I am trying to draw lines with canvas and I am changing the coordinates with a for loop.
here is my canvas element:
<canvas id="c" width="300px" height="300px"></canvas>
and here is the js codes:
var c = document.getElementById('c');
ci = c.getContext('2d');
for(var a = 18; a < 300; a +=18){
fnc(a, ci);
}
function fnc(x, ci){
ci.strokeStyle = 'red';
ci.moveTo(0, x);
ci.lineTo(300, x); ci.lineWidth = 0.2; ci.stroke();
}
As you can see I am trying to draw these lines with 18px spaces between them. But the thickness of the lines and the color(or opacity, I am not sure) are changing from top to bottom.
Here is a fiddle : http://jsfiddle.net/J6zzD/1/
So what is wrong with that I can't find my mistake. Why are the color and the thicknesses are different?
UPDATE :
I just wrote these lines out of the function and now all the lines becomes faded but thicknesses are same. So strange :
ci.strokeStyle = 'red';
ci.lineWidth = 0.2; ci.stroke();
here is demo : http://jsfiddle.net/J6zzD/4/
That's again the eternal issue of forgetting to call beginPath.
Each time you call moveTo then lineTo, you create a new *sub*path, which adds to the current Path.
Then each time you call stroke(), the current path, so all the current subpaths get re-drawn, when the last added path is drawn for the first time.
Since opacities will add-up, top lines will reach 100% opacity (alpha=255) when the bottom line, drawn once, will have a 20% opacity (lineWidth=0.2) .
In your second fiddle, you stroke only once, so all lines have 20% opacity, which is correct for the 0.2 lineWidth.
So : use beginPath before drawing a new figure.
In this case you have two choices :
• draw line by line
OR
• draw once a path with all lines as subpath.
(see code below).
TIP : To get clean lines remember that pixels's center is at the (+0.5, +0.5) coordinates of each pixels, so
a 'trick' is to translate by 0.5, 0.5 on app start, then only use rounded coordinates and lineWidth.
1) draw line by line
http://jsfiddle.net/gamealchemist/J6zzD/6/
var c = document.getElementById('c');
var ctx = c.getContext('2d');
ctx.translate(0.5, 0.5);
ctx.lineWidth = 1;
for (var y = 18; y < 300; y += 18) {
strokeLine(ctx, y);
}
function strokeLine(ctx, y) {
ctx.beginPath();
ctx.strokeStyle = 'red';
ctx.moveTo(0, y);
ctx.lineTo(300, y);
ctx.stroke();
}
2) draw multiple subPath :
(you can have only one color for one stroke() )
http://jsfiddle.net/gamealchemist/J6zzD/7/
var c = document.getElementById('c');
var ctx = c.getContext('2d');
ctx.translate(0.5, 0.5);
ctx.lineWidth = 1;
ctx.strokeStyle = 'red';
ctx.beginPath();
for (var y = 18; y < 300; y += 18) {
addLineSubPath(ctx, y);
}
ctx.stroke();
function addLineSubPath(ctx, y) {
ctx.moveTo(0, y);
ctx.lineTo(300, y);
}
See: https://developer.mozilla.org/en-US/docs/Web/Guide/HTML/Canvas_tutorial/Applying_styles_and_colors#A_lineWidth_example
Because canvas coordinates do not directly reference pixels, special care must be taken to obtain crisp horizontal and vertical lines.
Basically, because you're trying to draw a line that's 0.2 pixels wide, the browser does some math to approximate a continuous number into discrete units and you get your "fading" lines.
So now we can fix up your code by changing context.lineWidth to 1 (I actually remove it because it defaults to 1) and shifting everything down by half a pixel.
var c = document.getElementById('c');
ci = c.getContext('2d');
for(var a = 18.5; a < 300.5; a +=18)
{
fnc(a, ci);
}
function fnc(x, ci)
{
ci.strokeStyle = 'red';
ci.moveTo(0, x);
ci.lineTo(300, x);
ci.stroke();
}
Demo
Related
I want to create a striped pattern with HTML5 canvas, where the thickness of lines for the striped pattern should be configurable using the property lineWidth.
