I am using the following code to route click events on an img tag to an input radio below it. The code works perfectly on Chrome and other browsers, but on IE (specifically IE 11) I must double click to get the radio selected instead of just single click to get the radio input selected. Can someone please tell me what I am doing wrong, missing here? Thanks
<script type="text/javascript">
$(document).ready(function() {
$('#Img1').click(function() {
$('#radio1').trigger('click');
});
});
</script>
<div class="imagesPrev col four center">
<label class="label_radio images" for="radio1">
<div class="labelText">
<img id="Img1"src="image1.gif" alt="Image 1" />
<input type="radio" id="radio1" name="radio1" value="image1"/>
</div>
<div style="height:10px;"></div>
Image Title <br/>
</label>
</div>
Notes:
- I also noticed that I don't have to double click as normal double click, but it has to be two clicks. Meaning one click then I can wait for like 10-15 seconds then do the 2nd click to get the click event routed to the radio input.
http://jsfiddle.net/89wTk/
You should use .prop(); when dealing with checkbox/radio inputs.
$(document).ready(function() {
$('#Img1').click(function() {
var checkBox = $("#radio1");
checkBox.prop("checked", !checkBox.prop("checked"));
});
});
Have you tried using a label tag with a for attribute for this feature instead, this could solve your problem and be more browser compatible.
<label for="radio1"><img id="Img1"src="image1.gif" alt="Image 1" /></label>
<input type="radio" id="radio1" name="radio1" value="image1"/>
I can understand if this doesn't achieve what you need, but using this method should work using HTML markup instead of jQuery
relatively horrible jsfiddle demoing this:
http://jsfiddle.net/andyface/d25KS/
I remember that some version of IE don't support clicking objects other than links or buttons :(
Perhaps try using:
$("#radio1").checked(true);
or
$("#radio1").selected(true);
as a work around
Just simple, you don't have to use any Jquery for this, just keep everything inside the label:
<label for="radio_btn">
<img id="img"src="image1.gif" alt="Image here" />
<input type="radio" id="radio_btn" name="radio1" value="image1"/>
</label>
Working here: http://jsfiddle.net/fals/3phf4/
Your code example works fine in IE11 (desktop and metro). Is it possible that there is another click event on the page that is capturing and preventing the click event on the image? Maybe something is causing the page to lose focus (first click gets window focus second clicks the image)? Try putting an alert in the click function to see if the click is getting registered. If that's not the issue, try running the body of the function in the console to see if that is the issue. You might try other ways to trigger the event, as suggested by others. Or try the jQuery .triggerHandler("click") method.
I think your problem may be with your markup. You have your image and click events inside a label.
According to w3schools:
"...if the user clicks on the text within the element, it toggles the control."
http://www.w3schools.com/tags/tag_label.asp
That toggle is perhaps messing with your javascript. Try moving the markup outside of the label and see if that helps.
That's an easy one :).
The #img1 is encapsulated inside the
<label class="label_radio images" for="radio1">
So, without the jQuery part it's already working. Now when having the jQuery part, a single click will become a double click:
1) 'for' element of label_radio
2) the trigger in jQuery part
So, for x-browser, you should not wrap the img inside the label.
Or try to cancel the event in $('#Img1').click(function(event) { ...
You have both your img and radio wrapped in label.
HTML's default behavior is that click on label triggers radio/checkbox inside.
There are two ways you can solve your problem:
Remove javascript function altogether.
If there's additional reason for javascript, change your html markup, and move radio outside of the label. Also remove for attribute, cause it triggers radio selection. Something like this:
<div class="imagesPrev col four center">
<label class="label_radio images">
<div class="labelText">
<img id="Img1"src="image1.gif" alt="Image 1" />
</div>
</label>
<input type="radio" id="radio1" name="radio1" value="image1"/>
<div style="height:10px;"></div>
Image Title
</div>
<script type="text/javascript">
$(document).on('click','.Img1',function()
{
var checkBox = $(".radio1");
checkBox.prop("checked", !checkBox.prop("checked"));
});
</script>
<img class="Img1" src="image1.gif" alt="Image 1" />
<input type="radio" class="radio1" name="radio1" value="image1"/>
I am facing the same issue and its very weird .... the workaround that is working for me is that instead of using the trigger function .. put the code which is executed in the trigger click event in a javascript function and call that function instead of trigger event ... example is given below.
