Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 8 years ago.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Improve this question
I am working on a javascript quiz programme , and i have return a function to check what difficulty level the user wants . below is the code and the jsfiddle :
function getdifficulty(){
var j = 0;
var level = prompt('what level would you like 1. easy 2. intermediate 3.hard' , '')
if(level == easy){
j = questionseasy[0];
}
else if(level == intermediate){
j = questionseasyenuf[0];
}
else{
j = questionshard[0];
}
alert("you did it");
}
getdifficulty();
Jsfiddle here
now the problem is the the alert is not showing up ? whats the problem with this short piece of code ? (In the real programme though i will not use an alert but return statement , i even tried using document.write or console.log but none worked) .
prompt() returns a string. You need to make your comparisons strings by encapsulating them in double quotes (").
function getdifficulty(){
var level = prompt('what level would you like 1. easy 2. intermediate 3.hard' , '')
if(level == "easy"){
alert("easy");
}
else if(level == "intermediate"){
alert("intermediate");
}
else{
alert("hard");
}
}
getdifficulty();
JSFiddle
Also, in the implementation you have provided in your post, questionseasy, questionseasyenuf, and questionshard will not be defined. You must bring them into the scope of the function before you can start using them.
questionseasy is undefined. You can trace javascript as it runs in your browser console and see this.
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
Im trying to make a little program in js that overturns the text you typed in. The code runs fine, but the for loop gets completely ignored, it doesnt do even one block of code from inside of it.
document.getElementById("StartButtonText").addEventListener("click",function(){
var text_value = document.getElementById('TextValue').value;
console.log(text_value);
var text_length = text_value.length;
console.log(text_length);
var final_text;
var order;
for (order = 1; order >= text_length; order ++) {
final_text[order] = text_value[text_length - order + 1];
console.log('for loop log ',order);
final_text = final_text + final_text[poradie];
}
console.log('after loop log ',order);
document.getElementById("TextTurningResult").innerHTML = final_text;
console.log(final_text);
});
Any ideas why it doesnt run?
Your loop will run as long as order is greater or equals than text_length.
I guess you wanted to write:
for (order = 0; order < text_length; order ++) { ... }
You should change the condition in your for loop to
for(order = 1; order <= text_length; order++){
...
}
In your case, the condition is false at the first iteration only.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 3 years ago.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Improve this question
I am new to programming and JavaScript so please bear with me if its a stupid question.
I initialised two variables
let firstName = "blah";
let FirstName = "bleh";
When i write a below if statement i expected the output to be "right on" since the variable names are different (case-sensitive), but i get "boink". Could anyone kindly explain whats happening here?
if (firstName = FirstName) {
console.log('boink')
} else {
console.log('right on')
}
Could anyone kindly explain whats happening here
Actually firstName = FirstName is an Assignment expression and it will return the value on the right handside which is "bleh" which is truthy value. So the first block is executed
You are using assignment operator you need to use comparison operator(== or ===)
let firstName = "blah";
let FirstName = "bleh";
if (firstName === FirstName) {
console.log('boink')
}
else {
console.log('right on')
}
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
<body>
<h1>Operadores aritméticos</h1>
<h3>+ Adición (102+103)=</h3><p id="suma1"></p>
<h3>- Substracción</h3><p id="resta1"></p>
<h3>* Multiplicación</h3><p id="multi1"></p>
<h3>/ División</h3><p id="div1"></p>
<h3>% Módulo</h3><p id="mod1"></p>
<script>
var suma = (102+103);
var resta = (36-20);
var multiplicación = (27*30);
var división = (900/30);
var módulo = (106%3);
document.getElementById("suma1").innerHTML = suma;
document.getElementById("resta1")innerHTML = resta;
document.getElementById("multi1")innerHTML = multiplicación;
document.getElementById("div1")innerHTML = división;
document.getElementById("mod1")innerHTML = módulo;
</script>
Hello guys, I have a problem, im pretty new at this (programming with HTML, Js, etc.).The issue is that when I try to make my Js variables appear on HTML (with document.getElementById), they do not appear. Nevertheless, if erase every document.getElementById except the one containing "suma1", the browser displays me the result of the sum (205), but if I add even one of them, the browser doesn´t display anything.
I hope I was clear with my problem, it seems very simple but hard to explain.
Any suggestions?
Thanks in advance
The reason you're not seeing anything when you add the statements to populate resta1, multi1, div1, and mod1 is probably because they all have a syntax error. This is likely causing even the first statement (suma1, which is syntactically valid) not to work.
Valid Statement
The 1 statement that is working is document.getElementById("suma1").innerHTML = suma;
Invalid statements
All the other statements follow this pattern:
document.getElementById("id")innerHtml = variable;
Note that you're missing the . between getElementById("id") and innerHtml. If you add the missing . then it should all work as expected.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 7 years ago.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Improve this question
What is right syntax to check values based on if condition using && and ! operator?
I am getting an error and am confused by !.
main.js
if($scope.sysRecomm === 'High' && !($scope.busDecision==='21')){
$scope.disableSubmitButton = true;
}
if($scope.sysRecomm === 'High' && $scope.busDecision !== '21'){
$scope.disableSubmitButton = true;
}
use like this:
if($scope.sysRecomm === 'High' && $scope.busDecision !='21'){
&& requires both side of the operator to hold TRUE to return true value of entire expression.
For example:
if(X && Y) {
// this block is executed only if X & Y are true
}
Coming to negation operator ! , it negative the truth value of whatever expression it is attached to:
For example if negation operator is used inside a if block:
if(!X){
// executed only when X is false.
}
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
I'm working with this, but the issue is that only the first if ever functions correctly. If I change the order, each if statement works on its own, but the logic where if the first is false, then check the second, and so on isn't working. What am I missing here?
$("#search_button").click(function(){
var table = $('#main_index').DataTable();
var search_term = $("#second_select2 option:selected").text();
var first_s = $("#first_select2 option:selected").text();
if (first_s = 'District'){
table.columns(1).search(search_term).draw();
}
else if (first_s = 'Territory'){
table.columns(2).search(search_term).draw();
}
else if (first_s = 'Region'){
table.columns(0).search(search_term).draw();
}
else {
console.log('error');
}
});
If I console.log the search_term and first_s variables, I can see them changing and correctly working. And, as I said, without the if/else statements each of these works on its own.
In all your comparisons, you need to replace = by ===
You are using the assignment operator (=) in your comparisons. you should be using the identity operator: ===.
if (first_s = 'District'){
needs to be
if (first_s === 'District'){
as do the rest of the checks.