I searched through the forums anything that help me and nothing is working... I'm trying to do a login on Phonegap using a AJAX call to a PHP file located in a remote server but the PHP file is not returning anything... I post my codes:
The AJAX call:
$.ajax({
type: "POST",
data: 'userMail='+user+'&userPassword='+password,
dataType : 'html',
url : "http://www.eega.nl/app/login.php",
crossDomain: true,
async: false,
success: function(data){
if(data!='error'){
window.localStorage["userId"] = data;
location.href = "schedule.html";
}else{
alert("failed login");
location.href = "index.html";
}
},
error: function(){
alert("error");
window.open('schedule.html');
}
});
The PHP file:
<?php
include 'connect.php';
header('Access-Control-Allow-Origin:*');
header('Access-Control-Allow-Methods: GET, PUT, POST, DELETE, OPTIONS, REQUEST');
header('Content-Type: application/json; charset=utf-8');
header('Access-Control-Max-Age: 3628800');
$data = array();
$userMail = $_POST["userMail"];
$userPassword = $_POST["userPassword"];
$cryptpass = md5($userPassword);
$sql = "SELECT tr_adr_id FROM elo_users WHERE email = '" . $userMail . "' AND crypt = '" . $cryptpass . "'";
//mysql_real_escape_string($userMail),
//mysql_real_escape_string($cryptpass));
$result = mysqli_query($sql);
//if($data = mysql_fetch_array($result)){
while($row = mysqli_fetch_array($result)) {
$data = $row['tr_adr_id'];
}
echo $data["tr_adr_id"];
mysqli_free_result($data);
mysqli_close();
?>
I tried to do the AJAX call with POST and GET and in the PHP file with the $_POST, $_GET and $_REQUEST and nothing of that worked for me...
Thank you in advance! I still working on that trying to figure out what is wrong in my code...
EDITED:
The index.html:
<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=320" user-scalable="no" />
<meta http-equiv="Content-type" content="text/html; charset=utf-8">
<link rel="stylesheet" href="css/bootstrap.min.css">
<link rel="stylesheet" href="css/bootstrap-theme.min.css">
<link rel="stylesheet" href="css/docs.min.css">
<link rel="stylesheet" href="css/jquery.mobile-1.4.3.min.css">
<link rel="stylesheet" href="css/general.css">
<script type="text/javascript" src="js/jquery-1.11.1.min.js"></script>
<script src="js/bootstrap.min.js"></script>
<script src="js/functions.js"></script>
<title>EegaApp</title>
<script type="text/javascript" charset="utf-8" src="cordova.js"></script>
</head>
<body>
<script type="text/javascript" src="js/jquery.mobile-1.4.3.min.js"></script>
<div id="eegaLogo">
<img class="bottom" src="images/eega_logo_loading.jpg"/>
<img class="top" src="images/eega_logo.jpg"/>
</div>
www.eega.nl
<!--*********Login form********-->
<form id="loginForm" class="form-signin" role="form" style="width:50%; text-align: center; margin-top: 55%; margin-left: 25%;" method="post">
<input id="userMail" name="userMail" class="form-control" type="email" autofocus="" required="" placeholder="Email"></input>
<input id="userPassword" name="userPassword" class="form-control" type="password" required="" placeholder="Password"></input>
<div>
<input type="checkbox" name="checkbox-0" id="checkbox-mini-0" class="custom" data-mini="true" />
<label for="checkbox-mini-0">Remember me</label>
</div>
<button type="submit" data-mini="true" onClick="login()">Login</button>
</form>
<!--*********End form*********-->
<!--THIS LINE IS JUST FOR TEST-->
schedule
<!--*********Footer*********-->
<div id="footer">
<script>
function openExternal(elem) {
window.open(elem.href, "_system");
return false; // Prevent execution of the default onClick handler
}
</script>
<a class="col-xs-4" href="http://9292.nl/#" target="_blank" onClick="javascript:return openExternal(this)"><img id="footer-icon" src="images/9292_icon.jpg" style="width: 60px; height: 60px;"/></a>
<a class="col-xs-4" ><img id="footer-icon" src="images/maps_icon.jpg" style="width: 60px; height: 60px;"/></a>
<a class="col-xs-4" ><img id="footer-icon" src="images/call_icon2.jpg" style="width: 60px; height: 60px;"/></a>
</div>
<!--********End footer*********-->
</body>
You are doing things a little difficult for yourself the way everything is laid out. Here are a few examples that will help you fix your code.
