Develop Reference

need help removing an IMG and replacing it with text in its position with javascript

Im working on a project and a part of it is making an image disapear on hover, and replace that with text in the same location! I have to do it through javascript.
im very new to front end web development so any help would be great!
.main-img1{
height: 400px;
width: 600px;
margin-top: 80px;
background-size: 600px 400px;
box-shadow: 10px 10px 5px rgb(24, 22, 22);
position: relative;
text-align: center;
font-size: 25px;
color: black;
border-radius: 50px;
}
.img1-text{
display: none;
position: absolute;
bottom: 8px;
left: 150px;
<section class="main-body">
<div>
<img class="main-img1" src="img/automotive.jpg">
<h1 class="img1-text" id="img1text"> Here are some samples of my automotive photography! I specialize in "Rolling Shots" which are caputring a vehicle in motion, while the background and foreground show the motion.</h1>
</div>

You can replace any element using the "magical" outerHTML like this...
First, I gave your image an ID to make javascript operations easier...
<img id="I" class="main-img1" src="img/automotive.jpg">
Now replace the image with a paragraph of text...
I.outerHTML='<p>Well what do you know!</p>';
For easy one-line HTML...
<img onmouseover="this.outerHTML='<p>Well what do you know!</p>';" class="main-img1" src="img/automotive.jpg">

First off, this is a very odd thing to do in Javascript. Usually hover states, appearing and disappearing, etc. are handled by CSS.
to do it in js you have to add a mouseover event listener to the image to execute a function to grab the element you want to disappear, add a css class to apply "display: none" to it, grab the element you want to appear and remove a class that adds "display: none" from it.
assuming you have a 'display-none' class on your text element that applies 'display: none' to it, you can do this:
const image = document.querySelector('.main-image1')
const text = document.querySelector('.img1-text')
image.addEventListener('mouseover', () => {
image.classList.add('display-none')
text.classList.remove('display-none')
}
if you were to do this with css its as simple as
.image {
z-index: 2;
}
.image:hover {
display: none;
}
.text {
z-index: 1;
}
that way the text is set behind the image and when you hover over the image it disappears. This also has the benefit of when you take your cursor off the image for the image to reappear where js will need to be told explicitly to do that.

Slider of images with undefined height

I'm trying to create a slider of images (previous/next) so the images slide to the left when I click "previous" and to the right when I click "next" with 0.5s of slowness, so it takes some animation. And when I reach the last image and click "next", I want images to "run backwards" to the first one, the same when I'm in the first one and click "previous", so it "run forward" until the last one.
I want the same behaviour this JSFiddle shows. (but I don't need the timer to move images automatically and don't need the "triggers" buttons, just "previous" and "next").
The problem here is that my images don't have fixed size. I define a width in percentage and can't define a height because I have responsive design, the image resizes as I resize the browser window.
The jQuery to previous/next actions is pretty easy, but I just can't find a way to add this animation when I remove/add the "active" class to my images (so they become visible or not).
I have already tried putting all images side by side and showing only the first one (setting container width equals to image width), so when I click "next" I just "move" the container to the left so it begins to display the next image, but it doesn't work because once I can't define the height of the images, they will appear underneath each other, not side by side.
JSFiddle
HTML
<div class="images">
<img class="active" src="1.jpg">
<img src="2.jpg">
<img src="3.jpg">
</div>
<div class="previous">previous</div>
<div class="next">next</div>
CSS
img {
width: 100px;
display: none;
float: left;
}
img.active {
display: block;
}
jQuery
$('.next').on('click', function() {
var active = $('img.active');
var next = active.next('img');
if (next.length) {
active.removeClass('active');
next.addClass('active');
} else {
active.removeClass('active');
$('.images img:first').addClass('active');
}
});

Well the problem is the height for sliding.
First you need to have an element which is the "picture frame" which hold all the other images. That's important.
For better imagination a picture:
Now you have several technics to show and hide images. One could be to set the opacity. When using transition: opacity .15s ease-in-out; The one Picture is fading out and the next on is fading in.
For the slideshow effect is given to the position of the visible image to its width to the left and the image previously purely new to his wide to the right and then to 0. Thus, moves the current picture on the left the frame out and the new comes out right in.
And here is the difficulty if the height is not the same. If the current image 300px high and the new 400px, so the image frame here would adjust his height immediately once the new image start to be visible.
The content below would start to jump with each slide.
Is that so desired???
If yes, I can make you an example how it works.

