I have this problem on how I could automatically update my webpage without refreshing. Could someone suggest and explain to me what would be the best way to solve my problem? Thanks in advance
add.php file
In this php file, I will just ask for the name of the user.
<form id="form1" name="form1" method="post" action="save.php">
<input type="text" name="firstname" id="firstname"/>
<input type="text" name="lastname" id="lastname"/>
<input type="submit" name="add" id="add" value="add"/>
</form>
save.php In this file, I will just save the value into the database.
$firstname=isset($_POST['firstname'])? $_POST['firstname'] : '';
$lastname=isset($_POST['lastname'])? $_POST['lastname'] : '';
$sql="Insert into student (sno,firstname,lastname) values ('','$firstname','$lastname')";
$sql=$db->prepare($sql);
$sql->execute();
studentlist.php In this file, i want to display the name I enter
$sql="Select firstname, lastname from student";
$sql=$db->prepare($sql);
$sql->execute();
$output="The List of students <br></br>";
while($result=$sql->fetch(PDO::FETCH_ASSOC))
{
$output.="".$result['firstname']." ".$result['lastname']."<br></br>";
}
Problem
When the two pages is open, I need to refresh the studentlist.php before i can see the recently added data.
thanks :D
You'll want to use ajax and jquery. Something like this should work:
add.php
add to the head of the document:
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){//loads the information when the page loads
var saveThenLoad = {
url: "save.php",//the file sending data to
type: 'POST',//sends the form data in a post to save.php
dataType: 'json',
success : function(j) {
if(j.error = 0){
$("#student_info").html(j.info);//this will update the div below with the returned information
} else {
$("#student_info").html(j.msg);//this will update the div below with the returned information
}
}
}
//grabs the save.submit call and sends to the ajaxSubmit saveThenLoad variable
$("#save").submit(function() {
$(this).ajaxSubmit(saveThenLoad);
return false;
});
//grabs the submit event from the form and tells it where to go. In this case it sends to #save.submit above to call the ajaxSubmit function
$("#add").click(function() {
$("#save").submit();
});
});
</script>
<!-- put this in the body of the page. It will wait for the jquery call to fill the data-->
<div id="student_info">
</div>
I would combine save and studentlist into one file like this:
$return['error']=0;
$return['msg']='';
$firstname=isset($_POST['firstname'])? $_POST['firstname'] : '';
$lastname=isset($_POST['lastname'])? $_POST['lastname'] : '';
$sql="Insert into student (sno,firstname,lastname) values ('','$firstname','$lastname')";
$sql=$db->prepare($sql);
if(!$sql->execute()){
$return['error']=1;
$return['msg']='Error saving data';
}
$sql="Select firstname, lastname from student";
$sql=$db->prepare($sql);
if(!$sql->execute()){
$return['error']=1;
$return['msg']='Error retrieving data';
}
$output="The List of students <br></br>";
while($result=$sql->fetch(PDO::FETCH_ASSOC))
{
$output.="".$result['firstname']." ".$result['lastname']."<br></br>";
}
$return['$output'];
echo json_encode($return);
Does this need to be in three separate files? At the very least, could you combine add.php and studentlist.php? If so, then jQuery is probably the way to go. You might also want to use some html tags that would make it easier to dynamically add elements to the DOM.
Here's the combined files:
<form id="form1" name="form1">
<input type="text" name="firstname" id="firstname"/>
<input type="text" name="lastname" id="lastname"/>
<input type="submit" name="add" id="add" value="add"/>
</form>
The List of students <br></br>
<ul id="student-list">
<?php
//I assume you're connecting to the db somehow here
$sql="Select firstname, lastname from student";
$sql=$db->prepare($sql);
$sql->execute();
while($result=$sql->fetch(PDO::FETCH_NUM)) //this might be easier to output than an associative array
{
//Returns will make your page easier to debug
print "<li>" . implode(" ", $result) . "</li>\n";
}
?>
</ul>
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script>
$(function(){
$('#form1').submit(function(event){
event.preventDefault();
//submit the form values
var firstname = $('#firstname').val();
var lastname = $('#lastname').val();
//post them
$.post( "test.php", { firstname: firstname, lastname: lastname })
.done( function(data) {
//add those values to the end of the list you printed above
$("<li>" + firstname + ' ' + lastname + "</li>").appendTo('#student-list');
});
});
});
</script>
You might want to do some testing in in the $.post call above to make sure it was handled properly. Read more about that in the docs.
