Develop Reference

Webpage displays incorrectly on different resolutions due to incorrect css

I'm having some issues with a webpage of mine, mainly on mobile devices but it also affects desktop devices too, I would be willing to award a bounty (as and when stackoverflow allows me) to whomever can help with these problems
HTML: http://pastebin.com/raw.php?i=bbFsMcwT
CSS: http://pastebin.com/raw.php?i=SGMwt3cs
JSFiddle: http://jsfiddle.net/D8SJD/
Issue 1 - Left/Right Scroll Image Buttons
Currently my left and right scroll image buttons are done in html using onmouseover and onmouseout I want to be able to convert them into css based "buttons"
Issue 2 - Dynamic Resolution(s)
The header and footers aren't dynamic with different resolutions for example, I created the page designed on a 1680x1050 monitor which looks like: Desktop 1680x1050 however making the window smaller it looks like: Desktop Small Window
On a Nexus 4 mobile phone on default zoom it looks like: Mobile Original Zoom
On a Nexus 4 mobile phone zoomed out to as far as it can go it looks like: Mobile Max Distance
On a Nexus 4 zoomed out and scrolled to the bottom (so that the browsers URL bar disappears) it looks like: Zoomed out without URL bar (the footer of the actual webpage vanishes)
On a Nexus 4 zoomed out and scrolled just off from the bottom (so that the browsers URL bar is visible) it looks like: Zoomed out with URL bar (the footer returns)
.
The placeholder image and arrows are supposed to be in the center of the footer and headers and should shrink in accordance to the screen resolution.
Mobile device default zoom (if possible) needs to be decreased so they can see more and on getting smaller (if possible) if it gets close to Mobile Original Zoom then the Up to Top, Down to Key, placeholder logos should vanish...
Please see images at bottom of this post
For the mobile devices I tried things like below just for testing but none of them worked...
#media (max-width: 640px) {
#header > a img {
display: none;
}
}
EDIT 14/11/2013 # 01:58GMT
On a 1920x1080 screen it looks kind of okay although there is a big gap between the text and the placeholder image as seen below:
On a 1680x1050 screen it looks roughly how it should take note of where "Semi" is located and compare to the 1920x1080 image from above.
On a 600x600 screen it appears as follows, which as you can see there is a big gap between the placeholder and the left arrow but on the right arrow there is no gap and infact it overflows, as for the text it too is too far to the right.

Type
#media screen and (max-width:640px) {
/* Your specific styles go here */
}
and dont forget to add
<meta name="viewport" content="width=device-width,initial-scale=1.0">
Hope that helps :-)

I see a border around your links, remove from your links:
a{
border:none ;
}
for first issue you can do it with CSS, just remove <img> tag inside <a> tag like this:
<div class="footleft">
<a class="def" href="javascript: void(0);">
</a>
</div>
create image buttons like this:
then set background to <a> tag like this:
#footer .footleft a {
width: 100px;
height: 47px;
display: block;
background: url(path/to/leftarrow.png);
background-position: 0 0;
}
#footer .footright a{
width: 100px;
height: 47px;
display: block;
background: url(path/to/rightarrow.png);
background-position: 0 0;
}
#footer .footleft a:hover , #footer .footright a:hover{
background-position: 0 100%;
}
second issue, I think if you remove position:absolute; from #header .headimage and #footer .footimage it will be okay.
and if your want to centerize headmid and footmid and footmidtwo you have two choices,
First: set fixed width to them and use CSS like this:
#footer .footmid {
top: 50%;
left: 50%;
position: absolute;
font-size: 15px;
width: 292px;
margin-left: -146px;
}
#footer .footmidtwo {
top: 70%;
left: 50%;
position: absolute;
font-size: 15px;
width: 126px;
margin-left: -63px;
}
#header .headmid {
top: 60%;
left: 50%;
position: absolute;
font-size: 15px;
width: 302px;
margin-left: -151px;
}
Second: if you need to have dynamic width you can use this CSS and JQuery:
CSS:
#header .headmid {
top: 60%;
left: 50%;
position: absolute;
font-size: 15px;
}
#footer .footmid {
top: 50%;
left: 50%;
position: absolute;
font-size: 15px;
}
#footer .footmidtwo {
top: 70%;
left: 50%;
position: absolute;
font-size: 15px;
}
JQuery:
var $widthhead = $(".headmid").width();
var $widthfoot = $(".footmid").width();
var $widthfoot2 = $(".footmidtwo").width();
$(".headmid").css("margin-left",$widthhead/2*(-1));
$(".footmid").css("margin-left",$widthfoot/2*(-1));
$(".footmidtwo").css("margin-left",$widthfoot2/2*(-1));
jsFiddle is here

