This piece of code was provided as a working solution to a previous question on flow control:
// an object to maintain a list of functions that can be called in sequence
// and to manage a completion count for each one
function Sequencer() {
this.list = [];
this.cnt = 0;
}
Sequencer.prototype.add = function(/* list of function references here */) {
this.list.push.apply(this.list, arguments);
}
Sequencer.prototype.next = function() {
var fn = this.list.shift();
if (fn) {
fn(this);
}
}
Sequencer.prototype.increment = function(n) {
n = n || 1;
this.cnt += n;
}
// when calling .decrement(), if the count gets to zero
// then the next function in the sequence will be called
Sequencer.prototype.decrement = function(n) {
n = n || 1;
this.cnt -= n;
if (this.cnt <= 0) {
this.cnt = 0;
this.next();
}
}
// your actual functions using the sequencer object
function test_1(seq, arg1, arg2, arg3) {
seq.increment();
// do something with arg1, arg2 and arg3
seq.decrement();
}
function test_2(seq) {
seq.increment();
// do something
seq.decrement();
}
function test_3(seq) {
seq.increment();
// do something
seq.decrement();
}
// code to run these in sequence
var s = new Sequencer();
// add all the functions to the sequencer
s.add(test_1, test_2, test_3);
// call the first one to initiate the process
s.next();
How can I pass arguments to test_1() when adding the function to s? For example (which obviously doesn't work):
s.add(test_1(10,'x',true), test_2);
Thanks
If the order was different, i.e. test_1(arg1, arg2, arg3, seq), you could use .bind:
s.add(test_1.bind(null, 10,'x',true) , test_2, test_3);
If you can't change the the order, pass an other function which in turn calls test_1:
s.add(function(seq) { test_1(seq, 10,'x',true); }, test_2, test_3);
You can access a function's given arguments with Function.arguments.
Related
I have been working to create a function that given another function will make that second function only callable once. not unlike the _.once() function.
the desired outcome is the following:
const oneTimeFunction = _.once(function(string) { string.split(''); })
oneTimeFunction('hello')
//returns: 'olleh', and if called again it would have no effect returning the same thing a the original call.
Currently this is what I have:
_.once = function (func) {
var called = 0;
let args = null;
if (arguments.length > 1) {
args = Array.prototype.slice.call(arguments,1);
}
return function () {
if (called === 0) {
console.log('being called');
called ++;
if (!args) {
console.log('without apply');
return func.call(arguments);
} else {
console.log('with apply');
return func.apply(this,args);
}
} else {
console.log('this has been called');
return null;
}
};
};
I am running into a wall as it is returning error type undefined even with everything I have tried. Any help, even to get to where it can call the function regardless of the one time only stipulation? Thanks!
create a variable that count how much this function is called
let count = 0;
function once(str) {
if(count < 1){
count++;
return str.split("").reverse().join("");
}
else return str;
}
console.log(once("hello")); // olleh
console.log(once("hello")); // hello
console.log(once("hello")); // hello
In reading your question, I'm seeing that you would like to always return the first value on subsequent calls:
"if called again it would have no effect returning the same thing a[s] the original call."
So I believe you want to do something like this:
function computeOnce(myFn) {
let origVal = undefined;
return function (...args) {
// if this is not set, this is the first call
if (!origVal) {
// execute the function and store it's return value
origVal = myFn(...args);
}
return origVal;
}
}
I have an array of functions, as in:
funcArray = [func1, func2, func3];
When in a given function, I want to execute the next function in the array. How do I do this? Here is my basic skeleton:
function func1() {
// I get current function caller
var currentFunc = func1.caller;
// I want to execute the next function. Happens to be func2 in the example.
}
I cannot use indexOf function, as one would for an array of strings or numbers.
NOTE: This question appears to be similar to this and the one it refers to. However, it is a different question.
I want to alter the sequence of processing by merely modifying the array. That's the goal. A possibly more efficient approach would be appreciated.
Clarification: Based upon some of the comments:
funcArray is global.
The goal is to implement middleware for a Node.js HTTP module in as simple and efficient a manner as possible without using any third-party modules.
Unless func1 closes over funcArray, you cannot have it reach out and find func2 and execute it, nor should you. Even if func1 does close over funcArray, it would be poor separation of concerns for func1 to reach out and find itself in funcArray and then execute func2.
