I have created an AJAX that can store and delete data from database. The adding of data is working fine also the delete function is working fine when the page is already refresh but the delete is not working when data is newly added or when the page is not refresh.
This how it works. When a new data is added, the data will display, the user has an option to delete the data or not. The data has a "X" to determine that it is a delete button. Right now, The delete only works when the page is refresh.
This my SAVING script, as you can see if saving is success it displays the data automatically, together with the span that has the delete function.
$("#wordlistsave").click(function()
{
var user = $("#getUser").val();
var title = $("#wordbanktitle").val();
var words = $("#wordbanklist").val();
var postID = $("#getPostID").val();
var ctrtest = 2;
var testBoxDiv = $(document.createElement('div'))
.attr("id", words);
var dataString = 'user='+user+'&title='+title+'&words='+words+'&id='+postID;
<?php if (is_user_logged_in()): ?>
$.ajax({
type: "POST",
url: "<?=plugins_url('wordlistsave.php', __FILE__ )?>",
data: dataString,
cache: false,
success: function(postID)
{
testBoxDiv.css({"margin-bottom":"5px"});
testBoxDiv.after().html('<span id="'+words+'" style="cursor:pointer">x '+postID+'</span>  <input type="checkbox" name="words[]" value="'+ words+ '">'+words );
testBoxDiv.appendTo("#test_container");
ctrtest++;
}
});
<?php else: ?>
alert('Fail.');
<?php endif; ?>
});
This is my delete function , when the user click the "X" span, the data will be deleted, but this only works after the page is refresh.
$("span").click(function()
{
var queryword=$(this).attr('id');
var postIDdel = $("#getPostID").val();
var dataString = 'queryword='+queryword+'&postID1='+postIDdel;
<?php if (is_user_logged_in()): ?>
$.ajax({
type: "POST",
url: "<?=plugins_url('worddelete.php', __FILE__ )?>",
data: dataString,
cache: false,
success: function(html)
{
$('div[id="'+queryword+'"]').remove();
}
});
<?php else: ?>
<?php endif; ?>
});
This is my HTML, the one that holds the querying of data and displaying of data.
<?php
global $wpdb;
$query_wordbanklist = $wpdb->get_results("SELECT meta_value, meta_id FROM wp_postmeta WHERE post_id = '$query_id' AND meta_key = '_wordbanklist'");
if($query_wordbanklist != null)
{
echo "<h3> Wordlist </h3>";
foreach($query_wordbanklist as $gw)
{
?> <div id="<?php echo $gw->meta_value ?>">
<span id="<?php echo $gw->meta_value ?>" style="cursor:pointer">x</span>   <input type="checkbox" name="words[]" value="<?php echo $gw->meta_value ?>"><?php echo $gw->meta_value; ?>
</div>
<?php
}
}
?>
All I wanted to achieve is to make the delete function works right after the data is stored. Right now it only works when the page is refresh. Any idea on this?
Perhaps try this...
$(document).on('click', 'span', function() {
// delete stuff in here
}
Related
I have a list of divs with unique IDs (they are inserted from my database). When I click on one of them I want to display content from my database in another div. For example, I have a div with class pizza. The query should look like this: SELECT * FROM product WHERE name = 'pizza'. So depending on what div you click you get different content. The code below doesn't work and is incomplete. I was trying to do some research myself, but I couldn't find anything useful.
//head
<script>
$(function () {
$('.product').on('click', function (e) {
e.preventDefault();
$.ajax({
type: "post",
url: 'php/recipe-container.php',
data: new FormData(this),
processData: false,
contentType: false,
success: function(response) {
$(".display_recipe").html(response);
},
error: function () {
}
});
});
});
</script>
//HTML
<div class="product" id="pizza">pizza</div>
<div class="product" id="lasagna">lasagna</div>
<div class="product" id="sushi">sushi</div>
<div class="display_recipe"></div>
// PHP (recipe-container.php)
<?php
function display_recipe(){
$con = mysqli_connect("localhost", "root", "", "cookbook");
$product = "'pizza'"; //just a placeholder
$sql = "SELECT * FROM product WHERE name = $product";
$res = mysqli_query($con,$sql);
while($row = mysqli_fetch_assoc($res)) {
$name = $row['name'];
$description = $row['description'];
$date = $row['date'];
echo $name;
echo "<br>";
echo $description;
echo "<br>";
echo $date;
echo "<br>";
}
mysqli_close($con);
}
display_recipe();
?>
Right now when I click the button nothing happens, even "pizza" placeholder doesn't work. Is there a simple way to do it?
JS file (AJAX code)
You can get the id attribute on click of the div with the class 'product' as coded below:
jQuery(function () {
jQuery('.product').on('click', function (e) {
var product = jQuery(this).attr('id');
$.ajax({
type: "post",
url: 'php/recipe-container.php',
data: {data:product},
processData: false,
contentType: false,
success: function(response) {
$(".display_recipe").html(response);
}
});
});
});
PHP file: get the posted data in this file use it in a query to fetch the result and return the result to the AJAX success handler as a response.
