I have this div
<div class="newDiv">
It is generating in loop, something like
<div class="newDiv">
<div class = "innerDiv">
SomeCode
</div>
</div>
<div class="newDiv">
<div class = "innerDiv">
SomeCode
</div>
</div>
<div class="newDiv">
<div class = "innerDiv">
SomeCode
</div>
</div>
Now I want to add another class "BrightDiv" with the div that generated at odd places like
with first and third div.
what should I do to add Class "BrightDiv" along with "newDiv" with every div at odd place?
Try this : You can use :odd or :even to select odd / even elements, but it is depend on the index position and not natural number count. So In your case, you want first and third position div i.e. with index= 0 and 2 which is even by index position and hence use :even.
$('div.newDiv:even').addClass('BrightDiv');
DEMO
You can use filter to select only the odd indexed divs
$(".newDiv").filter(function() {
return $(this).index() % 2 == 1;
}).addClass("BrightDiv");
this will give you a solution $("div:even").addClass("BrightDiv");
Ways to achieve this:
CSS:
.newDiv:nth-child(odd) { /*CSS*/ }
or
.newDiv:nth-child(2n-1) { /*CSS*/ }
jQuery:
$('.newDiv:odd').addClass('BrightDiv');
Related
I'm using Javascript and I'm having problems trying to remove several elements.
Each div has a specific ID, like this:
<div id='1'></div>
<div id='2'></div>
<div id='3'></div>
<div id='4'></div>
Each div has a button that fires the remove() function
document.getElementById(count).remove()
Count is a variable that is increased whenever I create a new div
The remove() function works, but it creates a gap. IF i remove the div with id=2, then:
<div id='1'></div>
<div id='3'></div>
<div id='4'></div>
But I would like that the remaining IDs could downshift like this:
<div id='1'></div>
<div id='2'></div>
<div id='3'></div>
I guess I need a for loop but I can't understand how to make it
Use a class on each element, like this:
<div class="a" id='1'></div>
<div class="a" id='2'></div>
<div class="a" id='3'></div>
<div class="a" id='4'></div>
And call the following function after each removal:
function resetId(){
const list = document.getElementsByClassName("a")
for(let i = 0; i < list.length; i++){
list[i].id = i + 1
}
}
However, it might be better to just not use IDs in this case. By applying the same class to all your elements, there's no need to readjust the numbering, and you can select (or remove) the nth element using:
document.getElementsByClassName("a")[n]
This would probably be best achieved using jquery.
Here is the working code below:
$("div").each(function(i) {
$(this).attr('id', ++i);
});
$("#remove").click(function() {
$("#2").remove();
$("div").each(function(i) {
$(this).attr('id', ++i);
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id=""><span>0</span></div>
<div id=""><span>0</span></div>
<div id=""><span>0</span></div>
<div id=""><span>0</span></div>
<div id=""><span>0</span></div>
remove
How it works
First $(this).attr('id', ++i); this line here is used to add a number to div id. Ive repeated it in the remove function [("#remove").click(function()] This is because once a div has been removed the will be a number change.
This in affect is a loop. Without all the lines of code. Which is why i like jquery :)
The div id name is found here after they have been written $("#2").remove(); #2 refers to the <div id="2"> As you would in css.
If you notice, with an inspection the numbers down shift as 1 is removes as per your request.
In order to use jquery you have to link the library. <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
A Pure Javascript Version
function resetId(){
var div=document.getElementsByClassName("div")
for(i in div){
div[i].id=i++
}
}
function clicked() {
var elem = document.getElementById("1");
elem.parentNode.removeChild(elem);
resetId();
}
<div class="div" id="0">div</div>
<div class="div" id="1">div</div>
<div class="div" id="2">div</div>
<div class="div" id="3">div</div>
Remove
How it Works
This section here is your loop:
for(i in div){
div[i].id=i++
}
This section quite simply rewrites the numbers 0 - 4 after one has been removed.
The reason it starts from 0, is because in programming we start counting from 0. Hay 0 is a number too guys :).
The i++ Is a basically a mini int [ish] that is increased as the loop counts through how many divs there are.
This var elem = document.getElementById("1"); & this elem.parentNode.removeChild(elem); Is why I find jquery more acceptable in this situation. Its a bit less faf.
Finally resetId(); We have to call the function otherwise it doesn't that anything has changed, because computers are silly and need to be told.
