I'm trying to use JavaScript to insert HTML ruby characters on my text. The idea is to find the kanji and replace it with the ruby character that is stored on the fgana array. My code goes like this:
for (var i = 0; i < kanji.length; i++) {
phrase = phrase.replace(kanji[i],"<ruby><rb>" + kanji[i] + "</rb><rt>" + fgana[i] + "</rt></ruby>");
}
It does that just fine when there aren't duplicated characters to be replaced, but when there are the result is different from what I except. For example, if the arrays are like this:
kanji = ["毎朝","時","時"]
fgana = ["まいあさ"、"とき"、"じ"]
And the phrase is あの時毎朝６時におきていた the result becomes:
あの<ruby><rb><ruby><rb>時</rb><rt>じ</rt></ruby></rb><rt>とき</rt></ruby><ruby><rb>毎朝</rb><rt>まいあさ</rt></ruby> 6 時 におきていた。
Instead of the desired:
あの<ruby><rb>時</rb><rt>とき</rt></ruby><ruby><rb>毎朝</rb><rt>まいあさ</rt></ruby> 6 <ruby><rb>時</rb></ruby></rb><rt>じ</rt> におきていた。
To illustrate it better, look at the rendered example:
Look at how the first 時 receives both values とき and じ while the second receives nothing. The idea is to the first be とき and the second じ (as Japanese has different readings for the same character depending on some factors).
Whats might be the failure on my code?
Thanks in advance
It fails because the char you are looking for still exists in the replaced version:
...replace(kanji[i],"<ruby><rb>" + kanji[i]...
And this one should work:
var kanji = ["毎朝", "時", "時"],
fgana = ["まいあさ", "とき", "じ"],
phrase = "あの時毎朝 6 時におきていた",
rx = new RegExp("(" + kanji.join("|") + ")", "g");
console.log(phrase.replace(rx, function (m) {
var pos = kanji.indexOf(m),
k = kanji[pos],
f = fgana[pos];
delete kanji[pos];
delete fgana[pos];
return "<ruby><rb>" + k + "</rb><rt>" + f + "</rt></ruby>"
}));
Just copy and paste into console and you get:
あの<ruby><rb>時</rb><rt>とき</rt></ruby><ruby><rb>毎朝</rb><rt>まいあさ</rt></ruby> 6 <ruby><rb>時</rb><rt>じ</rt></ruby>におきていた
Above line is a bit different from your desired result thou, just not sure if you indeed want this:
...6 <ruby><rb>時</rb></ruby></rb><rt>じ</rt>...
^^^^^ here ^ not here?
Related
I am working with a javascript program that needs to be formatted a certain way. Basically, I need to have each section of information from an array be a set length, for example 12 characters long, and no more than that.
The problem I am running into comes when a value in the array is NOT 12 characters long. If I have a value that is less than the 12 characters the remaining character allotment needs to be filled with blank spaces.
The length of each section of information varies in size and is not always 12. How can I add X number of blank spaces, should the length not meet the maximum requirement, for each section?
This is where I am at with adding space:
str = str + new Array(str.length).join(' ');
I am pretty sure what I have above is wrong but I believe I am on the right track with the .join function. Any ideas?
EDIT: I was asked to show a wanted outcome. It is a bit complicated because this javascript is being run out of a web report tool and not out of something like Visual Studio so its not traditional JS.
The outcome expected should look something like:
Sample Image
So as shown above the data is in one line, cutting off longer strings of information or filling in blank spaces if its too short for the "column" to keep that nice even look.
try this code and leverage the wonders of the map function:
let say your array is:
var myArr = ["123456789012", "12345678901", "123"];
now just apply this function
myArr.map(function(item){ //evalueate each item inside the array
var strLength = item.length; //apply this function to each item
if (strLength < 12){
return item + ' '.repeat(12-item.length) //add the extra spaces as needed
} else {
return item; // return the item because it's length is 12 or +
}
})
What you are looking for is the ' '.repeat(x) - where x is the times you want to repeat the string you have set, it could be '*'.repeat(2) and you would get '**', if you want to understand more about it look at the docs
depending on which version of javascript, this might work:
if (str.length < 12) str += ' '.repeat(12 - str.length);
Not exactly sure how you're setup -- but something like the following will accept an array and return another array with all its values being 12 characters in length.