If you really need three files, then you'll might need to use ajax to do some sort of polling on studentlist.php using setTimeout to see if you have any new items.
The cheap-way is using a meta-refresh to refresh your page (or use JavaScript setInterval and ajax).
The more expensive way is having a Realtime JavaScript application. Look at Socket.IO or something like that.
Related
Okay, this question was closed for not being clear enough, so I'm going to completely re-write it in as clear a form as I can...
Project: Room Booking System
Required Function: Check the database for existing bookings matching a criteria, return the result of 'COUNT' SQL query to a textbox which another function then looks to.
The values which need to be inserted into the COUNT criteria are as follows:
<h4>Date:</h4>
<input required type="text" name = "datebox" id = "datebox" ><br/>
<h4>Timeslot:</h4>
<input required type="text" name = "timebox" id = "timebox" ><br/>
<h4>Location:</h4>
<input required type="text" name = "roombox" id = "roombox" ><br/>
<h4>Person:</h4>
<input required type="text" name = "bookerbox" id = "bookerbox" ><br/>
</br>
Problem: I have a functioning php script which counts the number of rows in the database matching a criteria, which will then return the result to a textbox (main function sorted) when set up in a test directory with nothing else on the page. However, when I embed this php into an existing page (the new booking page) it doesn't work when the 'Check Availability' button is clicked. Instead, it reloads the page (as php does) which is not useful when users have already input their data for checking (and would need to re-enter it). I've Googled and have found that I need to use AJAX to run the php function in the background and then return the result to the textbox on the current page. I have never ever used AJAX and are only new to php, js etc. as it is, so I have no idea what I'm doing
How can you help: I need help in converting my existing code into a working solution to the above problem, probably using a combination of AJAX, PHP and JS functions.
Code:
PHP COUNT CODE (works)
<?php
if(isset($_POST['info'])) {
$con = mysqli_connect("x", "x", "x", "x");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT COUNT(*) FROM `Existing_Bookings` WHERE Date = '2019-12-30' AND Time = 'Period 6' AND Room = 'C3'";
if ($result=mysqli_query($con,$sql)) {
// Return the number of rows in result set
$rowcount = mysqli_num_rows($result);
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
echo $rowcount; // echo the data you want to send over ajax
}
?>
Area of php/html in which the result should be returned (id="availresult")
<h2>Check availability</h2>
<h4>Click the button below to check whether your options are available:</h4>
<h4>This will only check against other bookings. It is your responsibility to use the timetable above to check whether the room is actually free.</h4>
<button onclick="soflow()" id="checkAvail" >Check Availability</button>
<input onclick="unhideReview()" type="button" id="continue" value="Continue" disabled />
<input type="text" style="width: 30px;" id="availresult" value="1" />
Test AJAX function, as suggested by an existing reply to my post
<script>
function soflow() {
$.post('checkAvailability.php', {info: 'start'}, function(data) { //if you don't need to send any data to the php file then you can set the value to whatever you want
document.getElementById('availResult').innerHTML = data;
});
}
</script>
I have tried various ways to do this myself, including modifying the suggested AJAX code above, but I'm not sure how to get my values from my various textbox over to the PHP function. Also, I don't know how to tell whether the AJAX function is running, or whether there is an error somewhere. At present, the value shown in my 'availresult' textbox does not change.
I appreciate any help with this, and thank anyone who has tried to help so far. I'm not sure how much clearer I can make this - please don't close the question again.
