So I have an index.php and a r.php. R.php is the registration part. And index.php is the actual form. My question is how can I have errors from r.php be send back to index.php if they exist. So instead of displaying errors on r.php I want them on index.php and prevent the form from advancing.
Here's the index.php
<!DOCTYPE html>
<html>
<body>
<form method="post" action="r.php">
<input type="text" name="name" placeholder="Name">
<input type="submit">
</form>
</body>
Its all very simple. Now here's r.php
<?php
$name = $_POST['name'];
if ($name < 3){
//display error
}
else {
//proceed
}
?>
Should I do this with JS? Or this there a better way.
One way is to use sessions:
<?php session_start(); ?>
<!DOCTYPE html>
<html>
<body>
<?php echo isset($_SESSION['message']) ? $_SESSION['message'] : ''; ?>
<form method="post" action="r.php">
<input type="text" name="name" placeholder="Name">
<input type="submit">
</form>
</body>
<?php
session_start();
unset($_SESSION['message']);
$name = $_POST['name'];
if ($name < 3){ // you probably want strlen($name) < 3
$_SESSION['message'] = 'error';
header('Location: index.php');
exit;
}
else {
//proceed
}
?>
Other than sessions you could redirect back with a query string and use that:
header('Location: index.php?message=' . urlencode('some kind of error');
Then:
<?php echo isset($_GET['message']) ? $_GET['message'] : ''; ?>
Using a single script for this would be easier, just put this all in one file, and check to see if the form has been submitted. If the form has been submitted, you an just include the variables you want straight away.
This is pretty crude, but it gives you an idea of where you can go with this:
<?php
if (isset($_POST['name'])) {
// Begin processing form stuff
$name = $_POST['name'];
// Initialise error variable
$error = null;
if ($name < 3) {
// Display error, for example:
$error = 'Name is less than 3';
} else {
// Proceed
}
}
?>
<!DOCTYPE html>
<html>
<body>
<?php if ( ! empty($error)) { ?>
<p><?php echo $error; ?></p>
<?php } ?>
<form method="post" action="r.php">
<input type="text" name="name" placeholder="Name">
<input type="submit">
</form>
</body>
</html>
<!DOCTYPE html>
<html>
<?php
$msg = '';
if(isset($_GET['e'])
{
$msg = "Error! Input not valid.";
}
?>
<body>
<?php
if($msg!='')
{
echo "<font color='red'>".$msg."</font>";
}
?>
<form method="post" action="r.php">
<input type="text" name="name" placeholder="Name">
<input type="submit">
</form>
</body>
Just pass a variable e using GET request to the index page if an error is found.
<?php
$name = $_POST['name'];
if ($name < 3){
header("Location: index.php?e=error");
}
else {
//proceed
}
?>
GET request will send the variable e using the URL, and if e is found to be having a value, it means there was an error in r.php
Use javascript for simple form validation. In case you require some security stuff or db stuff, you can use session/cookie or use header function to go back.
Related
There's two pages: one is index.php and another is add-name.php . add-name.php has a form which takes a name and after a successful submission, it redirects to index.php page where all the names is shown.
I was wondering how can I show a message that the name has been added on index.php page after add-name.php page redirects to index.php page when it's submitted.
add-name.php
<?php
if ($_SERVER["REQUEST_METHOD"] === "POST"){
$name = $_POST["name"];
addName($name); // this addName function saves the name to a
file called names.txt and index.php page
uses this file to access all the names
header("Location: index.php");
}
?>
<form action="add-name.php" method="POST">
<label for="name">Name:</label>
<input type="text" name="name" id="name">
<input type="submit" name="submitButton" value="Save">
</form>
Use session
add-name.php
<?php
if ($_SERVER["REQUEST_METHOD"] === "POST"){
$name = $_POST["name"];
// addName($name);
session_start();
$_SESSION["name"] = "added";
header("Location: index.php");
exit();
}
?>
<form action="add-name.php" method="POST">
<label for="name">Name:</label>
<input type="text" name="name" id="name">
<input type="submit" name="submitButton" value="Save">
</form>
index.php
<?php
session_start();
if (isset($_SESSION["name"]) && $_SESSION["name"] === "added") {
echo "name added";
unset($_SESSION["name"]);
} else {
echo "just called";
}
# ...
When I'm using PHP in JavaScript, then all scripts don't work...
Even if I use php in comment.
<script>
//var variable = <?php echo json_encode($_SESSION['abc']); ?>;
</script>
This comment above destroy all scripts in <script></script> tags.
When I'll delete this line with the comment, then every script will work.
The same thing is when I just want to use PHP in JavaScript (without comment).
Could You help me ?
