I'm creating a Firefox for Android extension and I have a problem with a XML document retrieved from a XMLHttpRequest: I can't find a way to select a node. The better solution I found is this, but I got this error when selecting with xpath on the document:
WrongDocumentError: Node cannot be used in a document other than the one in which it was created
This is my code:
var parser = Cc["#mozilla.org/xmlextras/domparser;1"].createInstance(Ci.nsIDOMParser);
var parsedXml = parser.parseFromString(xmlhttp.responseText, "text/xml");
var xpathExpression = "//td[contains(.,'Raw text')]/../td[2]/pre";
var res = window.content.document.evaluate(xpathExpression, parsedXml, null, window.XPathResult.STRING_TYPE , null);
If I replace the "evaluate" with the next line:
var res = parsedXml.selectSingleNode(xpathExpression);
Then I get the following error:
[JavaScript Error: "parsedXml.selectSingleNode is not a function"
{file: "resource://gre/modules/addons/XPIProvider.jsm ->
jar:file:///data/data/org.mozilla.fennec/files/mozilla/ggz9zzjr.default/extensions/qrReader#qrReader.xpi!/bootstrap.js"
line: 61}]
Well, the name of the exception, WrongDocumentErrort gave it away. You're trying to call .evaluate() on a DOM (Document) that does not belong to the same Document .evaluate() is bound to.
The nsIDOMParser will actually return a new XMLDocument that has an .evaluate() itself, which you'll have to use.
var parser = Cc["#mozilla.org/xmlextras/domparser;1"].
createInstance(Ci.nsIDOMParser);
var parsedDoc = parser.parseFromString(
'<?xml version="1.0"?>\n<doc><elem>Raw text</elem></doc>',
"text/xml");
var xpathExpression = "//elem[contains(.,'Raw text')]";
var res = parsedDoc.evaluate(
xpathExpression,
parsedDoc,
null,
XPathResult.STRING_TYPE,
null);
console.log(res, res.stringValue);
Instead using nsIDOMParser, since your content seems to be originating from XHR anyway, and seems to be (X)HTML (indicated by your expression), it might be better to use XHR.responseType = "document" instead, which will parse a DOM from the response using the HTML parser.
var req = new XMLHttpRequest();
req.onload = function() {
var doc = req.response;
var h1 = doc.evaluate("//h1", doc, null, XPathResult.STRING_TYPE, null);
console.log(h1.stringValue);
// Alternative in some cases
h1 = doc.querySelector("h1");
console.log(h1.textContent);
};
req.open("GET", "http://example.org/");
req.responseType = "document"; // Parse as text/html
req.send();
parseFromString returns a document object. selectSingleNode is not a document function. Can't you select a node using the standard document.getElementsByClassname, document.getElementById, or document.querySelector?
try
var window = parsedXml.ownerDocument.defaultView;
var res = window.content.document.evaluate(xpathExpression, parsedXml, null, window.XPathResult.STRING_TYPE , null);
Related
I'm using XMLParser to get data from a tag.
This tag is like this :
<tagName elem="XXX"></tagName>
I want to get : XXX
According to documentation, I'm doing like :
parseMyXML = new DOMParser();
xmlDoc = parseMyXML.parseFromString(contentXML,"text/xml");
var code_XXX = xmlDoc.getElementsByTagName("tagName")[0].childNodes[0].nodeValue;
I have an error : Uncaught (in promise) TypeError: Cannot read property 'nodeValue' of undefined
What I need is to go into tagName and to get the contain of elem
It's an attribute not a child node.
xmlDoc.getElementsByTagName("tagName")[0].getAttribute("elem");
With jQuery you can do something like this.
var $xml = $.parseXML(xml),
value = $xml.find('tagName').text();
if you're using plain JS you should parse xml like this.
