I am getting error in Firefox SyntaxError: unterminated string literal when i try to include following code:
<script>
function makeProdiv(data){
var tbl_body = "";
var tbl_row = "";
tbl_row +="<?php foreach($data as $row) {} ?>" (Error at this line)
tbl_body += tbl_row;
return tbl_body;
}
</script>
If i remove this row then error disappears.
What i am trying: I am trying to loop through the result returned from DB and display values.
Please anyone can assist?
You most likely have double quotes in the content generated by PHP. You need to escape them properly, or, providing you don't have single quotes in the PHP content, you could do:
tbl_row +='<?php foreach($data as $row) { /* ... */} ?>';
As noted in the comments, having newlines in your PHP content might also cause this issue. Remove or replace them.
Try something like this:
<?php foreach ($data as $row) { ?>
tbl_row += <?php echo json_encode(whatever); ?>;
<?php } ?>
Using json_encode() will ensure that the PHP value is correctly encoded for Javascript.
Try this:
<?php foreach($data as $row) {?>
tbl_row +=<?php echo $row;?>
<? }?>
what it contain?the
'data' that is passed to this function "makeProdiv(data)"
& $data.
I guess $data is an array of "tr" fetched from db.
Related
I am using following code to pass PHP variables to javascript. but it is not working.
function gto(str) {
document.getElementById('goto').action = str;
document.getElementById('ID').value = <?php echo "$userid" ?>;
document.getElementById('name').value = <?php echo "$user_name" ?>;
document.getElementById('gname').value = <?php echo "$usergname" ?>;
document.getElementById('fmname').value = <?php echo "$userfname" ?>;
document.getElementById('img').value = <?php echo "$userimg" ?>;
document.getElementById('email').value = <?php echo "$useremail" ?>;
document.getElementById('goto').submit();
}
Following is the PHP code
<?php
if($_POST["name"] == null)
{
$user_name = 'Annomyous';
}
else{
$user_name = $_POST["name"];
$userid= $_POST["id"];
$usergname= $_POST["gname"];
$userfname= $_POST["fname"];
$userimg= $_POST["img"];
$useremail= $_POST["email"];
}
echo "<p style='color : white'>$user_name";
echo "$userid" ;
echo "$gname";
echo "$fname";
echo "$img";
echo "$email";
echo "$user_name";
echo "$user_name</p>";
$user_name =htmlspecialchars($user_name);
$user_name =str_replace("<script>","", $user_name);
?>
the output is a follows:
ReAlItY TuTs104598758504708047866ReAlItY TuTsReAlItY TuTs//this is php echo output.
JAVASCRIPT OUTPUT:-
function gto(str) {
document .getElementById('goto').action = str;
document.getElementById('ID').value = ;
document.getElementById('name').value = Annomyous;
document.getElementById('gname').value = ;
document.getElementById('fmname').value = ;
document.getElementById('img').value = ;
document.getElementById('email').value = ;
document.getElementById('goto').submit();
}
Function gto is called here:
<button class="w3-btn header-btn" onclick="gto('Contact.php');">Contact Us</button>
I can see in PHP output I am getting all variable output.
but nin juavascript im getting only Annonymous why????
I need to pass post variables to contact us so i am using the form tag and javascript but this is not working Please help me!
Thanks in Advance
values from php to js can be passed in many ways, here's one of them
try to pass the php values when calling the js function, like this:-
<button onclick="gto('Contact.php','<?php echo $userid;?>','<?php echo $username;?>');">Contact Us</button>
and then get values on js function like this:-
function gto(str,userid,username) {
document .getElementById('goto').action = str;
document.getElementById('ID').value = userid;
document.getElementById('name').value =username;
}
that's it, now use the values in js as your wish
Uh, found another issue. The js is in smart quotes, which won't work... "`" is invalid. use "'".
Also, w3schools can't handle php in their editor, so it's no use.
Example for POST requests: https://www.w3schools.com/code/tryit.asp?filename=FQSA8MJYGJ47
Hope this helps.
My code :
<?php echo ' <script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques".p);? >
The value of p is displayed as 0.
You need to close your php tag properly as well as the <script> tag like so:
<?php echo '<script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques" +p);</script>'; ?>
Also, change the . to a + as you are concatenating in javascript not PHP
The correct answer is:
<?php echo '<script>var p=0;for(var i=0;i<=5;i++){p++;}alert("ques" + p)'; ?>
Strings in single quotes will be escaped, use quotation marks instead.
<?php echo "<script>var p=0;for(var i=0;i<=5;i++){p++;}alert('ques' +p);</script>"; ?>
The mistakes in your code are,
Close your php tag properly - ?> instead of ? >
Close the script tag in the end - </script>
Close the single quote you started with echo
The correct code would be
<?php echo '<script>var p=0;for(var i=0;i<=5;i++){ p++; } alert("ques" + p); </script>'; ?>
I need to get javascript variable value in php file.
html example:
UPDATE:
$html = '
<script>
window.runParams.adminSeq="3423423423423";
window.runParams.companyId="2349093284234";
</script>';
Shout I use regex ? regex is very complex to me... any help ?