You can actually do this in Pure CSS!
You use an ID and a label (with a for attribute=for the targeted id)
That's basically it. All you have left is to style it! (Forked from Joshua Hibbert's Pen)
body {
background: #f7f4e2;
}
/* Slides */
.slider input {
display: none;
}
/* Buttons */
.slider label {
display: none;
cursor: pointer;
position: absolute;
top: 6em;
left: 50%;
transform: translateX(-50%);
color: #fff;
background: #000;
padding: 1.36em .5em;
opacity: .6;
font-size: 19px;
font-family: fantasy;
font-weight: bold;
transition: .25s;
}
.slider label:hover {
opacity: 1;
}
.previous {
margin-left: -188px;
}
.next {
margin-left: 188px;
}
#slide1:checked ~ .buttons .slide1 {
display: block;
}
#slide2:checked ~ .buttons .slide2 {
display: block;
}
#slide3:checked ~ .buttons .slide3 {
display: block;
}
#slide4:checked ~ .buttons .slide4 {
display: block;
}
/* Images */
.slider {
position: absolute;
top: 50%;
left: 50%;
width: 400px;
height: 300px;
margin-top: -150px;
margin-left: -200px;
white-space: nowrap;
padding: 0;
float: left;
transition: .25s;
overflow: hidden;
box-shadow: 0 0 0 3.12px #e8e8e8,
0 0 0 12.64px #eaebe4,
0 0 0 27.12px #000,
0 24px 3.824em 5.12px #000;
}
.slide {
width: 500em;
transition: .25s;
}
.slider img {
float: left;
width: 400px;
height: 300px;
}
#slide1:checked ~ .slide {
margin: 0;
}
#slide2:checked ~ .slide {
margin: 0 0 0 -400px;
}
#slide3:checked ~ .slide {
margin: 0 0 0 -800px;
}
#slide4:checked ~ .slide {
margin: 0 0 0 -1200px;
}
<div class="slider">
<input type="radio" name="slide" id="slide1" checked="true" />
<input type="radio" name="slide" id="slide2" />
<input type="radio" name="slide" id="slide3" />
<input type="radio" name="slide" id="slide4" />
<div class="buttons">
<!-- Slide 1 -->
<label for="slide4" class="slide1 previous"><</label>
<label for="slide2" class="slide1 next">></label>
<!-- Slide 2 -->
<label for="slide1" class="slide2 previous"><</label>
<label for="slide3" class="slide2 next">></label>
<!-- Slide 3 -->
<label for="slide2" class="slide3 previous"><</label>
<label for="slide4" class="slide3 next">></label>
<!-- Slide 4 -->
<label for="slide3" class="slide4 previous"><</label>
<label for="slide1" class="slide4 next">></label>
</div>
<div class="slide">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/872485/coldchase.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/980517/icehut_sm.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/943660/hq_sm.jpg">
<img src="http://dribbble.s3.amazonaws.com/users/322/screenshots/599584/home.jpg">
</div>
</div>
Although this method is the most compatible (except for old versions of IE) and depending on how you animate it this method can be more time consuming than a JS method, but can also be faster, it just depends on how you want the animations to go, or you could use a css library that does this for you.
Here are some css image sliders I recommend.
10 Amazing Pure CSS3 Image Sliders
http://bashooka.com/coding/pure-css3-image-sliders/
Pure CSS Image Slider Without Javascript #Codeconvey is a good solution for what you're looking for, but lots of CSS
http://codeconvey.com/pure-css-image-slider/
The downside to these along with what you're working on is that you can't touch to slide on a phone or tablet which is more common now a days with photo galleries.
I recommend checking out Fotorama it's amazing! :)

Perhaps not the ideal situation but at least it will give you an idea. you can use the animation function of jQuery and I also changed your code a bit. See demo here
Within your HTML I would say this:
<div id="images">
<div class="images-wrapper">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/02/In-the-spotlight.jpg">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/02/Bath-time-with-ducky.jpg">
<img src="http://www.cutestpaw.com/wp-content/uploads/2016/03/FB_IMG_1452981788903.jpg">
<img src="http://www.pictures-of-cats.org/images/Pixiebob-cat-list-of-cat-breeds-pictures-of-cats.jpg" />
</div>
</div>
<div class="previous">
previous
</div>
<div class="next">
next
</div>
and within your jQuery code you can animate the width:
$('.images-wrapper img:gt(0)').hide();
$('.next').click(function() {
$('.images-wrapper img:first-child').animate({width:'toggle'},350).next().fadeIn().end().appendTo('.images-wrapper');
});
$('.previous').click(function() {
$('.images-wrapper img:first-child').animate({width:'toggle'},350);
$('.images-wrapper img:last-child').prependTo('.images-wrapper').fadeOut();
$('.images-wrapper img:first-child').fadeIn();
});
With this implementation the whole process of changing and adding the active class to the image is removed and replaced by animation functions

