In PHP, if the text input "cmtx_comment" is empty, on form submit I show a javascript alert. After I press OK in the alert, the values entered by the user in all fields in the form are gone. How can I keep the user entered values, without adding code to the value of the input elements (something like <input type="text" name="something" value="<?php echo $_GET['something'];?>"> ?
if (empty($cmtx_comment)) { //if comment value is empty
echo <<<EOD
<script>
alert('Please enter a comment!');
</script>
EOD;
return false;
} else { //if comment entered
do stuff
Have you tried localStorage and form validation?
HTML:
<form method="post" action="" onSubmit="return saveComment();">
<input type="text" name="cmtx_comment" id="cmtx_comment" value="" />
<input type="submit" value="Save" />
</form>
JavaScript:
document.getElementById("cmtx_comment").value = localStorage.getItem("comment");
function saveComment() {
var comment = document.getElementById("cmtx_comment").value;
if (comment == "") {
alert("Please enter a comment in first!");
return false;
}
localStorage.setItem("comment", comment);
alert("Your comment has been saved!");
location.reload();
return false;
//return true;
}
Example
On first page load, you are presented with:
If you don't enter a comment, you get the alert:
If you do enter a comment, you get a different alert:
The page will then refresh (or post, simply un-comment the return true, and comment the location.reload), and you will still see the contents you posted the first time.
Related
Im running a form in a webshop that looks like this:
<form>
<input type="number" name="quantity" value="" required = "required" />
<input type="radio" name="homeDelivery" value="" required = "required" checked="true" />
<input type="radio" name="homeDelivery" value="" required = "required" />
<input type="submit" value="buy" name="submitBuy" class="buy formConfirm" />
</form>
After the submit button is pressed I run a simple error check in php from the info I get from $_POST. I have an array called $errors, if my error check finds any errors it adds them to my array, else not, and if the array stays empty til the end, my form will submit the data, else not.
I do however want to have a JS confirmbox after pressing submit, that will only popup if there are no errors in the actual form. So to my actual question:
Is it possible to check in javascript code if my $errors variable is empty? Something that works like this:
if(empty($errors)) {
//run code
}
If it is possible Id like my javascript code to look something like this(I think you get the idea);
$('.buyConfirm').on('click', function(){
if (errors == NULL) {
return confirm('Are you sure?');
}
else {
return false;
}
});
Any help is appreciated,
Cheers!
You need to output your PHP var as a JS array, best using json_encode, and then consume that in your condition
<script>
var errors = <?php echo json_encode($errors); ?>;
if (errors.length < 1) {
if (confirm("Are you sure?")) {
// User has no errors and has confirmed
} else {
// User has no errors but did not confirm
}
} else {
// User has errors
}
</script>
For one of my websites, I am designing a HTML form with jquery and PHP for sending the data through email.
The Jquery, checks for the empty /blank fields and sends alerts for each filed.
Once the form is submitted with full data, it sends success alert and send the input data through PHP.
Till this point the code works fine.
Once the data is submitted & success alert is shown, I want the html form to be refreshed / reloaded.
But this this not happening, as the form remains with the pre-entered data.
Kindly help me in this please. My Jquery & HTML form is given below.
JQUERY-CODE (with google libs 2.2)
JQUERY CODE
$(document).ready(function() {
$("#submit").click(function() {
var name = $("#name").val();
var email = $("#email").val();
var message = $("#message").val();
$("#returnmessage").empty(); // To empty previous error/success message.
// Checking for blank fields.
if (name == '') {
alert(" Please fill your name");
} else if (email == '') {
alert("Please fill your email");
} else if (message == '') {
alert("Please Fill message");
} else { alert("Your form submitted. We will contact you soon.");
$.post("xxx.php", { // To php file.
name: name,
email: email,
message: message
}, function(data) {
$("#returnmessage").append(data);
if (data == "Your form submitted. We will contact you soon.") {
$("#form")[0].reset(); // To reset form fields on success.
}
});
}
});
});
HTML FORM CODE:
<form id="form" method="post" action=" ">
<h4>FEED-BACK FORM</h4>
<p id="returnmessage"></p>
<label>Name: </label>
<input type="text" id="name" /><br>
<label>Email: </label>
<input type="text" id="email" /><br>
<label>Message: </label>
<input type="text" id="message" /><br>
<input type="button" id="submit" value="Submit"/>
</form>
check below js
if (data == "Your form submitted. We will contact you soon.") {
document.getElementById('form').reset(); // To reset form fields on success.
}
Or
if (data == "Your form submitted. We will contact you soon.") {
$('#form').find("input[type=text]").val(""); // To reset form fields on success.
}
you can clear the input fields by setting its value to ""
$("#name").val("");
$("#email").val("");
$("#message").val("");
The problem is most likely with your if statement. The line $("#form")[0].reset(); is correct, move it above the if statement to see it working.