For this example i will use an alert in case of a click on the element with id radio1.
Event definition
$('#radio1').on('click',function () {
alert("Hi");
})
So Instead of using $('#radio1').trigger('click'); we can put the alert in a javascript function and call the javascript function where ever i am calling the trigger click event.
Javascript function
function triggerClick(){
alert("Hi")
}
and just call this function(triggerClick()) where ever you are using $('#radio1').trigger('click');
Please let me know if this is helpfull
Try to use .click() instead of .trigger('click'):
<script>
$(document).ready(function() {
$('#Img1').click(function() {
$('#radio1').click();
});
});
</script>
it should work, see here for more info
Related
<input type="checkbox" runat="server" name="Seasonal" value="Seasonal" id="isASeasonal" onclick=" if ($(this).is(':checked')) { console.log('Worky'); $('#ShowIfChecked').show(); $('#HideIfChecked').hide(); } else { $('#HideIfChecked').show(); console.log("No Worky"); }" />
I've been attempting to do this with jQuery, but it hasn't been functioning properly, I have also done a thorough amount of research for ways to condense this code. I was trying to condense the statement with a ternary operator. If you could please assist me with a possible solution that would be great! Thanks (Ternary Solution would be amazing)
The issue with your code is that you have mis-matched quotes in the HTML due to the console.log("X") calls in your code that is messing up the attributes of the input element. If you check the console you'll most likely see some errors relating to this.
It's for this reason, amongst many others, that it's considered bad practice to use inline script (or CSS styling for that matter). The other issues are that it's bad for separation of concerns and makes the code harder to read an edit. It's far better practice to attach your event handlers using unobtrusive Javascript, like this:
$('.seasonal-checkbox').change(function() {
$('#ShowIfChecked').toggle(this.checked);
$('#HideIfChecked').toggle(!this.checked);
});
#ShowIfChecked {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" runat="server" name="Seasonal" value="Seasonal" id="isASeasonal" class="seasonal-checkbox" />
<div id="ShowIfChecked">Checked!</div>
<div id="HideIfChecked">Not Checked!</div>
Note the use of the change event over click, so that the event is still fired for user who navigate the web using the keyboard. Also note the simplified logic using toggle() to hide and show the relevant content in a single call to each method which negates the need for an if statement - and by proxy a ternary expression too.
You can change your onclick to a function, because at least for me, it is easier to see whats really going on.
So change
<input type="checkbox" runat="server" name="Seasonal" value="Seasonal" id="isASeasonal"
onclick=" if ($(this).is(':checked')) { console.log('Worky'); $('#ShowIfChecked').show(); $('#HideIfChecked').hide(); }
else { $('#HideIfChecked').show(); console.log("No Worky"); }" />
to
<input type="checkbox" runat="server"
name="Seasonal" value="Seasonal" id="isASeasonal" onclick="myFuncton(this)" />
Within your view:
<script>
myFunction(myCheckBox)
{
if(myCheckBox.Checked)
{
console.log('Worky');
$('#ShowIfChecked').show();
$('#HideIfChecked').hide();
}
else
{
$('#HideIfChecked').show(); console.log("No Worky");
}
}
</script>
Now to get the expression/Ternary Solution you want, you can change this script to look like this:
<script>
myFunction(myCheckBox)
{
myCheckBox.Checked ? (console.log('Worky'), $('#ShowIfChecked').show(),
$('#HideIfChecked').hide()); : ($('#HideIfChecked').show(), console.log("No Worky"));
}
</script>
You can find more Info about Ternary Solutions here
We dont write code like this. It fails on every code review.
Do this:
$('#isASeasonal').click(function() { ...});
https://api.jquery.com/click/
Seasonal Address:  <input type="checkbox" runat="server" clientidmode="Static" name="Seasonal" value="Seasonal" id="isASeasonal"/>
$('#ShowIfChecked').hide(); //Hid What needs to be shown if checked.
