Disable enter key and space if iframe body is empty onload - javascript

How to check if iframe content is empty then then disable "enter key" and "space"
else if Enable.
DEMO HERE
var iframeContainerVal = $("#textEditor").contents().find("body").text();
var container = document.getElementById("textEditor").contentWindow;
function checkPress(){
alert('In Fn')
$(container).keypress(function(event){
if (event.keyCode == 10 || event.keyCode == 13 || event.keycode == 32 ) {
alert('aaa');
event.preventDefault();
}
});
}
if(iframeContainerVal == true) {
checkPress()
}
else {
alert('false')
}

Use return false;
function checkPress(){
alert('In Fn')
$(container).keypress(function(event){
if (event.keyCode == 10 || event.keyCode == 13 || event.keyCode == 32 ) {
return false;
}
});
}
you used event.keycode == 32 in your If statement But, it should capital C in keycode like
event.keyCode == 32

Check for iframe empty content , iframe id = 'if'
if ($('#iframe').contents().find('body').children().length == 0) {
alert('I frame is empty');
if (event.keyCode == 32 || event.keyCode == 13) {
return false;
}
}

Related

Need help restricting a js function(that restricts invalid chars) to a particular input type

Hi i would like to restrict a function that allows only, numbers, back space and left & right arrow keys to inputs with number type, because when i implement it, it also affects my text inputs.
<script>
function chars(evt){
var key = window.event ? event.keyCode : event.which;
if (event.keyCode == 8 || event.keyCode == 46
|| event.keyCode == 37 || event.keyCode == 39) {
return true;
}
else if ( key < 48 || key > 57 ) {
return false;
}
else return true;
}
</script>
Assign an id to your <input>. Add an event listener to it, like :
function getKeyCode() {
var key = window.event ? event.keyCode : event.which;
if(event.keyCode == 8 || event.keyCode == 46
|| event.keyCode == 37 || event.keyCode == 39) {
console.log(true);
//return true;
} else if (key < 48 || key > 57) {
console.log(false);
// return false;
} else {
console.log(true);
// return true;
}
}
var el = document.getElementById("myInput");
el.addEventListener("keypress", getKeyCode);
<input type="text" id="myInput">

Detect keycode ALT+L via Javascript

I try to detect if a user presses F12 or ALT + L.
document.onkeydown = function (event) {
event = (event || window.event);
if (event.keyCode == 123 || (event.keyCode == 18 && event.keyCode == 76)) {
//do anything
return false;
}
}
What am I doing wrong?
event.keyCode contains only one value. You can use event.altKey do detect if the alt key is pressed.
document.onkeydown = function (event) {
event = (event || window.event);
if (event.keyCode == 123 || (event.keyCode === 76 && event.altKey)) {
//do something
return false;
}
}
The standard way is to create a bool to detect if the 'alt' key is currently held down and then a separate if to detect if that is true and if the L key as just been pressed - see the fiddle:
http://jsfiddle.net/L4cb9/1
var held = false;
...
else if (event.keyCode == 18) {held = true;}
if (held == true && event.keyCode == 76) {
alert();
}
...
document.onkeyup = function(event) {
if (event.keyCode == 18) {held = false;}
}
This is applicable to holding any combination of keys - you can create an array for multiple key holds greater than two:
held = [];
...
if (event.keyCode == i) {held[i] = true;}
...
and so on