Here is code which was cut by me (to give You only necessary part of code), please help :) :
<?php
session_start();
if (isset($_POST['login']) && isset($_POST['password']) && isset($_POST['email']))
{
$validation = true;
$firstName = $_SESSION['firstName'];
$lastName = $_SESSION['lastName'];
$street = $_SESSION['street'];
$phone = $_SESSION['phone'];
$login = $_POST['login'];
$password = $_POST['password'];
$email = $_POST['email'];
require_once "connect.php";
mysqli_report(MYSQLI_REPORT_STRICT);
try
{
$connection = new mysqli($host, $db_user, $db_password, $db_name);
if($connection->connect_errno!=0)
{
throw new Exception(mysqli_connect_errno());
}
else
{
if ($validation == true) // when validation process will be successfuly done - i cut validation process
{
if($connection->query("INSERT INTO users values (NULL, '$firstName', '$lastName', '$street', '$phone', '$login', '$password', '$email')"))
{
$_SESSION['abc'] = "done";
//here is also header(location) to login page
}
else
{
throw new Exception($connection->error);
}
}
$connection->close();
}
}
catch(Exception $e)
{
echo '<div class="error">error. sorry, please to register in other term</div>';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8" />
<script>
//there are other functions for local/session storage
function deleteSessionData()
{
var variable = "<?php echo $_SESSION['abc']; ?>";
if(variable == "done")
{
sessionStorage.removeItem('firstName');
sessionStorage.removeItem('lastName');
sessionStorage.removeItem('street');
sessionStorage.removeItem('phone');
sessionStorage.removeItem('login');
sessionStorage.removeItem('password');
sessionStorage.removeItem('email');
}
}
</script>
</head>
<body>
<form id="myForm" method="post">
<label for="login">Login: </label>
<input type="text" id="login" name="login">
<label for="password">Password: </label>
<input type="text" id="password" name="password">
<label for="email">E-mail:</label>
<input type="email" id="email" name="email">
<button onclick="java script: document.getElementById('myForm').submit();deleteSessionData();">Register</button>
</form>
</div>
</body>
</html>
you need to comment the php too
//var variable = <?php // echo json_encode($_SESSION['abc']); ?>;
I wouldn't inject PHP into javascript like this without sanitation though.
I have made two pages. I have used php form validation in my first page, i.e., form.php and I have to give action on second page i.e., data_ins.php. Please let me know how will it possible with my coding.
Here are my pages:
form.php
<?php $fnameErr = $lnameErr = "";
$fname = $lname= ""; if($_SERVER["REQUEST_METHOD"] == "POST") {
if(empty($_POST['fname']))
{
$fnameErr = "First Name is required";
}
else
{
$fname= formVal($_POST['fname']);
}
if(empty($_POST['lname']))
{
$lnameErr = "Last Name is required";
}
else
{
$lname= formVal($_POST['lname']);
} }
function formVal($data)
{
$data = trim($data);
$data = stripcslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?> <!DOCTYPE html> <html>
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<form method="POST" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
First Name:
<input type="text" name="fname"> <span style="color:red;"><?php echo $fnameErr ?></span> <br>
Last Name:
<input type="text" name="lname"> <span style="color:red;"><?php echo $lnameErr ?></span> <br>
<input type="submit" name="submit">
</form>
</body> </html>
data_ins.php
<?php $conn = mysqli_connect("localhost","root","","test_db");
$sql = "insert into records (FirstName, LastName) values ('$fname', $lname)";
if($result=mysqli_query($conn, $sql))
{
echo "Data Inserted Successfull";
}
else
{
echo "Invalid";
}
mysqli_error($conn); ?>
Personally, I think you may of made it harder than you needed to.
Here is what I'd do with the PHP side:
if (isset($_POST['submit']))
{
if (!empty($_POST['fname']))
{
if (!empty($_POST['lname']))
{
// Add Database insert code here..
} else {
echo "Last name is required";
}
} else {
echo "First name is required";
}
}
As for the form, you don't need to add the PHP self (just add the method) like so:
<form method="POST" action="">
First Name: <input type="text" name="fname"><br>
Last Name: <input type="text" name="lname"><br>
<input type="submit" name="submit">
</form>
Hope this helps more so than your initial idea of doing it.
PLEASE NOTE: I haven't added the $data trim etc in but you'd add these in firstly where // do code note is.
1.change your form like this
`<form method="POST" action="location of your data_ins.php">`
2.in your data_ins.php must have database config code or include it.
3.get your all form value in data_ins.php pass to insert query
<form method="POST" action="">
First Name: <input type="text" name="fname"><br>
Last Name: <input type="text" name="lname"><br>
<input type="submit" name="submit">
</form>
Besides your code, your method (as question is not about it).
To execute other .php file you can use PHP statements:
require
include
include_once
In your case require should be the one to use, like: require 'data_ins.php'; after validation.
I have a script where when a user get verified he/she is brought to Home.php. At the moment Home.php doesn't do much. But in the bottom left hand corner I have a log out button. And as you know when the user clicks on this button he expects his session to be destroyed and for him to be redirected to a log in page. Unfortunately you can't make a click listener in php. I have browsed for an hour looking for a solution but I have not been able to find the right key word or something.
