How to submit one form out of multiple with javascript - javascript

On my website I have a big list of all the letters people can view.
For every letter there is a form which sends some data from the letter to the next page. What I want to do is to submit the form with a link, and not with a button.
As far as I know, that is not possible with PHP. So i tried making what i want in Javascript.
My programming experience in Javascript is litterly 0%. I need some help with this :)
This is the code I'm using:
<script type="text/javascript">
function submitform()
{
document.forms["brief_weergeven"].submit();
}
</script>
<form id='brief_weergeven[]' action='<?php echo $main; ?>beveiligd/achterbanner/nieuwsbrief.php' method='POST'>
<input type='hidden' name='nummer' value='<?php echo $brieven[0]; ?>'>
<input type='hidden' name='datum_maand' value='<?php echo $maand_getal; ?>'>
<input type='hidden' name='datum_jaar' value='<?php echo $jaar; ?>'>
<a href="javascript: submitform()" class='button'>Nieuwsbrief <?php echo $brieven[0]; ?> (<?php echo $maand .' ' .$jaar; ?>)<BR></a>
</form>
This code runs for every letter. As you can see, I'm using a array to give all the forms a seperate ID. The only thing is that i have no idea how to let javascript know which forum i submitted.
How can I do this? Please remember that i know nothing about javascript, so please explain what you're doing in your answer.

You dont need javascript to do this, just use css to make your button look like a link:
Css:
button {
border:none;
padding:0;
background: none;
color: blue;
text-decoration: underline;
cursor: pointer;
}
html:
<button type="submit">Submit</button>

You can usedocument.getElementById('form-id')
And event handler like this
var form = document.getElementById('your-form-id');
form.onsubmit = function(){
// code
}

user574632 gave you a nice alternative. Still even want to use JavaScript you can try below.
Use the jQuery onclick method having the id attribute of the link as selector.
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
$("#submit_link").on("click", function(){
var form = $(this);
var url = form.attr("action");
var data = form.serialize();
$.post(url, data);
});
});
</script>
<form id='brief_weergeven[]' action='<?php echo $main; ?>beveiligd/achterbanner/nieuwsbrief.php' method='POST'>
<input type='hidden' name='nummer' value='<?php echo $brieven[0]; ?>'>
<input type='hidden' name='datum_maand' value='<?php echo $maand_getal; ?>'>
<input type='hidden' name='datum_jaar' value='<?php echo $jaar; ?>'>
<a href="#" id="submit_link" class='button'>Nieuwsbrief <?php echo $brieven[0]; ?> (<?php echo $maand .' ' .$jaar; ?>)<BR></a>
</form>