jquery keydown for only digits

i have an input box that is for payments, and i want to only allow number like x.xx, of course xxxx.x will work or xxxxx
i have the setup pretty much working minus some weird behavior. if the numbers 1 and 2 after the decimal can be 2 digits long (works) but if i press 3-9 then it only allows one of that digit. also 0's to the right of the decimal are being allowed infinitely.
heres what im working with. also i want to only allow the enter button and when its pressed then run a function
$('#money-button-input-box').keydown(function(event) {
var str = $(this).val()
if(str.length >= 1){
var rightHalf = str.split('.')[1];
if(rightHalf >= 3 && event.keyCode != 8 ){
event.preventDefault();
}
}
if( (event.keyCode == 190 || event.keyCode == 110) && str.replace(/[^.]/g, "").length >= 1 ){
event.preventDefault();
}
allowOnlyNumbers(event);
if (event.keyCode == 13) {
if($(this).val() == '')return;
enterPayment($(this));
}
});
and the function
function allowOnlyNumbers(events){
// Allow: backspace, delete, tab, escape, and enter
if ( events.keyCode == 46 || events.keyCode == 8 || events.keyCode == 9 || events.keyCode == 27 || events.keyCode == 13 ||
// allow decimals
events.keyCode == 190 || events.keyCode == 110 ||
// Allow: Ctrl+A
(events.keyCode == 65 && events.ctrlKey === true) ||
// Allow: home, end, left, right
(events.keyCode >= 35 && events.keyCode <= 39)) {
// let it happen, don't do anything
return;
} else {
// Ensure that it is a number and stop the keypress
if (events.shiftKey || (events.keyCode < 48 || events.keyCode > 57) && (events.keyCode < 96 || events.keyCode > 105 )) {
events.preventDefault();
}
}
}
http://jsfiddle.net/Qxtnd/
The problem of decimals is because you are using
rightHalf >= 3
which evaluates the actual number & not it's length, because javascript type-casts it to a number for the comparison. What you want instead is the number of digits, try
rightHalf.toString().length >= 2
Fiddle here http://jsfiddle.net/Qxtnd/1/
Edit
As long as rightHalf is a string you can do:
rightHalf.length >= 2
if rightHalf was a number you would get an exception doing that.
function isNumberKeyUp(event, obj, beforeLength, afterLength) {
var text = document.getElementById(obj).value;
var splitText = text.split('.');
if (splitText.length > 1 && splitText[1].length > afterLength) {
document.getElementById(obj).value = splitText[0] + "." + splitText[1].substring(0,2);
return false;
}
return true;
}
function isNumberKey(event, obj,beforeLength,afterLength) {
var keyCode1 = event.keyCode;
var keyCode = 0;
if (keyCode1 == 0)
keyCode = event.which;
else {
keyCode = keyCode1;
}
if ((keyCode >= 48 && keyCode <= 57) || keyCode == 46 || keyCode == 13 || keyCode == 27 || keyCode == 127 ) {
var text = document.getElementById(obj).value;
if (keyCode == 46 && keyCode1 == 0) {
if (text.toString().indexOf(".") != -1) {
return false;
}
}
if (keyCode == 46) {
if (text.toString().indexOf(".") != -1) {
return false;
}
}
var splitText = text.split('.');
if (splitText[0].length >= beforeLength) {
if (keyCode == 46 && text.toString().indexOf(".") == -1) {
return true;
} else if (text.toString().indexOf(".") != -1)
{
return true;
}
return false;
}
}
else {
return GetDefault(event);
}
return true;
}
function GetDefault(event) {
var keyCode = event.keyCode;
if (keyCode == 0)
keyCode = event.which;
if (keyCode == 8 || keyCode == 9 || keyCode == 35 || keyCode == 36 || keyCode == 37 || keyCode == 38 || keyCode == 39 || keyCode == 40 || keyCode == 46 || keyCode == 118) {
return true;
}
return false;
}
Below is the html to call this events
<input type="text" onkeyup="return isNumberKeyUp(event,'txtID',9,2);" onkeypress="return isNumberKey(event,'txtID',9,2);" required="required" id="txtID" maxlength="12" value="1.00" name="txtID">
Here's the FIDDLE
rightHalf.length >= 2
$('#money-button-input-box').keyup(function () {
$(this).val(FormatNumber($(this).val()));
});
function FormatNumber(val){
var split = val.split('.');
if (split.length>1) return OnlyNumbersAllowed(split[0])+'.'+OnlyNumbersAllowed(split[1]);
else return OnlyNumbersAllowed(split[0]);
}
function OnlyNumbersAllowed(val){
return val.replace(/\D/g, '');
}
http://jsfiddle.net/Qxtnd/7/
You could easly put this regex in any function, instead of writing what you have now.