Furter Reading
https://api.jquery.com/
http://www.lucemorker.com/blog/javascript-vs-jquery-quick-overview-and-comparison
Sounds like you should be using classes and referencing elements by index instead. IDs should remain persistent for clarity.
document.getElementsByClassName('my-class')[2].remove();
<div class="my-class" id="thing1">One</div>
<div class="my-class" id="thing2">Two</div>
<div class="my-class" id="thing3">Three</div>
<div class="my-class" id="thing4">Four</div>
I have a Div element on my HTML page, and that DIV is coming from an ASP.NET application, so the DIV ID is changing all the time but few words remain the same in that id.
For example:
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04
_NewGrid"> </div>
The only things which remains same all the time in above example are "_UWT" & "_NewGrid".
I know how to get the by Exact ID or atleast by using the 1 word in this: $( "div[id$='_UWT']" )
But I need to get this Div element by using the multiple parameters:
I need to check the "_UWT" and "_NewGrid" also.
If both words exist in the Div id, then return me the element only.
I need to get this DIV by JQuery.
I know I can set the ClientID to Static from ASP.NET, but that is not doable in my case.
Thanks.
To achieve this you can combine the 'attribute contains' selector (to find the _UWT) and the 'attribute ends with' selector (to find the _WebGrid), like this:
$('div[id*="UWT"][id$="_NewGrid"]').addClass('foo');
.foo {
color: #C00;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00_ctl01_ctl00_ctl04_NewGrid">Not this one</div>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04">Not this one</div>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04_NewGrid">This one</div>
One way could be:
$('div').each(function() {
if($(this).attr('id').includes('_NewGrid') && $(this).attr('id').includes('_UWT')) {
console.log($('div').attr('id'));
$(this).css('color','red') // do whatever you want with div
}
})
Demo:
$('div').each(function() {
if($(this).attr('id').includes('_NewGrid') && $(this).attr('id').includes('_UWT')) {
console.log($('div').attr('id'));
$(this).css('color','red')
}
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04
_NewGrid">11111</div>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04
_NewGri">222222222</div>
<div id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__ctl01_ctl00_ctl04
_NewGrid">3333333333333</div>
Try following way:
Add specific class I added here item-collection:
<div class="item-collection" id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04
_NewGrid">Div 1</div>
<div class="item-collection" id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00__UWT_ctl01_ctl00_ctl04">Div 2</div>
<div class="item-collection" id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00_ctl01_ctl00_ctl04
_NewGrid">Div 3</div>
<div class="item-collection" id="ctl00_ctl00_MainContent_DetailBody_ctl01_ctl02_ctl00_ctl01_ctl00_ctl04
_NewGrid">Div 4</div>
JS is:
var itemslist = [];
$(".item-collection").each(function(){
if($(this).attr("id").indexOf("_UWT") > -1 && $(this).attr("id").indexOf("_NewGrid")){
itemslist.push($(this))
}
})
console.log(itemslist);
I have two div's and what I am trying to do is loop through all the divs to check if the div has a class jsn-bootstrap3, I'm also trying to check to see if the div has any other classes, if it doesn't then I'd like to remove the jsn-bootstrap3 div so that the child content is whats left.
<div class="jsn-bootstrap3">
<div class="wrapper">
Div one
</div>
</div>
<div class="jsn-bootstrap3 block">
<div class="wrapper">
Div two
</div>
</div>
$('div').each(function() {
if ($(this).hasClass()) {
console.log($(this));
var class_name = $(this).attr('jsn-bootstrap3');
console.log(class_name);
}
});
jsFiddle
You can try something like
$('div.jsn-bootstrap3').removeClass('jsn-bootstrap3').filter(function () {
return $.trim(this.className.replace('jsn-bootstrap3', '')) == ''
}).contents().unwrap();
Demo: Fiddle
use the class selector to find div's with class jsn-bootstrap3 because we are not goint to do anything with others
use filter() to filter out div's with any other class
use unwrap() with contents() to remove the wrapping div
I'm using the liferay framework and I need to add a JavaScript detected inline height to a very very specific div in my page. The problem is I need to target it going through an unknown number of dynamically added divs with dynamically added classes and IDs. To complicate this even further, the divs are randomly siblings or nested in each other.