Related

Unable to get button value with loop Jquery

I am working with jquery and PHP,I want to display "buttons" according to database value(dynamic) and want to get button values in jquery, I am using "input type hidden", But right now getting value="1"(static), But I want to get "correct" value (if I select button 2 then 2 value should get in jquery)
Here is my HTML code
<?php $j=$records['start_range'];
$max= $records['end_range'];
for($i=$j;$i<=$max; $i++) { ?>
<button class="btn btn-scale btn-scale-asc-<?php echo $i; ?>">
<?php echo $i; ?>
<input type="hidden" <?php if($records['IsRatingQuestion']=="" || empty($records['IsRatingQuestion'])){ ?>name='ques_<?php echo $records['ques_id']; ?>' <?php } else{ ?>name='rangeR_<?php echo $records['ques_id']; ?>' <?php } ?> id="ratings" value="<?php echo $i; ?>">
</button>
<?php } ?>
Here is the script, Where I am wrong?
<script>
$(document).ready(function(){
$("#next1").click(function(){
var rating =$("#ratings").val();
alert(rating);
});
});
</script>
Before anything else, you need to remove input from inside that button. It's not a valid HTML.
Moreover, as mentioned in the comments, you cannot have the same id for all inputs, so I'd just remove it.
How about something like this:
$(document).ready(function() {
$('.item').each(function() {
var $button = $(this).find('button')
var $input = $(this).find('input')
$button.click(function() {
alert($input.val())
})
})
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="item">
<button>1</button>
<input type="hidden" value="1">
</div>
<div class="item">
<button>2</button>
<input type="hidden" value="2">
</div>
<div class="item">
<button>3</button>
<input type="hidden" value="3">
</div>
<div class="item">
<button>4</button>
<input type="hidden" value="4">
</div>
As far as I am understanding, you just want to show the value of the dynamic button using jquery. For this you just need to pass the value to the button using data attribute and then you can get the value using jquery.
<?php $j=$records['start_range'];
$max= $records['end_range'];
for($i=$j;$i<=$max; $i++) {
echo '<button class="get-value" data-value="'.$i.'">Button '.$i.'</button>';
} ?>
<input type="text" id="show-value">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$(document).on('click', '.get-value', function(){
var button_value = $(this).data('value');
$('#show-value').val(button_value)
});
});
</script>
I don't think putting an <input> inside of a <button> is valid html (although it seems to work?). Instead you can just assign those values as attributes of the button itself. Also ids have to be unique, so if you have a bunch of buttons with the same id, that is also invalid. I tend to stay away from ids and just use classes to avoid this.
Also, rather than having a bunch of choppy php, you can build a single string of html and echo it back all at once. By using double qoutes " on the outside of a string, you can use single quotes ' on the inside and drop variables right into the string without escaping or concatenating anything. Although you have to wrap associative arrays in brackets {} for it to parse correctly. PHP strings.
I'm guessing $name isn't a static variable, but without seeing the rest of your code, this is just an example:
<?php
$html = "";
$name = ($records["IsRatingQuestion"] == "" || empty($records["IsRatingQuestion"])) ?
"ques_{$records["ques_id"]}" :
"rangeR_{$records["ques_id"]}";
for($i = $records["start_range"]; $i <= $records["end_range"]; $i++) {
$html .= "<button class='btn btn-scale btn-scale-asc-$i ratings' name='$name'>$i</button>";
}
echo $html;
?>
$('.btn.ratings').on('click', function() {
//$(this).text() = $i
//$(this).attr('name') = $name
});

Javascript innerHTML with session PHP from other page

I have 2 page
the innerhtml onclick page (a.php)
the page that start session (b.php)
in a.php I write function onclick to change some text
and I add the session from b.php in this text, but nothing change in text
$(document).ready(function(){
$('.add-to-cart').on('click',function(){
document.getElementById('outside_cart_text').innerHTML =
"Qty type <?php echo $this->session->userdata('qty_type'); ?> amount <?php echo $this->session->userdata('qty_product');?>";
});
});
it change the original text to "Qty type amount". But session value not appear.
the question is how to make it appear instantly?
additional detail : My click is on the button sumbit to other page, but I have already use this trick. It work like ajax. so after click I still in the same page (and not reload)
<style>
.hide { position:absolute; top:-1px; left:-1px; width:1px; height:1px; }
</style>
<iframe name="hiddenFrame" class="hide"></iframe>
<form action="receiver.pl" method="post" target="hiddenFrame">
<input name="signed" type="checkbox">
<input value="Save" type="submit">
</form>
Maybe it would work if the variables are encoded in json format.
document.getElementById('outside_cart_text').innerHTML =
"Qty type
<?php echo json_encode($this->session->userdata('qty_type')); ?>
amount
<?php echo json_encode($this->session->userdata('qty_product'));?>";
});
$(document).ready(function(){
$('.add-to-cart').on('click',function(){
var qty_type = '<?php echo $this->session->userdata('qty_type'); ?>';
var amount = '<?php echo $this->session->userdata('qty_product'); ?>';
$("#outside_cart_text").html("Qty type "+qty_type+" amount "+amount);
});
});

