I'm trying to change my form action in my HTML then submit using javascript.
The conditions are in PHP .
I need help if anyone can assist me.
This is my PHP function :-
<?php
error_reporting(0);
if(isset($_POST['email'])){
$email=$_POST['email'];
if(!empty($email)) {
$chrono = 0;
} else {
$chrono = 1;
}
}
?>
The motive of the PHP is to check null email entry.
Here's the javascript function :-
<script type="text/javascript">
function fireform(val){
// missing codes
document.forms["demoform"].action=val;
document.forms["demoform"].submit();
}
// missing codes
</script>
HTML :-
<form name="demoform" action="">
<input type ="text" name="name" id="name">
<input type="hidden" name="buttonpressed" id="buttonpressed">
<input type="button" value="submit B" onclick="fireform('b')">
I want to do it in a way , when the user entered an empty email , the PHP will read it as chrono = 0.
Then goes to javascript , if the chrono equal to 0 , the action will remain empty.
If the chrono = 1 , the javascript will change the action of the form and submit.
I need help thanks.
Your flow is unclear: it seems that you want to change the form action from PHP, but PHP is triggered after the form submission. So there's something weird in your flow. You also don't seem to have a field called email in your markup. Add it (or rename the field name):
<input type="text" name="email" id="email">
Nonetheless, having an empty action means the form will be submitted to the page itself.
Probably what you need is a client side validation of the email field. In the fireform() JavaScript function, just add a check for email field:
function fireform(val){
if (document.forms["demoform"].email.value.length > 0){
document.forms["demoform"].action = val;
document.forms["demoform"].submit();
}
}
This should be enough to get what you need.
I would recommend checking the email field (for being empty) in javascript, and when you have set the proper action submit the form in javascript.
Check the field:
$('#<enter id of field>').val();
Update the action:
$('form').attr('action', 'Enter your updatet action here');
Submit the form:
http://api.jquery.com/submit/
Related
I'm trying to combine a form.submit() call with a jquery/ajax call to get a response from my php login script - I've just spent a few hours trying to hack together some of the hundreds of posts/examples on a similar topic but am out of ideas now so am hoping someone can help.
My sign in form looks like this...
<form id ="signInForm" action= "/userManagement/proxy_process_login.php" method="post" name="login_form">
<input required id="signInUserId" name="email" type="text" placeholder="Username/Email" class="input-medium">
<input required id="signInPassword" name="password" type="password" placeholder="Password" class="input-medium">
<button id="signin" name="signin" class="btn btn-success" onclick="signInSubmit(this.form, this.form.signInPassword);">Sign In</button>
</form>
The function signInSubmit() (called by the button's onclick) simply validates the text fields, and replaces the plain text password with a hashed version before finally calling "form.submit()", like this...
//ommited a bunch of text input validation
var p = document.createElement("input");
form.appendChild(p);
p.name = "p";
p.type = "hidden";
p.value = hex_sha512(password.value);
password.value = ""; // Make sure the plaintext password doesn't get sent.
form.submit();
My PHP script (proxy_process_login) also works fine before adding any jquery/ajax and essentially does this...
if (login($email, $password, $mysqli) == true) {
// Login success (ok to reload existing page)
header("Location: ../index.php?login=success");
exit();
} else {
// Login failed (do NOT want to reload page - just message "fail" back via AJAX so I can update page accordingly)
echo "fail";
exit();
}
But given the route I'm taking to submit the form, I'm struggling to incorporate an Ajax example - because I've got this new "form" variable (with the hashed p variable appended), so I can't use an Ajax call which refers back to the form using jquery like this...
$.ajax({type:'POST', url: '/userManagement/proxy_process_login.php', data:$('#signInForm').serialize(), success: function(response) {
console.log(response);
}});
(because the jquery reference doesn't include the new variable, and I've already specified the php script in the action attribute of my form)
And I also can't call something like "serialize()" on my "form" variable inside signInSubmit().
Any ideas on an appropriate way to structure a solution to this?! Thanks!
Unfortunately there is no callback for native form submission using action attribute , it was used in the past to redirect you to that page and show the results there.
Modern method now is to use ajax call , after perventingthe default submission.
Solution:
HTML:
<form id="myForm">
<!-- form body here --!>
</form>
Javascript:
$("#myForm").submit(function(e){
e.preventDefault();//prevent default submission event.
//validate your form.
//disable your form for preventing duplicate submissions.
//call you ajax here.
//upon ajax success reset your form , show user a success message.
//upon failure you can keep your fields filled , show user error message.