Okay I've tried to filter out all of the irrelevant code for this solution.
See the solution here.
Most of the time, it is best to use relative positioning to fit elements absolutely inside of another element. In your case, with three different strings to fit in a 300x80 window, it's a bit crowded. I tried to place things in a logical position to demonstrate.
By placing a container in the footimage div with relative position, you can then place every element inside the footimage div absolutely relavtive to the footimage div, rather than to the entire page.
For example, what you had:
#footer .footmid
{
position: absolute;
top: 50%;
left: 50%;
}
Will place the div of class footmid at a position 50% of the page height from the top of the page and 50% of the page width from the left of the page:
This will work if every user that visits your page has the exact same resolution, however it causes problems when the don't. Obviously, this isn't a perfect world, so different resolutions will visit your page.
What you can do is use relative positioning!
Basically I tell CSS that instead of moving 50% from the top and left of the window, move 50% from the top and left of the nearest parent element with relative positioning:
You can modify the bottom, left, and right attributes of my fiddle to move the footmid elements within the relative element .footimageContainer that is the same size and in the same position as the .footimage.
As far as your arrows, I wasn't quite sure what you were trying to accomplish; your question was pretty vague, so I simply made them fade out slightly when you mouseover them. Any mouseover/out events can be handled using CSS psuedo-elements.
.element //Native and mouseout
{}
.element:hover //onmouseover
{}
Remember that if you use pseudo-elements, you have to specify the attribute that will be changing in both the native and :hover rules.
.element
{color:red;}
.element
{color:black;}
If you have any additional questions on the arrows, let me know and I'll revise my answer.

http://jsfiddle.net/D8SJD/4/
Instead of using absolute positioning, you can just take advantage of the text-align center and images and text will center automatically.
If you want offset from center, try position:relative, and top, left, right etc and it will move relative to it's central position.
Elements that are display:inline; or display:inline-block; will align according to parents text-align property, in this case text-align:center.
#footer .footimage {
display:inline;
position:relative;
top:-10px;
}
#footer .footmid {
top: 50%;
width:100%;
position: absolute;
font-size: 15px;
}
#footer .footmidtwo {
top: 70%;
width:100%;
position: absolute;
font-size: 15px;
}

As per issue 2, i could be wrong but when targeting the image through the structure of the site
i.e.
headImg a img{...}
The style wouldn't work. But if you add classes to the images the style will work; the case could be that there are some unclosed divs or elements messing with the architecture.
<div class="headimage">
<img class="placeholder" src="http://placehold.it/300x80"/>
</div>
#media screen and (max-width: 640px) {
.placeholder {
display: none;
}
}
JsFiddle here - http://jsfiddle.net/Q5bEb/

Creating a cross on an image inside an HTML file

I have an image inside my page. After some javascript trigger event I want a cross appear on the image. Image will still be visible but cross will be on top.
What is the proper alternatives for this?
(I have similar question here that used HTML5 canvas)

I would create a wrapper for the both the image and the cross, and have them absolutely positioned within the wrapper. The wrapper itself would be fluid within the DOM, but the image and cross would be absolutely positioned so that the cross appears on top of the image. This can be done by setting the wrapper's position property to relative and using absolute positioning on its children.
As for the cross, I would use an image. This way you can set height and width to 100%, so that it will stretch with the wrapper. To control the sizing you would set width/height on the wrapper element, not the images themselves.
HTML
<div class="wrapper">
<img class="img" src="actual-image.jpg" />
<img class="cross-img" src="cross-image.jpg" />
</div>
CSS
.wrapper {
position:relative;
width: 150px;
height: 150px;
}
.img, .cross-img {
position: absolute;
top: 0px;
left: 0px;
width: 100%;
height: 100%;
}
.cross-img {
opacity: 0.5;
}
It's then trivial to show or hide the cross. Here's a jquery snippet:
$('.cross-img').hide();
Here is a jsfiddle demonstrating this: http://jsfiddle.net/J69qR/

Transparent PNG Reacting to Sites Image Sliders and Content

I just stumbled across this guys site: http://mantia.me/
He has an awesome logo that reacts to the content the site is currently showing, if you wait on his homepage the logo changes with the slide show of images. I was wondering if anyone knows how to replicate the effect. I'm guessing it's a transparent png with a rotating master background then the site is layered on top, but I'm probably wrong.
Any guesses on how to make something similiar?
Images:

It's really simple what he has. Like you mention it's a transparent PNG that matches the given background ( in this case white ) and places it on top of it with z-index. The rest is just jQuery with fadeIn and fadeOut images.
You can view the png on top of the image transitions.
So basically you just need a div with position:relative set the width the height of it; then add another div inside it which has the jQuery Slideshow (check this out: http://medienfreunde.com/lab/innerfade/), set it a z-index:0 Then add another div (which will go on top of the slider) and add it a background with z-index to something higher than 0 and you're good to go.