UPDATE:
(index.php):
<html>
<head>
<title>Test</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
</head>
<body>
<h4>Date:</h4>
<input required type="text" name = "datebox" id = "datebox" ><br/>
<h4>Timeslot:</h4>
<input required type="text" name = "timebox" id = "timebox" ><br/>
<h4>Location:</h4>
<input required type="text" name = "roombox" id = "roombox" ><br/>
<h4>Person:</h4>
<input required type="text" name = "bookerbox" id = "bookerbox" ><br/>
<br/>
<h2>Check availability</h2>
<h4>Click the button below to check whether your options are available:</h4>
<h4>This will only check against other bookings. It is your responsibility to use the timetable above to check whether the room is actually free.</h4>
<button onclick="soflow()" id="checkAvail" >Check Availability</button>
<input onclick="unhideReview()" type="button" id="continue" value="Continue" disabled />
<input type="text" style="width: 30px;" id="availresult" value="1" />
<script>
function soflow() {
var var_date = $('#datebox').val();
var var_time = $('#timebox').val();
var var_room = $('#roombox').val();
$.post('checkAvailability.php', {info: 'start', date: var_date, time: var_time, room: var_room}, function(data) {
document.getElementById('availResult').innerHTML = data;
});
}
</script>
</body>
</html>
(test.php):
<?php
if(isset($_POST['info'])) {
$con = mysqli_connect("x", "x", "x", "x");
if (mysqli_connect_errno()) { // Check connection
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$date = mysqli_real_escape_string($con, $_POST['date']);
$time = mysqli_real_escape_string($con, $_POST['time']);
$room = mysqli_real_escape_string($con, $_POST['room']);
$sql="SELECT COUNT(*) FROM `Existing_Bookings` WHERE Date = '$date' AND Time = '$time' AND Room = '$room'";
if ($result=mysqli_query($con,$sql)) {
// Return the number of rows in result set
$rowcount = mysqli_num_rows($result);
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
echo $rowcount; // echo the data you want to send over ajax
}
?>
You could also do ajax with pure JavaScript, but this is simpler.
Also note that this is just an example on how to do an ajax connection in the first place.
I am trying to display the data i retrieve from the database but it is not being displayed. I have a function in the file getComments.php called "getComments(page)" page is just a integer parameter to choose that database. and as you can see that i need to call this function to print the users comments. I am trying to use "load" but it is not being successful i just want to call this function to load the comments on the page. thank you in advance.
<?php
use TastyRecipes\Controller\SessionManager;
use TastyRecipes\Util\Util;
require_once '../../classes/TastyRecipes/Util/Util.php';
Util::init();
function getComments($page){
echo "<br><br>";
$controller = SessionManager::getController();
$controller->getComments($page);
SessionManager::setController($controller);
}
and in my web page where i want to display it using java script, i tried the following
<div class="page" id="comments">
<p class="style">Comments</p>
<button class="btn" id="load-comments">See Previous Comments</button><br>
<br><br>
<?php
if(isset($_SESSION['u_id'])){
echo " <input type='hidden' id='uid' value = '".$_SESSION['u_uid']."'>
<input type='hidden' id='date' value = '".date('Y-m-d H:i:s')."'>
<textarea id='message'></textarea><br>
<button class = 'btn' type = 'submit' id = 'submitCom'>Comment</button>";
}
else{
echo "<p>Please log in to comment</p>";
}
?>
</div><br>
<script>
$(document).ready(function(){
$("#load-comments").click(function(){
document.getElementById('#comments').innerHTML =
$("#comments").load("../extras/getComments.php", getComments(1));
});
});
</script>
Just change your click handler to this:
$("#load-comments").click(function(){
$("#comments").load("../extras/getComments.php", { page: 1 }); //i also added where the elements are loaded
});
and in getComments.php (if practical, otherwise you might need to create a new PHP file which calls the getComments() function and call that from the click handler instead) add something like:
if (isset($_POST['page'])) {
getComments($_POST['page']);
// do any other necessary stuff
exit;
}
I have a contact us form:
<form id="contactus" name="contactus" action="html_form_send1.php" method="post">
<label for="name">Name:</label><br />
<input type="text" id="name" name="name" maxlength="50" size="59" autofocus required/><br /><br />
<label for="email">E-Mail Address:</label><br />