Notice how the data:{} is laid out. Notice how the success is laid out.
$.ajax({
type: "GET",
url: "../ajax.php",
dataType: "json",
data: {
type: "getLineComments",
saleId: $(this).attr('saleId'),
lineId: $(this).attr('lineId')
},
success: function (json) {
$content.empty();
$content.slideToggle(500, function () {
if(json.Row !== undefined && json.Row.length > 0)
{
for(var i=0;i < json.Row.length;i++)
{
var item = json.Row[i];
//console.log(item);
//console.log(item.REMARK_LIN);
$content.append("<li>" + item.REMARK_LIN + "</li>");
}
}
else
{
if(json.Row !== undefined)
$content.append("<li>" + json.Row.REMARK_LIN + "</li>");
else
$content.append("<li>No Comments</li>");
}
$header.text(function () {
//change text based on condition
return $content.is(":visible") ? "Collapse Line Remarks" : "Expand Line Remarks";
});
});
},
error: function(e)
{
console.log(e);
}
});
Also one thing that will help you quite a bit is using the php function json_encode - http://php.net/manual/en/function.json-encode.php
For example
echo json_encode(mysqli_fetch_array($result));
Related
Basically i find code on the internet to test and use it.
the problem is that when i reload the page, the data disappears.
what i want to happen is for the data or the value to just stay.
Thanks guys
Here is the code in index.html
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Pass Data to PHP using AJAX without Page Load</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script
src="https://code.jquery.com/jquery-2.2.4.js" integrity="sha256-iT6Q9iMJYuQiMWNd9lDyBUStIq/8PuOW33aOqmvFpqI=" crossorigin="anonymous"></script>
</head>
<body>
<div class="container">
<h2>Enter Some Data Pass to PHP File</h2>
<div class="row">
<div class="col-md-3">
<form>
<div class="form-group">
<input type="text" id="pass_data" class=" form-control">
<input type="button" class="btn btn-success" onclick="passData();" value="Set">
<p id="message"></p>
</div>
</form>
</div>
</div>
</div>
</body>
<script type="text/javascript">
function passData() {
var name = document.getElementById("pass_data").value;
var dataString = 'pass=' + name;
if (name == '') {
alert("Please Enter the Anything");
} else {
// AJAX code to submit form.
$.ajax({
type: "POST",
url: "post.php",
data: dataString,
cache: false,
success: function(data) {
$("#message").html(data);
},
error: function(err) {
alert(err);
}
});
}
return false;
}
</script>
</html>
and here is my php code
<?php
$pass=$_POST['pass'];
echo json_encode($pass);
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Pass Data to PHP using AJAX without Page Load</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script
src="https://code.jquery.com/jquery-2.2.4.js"
integrity="sha256-iT6Q9iMJYuQiMWNd9lDyBUStIq/8PuOW33aOqmvFpqI=" crossorigin="anonymous"></script>
</head>
<body>
<div class="container">
<h2>Enter Some Data Pass to PHP File</h2>
<div class="row">
<div class="col-md-3">
<form>
<div class="form-group">
<input type="text" id="pass_data" class=" form-control">
<input type="button" id="success" class="btn btn-success" value="Set">
<p id="message"></p>
</div>
</form>
</div>
</div>
</div>
</body>
<script type="text/javascript">
$("#success").click(function () {
var name = document.getElementById("pass_data").value;
var dataString = 'pass=' + name;
if (name == '') {
alert("Please Enter the Anything");
} else {
// AJAX code to submit form.
$.ajax({
type: "POST",
url: "post.php",
data: dataString,
cache: false,
success: function (data) {
$("#message").html(data);
localStorage.setItem("data",data);
},
error: function (err) {
alert(err);
}
});
}
return false;
})
$(document).ready(function () {
var someVarName = localStorage.getItem("data");
console.log(someVarName)
$("#message").html(someVarName);
});
</script>
</html>
First of all i changed your js code to use more jquery syntax, as you already have included it (i trigger the on click event on the script and i don't put it in in html). After that in order not to lose your variable after refresh on ajax success i pass the value of data to localstorage, and after refresh (on document ready) i retrieve it and display it in the label.
