When i select the radio button then i want to hide one div and when i uncheck the radio button then i want to show that div . please if anyone know. I want to hide div on check the radio button.
<input type="radio" id="fix" name="price" checked="checked" value="fix">
<div id="hour">
<input type="text" name="rs"/>
</div>
You can use the change() function from jQuery that triggers when the selector has been changed. Then just compare the val() with your value, and take action.
$("input[type='radio']").change(function() {
if ($(this).val() == "fix") {
// show div
} else {
// hide div
}
});
You have single radio button you probably want to use checkbox instead. As single radio button could not be unchecked.
Live Demo
Html
<input type="checkbox" id="fix" name="price" checked="checked" value="fix">
Javascript
$('#fix').change(function(){
$('[name=rs]')[0].style.display = this.checked ? 'block' : 'none';
});
$("input[type='radio']").change(function() {
if ($(this).val() == "fix") {
document.getElementById("hour").style.display = '';
} else {
document.getElementById("hour").style.display = 'none';
}
});
Simple solution.
We can't uncheck a radio button when there is only one.
So, change the input type to checkbox. Then you can use this CSS:
:checked + #hour{
display: none;
}
Working Fiddle
Related
I'm trying to implement a radio button, which if clicked should get more options for the user to fill in.
Here's what I've tried.
<script>
function addmentor() {
if ( document.getElementById("type_Computer").checked ) {
document.getElementById('nextSetOfComputerOptions').style.display = "";
} else {
document.getElementById('nextSetOfComputerOptions').style.display = "none";
}
}
</script>
<input type="radio" name="type" id="type_computer" value="Computer" onClick="addmentor()">Add Mentor</button>
<div id="nextSetOfComputerOptions" style="display:none;">
.
.
</div>
The above code doesn't work. When I am clicking the radio button, nothing happens, the part of the form is always hidden.
EDIT: I originally misunderstood the question and have now adjusted my answer.
Additionally, I have also included a function that will hide your input if another radio button is clicked.
See the snippet below:
//your checkbox
var checkbox = document.getElementById("type_computer");
//your div
var inputDiv = document.getElementById("nextSetOfComputerOptions");
//function that will show hidden inputs when clicked
function addmentor() {
if (checkbox.checked = true) {
inputDiv.style.display = "block";
}
}
//function that will hide the inputs when another checkbox is clicked
function hideInputDiv() {
inputDiv.style.display = "none";
}
<input type="radio" name="type" id="type_computer" value="Computer" onChange="addmentor();" ">Add Mentor</input>
<input type="radio" name="type" onClick="hideInputDiv();">Other radio input</input>
<div id="nextSetOfComputerOptions" style="display: none;">
<input placeholder="PC"></input>
<input placeholder="Mac"></input>
</div>
I'm using JavaScript to show/hide additional fields in my form depending on whether the relevant checkbox is clicked. The fields are hidden and they do show when the checkbox is ticked, but DO NOT hide when it is un-ticked. However, the fields do hide when I tick the checkbox again.
I have the checkbox with id='cb_post' and an onclick command to fetch showDiv() from my external javascript file. I also have the hidden field with id='hiddenDiv'.
My javascript script is simple:
function showDiv() {
if (document.getElementById('hiddenDiv').style.display == 'block') {
(document.getElementById('hiddenDiv').style.display = 'none');
} else {
document.getElementById('hiddenDiv').style.display = 'block';
}
}
Can anyone advise on how to hide the fields when the checkbox is unticked?
You should think about using jQuery
$("#hiddenDiv").hide();
$("#hiddenDiv").show();
and something nicer
$("#hiddenDiv").fadeOut();
$("#hiddenDiv").fadeIn();
I think using jQuery toggle would fit better for your problem:
<input type="checkbox" id="cb_post">
<div id = "hiddenDiv">
<li>Toggle me</li>
</div>
$("#cb_post").on('click', function(){
$("#hiddenDiv").toggle();
});
Maybe using the event onchange instead of onclick would be more elegant.
https://jsfiddle.net/qqL0sxxs/
Here is working code :
var chebx = document.getElementsByClassName('toggleField');
for (var i = 0; i < chebx.length; i++) {
chebx[i].addEventListener('click', toggleField, false);
}
function toggleField() {
var field = document.getElementById(this.dataset.target);
if (field) {
switch (this.checked) {
case true:
if (field.classList.contains('hide')) {
field.classList.remove('hide');
} else {
field.classList.add('hide');
}
break;
default:
break;
}
}
}
.hide {
display: none;
}
<lable for='toggleField'>Toggle Field</lable>
<input type="checkbox" data-target='field1' class='toggleField'>
<input type='text' class='hide' id='field1' />
<hr>
<lable for='toggleField'>Toggle Field</lable>
<input type="checkbox" data-target='field2' class='toggleField'>
<input type='text' class='hide' id='field2' />
I have an input field that only shows when the option "Other" is checked. The input field fades out when I uncheck the "Other" checkbox, but I would also like the input field to fade out say if, instead of unchecking the "Other" checkbox I check another checkbox of the same group. Therefore, the "Other" input field should not be visible unless "Other" is checked. I have the javascript partially working, but when I check another checkbox the "Other" input field stays visible.