<input type="email" id="email" name="email" maxlength="50" size="59" required/><br /><br />
<label for="question">Question:</label><br />
<textarea id="question" name="question" maxlength="1000" cols="50" rows="6" required></textarea><br /><br />
<input class="c1_scButton" type="submit" id="submit" name="submit" value="Send" />
</form>
I want it to call my mail PHP script using this AJAX code:
var msg = "";
name = $("#name").val();
email = $("#email").val();
question = $("#question").val();
//validation phase
function isValidEmailAddress(emailAddress) {
var pattern = new RegExp(/^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([az]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))#((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$/i);
return pattern.test(emailAddress);
};
function validate(e) {
if (name == "") {
msg = " valid name";
}
if (!isValidEmailAddress(email)) {
msg = msg + " valid email address";
}
if (question == "") {
msg = msg + " valid question or comment";
}
}
// on submit, Validate then post to PHP mailer script
$(function() {
$("#contactus").on('submit', function(e) {
e.preventDefault();
validate(e);
if msg != "" {
e.preventDefault();
$("#alert").html "Please enter a" + msg;
} else {
$.post('/html_form_send1.php', $(this).serialize(), function(data) {
$('#alert').css(color: "black")
$('#alert').html("<h2>Thank you for contacting us!</h2>")
.append("<p>We will be in touch soon.</p>");
}).error(function() {
$('#alert').css(color: "red")
$('#alert').html("<h2>Something went wrong. Your Question was not submitted. /n</h2>").append("<p>Please try again later or email us at <a href=href="
mailto: support# allegroaffiliates.com ? Subject = Contact Us Form " target="
_top ">support#allegroaffiliates.com.</a> </p>");
});
};
});
});
The script is called at the bottom of the HTML page after another script, but it isn't loading. I suspect that it is due to a code error but I can't find the error. Can anybody give me an idea why it wont load?
Side note: I do know that HTML5 will validate the script, but I have the validation in place for when HTML5 is not available.
Thank you for your help.
A few troubleshooting suggestions:
(1) When specifying the ajax processor file, either this $.post('html_form_send1.php' or this $.post('./html_form_send1.php' but not this $.post('/html_form_send1.php'
(2) Instead of using the shortcut code $.post(), use the full form of the method until you are pretty good at it:
var varvalue = $('#first_name').val();
var nutherval = $('#last_name').val();
$.ajax({
type: 'post',
url: 'your_secondary_file.php',
data: 'varname=' +varvalue+ '&lname=' +nutherval,
success: function(d){
if (d.length) alert(d);
}
});
(3) Disable validation routine until the rest is working, then work on that when you know everything else is working correctly
(4) Change your ajax processor file html_form_send1.php to just echo back a response to make sure you've got the AJAX working. Then, once you get the response, change it to echo back the variable you are sending. Then build it into the final desired product. But initially, something dead simple, like this:
your_secondary_file.php:
<?php
$first_name = $_POST['varname'];
$last_name = $_POST['lname'];
echo 'Received: ' .$first_name .' '. $last_name;
die();
(5) Instead of using .serialize(), initially just grab one or two field values manually and get that working first. Note that .serialize() produces JSON data, while the simpler method is straight posted values, as in sample code in this answer. Get it working first, then optimize.
(6) Note that the dataType: parameter in the AJAX code block is for code coming back from the PHP side, not for code going to the PHP side. Also note that the default value is html, so if you aren't sending back a JSON object then just leave that param out.
(7) In my AJAX and PHP code samples above, note the correlation between the javascript variable name, how it is referenced in the AJAX code block, and how it is received on the PHP side. I was very deliberate in the names I chose to allow you to follow the var name => var value pairing all the way through.
For example, the input field with ID first_name is stored in a variable called varvalue (dumb name but intentional). That data is transmitted in the AJAX code block as a variable named varname, and received on the PHP side as $_POST['varname'], and finally stored in PHP as $first_name
Review some simple AJAX examples - copy them to your system and play with them a bit.