Of course every time you put a new value and display it, it over-writes the previous one, so after refresh you display the latest value put in your input field.
I am not sure I understand what you mean but...
Before this line:
<!DOCTYPE html>
enter
<?php session_start(); ?>
In this line add
<input type="text" id="pass_data" class=" form-control" value="<?php echo $_SESSION['VAL']; ?>">
and in your php file:
<?php session_start();
$pass=$_POST['pass'];
$_SESSION['VAL'] = $pass;
echo json_encode($pass);
?>
I am trying to send a string via ajax using the GET method but whenever that string contains some punctuation characters those characters do not appear when I use the echo in php.
For example if I send a string "sub + 12" the php will echo "sub 12"
If I send "&()*", php will echo an empty string.
Why does this happen?
Are there any special characters that the string cannot contain?
you encodeURIComponent(). this is demo code which you can check
something like this encodeURIComponent(yourtext)
first this html code . in text filed enter your text and check this output, this is onkeyup so enter text and check result
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>PHP, jQuery search demo</title>
<link rel="stylesheet" type="text/css" href="my.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$("input").keyup(function () {
$('#results').html('');
var searchString = $("#search_box").val();
var data = 'search_text=' + encodeURIComponent(searchString);
if (searchString) {
$.ajax({
type: "GET",
url: 'edit.php',
data: data,
dataType: 'text',
async: false,
cache: false,
success: function (result) {
$('#results').html(result);
//window.location.reload();
}
});
}
});
});
</script>
</head>
<body>
<div id="container">
<div style="margin:20px auto; text-align: center;">
<form method="post" action="do_search.php">
<input type="text" name="search" id="search_box" class='search_box'/>
<input type="submit" value="Search" class="search_button"/><br/>
</form>
</div>
<div>
<div id="searchresults">Search results :</div>
<ul id="results" class="update">
</ul>
</div>
</div>
</body>
</html>
then create edit.php file
<?php
$searchquery = $_GET['search_text'];
echo $searchquery;
?>
then check result . which is working
Output is
Search results :
&()*
Use encodeURI() before sending the request.
This question already has answers here:
PHP session variables not preserved with ajax
(6 answers)
Do AJAX requests retain PHP Session info?
(8 answers)
Set php session via ajax
(3 answers)
Closed 5 years ago.
I'm working with a simple login system with php/sql.
used it several weeks working on localhost, but now that the site is actually online, my login page doesn't work (only if i refresh the page)
working with session.
Are there any tips/things i can try to make it actually go to my index.php instead of manually refreshing the page? As i said it worked locally, nothing changed when going online.
LOGIN.JS
$(document).ready(function () {
"use strict";
$("#submit").click(function () {
var username = $("#myusername").val(), password = $("#mypassword").val();
if ((username === "") || (password === "")) {
$("#message").html("<div class=\"alert alert-danger alert-dismissable\"><button type=\"button\" class=\"close\" data-dismiss=\"alert\" aria-hidden=\"true\">×</button>Please enter a username and a password</div>");
} else {
$.ajax({
type: "POST",
url: "checklogin.php",
data: "myusername=" + username + "&mypassword=" + password,
dataType: 'JSON',
success: function (html) {
//console.log(html.response + ' ' + html.username);
if (html.response === 'true') {
windows.location.assign("http://kdlk.heijsgroep.nl/heijs/index.php");
window.location.reload(true);
return html.username;
} else {
$("#message").html(html.response);
}
},
error: function (textStatus, errorThrown) {
console.log(textStatus);
console.log(errorThrown);
},
beforeSend: function () {
$("#message").html("<p class='text-center'><img src='images/ajax-loader.gif'></p>");
}
});
}
return false;
});
});
main_login.php
<?php
session_start();
if (isset($_SESSION['username'])) {
header("location:../index.php");
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Login</title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<!-- Bootstrap -->
<link href="../css/bootstrap.css" rel="stylesheet" media="screen">
<link href="../css/main.css" rel="stylesheet" media="screen">
<link href="../style.css" rel="stylesheet" type="text/css">
</head>
<body>
<div class="container">
<form class="form-signin" name="form1" method="post" action="checklogin.php">
<h2 class="form-signin-heading">Please sign in</h2>
<input name="myusername" id="myusername" type="text" class="form-control" placeholder="Username" autofocus>
<input name="mypassword" id="mypassword" type="password" class="form-control" placeholder="Password">
<!-- The checkbox remember me is not implemented yet...
