my problem is the following code is not working without an alert().I am using a two level select/deselct all box. but the code is working for one level only. It is not being able to deselect the 'select all' checkbox on unchecking a single checkbox or vice-versa without the alert..
alert('17');
$('input.DataCheckAll').click(function() {
if ($('input.DataCheckAll').length == $('input.DataCheckAll:checked').length) {
$('input.CheckAll').prop('checked', true);
} else {
$('input.CheckAll').prop('checked', false);
}
});
if ($('input.CheckAll').length > 0) {
$('input.CheckAll').attr('checked', false);
$('input.CheckAll').click(function() {
if (this.checked) {
$('input.DataCheckAll').each(function() {
this.checked = true;
});
} else {
$('input.DataCheckAll').each(function() {
this.checked = false;
});
}
});
}
It's highly likely that you just need to wrap it in $(function() { /* code */ });. At present, your code is being stopped by the alert, which lets the document load in the background so by the time you close the alert, the page is ready for everything you're trying to do.
By just telling it to wait until the page has finished loading, you shouldn't need the alert any more.
$(function() {
// code
});
is exactly the same as
$(document).ready(function() {
// code
});
The code is probably running before the dom is ready, Try this:
$(function(){ //by passing jQuery a function instead of a selector
// it will call the function when the dom is ready
$('input.DataCheckAll').click(function() {
if ($('input.DataCheckAll').length == $('input.DataCheckAll:checked').length) {
$('input.CheckAll').prop('checked', true);
} else {
$('input.CheckAll').prop('checked', false);
}
});
if ($('input.CheckAll').length > 0) {
$('input.CheckAll').attr('checked', false);
$('input.CheckAll').click(function() {
if (this.checked) {
$('input.DataCheckAll').each(function() {
this.checked = true;
});
} else {
$('input.DataCheckAll').each(function() {
this.checked = false;
});
}
});
}
});
You should execute your jquery script after DOM is ready, so wrap it inside $(function(){});
NOTE - Also, you need not to iterate $('input.DataCheckAll') using .each(), to check / uncheck. You can simply use $('input.DataCheckAll').prop('checked',true);
$(function(){
$('input.DataCheckAll').click(function() {
if ($('input.DataCheckAll').length == $('input.DataCheckAll:checked').length) {
$('input.CheckAll').prop('checked', true);
} else {
$('input.CheckAll').prop('checked', false);
}
});
if ($('input.CheckAll').length > 0) {
$('input.CheckAll').attr('checked', false);
$('input.CheckAll').click(function() {
/*if (this.checked) {
$('input.DataCheckAll').each(function() {
this.checked = true;
});
} else {
$('input.DataCheckAll').each(function() {
this.checked = false;
});
}*/
// to select / deselect all data check boxes
$('input.DataCheckAll').prop('checked',this.checked);
});
}
});
Related
Hiding a div (for example #popover) on click is easy:
$(document).ready(function() {
$("#trigger").click(function(e) {
$("#popover").toggle();
e.stopPropagation();
});
$(document).click(function(e) {
if (!$(e.target).is('#popover, #popover *')) {
$("#popover").hide();
}
});
});
But isn't this function fired every time the user uses a click? (Which does not make sense for me). Can I somehow limit this function to fire only if #popover is already visible?
In that case you can try using $(document).one(function(e) {...}); every time you show #example.
$(document).ready(function() {
var didBindToBody = false;
function closePopOverOnBodyClick() {
didBindToBody = true;
$(document).one('click', function(e) {
if (!$(e.target).is('#popover, #popover *')) {
$("#popover").hide();
}
else {
closePopOverOnBodyClick();
}
didBindToBody = false;
});
}
$("#trigger").click(function(e) {
$("#popover").toggle();
e.stopPropagation();
if (!didBindToBody && $("#popover").is(":visible")) {
closePopOverOnBodyClick();
}
});
closePopOverOnBodyClick();
});
DEMO
You could try something like
$(document).click(function(e) {
if (!$('#example').is(":visible")) {
return false;
} else if (!$(e.target).is('#popover, .login-panel *')) {
$("#popover").hide();
}
});
Or you could combine the two conditionals into one, just thought I'd keep it separate for readability and to make my suggestion easier to spot.
I need to write custom validated form in Wordpress. After the click on For-Author radio button some checkboxes group should be marked as not required. I tried to change "aria-required" attributes to "false" or remove and add class "wpcf7-validates-as-required" but it doesn't work. I also tried to reinit wpcf7 by
$('div.wpcf7 > form').wpcf7InitForm();
but it's also doesn't work.