$("#isASeasonal").click(function () { //Used Click event on checkBox
($("#isASeasonal").is(':checked')) ? (console.log('worky'), $('#ShowIfChecked').show(), $('#HideIfChecked').hide()) : (console.log('no worky'), $('#HideIfChecked').show(), $('#ShowIfChecked').hide());
What fixed my issue was that in ASP.net I needed to add clientidmode="static" to the div's that I was trying to hide & show. I still don't understand the reason why, I'm currently looking more into it but this is what worked for me but above you can see the majority of the final product with the ternary operator!! Yay.
I am trying to show-hide div using jquery on click of radio buttons. It might be a weird question to ask but my brain is not digging more and i know that is easy task to do.
Below is HTML
<input type="radio" value="Active Now" class="tabActive" id="active-radio1"
/>Participations
<input type="radio" value="Not Active Now" class="tabNotActive"
id="active-radio2" />
Droppers
<div id="tabActive" class="tab-content">
</div>
<div id="tabNotActive" class="tab-content hide">
</div>
Below is JS
$("input:radio").off().on('click',function()){
var value = $(this).attr("class");
$("#"+value).show();
// I also tried
$("#"+value).toggleClass('hide'); /*Not right way, i know :)*/
$("#"+value+" .tab-content").toggleClass('hide')
});
I am not able to switch between divs due to hide class, but nothing worked
Note: The hide class is being added by framework and i can not modify it.
So, i need a perfect way to show hide these divs.
Try this.
$('input[type=radio]').on('click',function()) {
var id = $(this).attr('class'); // this is very prone to problems
$('.tab-content').addClass('hide')
$('#' + id).removeClass('hide');
});
You can try this one:
$(function() {
$("[name=toggler]").click(function(){
$('.toHide').hide();
$("#blk-"+$(this).val()).show('slow');
});
});
DEMO FIDDLE
My problem is that I'm not able to change picture based on different events, in my case, onmouseover. I'm using JavaScript and html5 standard.
Below is the affected html:
<img alt="" height="300" width="162" id="bronze" class="badges" src="bilder/Bronze160x310.png">
which is supposed to be reliant on the following piece:
<label class="block">
<input name="Radio" type="radio" id="b1" onmouseover='updatePic("pictures/hi_again.png")' onchange="enableProceed(); updatePrice();" value="2.9">
<span style="cursor:pointer">test</span>
</label>
I only have trouble with the onmouseover event. I haven't tested it thoroughly, but it seemed to work fine with onchange events.
The following is the JavaScript code:
function updatePic(newPic) {
document.getElementById("bronze").src = newPic;
}
When I run this the original picture becomes unavailable even if I have not begun any mouseover. I used a switch-system for my JavaScript before, but the same problem occured.
Thanks in advance.
JSFiddle: http://jsfiddle.net/xfkjL3as/3/
I believe I have achieved what you are attempting to do in this JSFiddle.
DEMO: http://jsfiddle.net/xfkjL3as/1/.
The HTML is as follows:
<img src="http://theunleashedreviewboard.files.wordpress.com/2013/08/angry-face.png" id="myImage">
<div>
<input type="radio" id="myRadioButton" value="100" />
<label for="myRadioButton">My Radio Button</label>
</div>
The JavaScript is as follows:
function updateImageSource(src)
{
var myImage = document.getElementById("myImage");
myImage.src = src;
}
var myRadioButton = document.getElementById("myRadioButton");
myRadioButton.addEventListener("mouseover", function(){
updateImageSource('http://www.worldpeace-uk.org/wp-content/uploads/2013/07/smiley-face.jpg');
}, false);
I have used JavaScript to attach the mouseover event to the radiobutton HTML element.
Sidenote: It is generally a better practice to separate your JavaScript code from your HTML. While HTML provides you attributes such as onmouseover to achieve this, I would recommend to keep the JavaScript code in a separate file (and link it).
This question answers how to link a separate JavaScript file.
I have horizontal jQuery checkbox. It should display some text when it is clicked and remove the text when it is clicked again and unchecked. However, when i first load the page and click on the box nothing happens. Then when i click it again to uncheck the text appears. It seems the opposite behaviour of what i expect is going on. Here is the code:
(I can solve this problem by simply inverting the boolean sign but i want to understand why this is happening).