After I read this answer, I understood that for coord x,y from moveTo()/lineTo(), I need to add like 2.5 for the ctx.lineWidth =5 or maybe create a formula based on thickness like this example. But I can't figure out how to change the values of those coordinates so the pattern remains striped like on the right, not random like in left
Below is my code. How should I calculate the coordonates x,y?
function createStrippedPattern(color) {
const pattern = document.createElement('canvas');
// create a 10x10 px canvas for the pattern's base shape
pattern.width = 10;
pattern.height = 10;
// get the context for drawing
const context = pattern.getContext('2d');
context.strokeStyle = color;
context.lineWidth = 5;
// draw 1st line of the shape
context.beginPath();
context.moveTo(2, 0);
context.lineTo(10, 8);
context.stroke();
// draw 2st line of the shape
context.beginPath();
context.moveTo(0, 8);
context.lineTo(2, 10);
context.stroke();
return context.createPattern(pattern, 'repeat');
};
function fillWithPattern(targetCanvas, patternCanvas) {
const ctx = targetCanvas.getContext('2d', {
antialias: false,
depth: false
});
const width = targetCanvas.width;
const height = targetCanvas.height;
ctx.fillStyle = patternCanvas;
ctx.fillRect(0, 0, width, height);
return targetCanvas;
}
fillWithPattern(
document.getElementById("targetCanvas"),
createStrippedPattern("red")
);
<canvas id="targetCanvas" width=30 height=30></canvas>
Code logic problems
The size of the pattern needs to match the slope of the line. That size must be expanded to allow for a set spacing between the lines.
Your code has a fixed size that does not match the slope of either of the lines you draw.
The lines you draw are both in different directions. You will never get them to create a repeatable pattern.
The code you have given is too ambiguous for me to understand what you wish to achieve thus the example adds some constraints that considers my best guess at your requirements.
Tileable striped pattern
The function in the example below creates a striped repeatable (tilded) pattern.
The function createStripedPattern(lineWidth, spacing, slope, color) requires 4 arguments.
lineWidth width of the line to draw
spacing distance between lines. Eg if lineWidth is 5 and spacing is 10 then the space between the lines is the same width as the line.
slope The slope of the line eg 45 degree slope is 1. I have only tested value >= 1 and am not sure if it will work below 1.
Nor have I tested very large slopes. The point of the example is to show how to draw the line on the pattern to repeat without holes.
color Color of line to draw.
The function works by creating a canvas that will fit the constraints given by the arguments. It then draws a line from the top left to bottom right corners. This leaves a gap in the repeating pattern at the top right and bottom left corners.
To fill the missing pixels two more lines are drawn. One through the top right corner and the other through the bottom left.
Note you could also just copy the canvas onto itself (offset to the corners) to fill the missing corner pixels. For pixel art type patterns this may be preferable.
Note that canvas sizes are integer values and lines are rendered at sub pixel accuracy. For very small input values there will be artifact as the relative error between the canvas (integer) pixel size and required (floating point) size grows larger
Example
The example contains the function to create the pattern as outlined above and then renders some examples.
The first canvas has inset patterns with each pattern increasing the line width will keeping the spacing and slope constant.
The second canvas just fills with a fixed lineWidth as 4, spacing as 8 and a slope of 3
function createAARotatedPattern(lineWidth, spacing, ang, color) {
const can = document.createElement('canvas');
const w = can.width = 2;
const h = can.height = spacing;
const ctx = can.getContext('2d');
ctx.fillStyle = color;
ctx.fillRect(0, 0, 2, lineWidth);
const pat = ctx.createPattern(can, 'repeat');
const xAx = Math.cos(ang);
const xAy = Math.sin(ang);
pat.setTransform(new DOMMatrix([xAx, xAy, -xAy, xAx, 0, 0]));
return pat;
}
function createStripedPattern(lineWidth, spacing, slope, color) {
const can = document.createElement('canvas');
const len = Math.hypot(1, slope);
const w = can.width = 1 / len + spacing + 0.5 | 0; // round to nearest pixel
const h = can.height = slope / len + spacing * slope + 0.5 | 0;
const ctx = can.getContext('2d');
ctx.strokeStyle = color;
ctx.lineWidth = lineWidth;
ctx.beginPath();
// Line through top left and bottom right corners
ctx.moveTo(0, 0);
ctx.lineTo(w, h);
// Line through top right corner to add missing pixels