})
this is a typical algorithm i use in any project i do , i recommend using parsley JS for front-end validation.
I am trying to create a form that manages a list.
Only the supervisor should be allowed to delete items from the list.
In order to do this I have the following code (this is created by php for each item in the list) :
<form id ="delete_item" name="delete_item" method="post" action="delete_item.php"
<input type="hidden" name="item_id" id="item_id" value="12345678">
<input type="image" alt="submit" src=".\images\delete.png" id="item_delete_execute" name="item_delete_execute">
</form>
the javascript file for this form contains the following:
$(document).ready(set_up_listeners);
function set_up_listeners() {
$("#delete_item").submit(confirm_delete);
}
function confirm_delete() {
var pass;
pass = prompt("in order to delete this item, please enter your password", "");
(code here to verify password, using ajax to execute a php script that checks against the database)
return (true if the password checks out, so it can continue with the post, otherwise false);
}
is there a way to add the value that the variable pass has, so that the delete_item.php script can see it in one of its $_POST variables?
Thanks in advance for any help you can provide
I have the following form as part of my webpage:
<form id="collabAccess" onsubmit="submitCollabForm()" >
<div id="row-1">
<div class="two-col" id="email"><input type="text" placeholder="Enter email addresses separated by commas"/></div>
<div id="collabSelect" class="collab two-col styled-select">
<select id="collabaccess">
<option>Can Read</option>
<option>Can Write</option>
<option>Can Read & Write </option>
<option>Administrator </option>
</select>
</div>
</div>
<div id="message">
<textarea id="personalMessage" cols="154" rows="10" placeholder="Optional: include a personal message"></textarea>
</div>
<div id="submit-wrapper"><input type="submit" value="Add Collaborators" id="addCollaborators" disabled='disabled' class="small-btn disabled"/></div>
</form>
The function submitCollabForm() is as follows:
function submitCollabForm() {
console.log('in submitCollabForm');
var valid = validateEmails();
if (valid == false) {
var email = document.getElementById('email');
email.addClass('error');
}
}
where validateEmails() is just another js function for validating that the email addresses int he form have the correct format.
However, it looks like onsubmit is not being called at all. Even if I change things to onsubmit="console.log('xyz'), no console statement is being output. I've also checked for javascript errors in the console, but I am getting nothing.
Is there any reason why onsubmit is not working properly?
Your validation function needs to return false to stop the form from submitting. It's better to have
onsubmit="return submitCollabForm()"
See With form validation: why onsubmit="return functionname()" instead of onsubmit="functionname()"? for details.
The onsubmit handler is not called, because the form cannot be submitted by any normal means, i.e. the submit event cannot be caused. There is only one submit control, and it is declared as disabled.
if you feel all code is correct still it's not working then,
Simple steps to do,
1) create one script tag in the same page where your form is, create one function and set one alert and test it. If it is working then try following steps.
2) Try to check the path of your javascript file.
3) if path is correct, then change the name of your javascript function sometimes your name tag conflicts with your function name, and submit points to it, so your call is not reaching at your function. It happened with me. so I posted it here, hope it will be helpful to someone.
Hello and thank you for viewing my question. I am a complete beginner and am looking for simple ways to do the following...
What I have in seperate linked documents:
HTML, CSS, Javascript, PHP
What I am having trouble with:
I need to use something like JSON (although I would also accept XML requests or Ajax at this point if they work) to transfer variables from Javascript to PHP. I need the variables to search in a database, so they need to be literally available within PHP (not only seen on a pop-up message or something).
I have seen a LOT of different ways to do this, I have even watched tutorials on YouTube, but nothing has worked for me yet. The things I am having the biggest problem with is that when I add a submit button to my form it doesn't submit my form and I don't know why.
Form code snippet:
<form id="form" name="input" method="post" action="javascript:proofLength();">
<input id="userinput" type="text" autofocus />
<input id="submit" type="button" value="submit" onsubmit="post();">
</form>
The second to last line there doesn't work. Do I need javascript to submit the form? Because I really thought that in this case it was part of the functionality of the form just like method="post"...
The other thing is that for JSON, I have no idea what to do because my variables are determined by user input. Therefore, I cannot define them myself. They are only defined by document.getElement... and that doesn't fit the syntax of JSON.
Those are really my main problems at the moment. So if anyone could show me a simple way to get this variable transfer done, that would be amazing.
After this I will need to search/compare in my database with some php/sql (it's already connecting fine), and I need to be able to return information back to a in HTML based on what I find to be true. I saw one example, but I am not sure that was very applicable to what I am doing, so if you are able to explain how to do that, that would be great also.
