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Object.assign Babel with external npm dep

I have an external NPM dependency that uses Object.assign. I want to use Babel, to assure compatibility with old browsers, either transforming Object.assign via helper or substituting it using another method, but it is not working.
PS: I can use a polyfill at the top of the code, i want to avoid this since it is a library (https://babeljs.io/docs/plugins/transform-object-assign/)
The dependency is : https://github.com/krux/postscribe
via var postscribe = require('postscribe');
my .babelrc conf:
{
"presets": [
["env", {
"targets": {
"browsers": ["Android 4", "iOS 7"]
}
}]
],
"plugins": ["transform-object-assign"]
}
Gulp conf:
gulp.task('adtag', function () {
// set up the browserify instance on a task basis
var b = browserify({
entries: './src/adtag/main.js',
debug: true
}).transform(babelify)
return b.bundle()
.pipe(source('smaatoAdTag.min.js'))
.pipe(buffer())
.pipe(sourcemaps.init({
loadMaps: true
}))
// Add transformation tasks to the pipeline here.
.pipe(uglify())
.on('error', gutil.log)
.pipe(sourcemaps.write('./'))
.pipe(gulp.dest('./dist/adtag/'));
});
Is there any way to substitute Object.assign if is in a dependency and not in the main code?

Check out the docs for babelify
You could use :
browserify().transform("babelify", {
global: true,
ignore: /\/node_modules\/(?!postscribe\/)/
});

GulpUglifyError:Unable to minify JavaScript

I am trying to minify my script files for which i am using gulp task runner
And I am trying gulp-uglify plugin
Code:
gulp.task('concat', function() {
return gulp.src('app/**/*.js')
// .pipe(concat('script.js'))
.pipe(uglify())
.pipe(gulp.dest('./dist/'))
});
but i am getting error as
when i try to run gulp task as gulp concat
Any help would be appreciated

The main error is generated when you're using ES6 format. Use the gulp-uglify-es module instead of 'gulp-uglify' to overcome this error.
var uglify = require('gulp-uglify-es').default;
Note: gulp-uglify-es is no longer being maintained. You may want to use terser/gulp-terser instead:

To see the error in console:
var gutil = require('gulp-util');
gulp.task('concat', function() {
return gulp.src('app/**/*.js')
// .pipe(concat('script.js'))
.pipe(uglify())
.on('error', function (err) { gutil.log(gutil.colors.red('[Error]'), err.toString()); })
.pipe(gulp.dest('./dist/'))
});
To find the exact file, with line number of error register and run this task:
var pump = require('pump');
gulp.task('uglify-error-debugging', function (cb) {
pump([
gulp.src('app/**/*.js'),
uglify(),
gulp.dest('./dist/')
], cb);
});

I think the top answers here are not explaining how to get the error. The docs have a section on error handling:
gulp-uglify emits an 'error' event if it is unable to minify a
specific file
So, just capture the error and do whatever you want with it (such as logging to console) to see the filename, line number, and additional info:
uglify().on('error', console.error)
or in a larger context:
gulp.task('foo', () => {
return gulp.src([
'asset/src/js/foo/*.js',
'asset/src/js/bar/*.js',
])
.pipe(uglify().on('error', console.error))
.pipe(concat('bundle.js'))
.pipe(gulp.dest('./'));
});
This gives you a super helpful error!
{ GulpUglifyError: unable to minify JavaScript
at [stack trace])
cause:
{ SyntaxError: Continue not inside a loop or switch
[stack trace]
message: 'Continue not inside a loop or switch',
filename: 'ProductForm.js',
line: 301,
col: 37,
pos: 10331 },
plugin: 'gulp-uglify',
fileName:
'/asset/src/js/foo/ProductForm.js',
showStack: false }

Have you used ES6 format in your script file?
If so try ES5 now because when you do gulp-uglify it doesnt understand ES6 format as of now
and after that try your code
gulp.task('concat', function() {
return gulp.src('app/**/*.js')
.pipe(concat('script.js'))
.pipe(uglify())
.pipe(gulp.dest('./dist/'))
});
and run the task gulp concat it will work

For me, it was a deprecated option "preserveComments" that generated the error (and completely crashed the script).
Found the issue using:
gulp.task('concat', function() {
return gulp.src('app/**/*.js')
.pipe(uglify())
.on('error', function (err) { console.log( err ) })
.pipe(gulp.dest('./dist/'))
});

Try using this
var concat = require('gulp-concat');
var uglify = require('gulp-uglify');
var minifyJS = require('gulp-minify');
gulp.task('concat', function() {
return gulp.src('app/**/*.js')
.pipe(minifyJS())
.pipe(concat('bundle.min.js'))
.pipe(uglify({ mangle: false }))
.pipe(gulp.dest('./dist/'));
});

you may have syntax error or used ES6 syntax. you can try https://skalman.github.io/UglifyJS-online/ firstly.