<label class="checkbox">
<input type="checkbox" value="remember-me"> Remember me
</label>
-->
<button name="Submit" id="submit" class="btn btn-lg btn-primary btn-block" type="submit">Sign in</button>
<div id="message"></div>
</form>
</div> <!-- /container -->
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="js/jquery-2.2.4.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script type="text/javascript" src="js/bootstrap.js"></script>
<!-- The AJAX login script -->
<script src="js/login.js"></script>
</body>
</html>
login header
<?php
//PUT THIS HEADER ON TOP OF EACH UNIQUE PAGE
session_start();
if (!isset($_SESSION['username'])) {
header("location:login/main_login.php");
}
?>
Basically I've got a AJAX Login page that is working and everything but when I successfully login I want it to redirect to a page without it reloading I'm not sure how its done as I am very new to langauge. Many thanks
index.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript" src="jquery.js"></script>
<link rel="stylesheet" href="styles.css" type="text/css" />
<title>Popup Login</title>
<script type="text/javascript">
$(document).ready(function(){
$("#login_a").click(function(){
$("#shadow").fadeIn("normal");
$("#login_form").fadeIn("normal");
$("#user_name").focus();
});
$("#cancel_hide").click(function(){
$("#login_form").fadeOut("normal");
$("#shadow").fadeOut();
});
$("#login").click(function(){
username=$("#user_name").val();
password=$("#password").val();
$.ajax({
type: "POST",
url: "login.php",
data: "name="+username+"&pwd="+password,
success: function(html){
if(html=='1')
{
$("#login_form").fadeOut("normal");
$("#shadow").fadeOut();
$("#profile").html("<a href='logout.php' id='logout'>Logout</a>");
}
else
{
$("#add_err").html("Wrong username or password");
}
},
beforeSend:function()
{
$("#add_err").html("Loading...")
}
});
return false;
});
});
</script>
</head>
<body>
<?php session_start(); ?>
<div id="profile">
<?php if(isset($_SESSION['user_name'])){
?>
<a href='logout.php' id='logout'>Logout</a>
<?php }else {?>
<a id="login_a" href="#">login</a>
<?php } ?>
</div>
<div id="login_form">
<div class="err" id="add_err"></div>
<form action="login.php">
<label>User Name:</label>
<input type="text" id="user_name" name="user_name" />
<label>Password:</label>
<input type="password" id="password" name="password" />
<label></label><br/>
<input type="submit" id="login" value="Login" />
<input type="button" id="cancel_hide" value="Cancel" />
</form>
</div>
<div id="shadow" class="popup"></div>
</body>
</html>
login.php
<?php
session_start();
$username = $_POST['name'];
$password = $_POST['pwd'];
$mysqli=mysqli_connect('');
$query = "SELECT * FROM user WHERE username='$username' AND password='$password'";
$result = mysqli_query($mysqli,$query)or die(mysqli_error());
$num_row = mysqli_num_rows($result);
$row=mysqli_fetch_array($result);
if( $num_row >=1 ) {
echo '1';
$_SESSION['user_name']=$row['username'];
}
else{
echo 'false';
}
?>
When I successfully login I want it to redirect to a page without it reloading
As long as the page to be redirected to is on the same domain, or you can set CORS headers properly, and you can deal with relative links, then in your success callback you can replace the entire page's HTML with that of the new page.
You can start another ajax call for your new page, and use document.write() to obliterate the existing HTML like so:
...
success: function(html){
if(html=='1') {
$("#login_form").fadeOut("normal");
$("#shadow").fadeOut(400, function(){
// Completely replace the page's HTML
$.ajax({
type: 'GET',
url: 'http://example.com/logged-in',
async: false, // You want this synchronous
success: function(data) {
// This code block replaces your current page seamlessly
document.open();
document.write(data);
document.close();
},
error: function(e){
alert(e.message);
}
});
});
}
...