Simplest solution (I think) is to force the items to be of the same size, by placing them in a div. You can even have the div show the image without the use of an img tag, by using the background-image CSS feature (see http://www.w3schools.com/css/css3_backgrounds.asp for more details).
The item CSS could look like:
.item {
background-size: contain;
background-position: center;
}
and in each item in the HTML:
<div class='item' style='background-image: url(img1.jpg)' />
<div class='item' style='background-image: url(img2.jpg)' />
<div class='item' style='background-image: url(img3.jpg)' />

I finally got there.
HERE is the fiddle with the solution I developed.
The main problem in the implementation of this image slider was that images, althought were all the same size, have dynamic width (defined in % on CSS) and dynamic height (not defined on CSS).
The solution was basically put an "fake" image (with opacity: 0) inside my container so the container get the actual size of images I will use in the slider; put a div to "hold" the real images with position: absolute and give it a width calculted by number of images * 100%; and for last, give each image in my slider a width of x%, based on number of images.
In the jQuery, I "move" the "images holder div" always by %, never by static values, once the width of everything can change if I resize the window.
If you start to slide the images to the left and right and then resize the window, you will see that it continues to work perfectly.

I have implemented using css3 animations. However this will require manipulating animation values in css every time a slide gets added or removed.
#keyframes slideAnim {
0% {
transform: translateX(0)
}
12.5% {
transform: translateX(0%);
}
25% {
transform: translateX(-25%);
}
37.5% {
transform: translateX(-25%)
}
50% {
transform: translateX(-50%)
}
62.5% {
transform: translateX(-50%)
}
75% {
transform: translateX(00%);
}
89.5% {
transform: translateX(00%)
}
100% {
transform: translateX(00%)
}
}
Here the animation values are set such that there is a pause between slide transitions. I have added a parent frame to show only one slide at a time.
Please refer this fiddle.

Javascript, HTML5 (canvas) progressbar with update

I'm looking for the best way to do a progress bar (in my case it's a life bar for a game) in an html5 canvas.
I don't know if it's better to use javascript and dom element, or draw this bar directly in the canvas.
I need an update function, for example myBar.updateValue(40), and I need to show the new bar without refresh all the page or all the canvas, of course.
Do you know something like that? An existing script? Thanks!

It’s very easy in HTML/CSS:
<style>
#progress-holder{width:400px;height:20px;background:grey}
#progress{width:0;height:100%;background:black}
</style>
<div id="progress-holder">
<div id="progress"></div>
</div>
<script>
var progress = document.getElementById('progress');
function updateValue(perc) {
progress.style.width = perc+'%';
}
updateValue(40);
</script>
DEMO: http://jsbin.com/EGAzAZEK/1/edit
And animating with CSS: http://jsbin.com/EGAzAZEK/3/edit

HTML:
<div class='progress'>
<div class='progress-bar' data-width='//Enter a percent value here'>
<div class='progress-bar-text'>
Progress: <span class='data-percent'>//This is auto-generated by the script</span>
</div>
</div>
</div>
CSS:
html, body {
margin: 0;
padding: 15px;
width: 100%;
height: 100%;
position: relative;
color: #fff;
}
.progress {
position: relative;
width: 100%;
height: 30px;
}
.progress-bar {
margin-bottom: 5px;
width: 0%;
height: 30px;
position: relative;
background-color: rgb(66, 139, 202);
}
.progress-bar-text {
position: absolute;
top: 0px;
width: 100%;
text-align: center;
/*
Do not change the values below,
unless you want your text to display away from the bar itself. */
line-height: 30px;
vertical-align: middle;
}
jQuery:
$('.progress-bar').each(function (){
var datawidth = $(this).attr('data-width');
$(this).find("span.data-percent").html(datawidth + "%");
$(this).animate({
width: datawidth + "%"
}, 800);
});
Link to JSFiddle
The HTML data-width attribute is used to track the percent the bar should be set to. Change it to your liking.
The jQuery script works with ALL progress bars on your page (See the JSFiddle, so you don't have to copy and paste the same jQuery for every new progress bar.
(Just be sure to keep the structure of the HTML, or change it to your liking).
The div "progress" is just an expander, it can be named whatever your want - without you having to change the jQuery.
EDIT:
If you can use Javascript & HTML, don't use a canvas. Canvas (imho) are good for only 1 thing: Seat bookings for concerts, theaters and alike.