if (window.DOMParser) {
// code for modern browsers
parser = new DOMParser();
xmlDoc = parser.parseFromString(text,"text/xml");
} else {
// code for old IE browsers
xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async = false;
xmlDoc.loadXML(text);
}
I'm trying to search for particular nodes in office xml. I'm using wgxpath for it. Here is my code. But every time empty result is returned. Probably wgxpath doesn't work with namespaces (although it accepts nsResolver as parameter)
Word.run(function (ctx) {
var xml = ctx.document.body.getOoxml();
ctx.sync().then(function () {
try {
var parser = new DOMParser();
var doc = parser.parseFromString(xml, "text/xml");
var win = { 'document': doc };
wgxpath.install(win);
var nsResolver = doc.createNSResolver(doc.ownerDocument == null ? doc.documentElement : doc.ownerDocument.documentElement);
var result = doc.evaluate("/pkg:package/pkg:part/pkg:xmlData/w:styles/w:docDefaults/w:pPrDefault/w:pPr/w:spacing", doc, nsResolver, win.XPathResult.ANY_TYPE, null);
var items = [];
try {
var item = result.iterateNext();
while (item) {
items.push(item);
item = result.iterateNext();
}
}
catch (e) {
reject(e);
}
resolve(items);
});
});
I've also tried another example with simple xml:
var parser = new DOMParser();
var test = "<pkg:count xmlns:pkg='http://schemas.microsoft.com/office/2006/xmlPackage'><pkg:a>1</pkg:a></pkg:count>";
var doc = parser.parseFromString(test, "text/xml");
var win = { 'document': doc };
wgxpath.install(win);
var nsResolver = function(prefix) {
var ns = {
'pkg': 'http://schemas.microsoft.com/office/2006/xmlPackage'
};
return ns[prefix] || null;
}
var result = doc.evaluate('/pkg:count/pkg:a', doc, nsResolver, win.XPathResult.ANY_TYPE, null);
Result is the same: with prefixes empty result is returned, but if I remove prefixes, evaluation works.
How can I evaluate xml with namespaces in office add ins? Any other solution? I've tried to use ActiveXObject("Microsoft.XMLDOM"), but get "Can't create object" exception.
The built in XML parsing methods do support namespaces, but not xpath.
E.g. Document.getElementsByTagNameNS
I'm able to parse XML documents in the browser and get error messages using the following code:
// Internet Explorer
var xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.loadXML(txt);
var hasError = (xmlDoc.parseError.errorCode != 0);
// Firefox, Opera, Webkit
var parser = new DOMParser();
var xmlDoc = parser.parseFromString(text, "text/xml");
var hasError = (xmlDoc.getElementsByTagName("parsererror").length > 0);
But I need to be able to parse an HTML document and check for errors.
Is there an HTML parser I can access in the same way as I'm accessing the XML parser?
UPDATE:
It looks like at least in Firefox I can attempt to create an HTML dom and parse the contents. But it doesn't seem to throw any error or return an error message no matter what I throw at it:
var text = "<html><body><label>test</labe></body></html>";
var parser = new DOMParser();
//var func = function (e) { console.log(e); };
//parser.attachEvent("InvalidStateError", func); // no attachEvent, no addEventListener
var htmlDoc = parser.parseFromString(text, "text/html");
var hasError = (htmlDoc.getElementsByTagName("parsererror").length > 0);
console.log("Has error: " + hasError); // also false. no errors ever.
console.log(htmlDoc);
This page, this page and this page helped me understand the DOMParser class more.
I need to transform an xml doc into another xml doc using xslt in ie9 or above versions.
I am trying to transform an xml doc using xslt in ie9. When i used transformNode() function it is working fine in ie8(code:: resultDocument = XML.transformNode(XSL);) but in ie9 transformNode function is not defined showing error::SCRIPT438: Object doesn't support property or method 'transformNode'
I found a solution for ie9 as given below
if (window.ActiveXObject) {
console.log('inside hi');
var xslt = new ActiveXObject("Msxml2.XSLTemplate");
var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument");
xslDoc.loadXML(xsltDoc.xml);
console.log(xslt.styleSheet);
xslt.stylesheet = xslDoc;
var xslProc = xslt.createProcessor();
xslProc.input = xmlDoc;
xslProc.transform();
return xslProc.output;
}
but when i run this i get an error: SCRIPT16389: The stylesheet does not contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document.
