Develop Reference

How to prevent a form from opening action url and only print when submitted?

i am building a form and when i submit it it opens the action url. I want to submit the form on click button which should not open the target url but submit the request. as well as i want to print a message after submit and form should be cleared after submit.
<form id="contact" action="https://control.msg91.com/api/sendhttp.php" method="post">
<h3>Send SMS</h3>
<h4>Build in Process</h4>
<fieldset>
<input name="authkey" type="hidden" value="auth key as required"/>
<input name="mobiles" placeholder="Mobile Number" type="text" tabindex="1" maxlength="10" required >
</fieldset>
<fieldset>
<textarea name="message" placeholder="Type your message here...." tabindex="2" maxlength="320" required></textarea>
</fieldset>
<input name="sender" type="hidden" value="FAKEin" />
<input name="route" type="hidden" value="4" />
<input name="country" type="hidden" value="0" />
<fieldset>
<button name="submit" type="submit" id="contact-submit" data-submit="...Sending">Submit</button>
</fieldset>
</form>
any help how can i do this?
also can i add a hidden text in message tab that should add to the message tab in post/get as + instead of &
eg. actionurl.php?authkey=custommade&mobiles=9999999999&message=orginal+message+hidden+message&sender=FAKEin&route=4&country=0&submit=
You can also check the source code of page https://www.tricksbygoogle.com/sms/sms.php

Basically You can't .
The only solution here I see , is using ajax query and use javascript to clear form.
This example I provide is no redirections at all. What means you page will not be reloaded.
Maybe little jquery will help.
var result_func = function(response){
if(response.allOk){
$this.reset();
}
}
$('#contact').submit(function(e){
e.preventDefault()l
var $this = $(this);
var data = $this.serialize();
$.post($this.attr('action'),data,result_func.bind($this));
});
Header location will work , but user still will be redirected.

Based on your question, and the comments it looks like you're going to have to do a little bit of research. Here are some tips though.
If you would like to include the functions from a page without actually visiting the page, than you can use what is called an include statement. This will keep the browser from visiting that page while still executing it. - http://php.net/manual/en/function.include.php
To display a message you're going to need to hide and show the element with javascript. I would suggest viewing this question - Hide div after a few seconds
Basically on submit, you're going to want to check for the variables from your form. You would run a php if statement.
Then, if those variables exist you are going to want to include your action page.
In the same if statement, you're going to want to echo a <div> with a class that has some javascript attached to it to hide it after a few seconds.
The form will automatically clear on submit.
if($variable != null){
include '/action.php' // --- you can add some GET variables to the end of this if you would like to.
echo '<div id="message">Message sent</div>'
}

Submit GCP POST form without changing page

I have a C# MVC website and I'm trying out Google Cloud Print(GCP) to print.
Google Provides this example
https://developers.google.com/cloud-print/docs/appDevGuide
<form action="https://www.google.com/cloudprint/submit" method="post" enctype="multipart/form-data" id="submitForm">
<input type="hidden" name="xsrf" value="xsrfTokenHere"/>
<input type="hidden" name="printerid" value="123456789"/>
<input type="hidden" name="ticket" value='{"version": "1.0", "print": {}}'/>
<input type="text" name="title" value="My Document"/>
<input type="text" name="contentType" value="application/pdf"/>
<input type="text" name="tag" value=""/>
<input type="file" name="content"/>
<input type="submit" value="Print"/>
</form>
Which does what it should.
But it sends the user to the Google website were it displays the JSON response.
Is there any way to skip this last part, e.g let the user submit the form without moving to the google website.
I've tried various jQuery AJAX and similar calls. I've also tried posting the form inside of an iframe but none of these work since Google does not allow Cross-Origin calls.
If there was a way to post this either in HTML, Javascript or C# without jumping to the google result page it would've been great.

Auto submit form on different page after query string is passed?

Is this possible?
So I have the code below on the first page:
<form method="get" action="http://webpage.com">
<input type="hidden" name="a" value="1">
<input type="hidden" name="b" value="2">
<input type="hidden" name="c" value="3">
<input type="submit" class="submit" value="submit">
</form>
And the form fields in the second page are prepoulated with 1, 2, 3. Would it be possible for me to auto-submit this second form on load using code from the first page if the pages are on different domains, or would the auto-submit have to be done from the second page?
I don't see how it would be done, but figured I would ask anyway.

