I'm looking to add to a string's value based on the output for multiple if statements but I don't seem to be having much success. I've declared comp_string="" at the beginning of the script then tried += so that for each condition that is true it adds a section on.
For the code example below if I submitted the value of www.facebook.com and www.twitter.com I would like comp_string to return 'fb=www.facebook.com&tw=www.twitter.com'
How would I go about concatenating/adding the string together and how do I add the & if more than one link is provided. I could add it to each string for any value thats not blank, but would an & on the end of the url with nothing following mess things up?
if (facebook_url != "") {
comp_string += "fb="+facebook_url;
}
if (twitter_url != "") {
comp_string += "tw="+twitter_url;
}
alert(comp_string);
A simple approach would be to add each string to an array, then join the array elements to produce the end result you are looking for.
var params = [];
if (facebook_url !== "") {
params.push("fb=" + facebook_url);
}
if (twitter_url !== "") {
params.push("tw=" + twitter_url);
}
alert(params.join("&"));
Reference
Related
I am in need of some modification to my function to allow for a search of two strings on one line of a value. I am trying to work through this on my own but I need some help. Here is an example of a cell value being looked at. Assume there are no leading or trailing newlines. Also, all the cells have the same format. same number of lines, same structure of membertype: last, first etc.
Say I want to see if this cell contains a team lead with the name of last2 or a Manager with the name first4. Both the type of employee and name would be user inputted.
I tried using the following that I created with the help of this.
indexOf(':(.*):')
It returns the position of the content between and including the colons. Then I tried the following:
flatUniqArr[0].search('Supervisor:')
This is where I'm stuck. It returns the index to the last digit of the first line.
My thought was to do a search of the user inputted name between the colons if they follow the user inputted member type. How can I accomplish this?
Clarifications:
The end goal is to verify that the name and member type are on the same line and excluded from an array I am building for .setHiddenValues(). So if they are on the same line exclude from list.
Here is the function I will be adding it to:
var flatUniqArr = colValueArr.map(function(e){return e[0].toString();})
.filter(function(e,i,a){
return (a.indexOf(e) == i && !(visibleValueArr.some(function(f){
return e.search(new RegExp(f,'i')) + 1;
})));
});
return flatUniqArr;
Where flatUniqArr is the list of hidden values. colValueArr is the array of values from a column. visibleValueArr is the name which is user inputted and memberType will be the member type.
Attempts using Liora's solution: (Updated... Works now)
var flatUniqArr = []
var lines = []
Logger.log(visibleValueArr)
Logger.log(memberType)
for (var i = 0; i < colValueArr.length; i++){
lines = colValueArr[i].toString().split('\n');
var found = false;
for(var j = 0; j < lines.length; j++){
var data = lines[j].toLowerCase().split(':')
if(data[0] == memberType.toString().toLowerCase() && data[1].indexOf(visibleValueArr.toString().toLowerCase()) != -1){
found = true;
}
}
Logger.log(found)
if(found == false){flatUniqArr.push(colValueArr[i])}
}
return flatUniqArr;
It works now. It seems like a lot of code though. I'd be open to alternative solutions if they are faster and/or less lines of code.
Updated: Added .toString().toLowerCase() as the user may input lowercase values.
I assume all the line have this format.
If you split each line with the separator ":"
var array = value.split(":")
Then you'd have
array[0] //the current role
array[1] //the list of name
array[2] //the email
And you can check each names then
if(array[0] == "Team Lead" && array[1].indexOf("last2") != -1)
An example with a linesplit:
var lines = value.toString().split("\n");
var found = false;
for(var i = 0; i < lines.length ; i++){
var data = value.split(":")
if(data[0] == "Team Lead" && data[1].indexOf("last2") != -1){
found = true;
}
}
How about just building the regex using the user input?
function search(line, employeeType, employeeName) {
var regexp = '/' + employeeType + ': ' + employeeName + '/'
return line.search(regexp)
}
Or better yet, if it always occurs at the beginning of the string, just use startsWith()
I'm showing hidden divs based on the contents of a query string parameter that's being parsed from another page, using indexof to check if a value is present - then displaying that value's corresponding div.