I am new to javascript/jquery. Can anyone please help me in resolving this. If there is any other function either in javascript or jquery it would be helpful.
Thanks in advance
With earlier versions of IE the responseXML document used to be an MSXML DOM document and MSXML implements XSLT and transformNode. With newer IE versions the responseXML document gives you an IE DOM document and IE does not implement XSLT and transformNode for its DOM document/nodes. Nor does an IE DOM document have a property xml you are trying to use in xslDoc.loadXML(xsltDoc.xml);.
Try changing that part of the code to
if (typeof XMLSerializer !== 'undefined') {
xslDoc.loadXML(new XMLSerializer().serializeToString(xsltDoc));
// now use xslDoc here
}
A different option is to use xslDoc.loadXML(xmlHttp.responseText); if you still have access to the XMLHttpRequest. There is also an option to ensure you get an MSXML responseXML, see try { xhr.responseType = 'msxml-document'; } catch(e){} line in http://blogs.msdn.com/b/ie/archive/2012/07/19/xmlhttprequest-responsexml-in-ie10-release-preview.aspx.
Your whole approach to object checking in your code is wrong, check for the object or property or method you want to use (e.g. if (typeof XSLTProcessor !== 'undefined') { // now use XSLTProcessor here }), not for completely different object like document.implementation.
I too had the SCRIPT16389: The stylesheet does not contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document error in IE9/10/11. I've found the following fixes it:
your code:
if (window.ActiveXObject) {
console.log('inside hi');
var xslt = new ActiveXObject("Msxml2.XSLTemplate");
var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument");
xslDoc.loadXML(xsltDoc.xml);
console.log(xslt.styleSheet);
xslt.stylesheet = xslDoc;
var xslProc = xslt.createProcessor();
xslProc.input = xmlDoc;
xslProc.transform();
return xslProc.output;
}
working code:
if (window.ActiveXObject) {
console.log('inside hi');
var xslt = new ActiveXObject("Msxml2.XSLTemplate");
var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument");
xslDoc.load(xsltDoc);
console.log(xslt.styleSheet);
xslt.stylesheet = xslDoc;
var xslProc = xslt.createProcessor();
xslProc.input = xmlDoc;
xslProc.transform();
return xslProc.output;
}
The change being line 6 - replace 'loadXML' with 'load' and 'xsltDoc.xml' with just 'xsltDoc'. Let me know how it goes!
Question: How do I syntax-check my XML in modern browsers (anything but IE)?
I've seen a page on W3Schools which includes an XML syntax-checker. I don't know how it works, but I'd like to know how I may achieve the same behavior.
I've already performed many searches on the matter (with no success), and I've tried using the DOM Parser to check if my XML is "well-formed" (also with no success).
var xml = 'Caleb';
var parser = new DOMParser();
var doc = parser.parseFromString(xml, 'text/xml');
I expect the parser to tell me I have an XML syntax error (i.e. an unclosed name tag). However, it always returns an XML DOM object, as if there were no errors at all.
To summarize, I would like to know how I can automatically check the syntax of an XML document using JavaScript.
P.S. Is there any way I can validate an XML document against a DTD (using JS, and not IE)?
Edit: Here is a more concise example, from MDN:
var xmlString = '<a id="a"><b id="b">hey!</b></a>';
var domParser = new DOMParser();
var dom = domParser.parseFromString(xmlString, 'text/xml');
// print the name of the root element or error message
dump(dom.documentElement.nodeName == 'parsererror' ? 'error while parsing' : dom.documentElement.nodeName);
NoBugs answer above did not work with a current chrome for me. I suggest:
var sMyString = "<a id=\"a\"><b id=\"b\">hey!<\/b><\/a>";
var oParser = new DOMParser();
var oDOM = oParser.parseFromString(sMyString, "text/xml");
dump(oDOM.getElementsByTagName('parsererror').length ?
