: 10px;
}
a {
display: inline-block;
position: relative;
line-height: 0;
}
img {
border: none;
vertical-align: middle;
}
ins {
background: url('/images/badge.png') no-repeat 0 0;
position: absolute;
left: 0;
top: 0;
width: 20px;
height: 20px;
}
Example:
In previous less successful attempts (see edit history), the problem was getting the image vertically centered ánd to get its parent the same size (in order to position the badge in the top-left of that parent). As inline element that parent doesn't care about the height of its contents and thus remains to small, but as block element it stretches to hís parent's size and thus got to high, see demonstration fiddle. The trick seems to be to give that parent a very small line-height (e.g. 0) and display it as an inline-block. That way the parent will grow according to its childs.
Tested in Opera 11, Chrome 11, IE8, IE9, FF4 and Safari 5 with all DTD's. IE7 fails, but a center-top alignment of the photo with badge at the right position isn't that bad at all. Works also for IE7 now because I deleted the spaces in the markup within the a tag. Haha, how weird!

EDIT3: This solution is very similar to my original solution. I didn't really look at your code much so I should have noticed this earlier. Your a tag is already wrapping each image so you can just add the badge in there and position it absolute. The a tag doesn't need width/height. Also you must add the badge image at the beginning of your a tag.
Demo: http://jsfiddle.net/wdm954/czxj2/1/
div.free_tile {
width: 176px;
height: 206px;
float: left;
}
a.img_container {
display: block;
margin-bottom: 10px;
}
span.transect_badge {
display:block;
position: absolute;
height: 20px;
width: 20px;
background-image: url('/images/transect-badge.png');
}
HTML...
<a class="img_container canonical" href="/photos/10">
<span class="transect_badge"></span>
<img class="canonical" src="path/to/img" />
</a>
Other solutions...
In my code I'm using SPAN tags so simulate images, but it's the same idea. The badge image, when positioned absolute, will create the desired effect.
Demo: http://jsfiddle.net/wdm954/62faE/
EDIT: In the case that you need jQuery to position. This should work (where .box is your container and .corner is the badge image)...
$('.box').each(function() {
$(this).find('.corner')
.css('margin-top', ( $(this).width() - $(this).find('.img').width() ) / 2);
$(this).find('.corner')
.css('margin-left', ( $(this).height() - $(this).find('.img').height() ) / 2);
});
EDIT2: Another solution would be to wrap each image with a new container. You would have to move the code that you use to center each image to the class of the new wrapping container.
Demo: http://jsfiddle.net/wdm954/62faE/1/
$('.img').wrap('<span class="imgwrap" />');
$('.imgwrap').prepend('<span class="badge" />');
Technically you can just add something like this to your HTML though without using jQuery to insert it.

Use an element other than <div>, e.g. <span> and put it inside your <a> element after the <img> element. Then, give the <a> element position:relative; and the <span> gets position:absolute; top:0px; left:0px;. That is, if you don't mind the badge also being part of the same link - but it's the easiest way. Also, the reason for using <span> is to keep your HTML4 valid, <div> would still be HTML5 valid, however.

I did find one solution using jQuery. I don't prefer this because it noticably impacts page loading, but it is acceptable if nothing else will work. I'm more interested in NGLN's idea which seems promising but I haven't entirely figured out yet. However, since this thread has picked up a lot of traffic I thought I'd post one solution that I came up with for future readers to consider:
Given this markup:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<span class="transect-badge"></span>
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
Same CSS as in question except:
span.transect-badge { display: block; height: 20px; width: 20px; position: absolute; background: url('/images/transect-badge.png'); }
Then this jQuery solves the problem:
$(function() {
$('img.canonical').load( function() {
var position = $(this).position();
$(this).next().css({ 'top': position.top+1, 'left': position.left+1 });
});
});
Like I said, though, this incurs noticeable run-time on the client end, so I'd prefer to use a non JS solution if I can. I'll continue to leave this question open while I test out and give feedback on the other solutions offered, with hopes of finding one of them workable without JS.