I have a logging page and I wanted to send the logging details in json format to the checkuser.php file which is a other page in the web site.
checkUser.php file will create a new window.
What is the best way to do this ? if possible please give me some example.
$("#myform").submit(function( e ) {
e.preventDefault();
$.ajax({
url: "blabla.com/api",
type: 'POST',
contentType: 'application/json',
data: JSON.stringify( { key: val } ) // <-------- HERE IS YOUR JSON
}).done(function() {
console.log('hooray!');
});
});
Suppose you have a login form as login.php with html form controls txtLogin and txtPassword and a Submit button. Once the user submits the form it would post data onto checkuser.php
You can write the following code that can push data in JSON format
$login = $_POST['txtLogin'];
$password = $_POST['txtPassword'];
$userArray = array('login'=>$login,'password'=>$password);
$json_array = json_encode($userArray);
Related
I have to recreate a form that was originally created using Jotform - it is here. I am struggling in one area. It is a pretty simple form, the only caveat being the ability to duplicate a form field form multiple entries. That part can be seen here. When the form is duplicated, I need to submit the form data as a JSON array. In the fiddle, I didn't put the regular form fields, here is how they and the cloned field need to submit the data.
q2_fullName[first]:test
q2_fullName[last]:test
q1_currentCommission1:[{"Instruments":"a","Commissions":"1","Margins":"a"},{"Instruments":"b","Commissions":"2","Margins":"b"},{"Instruments":"c","Commissions":"3","Margins":"c"}]
normally in my $.ajax handler, I just serialize the data, but that doesn't work in creating the json array for the cloned fields. Normally like so:
submitHandler: function(form) {
var dataString = $(form).serialize();
$.ajax({
type:'POST',
url: form.action,
data: dataString,
dataType: "json",
beforeSend: function(data){
//before send
},
success: function(data){
//success function
}
});
return false;
},
I need to somehow serialize the non cloned fields (I think) and create a json array out of the cloned values and assign them a key name
You can build the post data and the json string like this :
var data = {
// get/set the firstname etc
"q2_fullName":{
"first":"", // get firstname ie $("#first_2").val(),
"last":""
},
"q1_currentCommission1" :""
},
commisions = [];
$('.InsContain').each(function() {
var $inputs = $(this).find('input');
commisions.push({
"Instruments" : $inputs.eq(0).val(),
"Commissions" : $inputs.eq(1).val(),
"Margins" : $inputs.eq(2).val()
});
});
data.q1_currentCommission1 = JSON.stringify(commisions);
Posted data :
q2_fullName[first]:aaa
q2_fullName[last]:123
q1_currentCommission1:[{"Instruments":"1","Commissions":"1","Margins":"1"}]
Update fiddle here
I am trying to echo the contents of an input field on enter. I have a text input field that I create here:
echo '<form id="changePassForm" action="" method="post" enctype="multipart/form-data">
<div class="changePass">
<div class="changePassBtn">Change Password</div>
<input class = "passwordText" type="password" placeholder="Password" name="passwordText">
</div>';
The field calls this javascript function correctly:
$(".passwordText").keydown(function(event){
if(event.keyCode == 13){
$.ajax({
url: "../php/passwordchange.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
datatype: 'text',
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
console.log(data);
}});
console.log("WORKS!!");
}
});
Which references password change.php here:
<?php
session_start();
echo "Hello world";
$pass=$_POST['passwordText']; //name of input
echo $pass;
/*$dbh = new PDO("mysql:host=localhost;dbname=sqlserver", 'username', 'password');
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$checkforpass = "SELECT password FROM sqlserver.accounts WHERE username='".$username."'";*/
?>
I'm not versed in PHP but Hello world is output to console. How can I output/store value of text field in $pass?
Untested, off the cuff:
$(".passwordText").keydown(function(event){
if(event.keyCode == 13){
var pass = $('#changePassForm input').val();
$.ajax({
url: "../php/passwordchange.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: 'passwordText=' + pass, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
success: function(data) // A function to be called if request succeeds
{
console.log(data);
}});
console.log("WORKS!!");
}
});
Note also that it is dataType: not datatype:, and that dataType only affects returning data not data being sent to PHP
So, get it working simply first (as above), then get fancy with $('#changePassForm').serialize() etc.
Try as follows
$(".passwordText").keydown(function(event){
if(event.keyCode == 13){
var postData = $('#changePassForm').serializeArray();
$.ajax({
url: "../php/passwordchange.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: postData, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
datatype: 'text',
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
console.log(data);
}});
console.log("WORKS!!");
}
});
If you want to use FormData, you can see from the manual that the FormData object constructor takes an optional <form> element and you're using this, which refers to $(".passwordText"), which is a jQuery object. You can pass a form element by doing:
var form = document.getElementById("changePassForm");
var fd = new FormData(form);
Putting this all together we would then have:
$(document).ready(function() {
$(".passwordText").keydown(function(event){
if(event.keyCode == 13){
event.preventDefault();
var form = document.getElementById("changePassForm");
var fd = new FormData(form);
$.ajax({
url: "../php/passwordchange.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: fd, // Data sent to server, a set of key/value pairs (i.e. form fields and values)
dataType: 'text',
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
console.log(data);
}});
console.log("WORKS!!");
}
});
});
As an alternative you can manually append any values you want to have sent in the ajax request like this:
var fd = new FormData();
fd.append($(this).attr("name"), $(this).attr("value"));
Disclaimer:
With that said, the FormData interface is only available in IE >= 10, so if you are worried about cross browser compatibility you may want to consider simply using jQuery's serialize() method to send the data. As an added bonus, it's only 1 line of code.:
data: $("#changePassForm").serialize()
Im learning Ajax...normally I dont like posting about a subject I know very little of but I believe Im on the right path here (maybe not...?) so I will take a chance to find out.