Here is a demo:
$("#bye").fadeOut(1400, function(){
$.ajax({
type: 'GET',
url: 'http://enable-cors.org/',
async: false,
success: function(data) {
// This is a quick-n-dirty hack
// to get the relative links working for the demo
var base_href = '<base href="http://enable-cors.org/">';
document.open();
document.write(base_href + data);
document.close();
},
error: function(e){
alert(e.message);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div id="bye"><h1>Logged in Successfully</h1></div>
Firstly I apologize for posting another one of these questions, but I've dove through a ton of SO questions related to this topic and haven't be able to figure out my problem. I'm new to PHP and an amature at best using Jquery mobile and the like.
I'm attempting to post to a .php file and get a response back. Eventually this will evolve into a database posting yada yada. For now, I can't seem to get my response back from my post. I'm running Xampp to host the php, Jquery Mobile is being used in other functions so it does work properly,
HTML:
<form>
<p>Username: </p><input type="text" id="username" value="" />
<p>Password: </p><input type="text" id="password" value="" />
<input type="button" onclick="submitLogIn()" value="Log In" />
</form>
Javascript:
function submitLogIn() {
alert("Submitting: " + $('#username').val() + $('#password').val());
var dbURL = "http://localhost/testerpage.php";
$.post(dbURL, {
//These are the names of the form values
Username: $('#username').val(),
Password: $('#password').val()
}, function (data,status) {
alert(status); //Won't fire
alert(html); //Won't fire
var response = html;
alert(response); //Won't fire
if (response == "Success")
{
alert("Success!"); //Won't fire
//testlog.innerHTML = "Success";
}
else
{
alert("Failure!");//Won't fire
//testlog.innerHTML = "Failure";
}
});
alert("Finished"); //Fires
};
PHP
<?php
// VARS
$Username=$_GET["Username"]; //Also tried _POST
$Password=$_GET["Password"]; //Also tried _POST
//VALIDATION
if(
$Username=="" ||
$Password==""
) {
echo "Error";
} else {
echo "Success";
}
?>
My best guess is that something is wrong with the .php because all of the questions I've looked at seem to confirm my JavaScript is right. All of my alerts fire except the ones in the call back function. The username and password are also correctly being set so that isn't the problem. I tried using _POST and _GET in my .php, I originally was using _POST because I was posting data but I was following this question: (Phonegap contact form not working over PHP) and it did the opposite so I changed it. No difference. My .php is actually hosted for sure (I can navigate to it without an error). I also tried using the $.ajax function but had the same issues.
Thanks in advance.
EDIT: Added more of the HTML (all that should be relevant) per request, can't add it all as it is too long.
<html>
<head>
<meta charset="utf-8" />
<meta name="format-detection" content="telephone=no" />
<meta name="msapplication-tap-highlight" content="no" />
<!-- WARNING: for iOS 7, remove the width=device-width and height=device-height attributes. See https://issues.apache.org/jira/browse/CB-4323 -->
<meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width, height=device-height, target-densitydpi=device-dpi" />
<!-- Stylesheets -->
<link rel="stylesheet" href="css/snctfy2/snctfy2.css" />
<link rel="stylesheet" href="css/snctfy2/jquery.mobile.icons.min.css" />
<link rel="stylesheet" type="text/css" href="css/index.css" />
<link href="jquerymobile/jquery.mobile.structure-1.4.2.min.css" rel="stylesheet" type="text/css" /> <!-- Add .structure after theme-->
<!-- Jquery core -->
<script src="js/jquery.js" type="text/javascript"></script>
<!-- Jquery mobile library file -->
<script src="jquerymobile/jquery.mobile-1.4.2.min.js" type="text/javascript"></script>
<!-- DateBox -->
<link rel="stylesheet" type="text/css" href="css/jqm-datebox.css" />
<script type="text/javascript" src="js/datebox/jqm-datebox.core.js"></script>