(new XMLSerializer()).serializeToString(oDOM) : "all good"
);
You can also use the package fast-xml-parser, this package have a validate check for xml files:
import { validate, parse } from 'fast-xml-parser';
if( validate(xmlData) === true) {
var jsonObj = parse(xmlData,options);
}
Just F12 to enter developer mode and check the source there you can then search validateXML and you are to locate a very long complete XML checker for your reference.
I am using react and stuff using the DOMParser to present the error message as:
handleXmlCheck = () => {
const { fileContent } = this.state;
const parser = new window.DOMParser();
const theDom = parser.parseFromString(fileContent, 'application/xml');
if (theDom.getElementsByTagName('parsererror').length > 0) {
showErrorMessage(theDom.getElementsByTagName('parsererror')[0].getElementsByTagName('div')[0].innerHTML);
} else {
showSuccessMessage('Valid Xml');
}
}
Basic xml validator in javscript. This code may not valid for advance xml but basic xml.
function xmlValidator(xml){
// var xml = "<note><to>Tove</to><from>Jani</from><heading>Reminder</heading><body>Don't forget me this weekend!</body></note>";
while(xml.indexOf('<') != -1){
var sub = xml.substring(xml.indexOf('<'), xml.indexOf('>')+1);
var value = xml.substring(xml.indexOf('<')+1, xml.indexOf('>'));
var endTag = '</'+value+'>';
if(xml.indexOf(endTag) != -1){
// console.log('xml is valid');
// break;
}else{
console.log('xml is in invalid');
break;
}
xml = xml.replace(sub, '');
xml = xml.replace(endTag, '');
console.log(xml);
console.log(sub+' '+value+' '+endTag);
}
}
var xml = "<note><to>Tove</to><from>Jani</from><heading>Reminder</heading><body>Don't forget me this weekend!</body></note>";
xmlValidator(xml);
/**
* Check if the input is a valid XML file.
* #param xmlStr The input to be parsed.
* #returns If the input is invalid, this returns an XMLDocument explaining the problem.
* If the input is valid, this return undefined.
*/
export function xmlIsInvalid(xmlStr : string) : HTMLElement | undefined {
const parser = new DOMParser();
const dom = parser.parseFromString(xmlStr, "application/xml");
// https://developer.mozilla.org/en-US/docs/Web/API/DOMParser/parseFromString
// says that parseFromString() will throw an error if the input is invalid.
//
// https://developer.mozilla.org/en-US/docs/Web/Guide/Parsing_and_serializing_XML
// says dom.documentElement.nodeName == "parsererror" will be true of the input
// is invalid.
//
// Neither of those is true when I tested it in Chrome. Nothing is thrown.
// If the input is "" I get:
// dom.documentElement.nodeName returns "html",
// doc.documentElement.firstElementChild.nodeName returns "body" and
// doc.documentElement.firstElementChild.firstElementChild.nodeName = "parsererror".
//
// It seems that the parsererror can move around. It looks like it's trying to
// create as much of the XML tree as it can, then it inserts parsererror whenever
// and wherever it gets stuck. It sometimes generates additional XML after the
// parsererror, so .lastElementChild might not find the problem.
//
// In case of an error the <parsererror> element will be an instance of
// HTMLElement. A valid XML document can include an element with name name
// "parsererror", however it will NOT be an instance of HTMLElement.
//
// getElementsByTagName('parsererror') might be faster than querySelectorAll().
for (const element of Array.from(dom.querySelectorAll("parsererror"))) {
if (element instanceof HTMLElement) {
// Found the error.
return element;
}
}
// No errors found.
return;
}
(Technically that's TypeScript. Remove : string and : HTMLElement | undefined to make it JavaScript.)