Query string: index.html?q1=bag1,bag2,bag3
var urlParams;
(window.onpopstate = function () {
var match,
pl = /\+/g, // Regex for replacing addition symbol with a space
search = /([^&=]+)=?([^&]*)/g,
decode = function (s) { return decodeURIComponent(s.replace(pl, " ")); },
query = window.location.search.substring(1);
urlParams = {};
while (match = search.exec(query))
urlParams[decode(match[1])] = decode(match[2]);
})();
Then using indexOf to show divs based on the value:
if ((urlParams["q1"]).indexOf("bag1") >= 0) {
$(".content1").show();
} else
if ((urlParams["q1"]).indexOf("bag2") >= 0) {
$(".content2").show();
} else
if ((urlParams["q1"]).indexOf("bag3") >= 0) {
$(".content3").show();
}
However, it's only displaying the first div and not the second or third.
I know it'll be a simple solution - bit stuck on it. Any help appreciated!
You need to remove the else clauses, as the interpreter will stop after the first if is true. So your code should look like
if ((urlParams["q1"]).indexOf("bag1") >= 0) {
$(".content1").show();
}
if ((urlParams["q1"]).indexOf("bag2") >= 0) {
$(".content2").show();
}
if ((urlParams["q1"]).indexOf("bag3") >= 0) {
$(".content3").show();
}
I'd suggest using your bag1 etc values as IDs instead of classes to identify the separate content sections. If a class only identifies one element then you're doing it wrong.
You should then tag all of your content elements with the same class (e.g. content) so that you can .hide() on all of them before running .show on the ones that you want to remain visible. As written any elements that are already visible will remain visible when you pop state even if they weren't supposed to be.
Your parameter extracting code is OK, but having got your q1 value I would just do this:
var q1 = urlParams.q1;
if (q1 !== undefined) {
$('.content').hide(); // show nothing
q1.split(',').forEach(function(id) {
$('#' + id).show();
});
}
thereby removing all of the (broken) conditional logic.
Using javascript, im trying to make a node.js module to parse predicate logic statements.
I've been working on this regex for a bit and I just can't get it to behave the way i want
1. /\(((?:[^{}]*\([^{}]*\))*[^{}]*?)\)/
2. .replace(/\)((?:[^{}]*\)[^{}]*\))*[^{}]*?)\(/,'):::(')
the latter works fine on things like (a&s&d&a&s&d)->(a&s&(d)&s|(d)) but i just switched the delimiters...
what I'm trying to do is change a statement like
((r|a)&(s|r))&(~r)->(r|(q&r))->q
into
1->2->q
I can certainly write a procedural function to do it, that would be a fine solution. But Im really stuck on this.
The only real specification is the regex needs to respect the outermost parenthesis the most, and be able to replace separate ones.
Because this is not regex friendly I put togethor a couple of functions that do what you are looking for. The first matches parenthesis with depth:
function match_parens(code_to_test, level, opening, closing){
var sub_match, matched;
return code_to_test.replace(new RegExp('^([^'+opening+closing+']*(.))[\\s\\S]*$'), function(full_match, matched, $2, offset, original){
if ($2 == opening){
sub_match = match_parens(original.substr(offset+matched.length), level + 1, opening, closing);
matched = matched + sub_match
}
else if (level > 1){
sub_match = match_parens(original.substr(offset+matched.length), level - 1, opening, closing);
matched += sub_match;
}
return matched;
});
}
This function takes a string and returns everything up until the closing element.
The next function helps pulls a string passed to it apart, replacing all content in parenthesis with escalating numbers:
function pull_apart(testString){
var count = 1,
returnString = '',
tempIndex = testString.indexOf('(');
while (tempIndex !== -1){
returnString += testString.substring(0,tempIndex)+count;
count += 1;
testString = testString.substring(testString.indexOf('(') + match_parens(testString.substr(tempIndex + 1), 1, '(', ')').length+1)
tempIndex = testString.indexOf('(');
}
returnString += testString;
return returnString;
}
Running pull_apart('((r|a)&(s|r))&(~r)->(r|(q&r))->q') returns "1&2->3->q", which is what you are looking for. While this is not entirely regex, it is utilized in the paren matching function up above. I'm not sure if this fits whatever use case you had in mind, but hopefully it helps.