Event is not defined error in javascript only Firefox

I use the following script to validate the text box to enter only numbers and (.) which means it is decimal textbox validation. It was work fine in Internet Explorer and Google Chrome. If I execute the function in FireFox I get the following Error:
Event Is not Defined.
How to solve this?
function abc(event) {
if (event.keyCode > 47 && event.keyCode < 58) {
return true;
}
if (event.keyCode == 8 || event.keyCode == 46)
{
return true;
}
return false;
}
I call this function like this:
$('.decimalValidate').live('keypress',function(){
var decimalid=$(this).attr("id");
var decimalval=$('#'+decimalid).val();
var decimalvalidate=abc(decimalval);
if(decimalvalidate == false)
return false;
});
I assign this validation for text box like this:
input type="text" id="Total" class="abc"
Try this
function abc(event) {
if(!event)
event= window.event;
if (event.keyCode > 47 && event.keyCode < 58) {
return true;
}
if (event.keyCode == 8 || event.keyCode == 46)
{
return true;
}
return false;
}
and
$('.decimalValidate').live('keypress',function(e){
var decimalid=$(this).attr("id");
var decimalval=$('#'+decimalid).val();
var decimalvalidate=abc(evt); //keypress event
if(decimalvalidate == false)
return false;
});
decimalval is not an Event object, and you have to pass it to the abc function in ordert to find out which key you pressed:
$('.decimalValidate').live('keypress',function(ev){
var decimalid=$(this).attr("id");
var decimalval=$('#'+decimalid).val();
var decimalvalidate=abc(ev);
if(decimalvalidate == false)
return false;
});
$('.decimalValidate').live('keypress',function(e){
var decimalvalidate=abc(e); //this will point to the event of the keypress.
if(decimalvalidate == false)
return false;
});
I am not sure why you did all of the decimalid and decimalval operations, but if you want the event, do as I wrote in the edited code above.
Good luck.
$('.decimalValidate').on('keypress',function(event){
var decimalid = $(this).attr("id");
var decimalval = $('#'+decimalid).val();
var decimalvalidate = abc(event);
if(decimalvalidate == false)
return false;
});
function abc(event) {
if (event.keyCode > 47 && event.keyCode < 58) {
return true;
}
if (event.keyCode == 8 || event.keyCode == 46)
{
return true;
}
return false;
}
It helps you..

javascript : key validation

im using javascript to validate keys in textbox. it is not working :(
function numeric(e) {
return ((e.keyCode == 8) ||
(e.keyCode == 9) ||
(e.keyCode > 47 && e.keyCode < 58) ||
(e.keyCode > 36 && e.keyCode < 41) ||
(e.keyCode == 46) ||
(e.keyCode > 95 && e.keyCode < 106) ||
e.keyCode == 190 ||
e.keyCode == 110);
}
help me...
function numeric(e) {
e = e || window.event;
keycode = e.keyCode || e.which;
if(keycode === 13){
alert("cheese");
}
}
I know that in I.E. you can set event.keyCode=0 to suppress the key appearing in the control. But I think you need to trap the onkeydown. Firefox might have an equivalent. This is good because it prevents the key actually "arriving" at the control.
Also keep in mind that you might need to handle combinations of Shift + key and alt + key.
a good debug technique for this sort of thing is to say windows.status = event.keyCode,
and you can see what the keycode is as you type it...
Just try out the following code. I have checked F5 keycode, you can check as you want
function disableKey(event)
{
if (!event) event = window.event;
if (!event) return;
var keyCode = event.keyCode ? event.keyCode : event.charCode;
if (keyCode == 116) {
showMsg("This functionality is disabled.");
window.status = "F5 key detected! Attempting to disabling default response.";
window.setTimeout("window.status='';", 2000);
// Standard DOM (Mozilla):
if (event.preventDefault) event.preventDefault();
//IE (exclude Opera with !event.preventDefault):
if (document.all && event && !event.preventDefault) {
event.cancelBubble = true;
event.returnValue = false;
event.keyCode = 0;
}
return false;
}
}
function setEventListenerForFrame(eventListener)
{
document.getElementById('your_textbox').onkeydown = eventListener;
//frames['frame'].document.onkeypress = eventListener;
}
<body onload="setEventListener(disableKey);">
Try this if you want a numbers only textbox:
function numbercheck(event) {
var unicode = event.charCode; var unicode1 = event.keyCode; if (navigator.userAgent.indexOf("Firefox") != -1 || navigator.userAgent.indexOf("Safari") != -1) {
if (unicode1 != 8) {
if ((unicode >= 48 && unicode <= 57) || unicode1 == 37 || unicode1 == 39 || unicode1 == 35 || unicode1 == 36 || unicode1 == 9 || unicode1 == 46)
{ return true; }
else
{ return false; }
}
}
if (navigator.userAgent.indexOf("MSIE") != -1 || navigator.userAgent.indexOf("Opera") == -1) {
if (unicode1 != 8) {
if (unicode1 >= 48 && unicode1 <= 57)
{ return true; }
else
{ return false; }
}
}
}
And in your textbox call it on the onkeypress event:
onkeypress="return numbercheck(event)"

Categories

Resources