To fetch the data posted from the ajax in this php file you can use $_POST['data'] as stated below:
$product = $_POST['data'];
Use that variable in your sql query to fetch the result and then change the structure of your response as stated below:
//saving the html response in a variable named "response"
$response = $name.'<br>';
$response .= $description.'<br>';
$response .= $date.'<br>';
//echo response will send the response variable back to the AJAX success handler.
echo $response;
I am trying to make some code where a click of a SQL html button can display a different SQL table as a popup. I have already gotten the variable from the table to pass through using this:
echo "<td><a class='btn-floating btn-large waves-effect waves-light black' onclick='partSearch(".$product.")' value='display'><i class='material-icons'>search</i></a></td>";
The 'part search' code is as follows:
<script type="text/javascript">
function partSearch() {
$.ajax({
url: 'serv.php?id=<?php echo $product ?>',
type: 'GET',
success: function(result){
var obj = jQuery.parseJSON(result)
alert(obj)
}
})
}
</script>
Even though the variable is passed through to 'serv.php', I can't manage to get the sql data to be returned as a popup using alert. All I get is either nothing or [object, Object]. This is the SQL/php code:
<?php
include 'includes/dbh.inc.php';
$id = $_GET['id'];
$result = mysqli_query($conn,"SELECT * FROM pr WHERE product_ID='".$id."'");// test this
$rows = array();
while($r = mysqli_fetch_assoc($result)){
$rows[] = $r;
}
echo json_encode($rows);
?>
Any help is appriciated
<script type="text/javascript">
function partSearch() {
var product_id = "<?php echo $product; ?>";
$.ajax({
url: 'serv.php?id=product_id',
type: 'GET',
success: function(result){
alert(result);
}
})
}
</script>
I want to send id of element to php and create session for this.
This is piece from php file:
<?php
$sql = "SELECT id FROM products";
$result = mysqli_query($con,$sql);
while($row = mysqli_fetch_array($result)) {
?>
<tr class="table-manufacture-tr">
<td class="table-manufacture-td-statys">
<div class="warehouse-window-content-dropdown-plus2 plus">
<a class="open_item" data-id=<?php echo "\"".$row['p_id']."\"";?>
style="text-decoration: none; color: #D3D3D3;">Click</a>
</div>
</td>
</tr>
<?php
}
?>
And in this file javascript code:
$(document).on('click', '.open_item', function(event){
var data_item = this.getAttribute("data-id");
$.ajax({
url: 'get_id.php',
type: 'POST',
data-type: 'json',
data: { id: data_item },
contentType: 'application/x-www-form-urlencoded',
success: function(data){
console.log(data);
},
error: function(){
console.log("not working");
}
});
});
This is get_id.php:
<?php
session_start();
$_SESSION['item_id'] = json_encode($_POST);
header("Content-Type: application/json", true);
?>
I have tried also without content types and without json. "var data_item" prints id correct, but php doesn't create session and in console also clear(nothing).
The reason that you are not getting data in session is, you are not assigning proper value to session. Also it should be json_decode not json_encode.
replace
$_SESSION['item_id'] = json_encode($_POST);
with
if (!empty($_POST['id'])) {
$_SESSION['item_id'] = json_decode($_POST['id']); // use json_decode
}
It seems to me that you are making some small mistake in your code like you are echoing $row['p_id'] while your query should return id instead p_id also you are making mistake in ajax you are sending data-type JavaScript assuming your code is subtracting so try to use this code i code below.
// modify your php code
<?php
$sql = "SELECT id FROM products";
$result = mysqli_query($con,$sql);
while($row = mysqli_fetch_assoc($result)) { ?>
<tr class="table-manufacture-tr">
<td class="table-manufacture-td-statys">
<div class="warehouse-window-content-dropdown-plus2 plus">
<a class="open_item" data-id=<?php echo "\"".$row['id']."\"";?>
style="text-decoration: none; color: #D3D3D3;">Click</a>
</div>
</td>
</tr>
<?php } ?>
// modify your jQuery
$(document).on('click', '.open_item', function(event){
var data_item = $(this).data("id");
$.ajax({
url: 'get_id.php',
type: 'POST',
dataType: 'json',
data: { id: data_item },
success: function(data){
console.log(data);
},
error: function(){
console.log("not working");
}
});
});
<?php
session_start();
header("Content-Type: application/json", true);
$_SESSION['item_id'] = json_encode($_POST["id"]);
echo json_encode(['data_id' => $_SESSION['item_id']]);
?>
You can use
$_SESSION['item_id'] = json_encode($_POST['id']);
instead of
$_SESSION['item_id'] = json_encode($_POST);
this will work fine.