Here is how he does it:
HTML
<div id="content">
<div id="feature"></div>
<div id="navigation"></div>
</div>
CSS
#content {
position: relative;
width: 800px;
margin: 64px auto;
font: normal 13px/16px "myriad-pro-1","myriad-pro-2", sans-serif;
color: #404040;
}
#navigation{
position: absolute;
z-index: 1000;
top: 0;
left: 0;
width: 800px;
height: 46px;
background: transparent
url(http://mantia.me/wp- content/themes/minimalouie/img/nav.png)
no-repeat top left;
}
#feature {
width: 800px;
height: 466px;
overflow: hidden;
background-color: aqua;
}
And then he just adds an img element to #feature.
<div id="feature">
<img src="http://mantia.me/images/supermariobros_large.jpg"
alt="Super Mario Bros.">
</div>
See fiddle.

Best way to size an element to the size of another element

I am using an old CSS trick to get a semi-transparent background for some content, without the content appearing semi-transparent. Here is the HMTL:
<div id="frame">
<div id="opacityFrame">
</div>
<div id="contentFrame">
<div>
<!-- Main Site Content Here -->
</div>
</div>
</div>
Here is the corresponding CSS:
#frame
{
width: 90%;
margin: auto;
position: relative;
z-index: 0;
}
#opacityFrame
{
background: #00ff00;
opacity: .15;
top: 0;
left: 0;
position: absolute;
width: 100%;
height: 100%;
z-index: 1;
}
#contentFrame
{
top: 0;
left: 0;
position: absolute;
height: 100%;
width: 100%;
z-index: 1;
}
My problem is that because #frame is position: relative, it's height does not dynamically expand with its content. Both #opacityFrame and #contentFrame are set to 100% height and width and they appropriately expand to fill #frame which is great. The issue is that I need #frame's height to grow with the contents of the child DIV of #contentFrame because that DIV's height dynamically adjusts with the content placed in it.
I ended up having to create a jQuery function:
function resizeFrame()
{
$('#frame').height($('#contentFrame > div').height());
}
NOTE: The reason there is a child DIV of #contentFrame is because #contentFrame's height always reads as zero for some weird reason. I'm assuming it has to do with its position being absolute.
This code works great and accurately resizes #frame's height to the height of the child DIV of #contentFrame. However, I do a lot of ajax that changes the content within that DIV. One solution would be to call resizeFrame() with EVERY ajax event but it just seems so tedious. Is there an event or something I can tie to that would execute this function without my explicitly having to call it? I tried the following events but they didn't seem to work; maybe I did them wrong.
$('#subFrame > div').resize()
$('#subFrame > div').change()
Neither of these seemed to fire when the contents of the child DIV were modified. Maybe I'm going about this the wrong way? I do not want to use transparent images for the background.

Try taking position: absolute off of the contentFrame but leaving it on the opacityFrame. That should cause it's parent to resize, and the opacityFrame to still overlay everything.

do you have to use opacity? If it's a solid color, consider RGBA or if it's not solid, consider a semi-transparent PNG. That way you can nest them.

auto-resize images in posts with link to image URL?

This will be used in my community website (forum, articles) where some users post very large image.
I can auto-resize the images using below codes
#post img {
max-height: 1000px;
max-width: 700px;
}
But one more, I want (on every resized image) a link created to that image URL. So when visitor click the link, they can see the image actual size.

Sure, not a problem. You can use position: absolute to move a link up over the image:
HTML
<div class="img">
<img src="your-img.jpg"/>
View Full Sized
</div>
CSS
#post .img {
position: relative;
}
#post img {
max-height: 1000px;
max-width: 700px;
position: relative;
z-index: 1;
}
#post a.full-size {
position: absolute;
z-index: 2;
/* Change this to move the link around */
top: 0px;
left: 0px;
}
The reason you need the extra <div class="img"> is so there's a relatively positioned parent for the absolutely positioned link. This causes the link to use its parent as its coordinate system, rather than the document.

You can do this simply with HTML:
<a href='image.jpg'><img src='image.jpg' alt='image'></a>
When the user clicks on the image, it will take them to the original full-sized image.