The main error to Unable to minifies JavaScript is the path not found. You can use the task usemin For this you need:
$ sudo npm install gulp-usemin --save-dev
$ sudo npm install gulp-livereload --save-dev
$ sudo npm install gulp-util --save-dev
and requires :
var usemin = require('gulp-usemin');
var livereload = require('gulp-livereload');
var gutil = require('gulp-util'); //gutil for error display
gulp.task('usemin',['jshint'], function(){
return gulp.src('./app/index.html')
.pipe(usemin({
css: [minifycss(),rev()],
scripts: [uglify().on('error', function(err) {gutil.log(gutil.colors.red('[Error]'), err.toString());this.emit('end');}),rev()]
}))
.pipe(gulp.dest('dist'))
.pipe(livereload());
});
Change the js: [uglify(), rev()] to scripts: [uglify(), rev()]

Gulp 4 & BrowserSync: Style Injection?

I'm attempting to use browser-sync with Gulp 4, but bs is not preserving state, and instead does a full refresh. This is not very useful. It seems bs no longer supports true injection. I filed an issue on GH if you want to contribute.
Here is the pertinent code:
// styles:dev task
gulp.task('styles:dev', function() {
return gulp.src(config.src)
.pipe(sourcemaps.init())
.pipe(postcss(config.postcss.dev))
.pipe(sourcemaps.write('.'))
.pipe(gulp.dest(config.dest.dev))
.pipe(browserSync.stream());
});
// browserSync task
gulp.task('browserSync', function(cb) {
browserSync.init(config, cb);
});
// Watch task:
gulp.task('watch:styles', function() {
return gulp.watch(config.paths.css,
gulp.series('styles:dev'));
});
gulp.task('watch', gulp.parallel('watch:styles'));
// default task
gulp.task('default',
gulp.series('clean:dev',
gulp.parallel('copy:dev', 'styles:dev'), 'browserSync', 'watch')
);
Thanks in advance.

Fixed. Here's where I went wrong:
The browser-sync constructor takes an options object, which can include a files array. Most of the tutorials I've read, including the gulpfile for Google's very own Web Starter Kit, do not include this. As it turns out, this is required for style injection to preserve state.
Furthermore, do not pass .stream() or .reload() as the final pipe in your styles task. It is not needed, and will short circuit style injection, forcing a full refresh.
Finally, the browserSync process must not be terminated, and watch and browserSync tasks must execute in parallel in order for live style injection to take place.
Hope this helps anybody facing this issue.
I also closed the corresponding github issue, and posted my gulpfile

Almost 3 years later Gulp 4 now looks a little bit different, see https://gulpjs.com/docs/en/getting-started/creating-tasks
To have a complete Gulp 4 kickstart example, see https://gist.github.com/leymannx/8f6a75e8ad5055276a71d2901813726e
// Requires Gulp v4.
// $ npm uninstall --global gulp gulp-cli
// $ rm /usr/local/share/man/man1/gulp.1
// $ npm install --global gulp-cli
// $ npm install
const { src, dest, watch, series, parallel } = require('gulp');
const browsersync = require('browser-sync').create();
const sass = require('gulp-sass');
const autoprefixer = require('gulp-autoprefixer');
const sourcemaps = require('gulp-sourcemaps');
const plumber = require('gulp-plumber');
const sasslint = require('gulp-sass-lint');
const cache = require('gulp-cached');
// Compile CSS from Sass.
function buildStyles() {
return src('scss/ix_experience.scss')
.pipe(plumber()) // Global error listener.
.pipe(sourcemaps.init())
.pipe(sass({ outputStyle: 'compressed' }))
.pipe(autoprefixer(['last 15 versions', '> 1%', 'ie 8', 'ie 7']))
.pipe(sourcemaps.write())
.pipe(dest('css/'))
.pipe(browsersync.reload({ stream: true }));
}
// Watch changes on all *.scss files, lint them and
// trigger buildStyles() at the end.
function watchFiles() {
watch(
['scss/*.scss', 'scss/**/*.scss'],
{ events: 'all', ignoreInitial: false },
series(sassLint, buildStyles)
);
}
// Init BrowserSync.
function browserSync(done) {
browsersync.init({
proxy: 'blog.localhost', // Change this value to match your local URL.
socket: {
domain: 'localhost:3000'
}
});
done();
}
// Init Sass linter.
function sassLint() {
return src(['scss/*.scss', 'scss/**/*.scss'])
.pipe(cache('sasslint'))
.pipe(sasslint({
configFile: '.sass-lint.yml'
}))
.pipe(sasslint.format())
.pipe(sasslint.failOnError());
}
// Export commands.
exports.default = parallel(browserSync, watchFiles); // $ gulp
exports.sass = buildStyles; // $ gulp sass
exports.watch = watchFiles; // $ gulp watch
exports.build = series(buildStyles); // $ gulp build