<?php
$html = '<script>
window.runParams.adminSeq="3423423423423";
window.runParams.companyId="2349093284234";
</script>';
$variables = ["adminSeq", "companyId"];
$counter = 0;
foreach($variables as $variable) {
preg_match_all('/"(.*?)"/', $html, $matches);
${"$variable"} = ($matches[1])[$counter];
$counter++;
}
echo $adminSeq; // Prints out: 3423423423423
echo $companyId; // Prints out: 2349093284234
?>
You can also use GET requests to do this. The link would look like http://localhost/?adminSeq=3423423423423&companyId=2349093284234 then get out these values in PHP with:
<?php
$adminSeq = $_GET["adminSeq"];
$companyId = $_GET["companyId"];
?>
i have the following code, but it will not work. i am trying to create a script output:
echo "<script type=\"text/javascript\"><!--\n";
echo "SLIDES = new slideshow(\"SLIDES\")\n";
// Now loop through the files, echoing out a new select option for each one
foreach( $files as $fname ) {
echo 's = new slide()\n';
echo 's.src = \"http://cashbackflorida.com/wpradmin/modules/wprrets/photos/'.$result ->MLS.'/'{$fname}\n\"';
echo 's.width = \"560\"\n';
echo 's.height = \"420\"\n';
echo 's.alt = \"{$fname}\"\n';
echo 's.text = unescape(\"\")\n';
echo 's.link = \"\"\n';
echo 's.target = \"\"\n';
echo 's.attr = \"\"\n';
echo 's.filter = \"\"\n';
echo 'SLIDES.add_slide(s)\n';
}
echo '--></script>\n';
Don't do it this way. Just output the array to JavaScript and deal with it there.
var files = <?php echo json_encode($files); ?>;
You'll find the problem in your string escaping
echo 's.height = \"420\"\n';
You can't escape in single quote strings like that. So try this
echo "s.height = \"420\"\n";
You do NOT need to escape single quotes within double quotes or visa versa, but you can only get a newline character like that in a double quote string.
I would recommend HEREDOC for this kind of string writing though.
$fnamej = json_encode($fname);
echo << EOT
s.height = "420";
s.alt = $fnamej;
EOT;
I am also inclined to say that you'd be better off handling this in javascript. This may end up behaving very badly all of a sudden, and it will take up more bandwidth.
I have this working script yet when I change it to retrieve(supposedly) the value inside $_SESSION["username"], it doesn't retrieve anything. The whole page is saved as .php as I am using some codes that uses PHP.
Code:
echo "<script type=text/javascript>";
echo "var hidden = false;";
echo "function actiondb1() {";
echo "if(!hidden) {";
echo "document.getElementById(\'clickdb1\').style.visibility = \'hidden\';";
echo "document.getElementById(\'db1\').style.visibility = \'visible\';";
echo "document.getElementById(\'db1\').disabled = false;";
echo "document.getElementById(\'db1\').value =".$_SESSION["username"];.";";
echo "}";
echo "}";
echo "</script>";
How can I make the script to properly retrieve the data inside $_SESSION["username"];?
Observe that, for instance, if the value of $_SESSION["username"] is John, your echo will be generating this result:
document.getElementById('db1').value = John;
But John is supposed to be a string and should be wrapped in quotation marks, otherwise JavaScript will understand it as a variable name (which value will be probably undefined).
As Havenard mentioned, this line is missing Javascript single quotes to properly denote a string variable:
echo "document.getElementById(\'db1\').value ='".$_SESSION["username"];."';";
However, you really shouldn't print JS out with PHP if you can help it. Though iatboy's answer answer won't ultimately fix your bug, it is a much cleaner way of doing things.
?>
<script type=text/javascript>;
var hidden = false;
function actiondb1() {
if(!hidden) {
document.getElementById('clickdb1').style.visibility = 'hidden';
document.getElementById('db1').style.visibility = 'visible';
document.getElementById('db1').disabled = false;
document.getElementById('db1').value ='<?php echo $_SESSION["username"];?>';
}
}
</script>;
<?php
Did you start session in this page?If you didn't,use the follow code to start session.
session_start();
Then change your code to
echo "<script type=text/javascript>";
echo "var hidden = false;\n";
echo "function actiondb1() {\n";
echo "alert('".$_SESSION['username']."')\n"; //test code
echo "if(!hidden) {\n";
echo "document.getElementById('clickdb1').style.visibility = 'hidden';\n";
echo "document.getElementById('db1').style.visibility = 'visible';\n";
echo "document.getElementById('db1').disabled = false;\n";
echo "document.getElementById('db1').value ='".$_SESSION["username"]."';\n";
echo "}\n";
echo "}\n";
echo "</script>";
it will be ok.