This is a code sample:
$radio.button.click(function (event) {
isAuthor(event)
});
var isAuthor = function (event) {
if ($(event.target).attr('data-author') == 'true') {
authorClicked = true;
} else {
authorClicked = false;
}
fieldUpdate();
};
var fieldUpdate = function () {
var $text = $('[name=pres-title]');
if (authorClicked) {
$text.prop('disabled', false).attr('aria-required', true).addClass('wpcf7-validates-as-required').attr('aria-invalid', false)
$fieldRequired.each(function () {
$(this).prop('disabled', false).attr('aria-required', true).addClass('wpcf7-validates-as-required').attr('aria-invalid', false);
});
} else {
$text.prop('disabled', true).attr('aria-required', false).removeClass('wpcf7-validates-as-required').attr('aria-invalid', false);
$fieldRequired.each(function () {
$(this).prop('disabled', true).attr('aria-required', false).removeClass('wpcf7-validates-as-required').attr('aria-invalid', false);
});
}
}
I am having trouble getting my script to work here. I am trying to target the show me span when the checkboxes are checked and it's not working.
Here is the code and link to fiddle: http://jsfiddle.net/dalond/nonyg6sm/
$('.single').live('change', ':checkbox', function() {
var target = $(this).closest('.single').prev().find('.showMe');
if ($(this).find('input:checked').length == 0) {
target.hide();
} else {
target.show();
}
});
I got it worked : http://jsfiddle.net/nonyg6sm/3/
$('input[type=checkbox]').click(function() {
var target = $(this).closest('.NoEd').prevAll(".Subs:first").find(".showMe");
if (this.checked) {
target.show();
} else {
target.hide();
}
});
You can modify it to feet your need.
UPDATE
http://jsfiddle.net/nonyg6sm/4/
$('input[type=checkbox]').click(function() {
var target = $(this).closest('.NoEd').prevAll(".Subs:first").find(".showMe");
if ($(this).closest('.NoEd').find("input[type=checkbox]:checked").length == 0) {
target.hide();
} else {
target.show();
}
});
here is my script. Now i can click one of these IDs and class "inputs" are visible. What i want is that I have to click on all elements.
$('#zwei,#sechs,#neun').bind('click', function() {
if( $(this).is(':checked')) {
$('.inputs').show();
} else {
$('.inputs').hide();
}
});
JSFiddle:
http://jsfiddle.net/CLYC6/20/
can you help me please? whats wrong?
FK
Use this:
$('#zwei,#sechs,#neun').bind('click', function() {
$('.inputs').show();
$('#zwei,#sechs,#neun').each(function (e) {
if (!$(this).is(':checked')) {
$('.inputs').hide();
return;
}
});
});
Here is a LIVE DEMO.
Because #Rastko is not happy with the current solution here is one more:
$('#zwei,#sechs,#neun').bind('click', function() {
var showInput = true;
$('#zwei,#sechs,#neun').each(function (e) {
if (!$(this).is(':checked')) {
showInput = false;
return;
}
});
if (showInput) {
$('.inputs').show();
} else {
$('.inputs').hide();
}
});
One more LIVE DEMO.
If statement should check whether all three are checked, and if input is not visible.
so:
if($('#zvei').is(':checked') && $('#neun').is(':checked') && $('#sechs').is(':checked') {
$('.inputs').show();
}
I am using this code to check if an inputbox is empty or not and it works fine but it only checks check a key is press not when the page loads.
It's does what it should but I also want it to check the status when the page loads.
Here is the current code:
$('#myID').on('keyup keydown keypress change paste', function() {
if ($(this).val() == '') {
$('#status').removeClass('required_ok').addClass('ok');
} else {
$('#status').addClass('required_ok').removeClass('not_ok');
}
});
Try the following:
$(function() {
var element = $('#myID');
var toggleClasses = function() {
if (element.val() == '') {
$('#status').removeClass('required_ok').addClass('ok');
} else {
$('#status').addClass('required_ok').removeClass('not_ok');
}
};
element.on('keyup keydown keypress change paste', function() {
toggleClasses(); // Still toggles the classes on any of the above events
});
toggleClasses(); // and also on document ready
});
The simplest way to do is trigger any of the keyup,keydown etc event on page load. It will then automatically call your specific handler
$(document).ready(function(){
$("#myID").trigger('keyup');
});
try checking the value on a doc ready:
$(function() {
if ($('#myID').val() == '') {
$('#status').removeClass('required_ok').addClass('ok');
} else {
$('#status').addClass('required_ok').removeClass('not_ok');
}
});
EDIT: just as an update to this answer, a nicer approach might be to use toggle class, set up in doc ready then trigger the event to run on page load.
function check() {
var $status = $('#status');
if ($(this).val()) {
$status.toggleClass('required_ok').toggleClass('ok');
} else {
$status.toggleClass('required_ok').toggleClass('not_ok');
}
}
$(function () {
$('#myID').on('keyup keydown keypress change paste', check);
$('#myID').trigger('change');
});
Well then why dont just check the field after the page is loaded?
$(document).ready(function(){
if ($('#myID').val() == '') {
$('#status').removeClass('required_ok').addClass('ok');
} else {
$('#status').addClass('required_ok').removeClass('not_ok');
}
});
$(document).ready(function(){
var checkVal = $("myID").val();
if(checkVal==''){
$('#status').removeClass('required_ok').addClass('ok');
}
else{
$('#status').addClass('required_ok').removeClass('not_ok');
}
});