var array = ['Test', 'Testing', 'Tested', 'This is not a Test'];
var adjustedArray = correctLength(array, 12);
function correctLength(array, length) {
array.map(function(v, i) {
if (array[i].length < length) {
array[i] += Array((length+1) - array[i].length).join('_');
}
// might not need this if values are already no greater than 12
array[i] = array[i].substring(0, length);
});
return array;
}
console.log(adjustedArray);
I am new in programing and right now I am working on one program. Program need to find the substring in a string and return the index where the chain starts to be the same. I know that for that I can use "indexOf". Is not so easy. I want to find out substrings with at moste one different char.
I was thinking about regular expresion... but not really know how to use it because I need to use regular expresion for every element of the string. Here some code wich propably will clarify what I want to do:
var A= "abbab";
var B= "ba";
var tb=[];
console.log(A.indexOf(B));
for (var i=0;i<B.length; i++){
var D=B.replace(B[i],"[a-z]");
tb.push(A.indexOf(D));
}
console.log(tb);
I know that the substring B and string A are the lowercase letters. Will be nice to get any advice how to make it using regular expresions. Thx
Simple Input:
A B
1) abbab ba
2) hello world
3) banana nan
Expected Output:
1) 1 2
2) No Match!
3) 0 2
While probably theoretically possible, I think it would very complicated to try this kind of search while attempting to incorporate all possible search query options in one long complex regular expression. I think a better approach is to use JavaScript to dynamically create various simpler options and then search with each separately.
The following code sequentially replaces each character in the initial query string with a regular expression wild card (i.e. a period, '.') and then searches the target string with that. For example, if the initial query string is 'nan', it will search with '.an', 'n.n' and 'na.'. It will only add the position of the hit to the list of hits if that position has not already been hit on a previous search. i.e. It ensures that the list of hits contains only unique values, even if multiple query variations found a hit at the same location. (This could be implemented even better with ES6 sets, but I couldn't get the Stack Overflow code snippet tool to cooperate with me while trying to use a set, even with the Babel option checked.) Finally, it sorts the hits in ascending order.
Update: The search algorithm has been updated/corrected. Originally, some hits were missed because the exec search for any query variation would only iterate as per the JavaScript default, i.e. after finding a match, it would start the next search at the next character after the end of the previous match, e.g. it would find 'aa' in 'aaaa' at positions 0 and 2. Now it starts the next search at the next character after the start of the previous match, e.g. it now finds 'aa' in 'aaaa' at positions 0, 1 and 2.
const findAllowingOneMismatch = (target, query) => {
const numLetters = query.length;
const queryVariations = [];
for (let variationNum = 0; variationNum < numLetters; variationNum += 1) {
queryVariations.push(query.slice(0, variationNum) + "." + query.slice(variationNum + 1));
};
let hits = [];
queryVariations.forEach(queryVariation => {
const re = new RegExp(queryVariation, "g");
let myArray;
while ((searchResult = re.exec(target)) !== null) {
re.lastIndex = searchResult.index + 1;
const hit = searchResult.index;
// console.log('found a hit with ' + queryVariation + ' at position ' + hit);
if (hits.indexOf(hit) === -1) {
hits.push(searchResult.index);
}
}
});
hits = hits.sort((a,b)=>(a-b));
console.log('Found "' + query + '" in "' + target + '" at positions:', JSON.stringify(hits));
};
[
['abbab', 'ba'],
['hello', 'world'],
['banana', 'nan'],
['abcde abcxe abxxe xbcde', 'abcd'],
['--xx-xxx--x----x-x-xxx--x--x-x-xx-', '----']
].forEach(pair => {findAllowingOneMismatch(pair[0], pair[1])});
I need to make a textbox with in there a word when i click on a button that word needs to convert into numbers useing charAt and that number needs to get +2 and than converted back into words and that word needs to get alerted i dont know what to do i find this really hard i made a function that is useless but i just want to show you what i did please help :)
function codeer(){
var woord2 = document.getElementById("woord")
var woordterug = woord2.charAt(0)
var woord234 = document.getElementById("woord");
var woord23 = woord234.charAt(str.length+2);
}
You could get the char code with String#charCodeAt from the character add two and build a new string with String.fromCharCode.