HTML
<input type="checkbox" id="residence_check" name="found"/>
<label for="residence_check">
Residence
</label>
<input type="checkbox" id="tradeshow_check" name="found"/>
<label for="tradeshow_check">
Tradeshow
</label>
<input type="checkbox" id="office_check" name="found"/>
<label for="office_check">
Office Building
</label>
<input type="checkbox" id="check_other" value="found_other" name="found"/>
<label for="check_other">
Other
</label>
<input type="text" id="check_input" placeholder="Other"/>
Javascript
$('#check_other').change(function() {
if($(this).is(":checked")) {
$('#check_input').fadeIn();
} else {
$('#check_input').fadeOut('fast');
}
});
From what I gather from your use case is that you don't want to use checkboxes, but radio buttons. If that is the case, this would be a good way to implement what you want:
http://jsfiddle.net/AeP58/1/
$('input[type=radio]').on('change', function() { //event on all radio buttons
if($(this).attr('id') == 'check_other' && $(this).prop('checked')) {
$('#check_input').fadeIn();
} else {
$('#check_input').fadeOut('fast');
}
});
If you do want checkboxes, you could change the code a bit and probably get what you want.
If you want to have some fun with checkboxes you could try this:
function showHideOtherInput() {
console.log($(this)[0]==$('#check_other')[0]);
var shouldShow=$('[id$="_check"]:checked').length===0 && $('#check_other').prop('checked');
console.log(shouldShow);
if(shouldShow) {
$('#check_input').fadeIn();
} else {
$('#check_input').fadeOut('fast');
}
}
$('#check_input').hide(); //since nothing is selected at this point just hide the input
$('#check_other').change(showHideOtherInput);
//for each XXXX_check checkbox trigger the show or hide function
$('[id$="_check"]').each(function(ix,el){$(el).change(showHideOtherInput)});
Hope this works for you.
:)
I'm very noob in javascript. My question is how do I show the value of my radio button when click?
I have this code:
<tr><td width="10px"></td><td width="60%">Neatness</td>
<td width="40%">
<input name="neat" type="radio" class="hover-star" value="1" title="Poor"/>
<input name="neat" type="radio" class="hover-star" value="2" title="Fair"/>
<input name="neat" type="radio" class="hover-star" value="3" title="Satisfactory"/>
<input name="neat" type="radio" class="hover-star" value="4" title="Outstanding"/>
</td></tr>
Say when my 1st radio button it will show 1 or so on.. How can I achieve this? Or better yet does anyone know how to do this in jquery.
Use the jQuery class selector and attach to the click event:
$('.hover-star').click(function () {
alert($(this).val());
}
Here's a working jsFiddle fiddle.
Alternatively, you could attach to the change event.
$('.hover-star').change(function () {
alert($(this).val());
}
Take a look at the jQuery selectors documentation.
With jQuery you can bind the click event to any element with class hover-star, and use the val method to get the value. This will fire whenever any radio button is clicked (even if the selection does not change):
$(".hover-star").click(function() {
var selectedVal = $(this).val();
});
You could also use the change event, which fires whenever the selected radio button changes:
$(".hover-star").change(function() {
var selectedVal = $(this).val();
});
You say you want to "show" the value of the radio button, but as you haven't provided more details it's difficult to say where you want to show it! But the principle will be the same as I have shown above - in the event handler function you can do whatever you need to with the value.
Update based on comments
As you want to put the value into a div, you can simply do this inside the change event handler:
$("#yourDivId").text($(this).val());
Try this
$('.hover-star').click(function () {
alert($(this).val());
}
Here you go ...
$('.hover-star').click(function (){$('#someDiv').text($(this).val());
Jquery COde:
$(".hover-star").change(function() {
var selectedVal = $(this).val();
alert(selectedVal);
});
See Demo: http://jsfiddle.net/rathoreahsan/wVa7c/
I have 2 radio buttons, what I want is if a user selects the top radio button then hide a textbox.
Not sure how to bind an event to a radio button.
Something like this:
<input type="radio" name="foo" value="top" />
<input type="radio" name="foo" value="bottom" />
And in jQuery:
$('input[name=foo]').click(function() {
if($(this).val() == "top") {
$('#textbox').hide();
} else {
$('#textbox').show();
}
});
click because change doesn't seem to work correctly on IE.
This will allow you to add the event to a selected radio, in case your radio's do not have the same name.
$('checkbox-selector').click(function() {
if ($(this).is(':checked')) {
$('textbox-selector').hide();
}
else {
$('textbox-selector').show();
}
});