ctx.moveTo(0, -h);
ctx.lineTo(w * 2, h);
// Line through bottom left corner to add missing pixels
ctx.moveTo(-w, 0);
ctx.lineTo(w, h * 2);
ctx.stroke();
return ctx.createPattern(can, 'repeat');
};
function fillWithPattern(canvas, pattern, inset = 0) {
const ctx = canvas.getContext('2d');
ctx.clearRect(inset, inset, canvas.width - inset * 2, canvas.height - inset * 2);
ctx.fillStyle = pattern;
ctx.fillRect(inset, inset, canvas.width - inset * 2, canvas.height - inset * 2);
return canvas;
}
fillWithPattern(targetCanvas, createStripedPattern(2, 6, 2, "#000"));
fillWithPattern(targetCanvas, createStripedPattern(3, 6, 2, "#000"), 50);
fillWithPattern(targetCanvas, createStripedPattern(4, 6, 2, "#000"), 100);
fillWithPattern(targetCanvas1, createStripedPattern(4, 8, 3, "#000"));
var y = 0;
var ang = 0;
const ctx = targetCanvas2.getContext('2d');
while (y < targetCanvas2.height) {
ctx.fillStyle = createAARotatedPattern(2, 5, ang, "#000");
ctx.fillRect(0, y, targetCanvas2.width, 34);
y += 40;
ang += 2 * Math.PI / (targetCanvas2.height / 40);
}
<canvas id="targetCanvas" width="300" height="300"></canvas>
<canvas id="targetCanvas1" width="300" height="300"></canvas>
<canvas id="targetCanvas2" width="300" height="600"></canvas>
Update
The above example now includes a second method createAARotatedPattern(lineWidth, spacing, ang, color) that uses the pattern transform. ang replaces slope from the original function and represents the angle of the pattern in radians.
It works by drawing the pattern aligned to the x axis and then rotates the pattern via a DOMMatrix.
It will create a pattern at any angle, though personally the quality can at times be less than the first method.
The example has a 3 canvas with strips showing the pattern drawn at various angles. (Note you do not have to recreate the pattern to change the angle)
I have been given the following task, but I am getting errors that can be seen when the code snippet is run. I would like some help figuring out what exactly I am doing wrong.
Basically, I need to draw a circle, make it so that it moves and changes the direction/color when touching the walls of the screen.
Task: create a Circle class with the following properties:
x - the initial value of the coordinate x
y is the initial value of the y coordinate
radius - values of width and height
color - fill color Describe the methods:
draw () - marks off on the screen an element that is described by the given properties
setColor (newColor) - Changes the fill color to newColor
move ({x = 0, y = 0}) - moves the captured object by the vector (x, y) - each time period (for example, 100 ms) changes (adds \ subtracts)
to the values x and y, respectively. When a circle collides with any
edge of the screen it is necessary to realize its mirror reflection
(change the value of the corresponding coordinate of the vector on the
opposite of the value of the sign, and call this method with the new
vector) and generate the collision event, collision, which is captured
at the document level.Hang on this event a handler that will change
the color of the pouring of the circle into another (random) value.
Movement occurs until the stop method is called.
stop () - stops the circle movement
If the Escape button on the keyboard was pressed, the movement should stop.
I created a canvas and set the frame to move. I drew a circle and tried to move it using setInterval(), but it seems like I'm losing the context.
let c = document.getElementById("mycanvas");
let ctx = c.getContext("2d");
let xinc = 1;
let yinc = 1;
class Circle {
constructor(xpos, ypos, radius, color) {
this.xpos = xpos;
this.ypos = ypos;
this.radius = radius;
this.color = color;
}
draw() {
ctx.beginPath();
ctx.arc(this.xpos, this.ypos, this.radius, 0, Math.PI * 2);
ctx.fillStyle = "red";
ctx.fill();
}
move(xpos, ypos) {
ctx.clearRect(0, 0, c.width, c.height);
ctx.beginPath();
this.draw();
xpos += xinc;
ypos += yinc;
console.log(xpos, ypos);
if ((this.xpos > c.width - this.radius) || (this.xpos < 0 + this.radius)) {
xinc = -xinc;
}
if ((this.ypos > c.height - this.radius) || (this.ypos < 0 + this.radius)) {
yinc = -yinc;
}
setInterval(this.move, 10);
//this.draw();
}
}
let circle = new Circle(200, 300, 50, "red");
circle.draw();
circle.move(200, 300);
<canvas id="mycanvas" width="1335" height="650" style="border: 1px solid"> </canvas>
I am just starting to learn events and DOMs, please help me correctly implement this task
You are passing this.move to setInterval with no context - just a function, with no this to call it in. You can pass in this.move.bind(this) to create a bound function. You can also do it once in the constructor: this.move = this.move.bind(this).