Before I get into the problem details, I still need to tell you about this form I am creating. I have a Registration form and once the user submits the form by clicking the Submit button, it will NOT go directly to a Successfully Registered page. The user will be seeing a Confirmation page prior to that. In this page, the user will see all the data he inputted for him to review. Below it are the Confirm button and the Return button (if user still likes/needs to edit his details, it will then show the form for him to edit once this button is clicked). But here's the thing, the Registration form page and the Confirmation page are in just the same page. What I did is that when the user submits the form, it will hide some elements including the Submit button and then just show the details he inputted. When the user clicks the Return button on the Confirmation page, it will just then show again the hidden fields so the user can edit his details.
What I did in preventing the form from submitting when there are errors is that I disabled the submit button. But it is not working. I am using bootstrap for my form so when there are errors, the input fields' borders would turn red and would obtain a class has-error. Here's what I did:
$("td .form-group").each(function() {
if($(this).hasClass('has-error') == true) {
$('#submit').attr('disabled', false);
} else {
$('#submit').attr('disabled',true);
}
});
But again, it is not working. I also googled some jQueries like the .valid() and .validate() functions but I'm not really sure about it and also didn't work for me.
I also did this code where the Submit button should disable when required fields are still empty. And it is perfectly working:
$('#submit').attr('disabled',true);
$('input[id^="account"]').keyup(function() {
if(($('#profile-company_name').val().length !=0) && ($('#account-mail_address').val().length !=0) && ($('#account-confirmemail').val().length !=0) && ($('#account-login_name').val().length !=0) && (($('#account-password').val().length !=0)) && ($('#account-confirmpassword').val().length !=0)) {
$('#submit').attr('disabled', false);
} else {
$('#submit').attr('disabled',true);
}
});
I hope you understand my problem. I will make it clearer if this confuses you.
What I did in preventing the form from submitting when there are errors is that I disabled the submit button. But it is not working.
When is it checking for errors? It needs to disable the submit button at the same time it is checking for errors. Your code doesn't work because there's no event telling it WHEN to execute. WHEN do you want submit button to be disabled?
Do you want it triggered when the field is validated or when the form is submitted?
You can't really tie it to the submit button unless you want to click it first to validate the form fields, and then again to submit validated fields. Then you'll need to figure out how to tell it that it's been validated like by a class, maybe? Only accept inputs that hasClass('valid')?
below are the changes
$(".form-group").find("td").each(function() {
if($(this).hasClass('has-error')) {
$('input[type="submit"]').prop('disabled', false);
} else {
$('input[type="submit"]').prop('disabled', true);
}
});
Try the following
$('#submit').click(function(){
var error = false;
$("td .form-group").each(function() {
if($(this).hasClass('has-error') == true) {
error = true;
return false; //break out of .each
}
});
return !error;
});
You can achieve this by maintaining 2 sections.
1. Form section
<form id="form1">
<input type="text" id="name" />
<input type="email" id="email" />
<input type="button" id="confirm" value="Confirm" />
</form>
2. Confirm section
<div id="disp_data" style="display: none;">
<lable>Name: <span id="name_val"></span></lable>
<lable>Email: <span id="email_val"></span></lable>
<input type="button" id="return" value="Return" />
<input type="button" id="submit" value="Submit" />
</div>
You have to submit the form by using js submit method on validating the form in confirm section (When the user clicks on submit button)
$("#submit").click(function(){
var error_cnt = false;
if($("#name").val() == '') {
error_cnt = true;
alert("Enter Name");
}
if($("#email").val() == '') {
error_cnt = true;
alert("Enter Email");
}
if(error_cnt == false) {
$("#form1").submit();
} else {
$("#disp_data").hide();
$("#form1").show();
}
Demo
You have to prevent the form from sumition by return back a boolean false so that it will stop the execution.
$('#submit').click(function(){
var ret = (($('#profile-company_name').val().length !=0) && ($('#account-mail_address').val().length !=0) && ($('#account-confirmemail').val().length !=0) && ($('#account-login_name').val().length !=0) && (($('#account-password').val().length !=0)) && ($('#account-confirmpassword').val().length !=0));
if(!ret) return false;
});
If you want to disable the submit button in case of any error you need to monitor the changes of each input fields. so better to give a class name to all those input fields like commonClass
then
function validation_check(){
var ret = (($('#profile-company_name').val().length !=0) && ($('#account-mail_address').val().length !=0) && ($('#account-confirmemail').val().length !=0) && ($('#account-login_name').val().length !=0) && (($('#account-password').val().length !=0)) && ($('#account-confirmpassword').val().length !=0));
return ret;
}
$("#submit").prop("disabled",true)
$(".commonClass").change(function(){
if(validation_check()){
$("#submit").prop("disabled",false)
}
else {
$("#submit").prop("disabled",true)
}
});
please use onsubmit attribute in the form element and write a javascript function to return false when there is any error. I've added fiddle you can try.