function codeer() {
var woord = document.getElementById("woord").value,
coded = '',
i;
for (i = 0; i < woord.length; i++) {
coded += String.fromCharCode(woord.charCodeAt(i) + 2);
}
console.log(coded);
}
<input id="woord" /> <button onclick="codeer()">cooder</button>
You should search the internet for a JavaScript rot13 example. In that code, you just need to replace the 13 with a 2, and it should work.
I am trying to edit a Greasemonkey/jQuery script. I can't post the link here.
The code is obfuscated and compressed with minify.
It starts like this:
var _0x21e9 = ["\x67\x65\x74\x4D\x6F\x6E\x74\x68", "\x67\x65\x74\x55\x54\x43\x44\x61\x74\x65", ...
After "decoding" it, I got this:
var _0x21e9=["getMonth","getUTCDate","getFullYear", ...
It is a huge list (500+ ). Then, it has some variables like this:
month = date[_0x21e9[0]](), day = date[_0x21e9[1]](), ...
_0x21e9[0] is getMonth, _0x21e9[1] is getUTCDate, etc.
Is it possible to replace the square brackets with the actual variable name? How?
I have little knowledge in javascript/jQuery and can not "read" the code the way it is right now.
I just want to use some functions from this huge script and remove the others I do not need.
Update: I tried using jsbeautifier.org as suggested here and in the duplicated question but nothing changed, except the "indent".
It did not replace the array variables with the decoded names.
For example:
jsbeautifier still gives: month = date[_0x21e9[0]]().
But I need: month = date["getMonth"]().
None of the online deobfuscators seem to do this, How can I?
Is there a way for me to share the code with someone, at least part of it? I read I can not post pastebin, or similar here. I can not post it the full code here.
Here is another part of the code:
$(_0x21e9[8] + vid)[_0x21e9[18]]();
[8] is "." and [18] is "remove". Manually replacing it gives a strange result.
I haven't seen any online deobfuscator that does this yet, but the principle is simple.
Construct a text filter that parses the "key" array and then replaces each instance that that array is referenced, with the appropriate array value.
For example, suppose you have a file, evil.js that looks like this (AFTER you have run it though jsbeautifier.org with the Detect packers and obfuscators? and the Unescape printable chars... options set):
var _0xf17f = ["(", ")", 'div', "createElement", "id", "log", "console"];
var _0x41dcx3 = eval(_0xf17f[0] + '{id: 3}' + _0xf17f[1]);
var _0x41dcx4 = document[_0xf17f[3]](_0xf17f[2]);
var _0x41dcx5 = _0x41dcx3[_0xf17f[4]];
window[_0xf17f[6]][_0xf17f[5]](_0x41dcx5);
In that case, the "key" variable would be _0xf17f and the "key" array would be ["(", ")", ...].