Instead, have other code that's in charge of running the functions.
If they're synchronous
If the functions complete their work synchronously, then it's simply:
funcArray.forEach(fn => fn());
or
for (const fn of funcArray) {
fn();
}
or if the result of one function should be passed to the next, you can use reduce:
const finalResult = funcArray.reduce((previousResult, fn) => fn(previousResult), undefined);
...where undefined is the value to pass to func1.
If they're asynchronous
If they don't do their work synchronously, you'll need to provide them a way to notify their caller that they've completed their work. Promises are a good, standard way to do that, but you could use simple callbacks instead.
If you make them return promises, for instance, you can use the old promise reduce trick:
funcArray.reduce((p, fn) => {
return p.then(() => {
fn();
});
}, Promise.resolve());
or if the result of one function should be passed to the next:
funcArray.reduce((p, fn) => {
return p.then(fn);
}, Promise.resolve());
You can provide an argument to Promise.resolve to set the value to pass to func1 (without one, it'll receive undefined).
You can bind to the function the index where it is in the array so you can use this index to get and call the next function:
var funcArray = [func1, func2];
var boundFuncArray = funcArray.map((f, i) => f.bind(null, i));
boundFuncArray[0]();
function func1(nextFunctionIndex) {
console.log('func1 called');
// Execute next function:
var nextFunc = boundFuncArray[nextFunctionIndex + 1];
nextFunc && nextFunc();
}
function func2(nextFunctionIndex) {
console.log('func2 called');
// Execute next function:
var nextFunc = boundFuncArray[nextFunctionIndex + 1];
nextFunc && nextFunc();
}
As T.J Crowder stated in the comment below, you can also bind the next function to the current one:
var funcArray = [func1, func2];
var boundFuncArray= funcArray.map((f, i, arr) => f.bind(null, arr[i + 1]));
boundFuncArray[0]();
function func1(nextFunc) {
console.log('func1 called');
// Execute next function:
nextFunc && nextFunc();
}
function func2(nextFunc ) {
console.log('func2 called');
// Execute next function:
nextFunc && nextFunc();
}
You can get the current function's name with arguments.callee.name, loop through the array of functions, and call the next function:
funcArray = [func1, func2, func3];
// Only func1() and func2() will be documented since the others have repeating code
function func1() {
// show the current function name
console.log(arguments.callee.name);
// loop the array of functions
for(var i = 0; i < funcArray.length; ++i)
{
// when the current array item is our current function name and
// another function exists after this then call it and break
if(funcArray[i] === arguments.callee && funcArray[i+1])
{
funcArray[i+1]();
break;
}
}
}
function func2() {
console.log(arguments.callee.name);
// some logic which switches our next function to be func4()
funcArray[2] = func4;
for(var i = 0; i < funcArray.length; ++i)
{
if(funcArray[i] === arguments.callee && funcArray[i+1])
{
funcArray[i+1]();
break;
}
}
}
function func3() {
console.log(arguments.callee.name);
for(var i = 0; i < funcArray.length; ++i)
{
if(funcArray[i] === arguments.callee && funcArray[i+1])
{
funcArray[i+1]();
break;
}
}
}
function func4() {
console.log(arguments.callee.name);
for(var i = 0; i < funcArray.length; ++i)
{
if(funcArray[i] === arguments.callee && funcArray[i+1])
{
funcArray[i+1]();
break;
}
}
}
// call the first function
funcArray[0]();
Output:
func1
func2
func4
I have solved it this way:
// Adding next options to array
function addNext(array) {
array.last = 1
Object.defineProperty(array, 'next', {get:
function() {
if(this.last < this.length) {
this.last++
return this[this.last-1]
} else {
this.last = 1
return () => {}
}
}
});
}
// The functions for array (has to be function and not arrow function)
function first(param) {
console.log('first',param)
return this.next(param)
}
function second(param) {
console.log('second',param)
return this.next(param)
}
function third(param) {
console.log('third',param)
return this.next(param)
}
// The array
let fns = [first,second,third]
// Adding next option to array
addNext(fns)
// Run first function from array
fns[0]('test')
I dont know if your functions require certain parameters but this is the first thing that came to my mind.
var functArray = [
function() {
console.log("function1 executed");
},
function() {
console.log("function2 executed");
},
function() {
console.log("function3 executed");
},
function() {
console.log("function4 executed");
}];
functArray.forEach(function(x){
x();
});
The accepted answer and other comments did help me, but the way I implemented it is as follows:
//The functions are defined as variables.