Here's what it looks like:
<div class="known-class">
<div class="unknown dynamicallygenerated"></div>
<div class="unknown dynamicallygenerated">
<div class="unknown dynamicallygenerated">
<div class="unknown dynamicallygenerated"></div>
<div class="unknown dynamicallygenerated">
<div class="DIV-I-WANT-TO-TARGET">this is the div i need to Target with my css/javascript</div>
</div>
</div>
</div>
obviously I can't target it simply with
function resize() {
var heights = window.innerHeight;
jQuery('.DIV-I-WANT-TO-TARGET').css('height', heights + "px");
}
resize();
Because that class is present elsewhere, I would rather target it with something like.
jQuery('.known-class .DIV-I-WANT-TO-TARGET')
Which obviously doesn't work because there's a ton of other divs in the middle and my div is not a child of ".known-class"
I was asking myself if there was any jQuery that could help. Something like:
Catch any div with .DIV-I-WANT-TO-TARGET class that is "generically" inside another div that has .known-class
Is this possible? thanks a lot for your help!
Something like this would work:
// this will target the known-class and find all children with DIV-I-WANT-TO-TARGET
$('div.known-class').find('div.DIV-I-WANT-TO-TARGET');
// this will target the known-class and find the first DIV-I-WANT-TO-TARGET
$('div.known-class').find('div.DIV-I-WANT-TO-TARGET').first();
$('div.known-class').find('div.DIV-I-WANT-TO-TARGET:first');
$('div.known-class').find('div.DIV-I-WANT-TO-TARGET:eq(0)');
$('div.known-class').find('div.DIV-I-WANT-TO-TARGET').eq(0);
You can try in your css file
.known-class div div div div{}
The last div being the DIV-I-WANT-TO-TARGET
Assuming that you are adding the divs starting from the outer to the inner
Assign an equal name plus a number starting from 1
<div class="known-class">
<div class="unknown dynamicallygenerated" id="dynamicdiv1"></div>
<div class="unknown dynamicallygenerated" id="dynamicdiv2">
<div class="unknown dynamicallygenerated" id="dynamicdiv3">
<div class="unknown dynamicallygenerated" id="dynamicdiv4"></div>
<div class="unknown dynamicallygenerated" id="dynamicdiv5">
<div class="DIV-I-WANT-TO-TARGET" id="dynamicdiv6"></div>
</div>
</div>
</div>
The use jQuery [.each][1] to loop through all the divs on the document
$( document.body ).click(function() {
$( "div" ).each(function( i ) {
if ( this.style.color !== "blue" ) {
this.style.color = "blue";
} else {
this.style.color = "";
}
});
});
When you reach the last item in numeric order. (you can use any split function) add the attributes to that div
you need to select last div inside the known-class:
$('.known-class').find('div:last').css('background', 'Red')
OR if you want to select all the .known-class :
$('.known-class').each(function() {$(this).find('div:last').css('background', 'Red')});
Actually your selector works just fine:
$('.known-class .DIV-I-WANT-TO-TARGET')
With a space, selectors will find any descendant.
The search is only limited to direct descendants (immediate children) if you use the > operator.
So $('.known-class > .DIV-I-WANT-TO-TARGET') would not find what you wanted.
If you have the following code:
<div class="parent">
<div class="1a"></div>
<div class="1b"></div>
<div class="2a"></div>
<div class="2b"></div>
<div class="3a"></div>
<div class="3b"></div>
</div>
Is there an efficient/easy way to wrap a new div around each a + b so it finishes looking like this:
<div class="parent">
<div class="new-1">
<div class="1a"></div>
<div class="1b"></div>
</div>
<div class="new-2">
<div class="2a"></div>
<div class="2b"></div>
</div>
<div class="new-3">
<div class="3a"></div>
<div class="3b"></div>
</div>
</div>
For example can I say something like:
wrap every two divs inside .parent with <div class="new-(incremental variable)"></div> (the new wrapping divs need to have a unique class)
Like this?
$('.parent > div:odd').each(function(i){
$(this)
.prev()
.addBack()
.wrapAll($('<div/>',{'class': 'new-' + (i+1)}));
});
Demo
Get the odd ones selected i.e 1, 3, 5 etc based on index(0 based); Iterate the odd ones get the prev element relative to the odd(which needs to be paired), use andSelf addBack to select that too and then use wrapAll on the pair.
if you want to ignore first x of them then do this:
$('.parent > div:gt(' + (x-1) + '):odd').each(function(i){
$(this)
.prev()
.addBack()
.wrapAll($('<div/>',{'class': 'new-' + (i+1)}));
})
Demo
You can literally use jQueries Wrap function. Take a look here!
http://api.jquery.com/wrap/
I'm not sure what you wish to achieve with the new wrapper divs but nth-child in CSS might be useful. Try something like this:
div.parent div {width:50%;}
div.parent div:nth-child(odd) {clear:both; float:left;}
div.parent div:nth-child(even) {float:right;}
...which will give you pairs of divs side by side.