Div with contentEditable wont post into form using Javascript

Okai, so I have this div:
// DESCRIPTION AREA
$body_html .= "<div id='seq-desc-".$seq_id_d."' contenteditable='true' data-text='Det som skal skje...'>";
$body_html .= $seq_desc_d;
$body_html .= "</div> ";
and this textarea:
$body_html .= "<textarea id='seq-desc-area-".$seq_id_d."' name='deta-".$seq_id_d."' style='display: none;'></textarea></td>";
In my form I use the following code to activate my Javascript code:
"<form action='planner_seq_save.php' id='save-".$seq_id_d."' name='save-".$seq_id_d."' method='POST' onsubmit='return getContent".$seq_id_d."'>";
getContent is defined like this:
function getContent'.$seq_id_d.'(){
document.getElementById("seq-desc-area-'.$seq_id_d.'").value = document.getElementById("seq-desc-'.$seq_id_d.'").innerHTML;
}
How come I get an empty return in my database when using POST?
I use $_POST['deta-(the id)'] to fetch my post.
Also I save my form using this code on a standard button. Could this make onsubmit not work?
onclick='document.forms['save-".$seq_id_d."'].submit();'
Been trying to find out what the problem is for a while now, and I really need someone elses opinion.
UPDATE:
Using console.log() I get no return within the function. So the function isn't running.
Full code can be found here
It looks like the submit event is not triggered when triggering the submit() method, therefore the onsubmit handler is not called. See another question for more info.
So you can try removing the onsubmit handler and trigger the getContent function from the onclick's one:
onclick='submitForm(id)'
function submitForm(id){
getContent(id);
document.forms(id).submit();
}
rename function getContent-'.$seq_id_d.'() to getContent_'.$seq_id_d.'()
correct textarea id in function document.getElementById("seq-desc-area-'.$seq_id_d.'").value to document.getElementById("seq-deta-area-'.$seq_id_d.'").value
correct function call in onsubmit onsubmit='return getContent-".$seq_id_d."' to onsubmit='return getContent_".$seq_id_d."()'
suppose that is all :)
full code
<?php
$seq_id_d = 1;
var_dump($_REQUEST);
?>
<div id='seq-desc-<?php echo $seq_id_d; ?>' contenteditable='true' data-text='Det som skal skje...'>werwerwqrewrqwer</div>
<form id='save-<?php echo $seq_id_d; ?>' name='save-<?php echo $seq_id_d; ?>' method='POST' onsubmit='return getContent_<?php echo $seq_id_d; ?>()'>
<textarea id='seq-deta-area-<?php echo $seq_id_d; ?>' name='deta-<?php echo $seq_id_d; ?>' style='display: none;'></textarea>
<input type="submit" value="ok">
</form>
<script>
function getContent_<?php echo $seq_id_d; ?>(){
document.getElementById("seq-deta-area-<?php echo $seq_id_d; ?>").value = document.getElementById("seq-desc-<?php echo $seq_id_d; ?>").innerHTML;
}
</script>

How can I reloaded URL link, that it stay the same after I click on submit button