This is my code
EDIT: You only really have to read some code from Home.php the est is only if someoe wants to run the code if they are not sure of their answer
Index.php(Login Page)
<?php
session_start();
mysql_connect("localhost","root","") or die ("cannot");
mysql_select_db("virtualdiary") or die ("db");
if (isset ($_POST["Username"])&& isset($_POST["Password"]))
{
$Username = $_POST["Username"];
$Password = $_POST["Password"];
$_SESSION["username"] = $Username;
$DB_Check = " SELECT * from users Where username = '".$Username."' and password = '".$Password."' " ;
$result = mysql_query($DB_Check);
if(mysql_fetch_assoc($result) === false){
$error = "invalid username or password";
}else{
header( 'Location: Home.php' ) ;
}
}
?>
<html>
<head>
<link type="text/css" rel="stylesheet" href="Index.css"/>
<title>Login</title>
</head>
<body>
<div id="main">
<div class="messages">
<?php
if(isset($error))
echo $error; ?>
</div>
<form action="Index.php" method="post">
<h5>Diary Name:</h5>
<input name="Username" type="text"/>
<h5>Password:</h5>
<input name="Password" type="password"/>
</br>
</br>
</br>
<input name="login" type="submit"/>
</form>
<p>Click HERE to register.</p>
</div>
</body>
</html>
Home.php
<?php
session_start();
echo "Username = " . $_SESSION["username"] . " !";
mysql_connect("localhost","root","") or die ("cannot");
mysql_select_db("virtualdiary") or die ("db");
if (isset($_POST["entry"])){
$entry = $_POST["entry"];
$submission = "INSERT INTO `virtualdiary`.`entries` (`entry`) VALUES ('". $entry . "')";
mysql_query($submission);
}
?>
<html>
<head>
<link type="text/css" rel="stylesheet" href="Home.css"/>
<title>Home</title>
</head>
<body>
<h1>Entry: </h1>
<form method="post" action="Home.php">
<textarea name="entry" rows="24" cols="87">
<?php
if (isset($_POST["entry"])){
echo $entry;
}
?>
</textarea>
</br>
</br>
<input name="submit" type="submit"/>
</form>
<button id="LogOut">Log Out</button>
</body>
</html>
From what I have found from searching around I will need a Home.js file with an ajax call. I don't know the first thing about Ajax so I will probably need code to paste or a very blunt tutorial.
Thanks
You could change the logout href to /Logout.php, and in Logout.php have
<?php
session_start();
session_destroy();
header('Location: /Index.php');
?>
That will simply destroy the users current session, then redirect the user back to the Index.php page.
The AJAX way would be (using jQuery, I can't remember the vanilla JS syntax for ajax calls)
$.ajax({
type: 'GET',
url: '/Logout.php',
success: function(msg) {
if (msg == 'loggedOut') {
window.location.href = 'Index.php';
}
}
});
And then you'd need to change Logout.php, instead of the header line, make it echo/die/print loggedOut (or a json string which would probably be better, but this is just an example).
What i'm trying to do here is to sends an email to a salesperson notifying them that their client has viewed a google docs presentation.
The query's Num=val is a serial number that I use to get the actual google doc's url out of a database and stuff it into a form.
My problem is that the page redirects before the data is retrieved, and ends up going to the default for the site, nitrofill.com.index
The gdform.php file has the header redirect, which works fine if I don't try to process the form when the page loads. Heres the code:
<?php
$sn=$_GET['num'];
echo $sn;
mysql_connect($hostname,$username, $password) OR DIE ('Unable to connect to database! Please try again later.');
mysql_select_db($dbname);
$selectSQL = "select * from `Presentations` where `serialnum` ='" . $sn ."'" ;
$result = mysql_query($selectSQL) or die(mysql_error());
$row = mysql_fetch_array($result, MYSQL_BOTH);
?>
<script type="text/javascript">
function myfunc () {
var frm = document.getElementById("notice");
frm.submit();
}
window.onload = myfunc;
</script>
<title>Nitrofill Document</title></head>
<body>
<form id="notice" action="http://m3sglobal.com/gdform.php" method="post">
<input type="hidden" name="subject" value="<?php echo (urldecode($row['recipient'])) . " has viewed the document you sent them."; ?>" />
<input type="hidden" name="redirect" value="<?php echo ((urldecode($row['docurl']))); ?>"/>
<label>Email:</label><input type="text" name="email" value="<?php echo (urldecode($row['tracker'])); ?>"/>
<label>Comments:</label><textarea name="comments" cols="40" rows="5">
Document Viewed:<?php echo ((urldecode($row['docurl']))); ?>
When Accessed:<?php echo ((urldecode($row['last_accessed']))); ?>
</textarea>
<input type="submit" name="submit"/>
</form>
The gdform.php does the redirect like this:
while (list ($key, $val) = each ($query_vars)) {
fputs($fp,"<GDFORM_VARIABLE NAME=$key START>\n");
fputs($fp,"$val\n");
fputs($fp,"<GDFORM_VARIABLE NAME=$key END>\n");
if ($key == "redirect") { $landing_page = $val;}
}
fclose($fp);
if ($landing_page != ""){
header("Location: " . $landing_page);
} else {
header("Location: http://".$_SERVER["HTTP_HOST"]."/");
}
Thanks for looking!
Code in HTML is executed top-down. You're submitting as soon as you get to that block of JavaScript, which is before you even render the form on the page.
Move your JS code to the bottom of the page, or execute it after the DOM is ready.