HTML FORM
<form action="" method="" onsubmit="return dosubmit();">
<input type="text" id="name" />
<input type="email" id="email" />
<input type="submit" value="Submit" />
</form>
JAVASCRIPT
function dosubmit() {
if(false) { //Check for errors, if there are errors return false. This will prevent th form being submitted.
return false;
} else {
return true;
}
}
Let me know if this fixes your issue.
I have a page that loads a random MP3 file on each refresh. The user has to guess a name based on the sound via text form input. I want to check their input against the stored string and refresh the page if it's correct. Otherwise, I wan't to give them an incorrect alert and stay on the same page so they can guess again:
<div class="ui-widget" align="center">
<form method="post" action="" class="answer_box" onsubmit="return submit();">
<p>Which hero is it? <input id="tags" name="guess" /></p>
<script>
var key = <?php echo json_encode($rand_key) ?>;
var info = document.getElementById("guess").value;
function submit() {
if (key==info){
alert('Correct!');
return true;
}
else {
alert('Incorrect!');
returnToPreviousPage();
return false;
}
}
</script>
</form>
</div>
Right now, it submits the information to a new page regardless of the input. The javascript alerts are also not showing (I suspect they do show, but the page then refreshes and they disappear). The key variable is the key from the randomly taken value of a PHP array, and info should be the text the user inputs.
Problems found:
you cant use submit as a function name a this is an HtmlForm object
document.getElementById("guess").value; is looking for an element with ID of "guess" and that does not exist.
I would rewrite your script like this:
<script>
var key = <?php echo json_encode($rand_key) ?>;
function my_submit(curr) {
var info = curr.guess.value;
if (key == info) {
alert('Correct!');
return true;
}
else {
alert('Incorrect!');
returnToPreviousPage();
return false;
}
}
</script>
<form onsubmit="return my_submit(this);">
<p>Which hero is it? <input id="tags" name="guess"/></p>
</form>
You have a problem here:
<input id="tags" name="guess" />
Your id is tags, not guess.
You should use document.getElementById("tags").value.
You are trying to retrieve the value of an element with id of "guess." Change this to "tags."
var info = document.getElementById("tags").value;
Also, as #CodeGodie mentioned, you need to change your function name to something other than submit.
Once again the novice JS is back again with a question. I want a confirmation tickbox at the end of my form before allowing the user to send me their details and if it's not ticked then they can't submit the form. I've had a look on here and tried using different examples of coding but I just find it all very confusing after looking at 10 or 20 pages of different code. Here is what I've written so far, from what I can make out my form just skips over my checkbox validation code which is obviously what I don't want to happen:
<head>
<script>
function validate (){
send = document.getElementById("confirm").value;
errors = "";
if (send.checked == false){
errors += "Please tick the checkbox as confirmation your details are correct \n";
} else if (errors == ""){
alert ("Your details are being sent)
} else {
alert(errors);
}
}
</script>
</head>
<body>
<div>
<label for="confirm" class="fixedwidth">Yes I confirm all my details are correct</label>
<input type="checkbox" name="confirm" id="confirm"/>
</div>
<div class="button">
<input type="submit" value="SUBMIT" onclick="validate()"/>
</div>
I would just enable/disable your button based on the checkbox state. Add an ID to your button, (i'll pretend the submit button has an id of btnSubmit)
document.getElementById("confirm").onchange = function() {
document.getElementById("btnSubmit").disabled = !this.checked;
}
Demo: http://jsfiddle.net/tymeJV/hQ8hF/1
you are making send be confirm's value.
send = document.getElementById("confirm").value;
This way send.checked will not work. Because you are trying to get the attribute checked from a value (probably, string).
For the correct use, try this:
send = document.getElementById("confirm");
sendValue = send.value;
sendCheck = send.checked;
Then you can test with
if (sendCheck == false){ //sendCheck evaluate true if checkbox is checked, false if not.
To stop form from submitting, return false; after the error alerts.
Here the complete code - updated to work correctly (considering the <form> tag has id tesForm):
document.getElementById("testForm").onsubmit = function () {
var send = document.getElementById("confirm"),
sendValue = send.value,
sendCheck = send.checked,
errors = "";
//validate checkbox
if (!sendCheck) {
errors += "Please tick the checkbox as confirmation your details are correct \n";
}
//validate other stuff here
//in case you added more error types above
//stacked all errors and in the end, show them
if (errors != "") {
alert(errors);
return false; //if return, below code will not run
}
//passed all validations, then it's ok
alert("Your details are being sent"); // <- had a missing " after sent.
return true; //will submit
}
Fiddle: http://jsfiddle.net/RaphaelDDL/gHNAf/
You don't need javascript to do this. All modern browsers have native form validation built in. If you mark the checkbox as required, the form will not submit unless it is checked.
<form>
<input type="checkbox" required=""/>
<button type="submit">Done</button>
</form>