Thank you very, very much.
April
You don't need ajax to submit this form. You don't even need javscript. Just do this:
<form id="form" name="input" method="post" action="mytarget.php">
<input id="userinput" name="userinput" type="text" autofocus />
<input id="submit" type="submit" value="submit" />
</form>
This will send the form data to mytarget.php (can be changed of course)
See that i have added the name attribute to your text-field in the form and i changed the type of the button to submit.
Now you can work the Data in mytarget.php like this:
<?
$username = $_POST['userinput'];
echo "Your name is: ".$username;
?>
You wanted to have a check for length in the submit. There are two ways to this:
Before the input is send (the server is not bothered)
Let the server Check the input
for 1 you will have to append a event listener, like this:
var form = document.getElementById("form");
form.addEventListener("submit", function(event){
console.log("test");
var name = form.elements['userinput'].value;
if(name.length < 3){
alert("boy your name is short!");
event.preventDefault();
}
});
Enter a name with less then 3 characters and the form will not be submitted. test here: http://jsfiddle.net/NicoO/c47cr/
Test it Serverside
In your mytarget.php:
<?
$username = $_POST['userinput'];
if(strlen($username) > 3)
echo "Your name is: ".$username;
else
echo "your name was too short!";
?>
You may also do all this with ajax. You will find a lot of good content here. But I'd recommend a framework like jQuery to do so.
The problem is in this line
<form id="form" name="input" method="post" action="javascript:proofLength();">
The action should be a PHP page (or any other type of server script) that will process the form.
Or the proofLength function must call submit() on the form
In the php page you can obtain variable values using $_GET["name"] or $_POST["name"]
To summarize; your code should look like this
<form id="form" name="input" method="post" action="yourpage.php">
<input id="userinput" type="text" autofocus />
<input id="submit" type="button" value="submit">
</form>
and for your php page:
<?php
$userinput = $_POST["userinput"];
//Do what ever you need here
?>
If you want to do something in your javascript before submitting the form, refer to this answer
I a have PHP form where I collect a bunch of values from text inputs, but for one input I have the input filled in via javascript (user selects a date from a calendar, that date then populates a text input). I've setup a simplified version of this:
<?php
$displayForm = true;
if ($_POST['submitFlag'] == 1) {
// Form was submitted. Check for errors and submit.
$displayForm = false;
$installationTime = $_POST['installation-time'];
// send e-mail notification
$recipients = "test#test.com";
$subject = "Test Email - Test Form Submission";
$message = wordwrap('Someone has filled out the secure form on test.com. Here\'s what they had to say:
Installation Time: ' . $installationTime .'
');
$headers = "From: test#test.com";
mail($recipients, $subject, $message, $headers);
// Output thank you message
?>
<h2>Thank You!</h2>
<?php if($installationTime == NULL){echo 'test failed: value submitted was null.';}else{echo 'test passed: value submitted was not null.';} ?>
<p>Your form has been submitted. Thank you for your interest in test.com.</p>
<?php
}
if ($displayForm) {
// If form was not submitted or errors detected, display form.
?>
<div class="note"><span class="required">*</span> Click me to set value of input.</div>
<form name="contactForm" id="contactForm" method="post" enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>?state=submit">
<label for="installation-time" class="service-time">The time you have selected for installation is: <span class="required">*</span></label>
<input type="text" name="installation-time" id="installation-time" disabled value="<?php echo $_POST['installation-time']; ?>" />
<input type="hidden" name="submitFlag" id="submitFlag" value="1" />
<input type="submit" name="submit" id="submit" value="Sign-Up" />
</form>
<?php
} // End of block displaying form if needed.
?>
And then in jQuery I do one of these:
$('.note').click(function(){
$('#installation-time').val('test string');
});
When I submit the form, the PHP variable that's supposed to collect that value is null. Every other input in the form works, and if I remove the javascript and manually enter the exact same text that I had set with JavaScript into the input it works as well.
The question really is why populating a field with javascript as opposed to manually typing the exact same string into a text input would break things. Again there are no errors and the input is populated correctly on the front end. Somehow posting the form just doesn't pick up on the value when it's set by javascript vs. typed manually. There has to be something really fundamental I'm missing here.
Any idea what's going on here? I've spent hours puzzling over this to no avail.
Update:
Code updated, test page:
http://dev.rocdesign.info/test/
Solution: can't post a disabled input. I actually tested that back in the beginning and must have missed that removing the "disabled" on the input made it work, so I mistakenly ruled it out and moved on.
Thanks for the responses everyone. And for anyone else with this problem: use a hidden input to post the value.