Prevent browserify from including module's dependencies

I'd like to use my NodeJS module in the browser - so I'm using browserify to process it.
Now, how can I stop browserify from including the module's dependencies in the bundle file? In this case the dependency is lodash and I'll be loading it separately in the index.html.
Here's what I've got so far:
index.html
<script src="lodash.js"></script>
<script src="my-module.js"></script>
index.js
var _ = require('lodash');
_.each([0, 1, 2], function(item) {
console.log(item);
});
gulp.js
var browserify = require('browserify'),
source = require('vinyl-source-stream');
gulp.task('browserify', function() {
return browserify()
.require('./index.js', {
expose: 'my-module'
})
.bundle()
.pipe(source('my-module.js'))
.pipe(gulp.dest('./'));
});

browserify-shim offers the option of setting up globals.
Here are the changes I've made to my code.
package.json
{
"browserify-shim": {
"lodash": "global:_"
},
"browserify": {
"transform": ["browserify-shim"]
}
}
gulp.js
gulp.task('browserify', function() {
return browserify('./index.js')
.require('./index.js', {
expose: 'my-module'
})
.transform('browserify-shim', {
global: true
})
.bundle()
.pipe(source('bundle.js'))
.pipe(gulp.dest('./'));
});

There's an option to exclude files:
Usage: browserify [entry files] {OPTIONS}
[...]
--ignore, -i Replace a file with an empty stub. Files can be globs.
--exclude, -u Omit a file from the output bundle. Files can be globs.
https://github.com/substack/node-browserify#usage
And the corresponding exclude function:
b.exclude(file)
Prevent the module name or file at file from showing up in the output bundle.
If your code tries to require() that file it will throw unless you've provided another mechanism for loading it.
So you should try this:
return browserify()
.require('./index.js', {
expose: 'my-module'
})
.exclude('lodash.js')
.bundle();

I figured this out.
const nodeOnlyModule = eval('require')('module-name');
This way you can trick browserify.

Unit Testing Angular + Browserify + Gulp and Jasmine

I'm having an angular project bundled with browserify using Gulp. Here is the tree
|--app
|--src
--js
-main.js
-otherFiles.js
|--spec
--mainspec.js <-- jasmin spec file
|--public
--js
--main.js
I'm having a gulp file which takes my source, main.js file, and browserifies it along with a gulp-jasmine tasks
gulp.task('js', function() {
return gulp.src('src/js/main.js')
.pipe(browserify({}))
.pipe(gulp.dest('public/js'));
});
gulp.task('specs', function () {
return gulp.src('spec/*.js')
.pipe(jasmine());
});
Along with some watch tasks etc.
Now, in my mainspec.js file, angular is not recognized, considering my test code:
describe("An Angular App", function() {
it("should actually have angular defined", function() {
expect(angular).toBeDefined();
});
});
And I'm getting an ReferenceError: angular is not defined error on terminal. I tried to require('angular'); on the first line but with no luck, getting a new error ReferenceError: window is not defined. I know there is something wrong with the setup and the test file not being able to reach the browserified files, but I can't just figure out the solution.
Any ideas?
Thanks in advance.

You need to define all aspects in your config file
function getKarmaConfig(environment) {
return {
frameworks : ['jasmine'],
files : [
// Angular + translate specified for build order
environment + '/js/jquery.min.js',
environment + '/js/angular.js',
environment + '/js/angular-translate.min.js',
environment + '/js/**/*.js',
'bower_components/angular-mocks/angular-mocks.js',
'test/unit/**/*.js'
],
exclude : [
],
browsers : ['PhantomJS'],
reporters : ['dots', 'junit','coverage'],
junitReporter: {
outputFile: 'test-results.xml'
},
preprocessors : {
'prod/js/*.js': ['coverage']
},
coverageReporter:{
type: 'html',
dir: 'coverage'
}
};
};
and define a gulp test task like this
gulp.task('test', ['build_prod'], function () {
var testKarma = getKarmaConfig(environment);
testKarma.action = 'run';
testKarma.browsers = ['PhantomJS'];
return gulp.src('./fake')
.pipe(karma(testKarma));
});
You just need to define src perfectly as per your structure. This will work :)