Also, the call to beginPath in move seems unnecessary.
Concerns to be addressed:
looks like the straight line on the left is higher than the one on the right. I don't want that. Why is that happening and how could I fix it?
Are all the lines(recs) the same length. not sure but it looks like the ones that go outwards at 0.7853981633974483 radians are smaller
window.onload = function(){
var canvas = document.getElementById("canvas");
var context = canvas.getContext("2d");
context.translate(200,200);
for(var i = 0; i < 5; i++){
context.save()
context.rotate(Math.PI / 4 * i);
context.fillStyle = "red";
context.fillRect(0,0,70,3 )
context.restore()
}
}
<canvas id="canvas" width="400" height="400"></canvas>
EDIT: Also I want to ask you how you would go about labeling these slices that make up the angle. for example slice 1 gets "1" and so on 1 2 3 4 5. it should be positioned by the vertex(angle)
Firstly, the lengths are all the same. If the appear different it is likely due to an illusion from the slight overlapping at the origin.
Now the reason why things aren't lining up is due to the nature of rotation and rectangles. When you rotate a rect the rotational origin is at the top left corner of the rectangle. So when rotated 180 degrees, the origin of the rectangle will be the bottom right. This can be seen more obviously if you widen your rectangles, and change their colours. For example:
var cols = ['red', 'green', 'blue', 'yellow', 'purple'];
window.onload = function(){
var canvas = document.getElementById("canvas");
var context = canvas.getContext("2d");
context.translate(200,200);
for(var i = 0; i < 5; i++){
context.save();
context.rotate(Math.PI / 4 * i);
context.fillStyle = cols[i];
context.fillRect(0,0,70,30);
context.restore();
}
}
<canvas id="canvas" width="400" height="400"></canvas>
Sow how do you fix this? One way to fix is to translate each rect on the y axis, half of its width after rotation. For example:
var cols = ['red', 'green', 'blue', 'black', 'purple'];
// the line width (technically rect height)
var width = 3;
var length = 70;
var canvas = document.getElementById("canvas");
var context = canvas.getContext("2d");
context.translate(200,200);
for(var i = 0; i < 5; i++){
var rotAmount = Math.PI / 4 * i;
context.save();
context.rotate(rotAmount);
context.translate(0, -(width / 2));
context.fillStyle = cols[i];
context.fillRect(0,0,length,width);
context.translate(length + 20, 0);
context.rotate(-rotAmount);
context.font="18px Verdana";
context.fillText(i+1,-5,5);
context.restore();
}
<canvas id="canvas" width="400" height="400"></canvas>
Also added fillText as per #markE's comment, to get you started with drawing the numbers.
So how does this work? Basically after drawing the line, you move the axis to where you want each number to be (translate), and then rotate the axis in reverse, the same amount that you originally rotated the line (rotate). This will rotate the numbers to their original coordinate system.
How to draw outer and inner border around any canvas shape?
I'm drawing several stroke-only shapes on an html canvas, and I would like to draw an inner and outer border around them.
draft example:
Is there a generic why to do it for any shape (assuming it's a closed stroke-only shape)?
Two methods
There is no inbuilt way to do this and there are two programmatic ways that I use. The first is complicated and involves expanding and contracting the path then drawing along that path. This works for most situations but will fail in complex situation, and the solution has many variables and options to account for these complications and how to handle them.
The better of the two
The second and easiest way that I present below is by using the ctx.globalCompositeOperation setting to mask out what you want drawn or not. As the stroke is drawn along the center and the fill fills up to the center you can draw the stroke at twice the desired width and then either mask in or mask out the inner or outer part.
This does become problematic when you start to create very complex images as the masking (Global Composite Operation) will interfere with what has already been drawn.
To simplify the process you can create a second canvas the same size as the original as a scratch space. You can then draw the shape on he scratch canvas do the masking and then draw the scratch canvas onto the working one.
Though this method is not as fast as computing the expanded or shrunk path, it does not suffer from the ambiguities faced by moving points in the path. Nor does this method create the lines with the correct line join or mitering for the inside or outside edges, for that you must use a the other method. For most purposes the masking it is a good solution.