<form>
<fieldset data-role="controlgroup" data-type="horizontal">
<legend>Select your type of Restaurant:</legend>
<input type="checkbox" name="checkbox-h-2a" id="checkbox-h-2a">
<label for="checkbox-h-2a" onclick="onfilter()">Vegetarian</label>
</fieldset>
</form>
<script>
function onfilter(){
if ($("#checkbox-h-2a").prop('checked')){
document.getElementById("hehe").innerHTML = "Yo there";
}
if (!($("#checkbox-h-2a").prop('checked'))){
document.getElementById("hehe").innerHTML = "";
}
}
</script>
You're already loading jQuery , so just use jQuery for everything - it is much easier , works better, really the only downside to jQUery is having to load it - and you're already doing that. So I would suggest using something like this:
$(function(){
$(document).on('click', '#checkbox-h-2a', function(){
if ( $(this).is(':checked') ) {
// Do stuff
}
else{
//Do stuff
}
});
});
Also, I hope you are actually closing your input element in your HTML , and that this is just a typo in your question
<input type="checkbox" name="checkbox-h-2a" id="checkbox-h-2a"
try:
<fieldset data-role="controlgroup" data-type="horizontal">
<legend>Select your type of Restaurant:</legend>
<label for="checkbox-h-2a" >Vegetarian
<input type="checkbox" name="checkbox-h-2a" id="checkbox-h-2a" />
</label>
</fieldset>
see how the label goes around the checkbox? also you can get rid on the inline function in HTML with the jQuery I provided
EDIT:
2 problems - one you selectd jQuery 1.6 , to you .on() you need a newer version , if you must use old jQuery let me know ,
the other problem is that all jQuery code must be wrapped in
$(document).ready(function(){
/// code here
});
or for short:
$(function(){
// code here
});
The problem is at the time of clicking on the label, the checkbox's checked has not been changed, so you have to toggle the logic (although it looks weird) or attach the handler to the onchange event of the checkbox input instead:
<!-- add onchange event handler -->
<input type="checkbox" name="checkbox-h-2a" id="checkbox-h-2a"
onchange="onfilter()"/>
<!-- and remove the click handler -->
<label for="checkbox-h-2a">Vegetarian</label>
Demo.
It involves how a label works, when clicking on the label, it looks for the attached input element via the for attribute and trying to change the appropriate property (checked for checkbox, radio, ...) or focusing the element (for textbox fields). So at the clicking time, it processes/calls your handler first. Hence the problem.
Note that this answer just fixes the issue, not trying to improve your code.
Have a look at this link.
The menu to the left is not clickable in chrome (When you open in new tab, it works fine), but works fine in Mozilla.
Please let me know if you have any thoughts on how to correct this.
Your menu not using Javascript to detect click events it is anchor tag. You will notice that in a webkit browser hovering over the link does not provide a pointer cursor.
Eg:
<a style="background-color:red;" href="/stores/unwrapindia/products/1/Artisan/2/Happily-Unmarried/65/New-Year/78/Promotions-">
<div class="fillDIV">
<input type="checkbox" name="attribute_value_44" value="44" class="CheckBoxClass" id="CheckBox1">
<label class="LabelSelected" for="CheckBox1" id="Label1">Chandigarh</label>
</div>
</a>
The problem could that the input is conflicting with the anchor tag in regards to the click event, because webkit is a bit confused about the div inside the anchor or you need to clean up your ID's. I do not see the reason for your using of the input and label, so at least test it with just the anchor.
The label elements within your links have a for attribute (which refer to hidden checkboxes). Something like:
<input type="checkbox" id="cb1" />
<label for="cb1">mooooo</label>
The link does not work once you set that attribute.
To fix your problem, simply remove the attribute - it does not benefit you anyway (having the checkbox checked is not helpful as you are navigating away from the page).
Here is an example.
My solution is add inline javascript code to tag A
onclick="document.location.href=this.getAttribute('href');"
Note
In html specification, an A element is not allowed to contain a DIV element, you can refer to
http://www.w3.org/TR/html4/sgml/dtd.html
for more information