Would it be possible for me to auto-submit this second form on load using code from the first page
No. Nothing you do on a page can influence the behaviour of the following page (other than by passing data to it that logic in the subsequent page triggers on).

how to call different servlet on clicking different button of html form

i have a html form i want to call two different servlet on clicking two different button how to change the form action run time
<form>
<input type="submit" value="Question Paper" style="height:25px; width:120px; background-color: royalblue;color: white;" />
<input type="submit" value="Instruction" style="height:25px; width:120px; background-color: royalblue;color: white;" />");
</form>
on clicking the button i want to call servlet1 and servlet2 on each button
please help me to solve this problem, thanks in advance

There are several ways to achieve this.
Probably the easiest would be to use JavaScript to change the form's action.
<input type="submit" value="SecondServlet" onclick="form.action='SecondServlet';">
But this of course won't work when the enduser has JS disabled (mobile browsers, screenreaders, etc).
Another way is to put the second button in a different form, which may or may not be what you need, depending on the concrete functional requirement, which is not clear from the question at all.
<form action="FirstServlet" method="Post">
Last Name: <input type="text" name="lastName" size="20">
<br><br>
<input type="submit" value="FirstServlet">
</form>
<form action="SecondServlet" method="Post">
<input type="submit"value="SecondServlet">
</form>
Note that a form would on submit only send the input data contained in the very same form, not in the other form.
Again another way is to just create another single entry point servlet which delegates further to the right servlets (or preferably, the right business actions) depending on the button pressed (which is by itself available as a request parameter by its name):
<form action="MainServlet" method="Post">
Last Name: <input type="text" name="lastName" size="20">
<br><br>
<input type="submit" name="action" value="FirstServlet">
<input type="submit" name="action" value="SecondServlet">
</form>
with the following in MainServlet
String action = request.getParameter("action");
if ("FirstServlet".equals(action)) {
// Invoke FirstServlet's job here.
} else if ("SecondServlet".equals(action)) {
// Invoke SecondServlet's job here.
}

GET request through a window click with paramters

I am new to HTML. I have got an URL in the following format:
dosomething?param1=abc&param2-xyz
This URL is guaranteed to be valid.
How I have got an HTML page with a button on that. What I want to do is to send a GET request to the URL by clicking the button.
I have tried this:
<form method="GET" action="dosomething?param1=abc&param2-xyz">
<button>DO Something</button>
</form>
The problem is that the parameters are missing on the server side.
What is the proper way to do this? I cannot make an Ajax call on this as it will be a file downloading action and people told me that it won't work with Ajax.
Javascript solution is OK for me.
Please help.

You dont need Javascript for this as you can simply form your request like
<form method="GET" action="dosomething">
<input type="hidden" name="param1" value="abc">
<input type="hidden" name="param2-xyz" value="">
<input type="submit" value="DO Something">
</form>
see http://www.w3schools.com/html/html_forms.asp
Of course you could also use Javascript, you might want to look into using JQuery with http://api.jquery.com/jQuery.get/
see also HTTP GET request in JavaScript?
Furthermore, out of interest, what did "people" tell you about "Ajax won't work"?

The GET paramaters are passed by the input tag. This is a proper way :
<form method="GET" action="dosomething.php">
<input type="text" name="customparam" />
<input type="hidden" name="param1" value="value1" />
<input type="hidden" name="param2" value="value2" />
<input type="submit" />
</form>
When you will click on the submit button, you will be on dosomething.php?customparam=whatiwrote&param1=value1&param2=value2
On your page "dosomething.php", you can access these params with that :
<?php
$customparam = $_GET['customparam'];
$param1= $_GET['param1'];
$param2= $_GET['param2'];
echo "The value of param1 is : ".$param1;
?>
If the params don't move, you can also put them in a link directly with :
<a href="dosomething.php?param1=value1&param2=value2" >My link </a>