Two photos positioned on each other. Show one on hover. Possible with css or only javascript?

What I want to do is to show the top photo (which is set to visibility: hidden) on hover. I have two photos positioned on each other like this:
<div class="frame">
<img src="./img/portfolio/default1.jpg" width="300" height="178" alt="Title Here"></a>
<div class="boxwrapper" style="visibility: hidden;"></div>
</div>
Added the second photo through css:
.boxwrapper {
background: url("../img/boxPlus.gif");
position: relative;
width: 300px;
height: 178px;
left: -6px;
top: -184px;
z-index: 1000;
}
Is it possible to do with css? Tried (and several more options):
#frame img:hover .boxwrapper {
visibility: visible;
}
But it is not working. Or this is only possible with javascript? If yes, please give some tips as I am not too much of javascript guy. Thanks!

You could set the photo as background of the boxwrapper
.boxwrapper{
background: url("../img/boxPlus.gif");
}
.boxwrapper:hover{
background: url("../img/portfolio/default1.jpg");
}
if this is not possible you could add it as background trough a style attribute inside your html
<div class="boxwrapper" style="background: url('../img/boxPlus.gif');" ></div>

You'd have to put the :hover class on a parent container. CSS does not allow such things to trickle "up" the tree, only down.
.boxwrapper {
display: none;
}
.frame:hover .boxwrapper {
display: block;
}

Position badge over corner of image automatically

I have a layout where images "float" within a certain area. The layout looks like this:
The source like this:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<!-- EDIT: I am aware that I can put the badge here. See the edit notes and image below. -->
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
The CSS looks like this (in SCSS):
div.free_tile { width: 176px; height: 206px; float: left; margin: 0 20px 20px 0; position: relative;
&.last { margin: 0 0 20px 0; }
a.img_container { display: block; width: 176px; height: 158px; text-align: center; line-height: 156px; margin-bottom: 10px; }
img { margin: 0; border: 1px solid $dark3; display: inline-block; vertical-align: middle; #include boxShadow;
&.canonical { border: 1px solid $transect; }
}
.location, .taxonomy { width: 176px; }
.location { font-weight: 700; }
.taxonomy { line-height: 10px; font-size: 10px; text-transform: uppercase; height: 20px; overflow: hidden; }
}
div.transect_badge { height: 20px; width: 20px; background: url('/images/transect-badge.png'); }
So, basically the images are sitting vertically-aligned middle and text-aligned center, and they have a maximum width of 176 and max height of 158, but they're cropped to maintain the original aspect ratio so the actual top corner of each image falls differently depending on which image it is.
I have a badge that I'd like to put in the top corner of certain images (when the image is "canonical"). You see the style for this above (div.transect_badge).
The problem, of course, is I don't know where the top corner of the image will be so I can't hardcode the position via CSS.
I assume that I'll need to do this via jQuery or something. So, I started with a jQuery method to automatically append the badge div to any canonical images. That works fine, but I can't figure out how to position it over the top left corner.
How can this be done? (ideally using just HTML and CSS, but realistically using JS/jQuery)
--EDIT--
Here's the problem: The image is floating inside a container, so the corner of the image might fall anywhere inside the outer limits of the container. Here's an example of what happens if I try to use position:absolute; top:0; left:0 inside the same container the image is bound by:

It took some tryouts, but here it is: the size independent image badge positioner.
HTML:
<div class="tile">
<span class="photo">
<img src="/photos/10.jpg" alt="10" /><ins></ins>
</span>
<p class="location">Houston</p>
<p class="taxonomy">T6 | Conduit | Infrastructure</p>
</div>
CSS:
.tile {
float: left;
width: 176px;
height: 206px;
margin: 0 20px 20px 0;
}
.photo {
display: block;
width: 176px;
height: 158px;
text-align: center;
line-height: 158px;
margin-bottom: 10px;
}
a {
display: inline-block;
position: relative;
line-height: 0;
}
img {
border: none;
vertical-align: middle;
}
ins {
background: url('/images/badge.png') no-repeat 0 0;
position: absolute;
left: 0;
top: 0;
width: 20px;
height: 20px;
}
Example:
In previous less successful attempts (see edit history), the problem was getting the image vertically centered ánd to get its parent the same size (in order to position the badge in the top-left of that parent). As inline element that parent doesn't care about the height of its contents and thus remains to small, but as block element it stretches to hís parent's size and thus got to high, see demonstration fiddle. The trick seems to be to give that parent a very small line-height (e.g. 0) and display it as an inline-block. That way the parent will grow according to its childs.
Tested in Opera 11, Chrome 11, IE8, IE9, FF4 and Safari 5 with all DTD's. IE7 fails, but a center-top alignment of the photo with badge at the right position isn't that bad at all. Works also for IE7 now because I deleted the spaces in the markup within the a tag. Haha, how weird!

EDIT3: This solution is very similar to my original solution. I didn't really look at your code much so I should have noticed this earlier. Your a tag is already wrapping each image so you can just add the badge in there and position it absolute. The a tag doesn't need width/height. Also you must add the badge image at the beginning of your a tag.
Demo: http://jsfiddle.net/wdm954/czxj2/1/
div.free_tile {
width: 176px;
height: 206px;
float: left;
}
a.img_container {
display: block;
margin-bottom: 10px;
}
span.transect_badge {
display:block;
position: absolute;
height: 20px;
width: 20px;
background-image: url('/images/transect-badge.png');
}
HTML...
<a class="img_container canonical" href="/photos/10">
<span class="transect_badge"></span>
<img class="canonical" src="path/to/img" />
</a>
Other solutions...
In my code I'm using SPAN tags so simulate images, but it's the same idea. The badge image, when positioned absolute, will create the desired effect.
Demo: http://jsfiddle.net/wdm954/62faE/
EDIT: In the case that you need jQuery to position. This should work (where .box is your container and .corner is the badge image)...
$('.box').each(function() {
$(this).find('.corner')
.css('margin-top', ( $(this).width() - $(this).find('.img').width() ) / 2);
$(this).find('.corner')
.css('margin-left', ( $(this).height() - $(this).find('.img').height() ) / 2);
});
EDIT2: Another solution would be to wrap each image with a new container. You would have to move the code that you use to center each image to the class of the new wrapping container.
Demo: http://jsfiddle.net/wdm954/62faE/1/
$('.img').wrap('<span class="imgwrap" />');
$('.imgwrap').prepend('<span class="badge" />');
Technically you can just add something like this to your HTML though without using jQuery to insert it.

Use an element other than <div>, e.g. <span> and put it inside your <a> element after the <img> element. Then, give the <a> element position:relative; and the <span> gets position:absolute; top:0px; left:0px;. That is, if you don't mind the badge also being part of the same link - but it's the easiest way. Also, the reason for using <span> is to keep your HTML4 valid, <div> would still be HTML5 valid, however.

I did find one solution using jQuery. I don't prefer this because it noticably impacts page loading, but it is acceptable if nothing else will work. I'm more interested in NGLN's idea which seems promising but I haven't entirely figured out yet. However, since this thread has picked up a lot of traffic I thought I'd post one solution that I came up with for future readers to consider:
Given this markup:
<div class="free_tile">
<a class="img_container canonical" href="/photos/10">
<img class="canonical" src="http://s3.amazonaws.com/t4e-development/photos/1/10/andrew_burleson_10_tile.jpg?1303238025" alt="Andrew_burleson_10_tile">
<span class="transect-badge"></span>
</a>
<div class="location">Houston</div>
<div class="taxonomy"> T6 | Conduit | Infrastructure </div>
</div>
Same CSS as in question except:
span.transect-badge { display: block; height: 20px; width: 20px; position: absolute; background: url('/images/transect-badge.png'); }
Then this jQuery solves the problem:
$(function() {
$('img.canonical').load( function() {
var position = $(this).position();
$(this).next().css({ 'top': position.top+1, 'left': position.left+1 });
});
});
Like I said, though, this incurs noticeable run-time on the client end, so I'd prefer to use a non JS solution if I can. I'll continue to leave this question open while I test out and give feedback on the other solutions offered, with hopes of finding one of them workable without JS.