Below is a demo of the masking method to draw an inner or outer path. If you modify the mask by including drawing a stroke along with the fill you can also set an offset so that the outline or inline will be offset by a number of pixels. I have left that for you. (hint add stroke and set the line width to twice the offset distance when drawing the mask).
var demo = function(){
/** fullScreenCanvas.js begin **/
var canvas = ( function () {
canvas = document.getElementById("canv");
if(canvas !== null){
document.body.removeChild(canvas);
}
// creates a blank image with 2d context
canvas = document.createElement("canvas");
canvas.id = "canv";
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
canvas.style.position = "absolute";
canvas.style.top = "0px";
canvas.style.left = "0px";
canvas.style.zIndex = 1000;
canvas.ctx = canvas.getContext("2d");
document.body.appendChild(canvas);
return canvas;
})();
var ctx = canvas.ctx;
/** fullScreenCanvas.js end **/
/** CreateImage.js begin **/
// creates a blank image with 2d context
var createImage = function(w,h){
var image = document.createElement("canvas");
image.width = w;
image.height =h;
image.ctx = image.getContext("2d");
return image;
}
/** CreateImage.js end **/
// define a shape for demo
var shape = [0.1,0.1,0.9,0.1,0.5,0.5,0.8,0.9,0.1,0.9];
// draws the shape as a stroke
var strokeShape = function (ctx) {
var w, h, i;
w = canvas.width;
h = canvas.height;
ctx.beginPath();
ctx.moveTo(shape[0] *w, shape[1] *h)
for (i = 2; i < shape.length; i += 2) {
ctx.lineTo(shape[i] * w, shape[i + 1] * h);
}
ctx.closePath();
ctx.stroke();
}
// draws the shape as filled
var fillShape = function (ctx) {
var w, h, i;
w = canvas.width;
h = canvas.height;
ctx.beginPath();
ctx.moveTo(shape[0] * w,shape[1] * h)
for (i = 2; i < shape.length; i += 2) {
ctx.lineTo(shape[i]*w,shape[i+1]*h);
}
ctx.closePath();
ctx.fill();
}
var drawInOutStroke = function(width,style,where){
// clear the workspace
workCtx.ctx.globalCompositeOperation ="source-over";
workCtx.ctx.clearRect(0, 0, workCtx.width, workCtx.height);
// set the width to double
workCtx.ctx.lineWidth = width*2;
workCtx.ctx.strokeStyle = style;
// fill colour does not matter here as its not seen
workCtx.ctx.fillStyle = "white";
// can use any join type
workCtx.ctx.lineJoin = "round";
// draw the shape outline at double width
strokeShape(workCtx.ctx);
// set comp to in.
// in means leave only pixel that are both in the source and destination
if (where.toLowerCase() === "in") {
workCtx.ctx.globalCompositeOperation ="destination-in";
} else {
// out means only pixels on the destination that are not part of the source
workCtx.ctx.globalCompositeOperation ="destination-out";
}
fillShape(workCtx.ctx);
ctx.drawImage(workCtx, 0, 0);
}
// clear in case of resize
ctx.globalCompositeOperation ="source-over";
ctx.clearRect(0,0,canvas.width,canvas.height);
// create the workspace canvas
var workCtx = createImage(canvas.width, canvas.height);
// draw the outer stroke
drawInOutStroke((canvas.width + canvas.height) / 45, "black", "out");
// draw the inner stroke
drawInOutStroke((canvas.width + canvas.height) / 45, "red", "in");
// draw the shape outline just to highlight the effect
ctx.strokeStyle = "white";
ctx.lineJoin = "round";
ctx.lineWidth = (canvas.width + canvas.height) / 140;
strokeShape(ctx);
};
// run the demo
demo();
// incase fullscreen redraw it all
window.addEventListener("resize",demo)
I'm working on concept maps application, which has a set of nodes and links. I have connected the links to nodes using the center of the node as reference. Since I have nodes with different size and shapes, it is not advisable to draw arrow-head for the link by specifying height or width of the shape. My approach is to draw a link, starting from one node, pixel by pixel till the next node is reached(here the nodes are of different color from that of the background), then by accessing the pixel value, I want to be able to decide the point of intersection of link and the node, which is actually the co-ordinate for drawing the arrow-head.
It would be great, if I could get some help with this.
Sample Code:
http://jsfiddle.net/9tUQP/4/
Here the green squares are nodes and the line starting from left square and entering into the right square is the link. I want the arrow-head to be drawn at the point of intersection of link and the right square.