I created an instant search similar to google search using JQuery.
Q1.
The post to search.php using search function searchq() then print out the returned result works fine, but the createq() function doesn't work at all, it didn't triggered when I using alert() to test, any ideas on how to fix it so the variable txt could be post to create_object.php (which has been post successfully to search.php).
Q2
I want to create a function that allow the user to direct to the first search result(which is anchored with an url) when the enter is pressed, any idea how to achieve this? I tried something but it messed up.
Note that I didn't include the connect to database function here. Coz I think the database username and password setting would be different to yours.So please create your own if you want to test it. The mysql is set with a table is called "objects", and it has one column named "name".
Thanks in advance!
<html>
<!-- google API reference -->
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<!-- my own script for search function -->
<center>
<form method="POST">
<input type="text" name="search" style="width:400px " placeholder="Search box" onkeyup="searchq();">
<input type="submit" value=">>">
<div id="output">
</div>
</form>
</center>
<!-- instant search function -->
<script type="text/javascript">
function searchq(){
// get the value
var txt = $("input").val();
// post the value
if(txt){
$.post("search.php", {searchVal: txt}, function(result){
$("#search_output").html(result+"<div id=\"create\" onclick=\"creatq()\"><br>Not found above? Create.</div>");
});
}
else{
$("#search_output").html("");
}
};
function createq(){
// allert for test purpose
alert("hi");
$.post( "create_object.php",{creatVal:txt} );
}
</script>
</html>
PHP file (search.php)
<?php
if(isset($_POST["searchVal"])){
//get the search
$search=$_POST["searchVal"];
//sort the search
$search=preg_replace("#[^0-9a-z]#i","",$search);
//query the search
echo "<br/>SELECT * from objects WHERE name LIKE '%$search%'<br/>";
$query=mysqli_query($conn,"SELECT * from objects WHERE name LIKE '%$search%'") or die("could not search!");
$count=mysqli_num_rows($query);
//sort the result
if($count==0){
$output="there was no search result";
}
else{
while($row=mysqli_fetch_assoc($query)){
$object_name=$row["name"];
$output.="<div><a href='##'".$object_name."</a></div>";
}
}
echo $output;
}
?>
php file (create_object.php)
<?php
if(isset($_POST["createVal"])){
$name=$_POST["createVal"];
var_dump($name);
}
?>
Two questions in one!
Q1: The problem appears to be a misspelling in the onclick function:
onclick=\"creatq()\"
should be
onclick=\"createq()\"
Q2: Pressing enter will submit the form, so you use the submit handler to catch the enter press then redirect:
$(function() { //shorthand document.ready function
$('form ').on('submit', function(e) { //use on if jQuery 1.7+
e.preventDefault(); //prevent form from submitting
$url = $('#search_output div:first a').attr('href'); // find first link
window.location.href = $url; // redirect
});
});
(credit to this answer for most of the work)
A grid table is displayed via PHP/MySQL that has a column for a checkbox that the user will check. The name is "checkMr[]", shown here:
echo "<tr><td>
<input type=\"checkbox\" id=\"{$Row[CONTAINER_NUMBER]}\"
data-info=\"{$Row[BOL_NUMBER]}\" data-to=\"{$Row[TO_NUMBER]}\"
name=\"checkMr[]\" />
</td>";
As you will notice, there is are attributes for id, data-info, and data-to that are sent to a modal window. Here is the JavaScript that sends the attributes to the modal window:
<script type="text/javascript">
$(function()
{
$('a').click(function()
{
var selectedID = [];
var selectedBL = [];
var selectedTO = [];
$(':checkbox[name="checkMr[]"]:checked').each(function()
{
selectedID.push($(this).attr('id'))
selectedBL.push($(this).attr('data-info'))
selectedTO.push($(this).attr('data-to'))
});
$(".modal-body .containerNumber").val( selectedID );
$(".modal-body .bolNumber").val( selectedBL );
$(".modal-body .toNumber").val( selectedTO );
});
});
</script>
So far so good. The modal retrieves the attributes via javascript. I can choose to display them or not. Here is how the modal retrieves the attributes:
<div id="myModal">
<div class="modal-body">
<form action="" method="POST" name="modalForm">
<input type="hidden" name="containerNumber" class="containerNumber" id="containerNumber" />
<input type="hidden" name="bolNumber" class="bolNumber" id="bolNumber" />
<input type="hidden" name="toNumber" class="toNumber" id="toNumber" />
</form>
</div>
</div>
There are additional fields within the form that the user will enter data, I just chose not to display the code. But so far, everything works. There is a submit button that then sends the form data to PHP variables. There is a mysql INSERT statement that then updates the necessary table.