I don't know what you are trying to do, but from your JS, it looks like that you are expecting that the PHP script --which you post some data to it-- to return a json with the data you have just posted in it. In that case, try this, change your get_id.php to be like:
<?php
session_start();
$_SESSION['item_id'] = json_encode($_POST);
header("Content-Type: application/json", true);
echo $_SESSION['item_id'];
?>
I'd troubleshoot this by making sure the click handler is actually going off. Put alert("clicked"); as the first thing in the in the click handler to make sure.
For the meantime, remove the contentType in the json call. Also remove the dataType (data-type) entirely. On the php side, replace the header() line so (as mentioned) the php is just:
session_start();
$_SESSION['item_id'] = $_POST["id"];
echo $_SESSION['item_id'];
Do not use json_encode/decode right now. From your code, it is not needed.
So i have a for each function that prints the "local" column from this database:
https://i.imgur.com/IzKOzkt.png
It is working all good till here, this is what i get:
https://i.imgur.com/WH7d4uh.png
Now i want to send variables by post, when the user clicks on different menu items, i've tried everything, but i cant get it to work. Here is my code:
<?php
$query = "SELECT * FROM credenciais_sensores where ambiente = '1'";
$results = mysqli_query($conn, $query);
foreach ($results as $result){
$local = $result['local'];
$local = substr($local,0,7);
echo "<li><a class='clsPostData' data-oxiid='".$result['oxi_sensorid']."' data-oxikey='".$result['oxi_apikey']."' data-redoxid='".$result['redox_sensorid']."' data-redoxkey='".$result['redox_apikey']."' href='#'>".$local."</a></li>";
}
?>
This is working fine, the menu is being printed as i want, but now i cant get to post the data i want, like the "oxi_sensorid", etc... Here is my javascript:
<script type="text/javascript">
$(function(){
$('.clsPostData').click(function(e){
e.preventDefault();
var objPost = {};
objPost.oxiid = $(this).data('oxiid');
objPost.oxikey = $(this).data('oxikey');
objPost.redoxid = $(this).data('redoxid');
objPost.redoxkey = $(this).data('redoxkey');
$.ajax({
url: 'getObjects.php',
type: 'post',
data: objPost
}).done(function(responseFromPhp){
//Do something with the response, like
alert(responseFromPhp.message);
});
});
});
</script>
And my getObjects.php file:
<?php
$oxiid = $_POST["oxiid"];
$oxikey = $_POST["oxikey"];
$redoxid = $_POST["redoxid"];
$redoxkey = $_POST["redoxkey"];
$response["message"] = "Grettings from php, we receive your data: ".$oxiid . $oxikey . $redoxid . $redoxkey;
echo json_encode($response);
?>
But i'm always getting the popup saying "undefined" when i click on any menu item... Any help?
I think the problem there is you need to set the dataType to json. Try adding dataType: 'json' after type: 'post' on your ajax code:
$.ajax({
url: 'getObjects.php',
type: 'post',
dataType: 'json', // add this
data: objPost
}).done(function(responseFromPhp){
//Do something with the response, like
alert(responseFromPhp.message);
});
I am trying to send an array from javascript to PHP script using ajax. This is the code I have so far.
<?php
$i = 1;
while (++$i <= $_SESSION['totalcolumns']) {
$range = $_SESSION["min-column-$i"] . ',' . $_SESSION["max-column-$i"];?>
<br><?php echo "Keyword" ?>
<?php echo $i -1 ?>
<br><input type="text" data-slider="true" data-slider-range="<?php echo $range ?>" data-slider-step="1">
<?php } ?>
<button type="button" >Update</button>
<script>
$("[data-slider]")
.each(function () {
var range;
var input = $(this);
$("<span>").addClass("output")
.insertAfter(input);
range = input.data("slider-range").split(",");
$("<span>").addClass("range")
.html(range[0])
.insertBefore(input);
$("<span>").addClass("range")
.html(range[1])
.insertAfter(input);
})
.bind("slider:ready slider:changed", function (event, data) {
$(this).nextAll(".output:first")
.html(data.value.toFixed(2));
});
$(".output")
.each(function() {
var parms = [];
parms.push($(this).text());
});
</script>
<script>
function loadXMLDoc()
{
$.ajax({
type: "POST",
url: "update.php",
data: { value : $(parms).serializeArray() },
success: function(data)
{
console.log (data);
}
});
}
$("button").on('click',function(){ loadXMLDoc(); });
</script>
In my $.output function, I am using the parms [] array to store all the UI slider values which I am trying to pass on to the next PHP script page on a button click event as defined in loadXMLDoc() function. In my PHP page, I am accessing them as below.
<?php
$uid = $_POST['value'];
echo "Am I getting printed";
echo $uid;
// Do whatever you want with the $uid
?>
However, I am not able to view the data in my update.php script. Can someone please let me know what am doing wrong?
This is the link to my work so far.
serializeArray returns the json object ,maybe you could try json_decode in your php script,simply like:
$uid_arr = json_decode($uid,true);
print_r($uid_arr);
Just Use
data: $(parms).serializeArray()