//They do not get hoisted, so must be defined first.
func1 = function (arg1, arg2) {
//Code to do whatever...
...
//Execute the next function.
//The name of the function is returned by executing nextFunc()
global[nextFunc()](arg1, arg2, arg3);
}
func2 = function (arg1) { //Note different type of args
...
}
//Note that this is an array of strings representing function names.
funcArray = ["func1", "func2", "func3",...]
//Start the execution...
func1(arg1, arg2);
function nextFunc() {
var currentFuncName = nextFunc.caller.name;
var index = funcArray.indexOf(currentFuncName);
if (index < funcArray.length)
return funcArray[index+1];
}
The sequence of functions to be executed is easily managed through the array funcArray. The number or type of arguments is not fixed for each function. Additionally, the functions control if they should stop the chain or continue with the next function.
It is very simple to understand requiring basic Javascript skills. No overheads of using Promises.
"global" gets replaced by "window" for browser. This is a Node.js implementation. The use of function names in the array will, however, break if you minify the JS code. As I am going to use it on the server, I do not expect to minify it.
You can do it in this way with promise.all if your functions to be executed in parallel.
let toBeExecutedList = [];
toBeExecutedList.push(() => this.addTwoNumber(2, 3));
toBeExecutedList.push(()=>this.square(2));
And Then wherever you want to use them, do it like this:
const resultArr = await Promise.all([
toBeExecutedList.map(func => func()),
]);
I am learning JavaScript and got a bit confused with the following exercise. I did had to create a filter that would accept another functions as a sorting method. The thing that I cant understand a bit is how exactly the for loop passes the value to the x. Can you please explain?
function filter(arr, func) {
var result = [];
for (var i = 0; i < arr.length; i++) {
var value = arr[i];
if (func(value)) {
result.push(value);
}
}
return result
}
function inBetween(a, b) {
return function(x) {
return a <= x && x <= b;
}
}
function inArray(arr) {
return function(x) {
console.log(x)
return arr.indexOf(x) != -1;
}
}
var arr = [1, 2, 3, 4, 5, 6, 7];
alert(filter(arr, function(a) {
return a % 2 == 0
})); // 2,4,6
alert( filter(arr, inBetween(3, 6)) ); // 3,4,5,6
alert( filter(arr, inArray([1, 2, 10])) ); // 1,2
I'll take this line as example:
filter(arr, inArray([1, 2, 10])) );
inArray is called with arr = [1, 2, 10].
It returns the following (anonymous) function, for that particular arr:
function (x) {
return arr.indexOf(x) != -1;
}
So the original line now can be pictured as:
filter(arr, function (x) {
return [1, 2, 10].indexOf(x) != -1;
});
Now filter is called with func set to that anonymous function. The following code calls that function:
if (func(value)) {
result.push(value);
}
So when this func is called, this really means the above anonymous function is called, and the parameter x gets set to value at the moment of the call. It is just like with any other function call, the parameters of the function get the values of the arguments in the actual call.
Your filter function accepts the array to filter, and a function that does the filtering. In this part:
for (var i = 0; i < arr.length; i++) {
var value = arr[i];
if (func(value)) { //here, you invoke the function on the array's values
result.push(value);
}
}
So if, for instance, we look at the inBetween(3, 6) function, which is this:
return function(x) {
return 3 <= x && x <= 6;
}
(If you don't understand this part, read some more about Closures)
So now that function is simply a function that accepts a value and returns true/false on whether or not it's between 3 & 6.
You eventually get an invocation on each of the array's values (1, 2, 3 ... 7) with the above function.
Same goes for all other functions you listed.
In this line:
filter(arr, inBetween(3, 6))
You are not "passing a function", but passing the result from a function call. The result is another (anonymous/unnamed) function.
From this line:
function filter(arr, func) {
We know name the function passed as an argument to filter is named func, then:
if (func(value)) {
executes this function.
In JavaScript, a function is just an object like other objects. To differentiate "function object reference" from "function calls", you can look for ().
inBetween is a function object reference, inBetween(x, y) means calling this function.
Anonymous functions can be defined, assigned to a variable, and passed as an argument as well. It may be executed instantly after definition as well:
function() {
alert("called!");
}();
This may look exotic to people new to JavaScript though.