I have read this question/answer and this one, but I can't get it to work in my situation.
I'm building a list of names from a json array returned from a php script. After the below code I'm putting the goTosList string into a label via jquery. I need each name to be on a new line.
The below code is just outputting
var goTosList = '';
if (data !== 'empty') {
// Build the go tos list as a comma-separated string
$.each(data, function(index,element) {
goTosList += (element['name'] === undefined ? '' : element['name']) + '\n\r';
});
}
I've tried just \r and just \n and without the single quotes. I can't get it to work.
If you are output is HTML and you want newlines you have two options:
Either use a <pre> tag as a wrapper to your text (not suitable here I think)
<pre>some Text
with newlines</pre>
or add <br> instead of \n\r:
some Text<br>with newlines
So in your code this would translate to
goTosList += (element['name'] === undefined ? '' : element['name']) + '<br>';
and later on insert this into the DOM by
$('#yourLabel').html( goTosList );
String(s) is dynamic
It is originated from onclick event when user clicks anywhere in dom
if string(s)'s first part that is:
"login<b>user</b>account"
is enclosed in some element like this :
"<div>login<b>user</b>account</div>",
then I can get it with this:
alert($(s).find('*').andSelf().not('b,i').not(':empty').first().html());
// result is : login<b>user</b>account
But how can i get the same result in this condition when it is not enclosed in any element .i.e. when it is not enclosed in any element?
I tried this below code which works fine when first part do not include any <b></b> but it only gives "login" when it does include these tags.
var s = $.trim('login<b>user</b> account<tbody> <tr> <td class="translated">Lorem ipsum dummy text</td></tr><tr><td class="translated">This is a new paragraph</td></tr><tr><td class="translated"><b>Email</b></td></tr><tr><td><i>This is yet another text</i></td> </tr></tbody>');
if(s.substring(0, s.indexOf('<')) != ''){
alert(s.substring(0, s.indexOf('<')));
}
Note:
Suggest a generic solution that is not specific for this above string only. It should work for both the cases when there is bold tags and when there ain't any.
So it's just a b or a i, heh?
A recursive function is always the way to go. And this time, it's probably the best way to go.
var s = function getEm(elem) {
var ret = ''
// TextNode? Great!
if (elem.nodeType === 3) {
ret += elem.nodeValue;
}
else if (elem.nodeType === 1 &&
(elem.nodeName === 'B' || elem.nodeName === 'I')) {
// Element? And it's a B or an I? Get his kids!
ret += getEm(elem.firstChild);
}
// Ain't nobody got time fo' empty stuff.
if (elem.nextSibling) {
ret += getEm(elem.nextSibling);
}
return ret;
}(elem);
Jsfiddle demonstrating this: http://jsfiddle.net/Ralt/TZKsP/
PS: Parsing HTML with regex or custom tokenizer is bad and shouldn't be done.
You're trying to retrieve all of the text up to the first element that's not a <b> or <i>, but this text could be wrapped in an element itself. This is SUPER tricky. I feel like there's a better way to implement whatever it is you're trying to accomplish, but here's a solution that works.
function initialText(s){
var test = s.match(/(<.+?>)?.*?<(?!(b|\/|i))/);
var match = test[0];
var prefixed_element = test[1];
// if the string was prefixed with an element tag
// remove it (ie '<div> blah blah blah')
if(prefixed_element) match = match.slice(prefixed_element.length);
// remove the matching < and return the string
return match.slice(0,-1);
}
You're lucky I found this problem interesting and challenging because, again, this is ridiculous.
You're welcome ;-)
Try this:
if (s.substring(0, s.indexOf('<')) != '') {
alert(s.substring(0, s.indexOf('<tbody>')));
}