Ive got 3 select boxes each box populates with values based on the the selection of the box before it:
Everything is working perfectly, when the user clicks submit I want to send the 3 textbox values to 3 php variables and echo it on the same page...
Now my data is not echoing (the data of the variables are not displaying) but when I look in my console on firefox I can see the value of the variables...
Here is the selection made on the select boxes
Here is what im seeing in my console
Yet it is does not echo on the page....?
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#resultForm input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
PHP below form
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$sport = $_POST['sport'];
$round = $_POST['round'];
$tournament=$_POST['tournament'];
echo $sport;
echo $round;
echo $tournament;
}
I don't see anything in your code that would make the values display on the page. You would need to either do some DOM insertion in your AJAX success function, or do a full page refresh and echo the data out via PHP (but that would probably defeat the purpose of doing an AJAX call in the first place.)
If you want to go the AJAX route, I would suggest editing your PHP to the following:
echo json_encode(array(
'sport' => $sport,
'round' => $round,
'tournament' => $tournament
));
This will return a JSON object for your jQuery AJAX call to consume.
In your jQuery success function, do something with those values, like so:
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
dataType: 'json',
success: function(data) {
$('<div></div>').text(data.sport).appendTo('body');
$('<div></div>').text(data.round).appendTo('body');
$('<div></div>').text(data.tournament).appendTo('body');
}
});
Note the additional dataType argument to $.ajax. To do it the right way, you'll also want to set your headers in your PHP response to "application/json"
You ajax is just displaying the output in console. Change the ajax success to display it in page.
Make changes after success as:
success:function(data){
$('someelementclassorid').text(data);
}
I have a module where the forms created are dynamic. So the number of inputs can defer always. Also, the array key can also defer.
My current method of posting form is this:
name = form_options[option_1] value = 1
On submitting the form using POST, I get the form as array in $_POST, which looks like this.
form_options(
option_1 => 1
)
But, now I am trying to implement the same thing using AJAX. So, I would need a common module to get all form values.
I found a way to do it.
var objectResult = $('#options_form').serializeArray();
console.log(objectResult);
This gives me a result like this:
0: Object
name: "form_options[option_1]"
value: "1"
How can parse this result to get an array like $_POST array, which I can send as data in AJAX.
P.S: All the form elements have name field as form_options[key]
You should use this for get post data in PHP file.
// You can use like this
var objectResult = $('#options_form').serializeArray();
$.ajax({
type: "POST", // Enter Request type GET/POST
url: 'action.php', // Enter your ajax file URL here,
dataType: 'json', // If you are using dataType JSON then in php file use die( json_encode($resultArray) );
data: objectResult, // Put your object here
beforeSend: function(){
alert('before');
},
error: function(data) {
console.log(data);
},
success: function(response){
console.log(response);
}
});
// In php file get values like this way
$_POST['form_options']
try like this,
In JQuery:
var objectResult = $('#options_form').serializeArray();
$.ajax({
type: 'POST',
url: 'yoururl'',
data: objectResult ,
success:function(data){
alert(data);
}
});
In your php:
<?php echo var_dump($_POST);?>
You can use jquery serialize with ajax directly, there is no need to use serializeArray:
$.ajax({
type:"post",
url:"formHandleSkript.php",
data: $("#options_form").serialize(),
success: function(response){
$(".result").html(response);
}
});
For more information see http://api.jquery.com/serialize/
The folowing post is related to: How to send image to PHP file using Ajax?
I managed to get this working as per the above post, but it fails to work on IE8.
Is there a way to get this to work on ie8+?
Here is my code:
$("form[name='uploader']").submit(function(e) {
var formData = new FormData($(this)[0]);
$.ajax({
url: dotnetpage,
type: "POST",
data: formData,
async: false,
success: function (msg) {
$('.js-ugc-image').attr('src', msg);
},
cache: false,
contentType: false,
processData: false
});
e.preventDefault();
});
IE 8 does not have formdata, you can use a hidden iframe and post it and read the results.
I've used a technique that was something like this
Clone the form, move original form into a hidden iframe (this needs to be done because you cant clone or set input type files value on IE) and then submit and read the result of the submit.
Something like this which is a code i used before and worked:
var $form = $('your form');//GET YOUR FORM
//Create Hidden iframe
var _hiddenIframe = $('<iframe id="_hiddenframe" style="display:none;"></iframe>');
//Create Copy Form and add the attributes of the original
var _copyForm = $('<form id="_copyForm" name="_copyForm" style="">');
_copyForm.attr({'method':$form.attr('method'),'action':$form.attr('action'), 'enctype':$form.attr('enctype')});
//Get original fields
$original = $form.children('*');
//Clone and append to form
$original.clone(true).appendTo($form);
//send the original fields to hidden form
$original.appendTo(_copyForm);
//Add the iframe to the body
_hiddenIframe.appendTo('body');
//Add the form to the hidden iframe
_copyForm.appendTo(_hiddenIframe.contents().find('body'));
var $r;
//submit the form
_copyForm.submit();
//after it reloaded(after post)
_hiddenIframe.on('load',function(){
//read result (maybe a json??)
$r = $.parseJSON(_hiddenIframe.contents().find('body').text());
//Do something with the result
if($r.result=='ok'){
//Do Something if ok
}
else{
//Do Something if error
}
});
No,sorry, IE8 doesn't support the FormData object. (See http://caniuse.com/#search=formdata)
Whay you can do is embed the <input type='file > tag in a separate form and submit it using jQuery.