This problem is giving me trouble:
Write a function, once, (see: http://underscorejs.org/#once) that
takes a function and returns a version of that function which can only
be called once. [Hint: you need a closure] You probably don't want to
be able to double charge someone's credit card. Here is an example of
how to use it:
var chargeCreditCard = function(num, price){
//charges credit card for a certain price
};
var processPaymentOnce = once(chargeCreditCard);
processPaymentOnce(123456789012, 200);
Here's how I tried to solve it:
var once = function(func) {
var invoked = 0;
return function() {
if (invoked === 0) {
invoked++;
return func();
}
};
};
The only problem I can see is you are not passing the arguments to the called function. You can use the arguments object and Function.apply() to do this.
var once = function (func) {
var invoked = 0;
return function () {
if (invoked === 0) {
invoked++;
return func.apply(this, arguments);
}
};
};
Demo: Fiddle
You are almost in the right path but you could also store the return value, pass the args and provide the this context:
function once(func) {
var val,
count = 2;
return function () {
if (--count > 0) {
val = func.apply(this, arguments);
} else {
//performance concern
func = null;
}
return val;
};
}
This is what I have borrowed from lodash to use in my codebase.
It is also worth noting that, passing the count variable as an argument would also let us to use it in a way that the func gets called less than count times
I have the following two functions:
var abc;
function updateNum() {
abc=0;
g.dbm.transaction("leagues").objectStore("leagues").openCursor(null, "prev").onsuccess = function (event) {
var teams, i;
team.filter({
attrs: ["tid", "abbrev", "region", "name", "cid"],
seasonAttrs: ["winp", "playoffRoundsWon"],
season: g.season
}, function (teams) {
// Sort teams by playoffs and winp, for first round
teams.sort(function (a, b) {
if (a.playoffRoundsWon < b.playoffRoundsWon) {
return -1;
}
if (a.playoffRoundsWon > b.playoffRoundsWon) {
return 1;
}
return a.winp - b.winp;
});
abc+=1;
});
};
}
function getNum() {
return abc;
}
What I am trying to do is update the variable abc inside the callback function and then return it. I do this by first calling the updateNum() function in another file. Then I assign a variable to the value of getNum()
Here is how a sample code would look like:
myFile.updateNum();
var number = myFile.getNum();
I am currently unable to return the updated value of num. number keeps returning 0 (the default value) instead of the newly updated value (which is 1).
How can I get it to show an updated value? Please let me know if I need to add any more information.
Well, if updateNum is async, it would have to take a callback as argument so that you can be notified when the number was updated.
E.g.
var num = 0;
function updateNumAsync(callback) {
setTimeout(function () {
num = 1;
callback && callback(num); //call the callback if provided
}, 500);
}
updateNumAsync(function (num) {
console.log(num); //updated num
});
Here is a general pattern for using an asynchronous function with a callback to pass the asynchronous results around. What is team.filter? You will need to design your code such that the asynchronous portion calls a callback() function that was passed to the enclosing function.
If filtering gives you problems you may want to look at https://github.com/caolan/async#filterarr-iterator-callback
(function main(){
getNum(function(err, abc){
console.log('thx for playing '+abc)
});
})();
function getNum(anotherCallback) {
// Whatever code relies on the result of an asynchronous function must be
// placed inside the callback function
countTeams(function(abc){
console.log('countTeams completed, abc='+abc);
var err = null;
anotherCallback(err, abc);
});
};
function countTeams(callback){
var abc=0;
g.dbm.transaction("leagues").objectStore("leagues").openCursor(null, "prev").onsuccess = function (event) {
var teams, i;
// I don't know what this filter function does, I am assuming it's synchronous
team.filter({
attrs: ["tid", "abbrev", "region", "name", "cid"],
seasonAttrs: ["winp", "playoffRoundsWon"],
season: g.season
}, function (teams) {
// Sort teams by playoffs and winp, for first round
teams.sort(function (a, b) {
if (a.playoffRoundsWon < b.playoffRoundsWon) {
return -1;
}
if (a.playoffRoundsWon > b.playoffRoundsWon) {
return 1;
}
return a.winp - b.winp;
});
abc+=1;
});
return callback(abc); // 0 or n depending on what team.filter does
};
};