I have simple form:
<div class="form-style-2">
<form action="" name="formular" id="formular" method="GET">
<label for="actual_position"><span>From: <span class="required"></span></span><input name="actual_position" type="text" maxlength="512" id="actual_position" class="searchField"
<?php if(!empty($actual_position)){ ?>
value="<?php echo $_GET['actual_position']?>"
<?php
}else {
?> value = ""; <?php
} ?>/></label>
<label for="final_position"><span>To: <span class="required"></span></span><input name="final_position" type="text" maxlength="512" id="final_position" class="searchField" <?php if(!empty($final_position)){ ?>
value="<?php echo $_GET['final_position']?>"
<?php
}else {
?> value = ""; <?php
} ?>/></label>
<input type="submit" value="Find path" />
And another multiselect in form who gets values form url link and compere with database and get som results. Here is a code:
<table width= "570px">
<tr><td width="200px" style="align:center"><b>Waypoints:</b> <br>
<tr><td width="370px"><select style="float:center; margin-left:5px" multiple id="waypoints">
if(!empty($urls)){
foreach($urls as $url){
if($result = $conn->query("SELECT * FROM $table where $ID = '$url' "));
$atraction = $result->fetch_array(); ?>
<option value="<?php echo $atraction['lat']. "," . $atraction['lon']; ?>"
> <?php echo "<b>".$atrction['City']. ", " . $atraction['Name'];?> </option>
<?php
}
}
?>
</select></td></tr>
<br>
</table>
</form>
And getting ID-s from url code:
if(!empty($_GET[$ID])){
$urls = $_GET[$ID];
foreach($urls as $url){
// echo $url;
}
}
... and after submit, it Post to URL some variables like this:
http://127.0.0.1/responsiveweb/travel.php?actual_position=Paris&final_position=Praha&ID[]=23&ID[]=15&ID[]=55
... very important for me are ID-s values ... but when I change for example actual position and then submit I lost my ID-s and I get something like this: http://127.0.0.1/responsiveweb/travel.php?actual_position=Berlin&final_position=Praha
Can you help me how to get after clicking on submit button full url link? Thanks
I had some trouble understanding your question OP, but I think I understood somehow what you ment, so I decided to try giving you a answer.
I have re-written your code, and tried to make somehow better code-structure. I have also used form method POST in my example, so you can see how you can change the get data on the redirection url.
See my code example here: http://pastebin.com/wQ7QCBmt
I also decided to use the form method POST instead of GET, so you can easily do back-end tasks, and extend your link if neccessary. You could also add more data to the link even when using GET. You could add an hidden input inside your form, example:
<input type="hidden" name="more_data" value="a_value" />

send php post variable to url using javascript when button is clicked

I have a php page which gets $page and $user using post method, I also have a button that i want, to open a URL in the same window using $page and $user variables when clicked, to use them with $_GET[] function.
i want my URL be like:
http://www.test.com/test.php?page=$page&user=$user
my code is like this:
<?php
$page=$POST_['page'];
$user=$POST_['user'];
<?
<html>
<head>
function openurl() {
var user=<?php echo "$user";?>;
var page=<?php echo "$page";?>;
open('www.test.com/test.php?page='+page'&user='+user,'_self');
}
</head>
<body>
<button onclick="openurl()" type="button">open url</button>
</body>
</html>
There is no need for scripting at all
If you want GET:
<?php
$page=$GET_['page']; // should be sanitized and you can use REQUEST for either
$user=$GET_['user'];
$parm = "page=".$page."&user=".$user;
?>
Open URL
If you need to post:
<form action="test.php" method="post">
<input type="hidden" name="page" value="<?php echo $page; ?>"/>
<input type="hidden" name="user" value="<?php echo $user; ?>"/>
<input type="submit" value="Open URL" />
</form>
Change these lines:
<?php
$page=$POST_['page'];
$user=$POST_['user'];
<?
....
var user=<?php echo "$user";?>;
var page=<?php echo "$page";?>;
open('www.test.com/test.php?page='+page'&user='+user,'_self');
to this:
<?php
$page=$_POST['page']; //incorrect $_POST declaration
$user=$_POST['user']; //incorrect $_POST declaration
?> //php tag incorrectly closed
....
var user=<?php echo $user;?>; //echoing a variable not string (no need for quotes)
var page=<?php echo $page;?>; // echoing a variable not string (no need for quotes)
open('www.test.com/test.php?page='+page+'&user='+user,'_self'); // link was broken, forget to put '+' after page variable in link.
You can create a form and via Javascript just run YOURFORMNAME.submit();
Use href in javaScript to move to another location:
location.href="www.test.com/test.php?page='+page'&user='+user"

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