I've created an example that does this. I use Bresenham's Line Algorithm to walk the line of whole canvas pixels and check the alpha at each point; whenever it crosses a 'threshold' point I record that as a candidate. I then use the first and last such points to draw an arrow (with properly-rotated arrowhead).
Here's the example: http://phrogz.net/tmp/canvas_shape_edge_arrows.html
Refresh the example to see a new random test case. It 'fails' if you have another 'shape' already overlapping one of the end points. One way to solve this would be to draw your shapes first to a blank canvas and then copy the result (drawImage) to the final canvas.
For Stack Overflow posterity (in case my site is down) here's the relevant code:
<!DOCTYPE html>
<html><head>
<meta charset="utf-8">
<title>HTML5 Canvas Shape Edge Detection (for Arrow)</title>
<style type="text/css">
body { background:#eee; margin:2em 4em; text-align:center; }
canvas { background:#fff; border:1px solid #666 }
</style>
</head><body>
<canvas width="800" height="600"></canvas>
<script type="text/javascript">
var ctx = document.querySelector('canvas').getContext('2d');
for (var i=0;i<20;++i) randomCircle(ctx,'#999');
var start = randomDiamond(ctx,'#060');
var end = randomDiamond(ctx,'#600');
ctx.lineWidth = 2;
ctx.fillStyle = ctx.strokeStyle = '#099';
arrow(ctx,start,end,10);
function arrow(ctx,p1,p2,size){
ctx.save();
var points = edges(ctx,p1,p2);
if (points.length < 2) return
p1 = points[0], p2=points[points.length-1];
// Rotate the context to point along the path
var dx = p2.x-p1.x, dy=p2.y-p1.y, len=Math.sqrt(dx*dx+dy*dy);
ctx.translate(p2.x,p2.y);
ctx.rotate(Math.atan2(dy,dx));
// line
ctx.lineCap = 'round';
ctx.beginPath();
ctx.moveTo(0,0);
ctx.lineTo(-len,0);
ctx.closePath();
ctx.stroke();
// arrowhead
ctx.beginPath();
ctx.moveTo(0,0);
ctx.lineTo(-size,-size);
ctx.lineTo(-size, size);
ctx.closePath();
ctx.fill();
ctx.restore();
}
// Find all transparent/opaque transitions between two points
// Uses http://en.wikipedia.org/wiki/Bresenham's_line_algorithm
function edges(ctx,p1,p2,cutoff){
if (!cutoff) cutoff = 220; // alpha threshold
var dx = Math.abs(p2.x - p1.x), dy = Math.abs(p2.y - p1.y),
sx = p2.x > p1.x ? 1 : -1, sy = p2.y > p1.y ? 1 : -1;
var x0 = Math.min(p1.x,p2.x), y0=Math.min(p1.y,p2.y);
var pixels = ctx.getImageData(x0,y0,dx+1,dy+1).data;
var hits=[], over=null;
for (x=p1.x,y=p1.y,e=dx-dy; x!=p2.x||y!=p2.y;){
var alpha = pixels[((y-y0)*(dx+1)+x-x0)*4 + 3];
if (over!=null && (over ? alpha<cutoff : alpha>=cutoff)){
hits.push({x:x,y:y});
}
var e2 = 2*e;
if (e2 > -dy){ e-=dy; x+=sx }
if (e2 < dx){ e+=dx; y+=sy }
over = alpha>=cutoff;
}
return hits;
}
function randomDiamond(ctx,color){
var x = Math.round(Math.random()*(ctx.canvas.width - 100) + 50),
y = Math.round(Math.random()*(ctx.canvas.height - 100) + 50);
ctx.save();
ctx.fillStyle = color;
ctx.translate(x,y);
ctx.rotate(Math.random() * Math.PI);
var scale = Math.random()*0.8 + 0.4;
ctx.scale(scale,scale);
ctx.lineWidth = 5/scale;
ctx.fillRect(-50,-50,100,100);
ctx.strokeRect(-50,-50,100,100);
ctx.restore();
return {x:x,y:y};
}
function randomCircle(ctx,color){
ctx.save();
ctx.beginPath();
ctx.arc(
Math.round(Math.random()*(ctx.canvas.width - 100) + 50),
Math.round(Math.random()*(ctx.canvas.height - 100) + 50),
Math.random()*20 + 10,
0, Math.PI * 2, false
);
ctx.fillStyle = color;
ctx.fill();
ctx.lineWidth = 2;
ctx.stroke();
ctx.restore();
}
</script>
</body></html>