Here is the PHP code (within the modal window):
<?php
$bol = $_POST['bolNumber'];
$container = $_POST['containerNumber'];
$to = $_POST['toNumber'];
if(isset($_POST['submit'])){
$bol = mysql_real_escape_string(stripslashes($bol));
$container = mysql_real_escape_string(stripslashes($container));
$to = mysql_real_escape_string(stripslashes($to));
$sql_query_string =
"INSERT INTO myTable (bol, container_num, to_num)
VALUES ('$bol', '$container', '$to')
}
if(mysql_query($sql_query_string)){
echo ("<script language='javascript'>
window.alert('Saved')
</script>");
}
else{
echo ("<script language='javascript'>
window.alert('Not Saved')
</script>");
}
?>
All of this works. The user checks a checkbox, the modal window opens, the user fills out additional form fields, hits save, and as long as there are no issues, the appropriate window will pop and say "Saved."
Here is the issue: when the user checks MULTIPLE checkboxes, the modal does indeed retrieve multiple container numbers and I can display it. They seem to be already separated by a comma.
The problem comes when the PHP variables are holding multiple container numbers (or bol numbers). The container numbers need to be separated, and I guess there has to be a way the PHP can automatically create multiple INSERT statements for each container number.
I know the variables need to be placed in an array somehow. And then there has to be a FOR loop that will read each container and separate them if there is a comma.
I just don't know how to do this.
When you send array values over HTTP as with [], they will already be arrays in PHP, so you can already iterate over them:
foreach ($_POST['bol'] as $bol) {
"INSERT INTO bol VALUES ('$bol')";
}
Your queries are vulnerable to injection. You should be using properly parameterized queries with PDO/mysqli
Assuming the *_NUMBER variables as keys directly below are integers, use:
echo '<tr><td><input type="checkbox" value="'.json_encode(array('CONTAINER_NUMBER' => $Row[CONTAINER_NUMBER], 'BOL_NUMBER' => $Row[BOL_NUMBER], 'TO_NUMBER' => $Row[TO_NUMBER])).'" name="checkMr[]" /></td>';
Then...
$('a#specifyAnchor').click(function() {
var selectedCollection = [];
$(':checkbox[name="checkMr[]"]:checked').each(function() {
selectedCollection.push($(this).val());
});
$(".modal-body #checkboxCollections").val( selectedCollection );
});
Then...
<form action="" method="POST" name="modalForm">
<input type="hidden" name="checkboxCollections" id="checkboxCollections" />
Then...
<?php
$cc = $_POST['checkboxCollections'];
if (isset($_POST['submit'])) {
foreach ($cc as $v) {
$arr = json_decode($v);
$query = sprintf("INSERT INTO myTable (bol, container_num, to_num) VALUES ('%s', '%s', '%s')", $arr['BOL_NUMBER'], $arr['CONTAINER_NUMBER'], $arr['TO_NUMBER']);
// If query fails, do this...
// Else...
}
}
?>
Some caveats:
Notice the selector I used for your previous $('a').click() function. Do this so your form updates only when a specific link is clicked.
I removed your mysql_real_escape_string functions due to laziness. Make sure your data can be inserted into the table correctly.
Make sure you protect yourself against SQL injection vulnerabilities.
Be sure to test my code. You may have to change some things but understand the big picture here.