The filter process would look like this:
Extract the key name using text processing on the js file. Result: _0xf17f
Extract the string src of the key array. Result:
keyArrayStr = '["(", ")", \'div\', "createElement", "id", "log", "console"]';
In javascript, we can then use .replace() to parse the rest of the JS src. Like so:
var keyArrayStr = '["(", ")", \'div\', "createElement", "id", "log", "console"]';
var restOfSrc = "var _0x41dcx3 = eval(_0xf17f[0] + '{id: 3}' + _0xf17f[1]);\n"
+ "var _0x41dcx4 = document[_0xf17f[3]](_0xf17f[2]);\n"
+ "var _0x41dcx5 = _0x41dcx3[_0xf17f[4]];\n"
+ "window[_0xf17f[6]][_0xf17f[5]](_0x41dcx5);\n"
;
var keyArray = eval (keyArrayStr);
//-- Note that `_0xf17f` is the key name we already determined.
var keyRegExp = /_0xf17f\s*\[\s*(\d+)\s*\]/g;
var deObsTxt = restOfSrc.replace (keyRegExp, function (matchStr, p1Str) {
return '"' + keyArray[ parseInt(p1Str, 10) ] + '"';
} );
console.log (deObsTxt);
if you run that code, you get:
var _0x41dcx3 = eval("(" + '{id: 3}' + ")");
var _0x41dcx4 = document["createElement"]("div");
var _0x41dcx5 = _0x41dcx3["id"];
window["console"]["log"](_0x41dcx5);
-- which is a bit easier to read/understand.
I've also created an online page that takes JS source and does all 3 remapping steps in a slightly more automated and robust manner. You can see it at:
jsbin.com/hazevo
(Note that that tool expects the source to start with the "key" variable declaration, like your code samples do)
#Brock Adams solution is brilliant, but there is a small bug: it doesn't take into account simple quoted vars.
Example:
var _0xbd34 = ["hello ", '"my" world'];
(function($) {
alert(_0xbd34[0] + _0xbd34[1])
});
If you try to decipher this example, it will result on this:
alert("hello " + ""my" world")
To resolve this, just edit the replacedSrc.replace into #Brock code:
replacedSrc = replacedSrc.replace (nameRegex, function (matchStr, p1Str) {
var quote = keyArry[parseInt (p1Str, 10)].indexOf('"')==-1? '"' : "'";
return quote + keyArry[ parseInt (p1Str, 10) ] + quote;
} );
Here you have a patched version.
for (var i = 0; i < _0x21e9.length; i++) {
var funcName = _0x21e9[i];
_0x21e9[funcName] = funcName;
}
this will add all the function names as keys to the array. allowing you to do
date[_0x21e9["getMonth"]]()
This question refers to one of mine about split(), and include an answered question about inserting specific thing if string number is x.
Basically, I have one big string, with a specific separator which is :, and I'm using .split() in a loop to print each part of the string into a different input using the separator to cut it. This works perfectly.
Now, what I want is to do a breakline after each 17 inputs (input 17 then linebreak, input 34 then linebreak, input 51...). I found a way to do it in the second link I shared, and the breakline works. The problem is that only the last line of inputs is now filled with the string parts (the last 7 parts of the string). All the other input are simply blank.
Here's the final code:
function cutTheString()
{
var str = document.getElementById('textareaString').value;
var arrayOfStrings = str.split(':');
for(var i = 0; i < arrayOfStrings.length; i++)
{
if ((i % 17) == 0)
{
document.getElementById('result').innerHTML += '<br />';
}
var div = document.getElementById('result');
var mi = document.createElement('input');
mi.setAttribute('type', 'text');
mi.setAttribute('size', '4');
mi.setAttribute('id', 'string' + (i+1));
div.appendChild(mi);
document.getElementById('string' + (i+1)).value = arrayOfStrings[i];
}
}
Interestingly, in if ((i % 17) == 0), let's replace 0 by x. If x < 17, only x - 17 inputs will be filled, starting by the last one of the list. If x > 17, all inputs will be filled, but the breaklines will obviously not work.
There is no error in the console, and my knowledge of Javascript makes me fail to understand why it's doing this. I quite see the correlation, but I can't think of any solution. I tried different operators than == without success.
You can test it on this JSFiddle. Thanks for your help!
Use
mi.setAttribute('value', arrayOfStrings[i]);
instead of
document.getElementById('string' + (i+1)).value = arrayOfStrings[i];
(before of div.appendChild(mi)).