<script type="text/javascript" src="js/datebox/jqm-datebox.mode.calbox.js"></script>
<script type="text/javascript" src="js/datebox/jqm-datebox.mode.datebox.js"></script>
<script type="text/javascript" src="js/datebox/jquery.mobile.datebox.i18n.en_US.utf8.js"></script>
<!-- Scripts (pre-load)-->
<script src="js/scripts.js" type="text/javascript"></script>
<!-- CSS Override -->
<link rel="stylesheet" type="text/css" href="css/override.css" />
<title>SNCTFY</title>
</head>
<body>
<!--there is some more <div> tags here unrelated-->
<!--------------------------------------------------------Login Page---------------------
-------------------------------------------->
<div data-role="page" id="login" data-theme="a" class="bPage">
<div data-role="content">
<form>
<p>Username: </p><input type="text" id="username" value="" />
<p>Password: </p><input type="text" id="password" value="" />
<input type="button" onclick="submitLogIn()" value="Log In" />
</form>
Register
<button onclick="showAlert()">Test</button>
<p id="testlog">Results</p>
</div>
</div>
<!-- more <div> pages -->
<!-- Scripts (post-load)-->
<script type="text/javascript" src="phonegap.js"></script>
<script type="text/javascript" src="cordova.js"></script>
<script type="text/javascript" src="js/index.js"></script>
<script type="text/javascript">
app.initialize();
</script>
</body>
</html>
EDIT2: Changed JavaScript to one of the answers to test
function submitLogIn() {
alert("Submitting: " + $('#username').val() + $('#password').val());
var username = $('#username').val();
var password = $('#password').val();
$.ajax({
type: "POST",
url: "http://localhost/testerpage.php",
data: { "Username": username, "Password": password },
success: function (data) {
if (data) {
alert(data);
}
else {
alert('Successfully not posted.');
}
}
});
};
Just try jquery Ajax
<body>
<form>
<p>Username: </p><input type="text" id="username" value="" />
<p>Password: </p><input type="text" id="password" value="" />
<input type="button" onclick="submitLogIn()" value="Log In" />
</form>
<script>
function submitLogIn() {
alert("Submitting: " + $('#username').val() + $('#password').val());
var username =$('#username').val();
var password = $('#password').val();
$.ajax({
type: "POST",
url: "http://localhost/testerpage.php",
data:{"Username":username,"Password":password},
success: function(data) {
if (data) {
alert(data);
}
else {
alert('Successfully not posted.');
}
}
});
}
</script>
</body>
</html>
in PHP
<?php
$Username=$_POST["Username"]; //Also tried _POST
$Password=$_POST["Password"]; //Also tried _POST
//VALIDATION
if(
$Username=="" ||
$Password==""
) {
echo "Error";
} else {
echo "Success";
}
?>
Try this:
function submitLogIn() {
alert("Submitting: " + $('#username').val() + $('#password').val());
var dbURL = "http://localhost/testerpage.php";
//These are the names of the form values
var username = $('#username').val();
var password = $('#password').val();
$.ajax({
url: dbURL,
type:'post',
data:'&username='+username+'&pass='+password,
success:function(response){
alert(response);
}
});
};
<?php
// VARS
$Username=$_POST["username"]; //Also tried _POST
$Password=$_POST["pass"]; //Also tried _POST
//VALIDATION
if(
$Username=="" ||
$Password==""
) {
echo "Error";
} else {
echo "Success";
}
?>
try this code
script
<script>
function submitLogIn() {
alert("Submitting: " + $('#username').val() + $('#password').val());
var dbURL = "http://localhost/testerpage.php";
$.post(dbURL, {
//These are the names of the form values
Username: $('#username').val(),
Password: $('#password').val()
}, function (data,status) {
if (data == "Success")
{
alert("Success!"); //Won't fire
//testlog.innerHTML = "Success";
}
else
{
alert("Failure!");//Won't fire
//testlog.innerHTML = "Failure";
}
});
alert("Finished"); //Fires
};
</script>
PHP
// VARS
$Username=$_POST["Username"]; //Also tried _POST
$Password=$_POST["Password"]; //Also tried _POST
//VALIDATION
if(
$Username=="" ||
$Password==""
) {
echo "Error";
} else {
echo "Success";
}