Develop Reference

Check the object already exists in array in Vue.js

I have a data:
data: function() {
return {
conversations:
[
]
}
}
I'm getting my data from response object: response.data.conversation
Is there a way to check this.conversations already contains response.data.conversation?

To build on your answer, if you're already using underscore or lodash you can use its _.any()/_.some() function:
var exists = _.any(this.conversations, function(conversation) {
return _.isEqual(conversation, response.data.conversation);
})
You can also use Array.prototype.some to do the same kind of thing:
var exists = this.conversations.some(function(conversation) {
return _.isEqual(conversation, response.data.conversation);
})
The benefits of these over your solution is that they'll return as soon as they find a match (instead of iterating through the whole array), though you could easily update your code to break out of the loop early.
Also, while _.isEqual() is cool, you might be able to get away with some simple property comparisons (if your objects are flat enough or, even better, you have a key that uniquely identifies a conversation) to determine if two objects are equivalent:
var exists = this.conversations.some(function(conversation) {
return conversation.id === response.data.conversation.id;
})

I figured it out:
Used underscore.js.
Iterate trought all objects in array and compare them with _.isEqual(a,b)
function
var count=0;
for(var i=0; i<this.conversations.length; i++ ) {
if(_.isEqual(this.conversations[i], response.data.conversation)) {
count++;
}
}
Then check the value of count variable:
if (count == 0) {
//Add element to array
this.conversations.push(response.data.conversation);
} else {
console.warn('exists');
}

Javascript: Determine if all of the elements in the array are keys in the object

I am trying to figure out if all of the elements in an array are keys in the object.
var obj = { name: 'Computer', cost: '$1,000' };
var myArray = [ 'name', 'cost', 'bio' ]; //another example would be var myArray = [];
for(var x = 0; x < myArray.length; x++){
if (myArray[x] in obj)
{
return true;
}
}
How can I check if all of the elements in an array are keys in the object?

Do it the other way around. If you find someone in the array who is NOT in the object then you return false. If you reach the end of the loop then you return true because all the keys were in the object.

Depending on what you want, this might do the trick:
function hasKeys(obj, keys) {
for (var i=0; i != keys.length; ++i) {
if (!(keys[i] in obj))
return false;
}
return true;
};
One subtlety you need to ask yourself: do you want to know if the object has the keys directly (i.e. not somewhere in its prototype stack?) If so, then replace keys[i] in obj with obj.hasOwnProperty(keys[i])

function hasKeys(obj, keys) {
return keys.every(Object.prototype.hasOwnProperty.bind(obj));
}
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/every states, "The every method executes the provided callback function once for each element present in the array until it finds one where callback returns a falsy value (a value that becomes false when converted to a Boolean). If such an element is found, the every method immediately returns false. Otherwise, if callback returned a true value for all elements, every will return true. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values" (emphasis mine).

Array.some() makes for a clean solution.
// object in question
var obj = { ... };
// keys that need to be present in the object
var keys = [ ... ];
// iterate through the whitelist until we find a key that doesn't exist in the object. If all exist, that means Array.some() is false.
var valid = !keys.some(function(key) {
return !obj.hasOwnProperty(key);
});
An alternative solution would be using a similar concept, but with Array.every(). It is to note that this will generally be slower because it always has to touch every element in the whitelist.
// iterate through the whitelist, making sure the object has each key.
var valid = keys.every(obj.hasOwnProperty);

This problem can be expressed in terms of set inclusion: does the set of property keys completely include the array of required keys? So we can write it as
includes(Object.keys(obj), arr)
So now we just need to write includes.
function includes(arr1, arr2) {
return arr2.every(function(key) {
return contains(arr1, key);
}
}
For contains, we could use Underscore's _.contains, or just write it ourselves:
function contains(arr, val) {
return arr.indexOf(val) !== -1;
}
If we are interested in conciseness at the possible expense of readability, we could shorten our definition of includes to use Function#bind instead of the anonymous function:
function includes(arr1, arr2) {
return arr2.every(contains.bind(0, arr1));
}
Now we have functions we can use for other things, instead of mixing up the two different aspects of the problem--the keys of an object, and set inclusion. If we really want to write an all-in-one function, it becomes the somewhat more readable:
function hasMany(obj, arr) {
return arr.every(_.contains.bind(0, Object.keys(obj));
}
If we want more readability, like we were writing a novel:
function object_has_required_keys(object, required_keys) {
var object_keys = Object.keys(object);
function key_is_present(key) {
return object_keys.indexOf(key) !== -1;
}
return required_keys.every(key_is_present);
}
Underscore's _.intersection
If we're lazy (or smart), we could use Underscore's _.intersection to implement includes:
function includes(arr1, arr2) {
return _.intersection(arr1, arr2).length === arr2.length;
}
The idea is to take the intersection, and if the first array includes the second entirely, then the intersection will contain all the elements of the second array, which we can check by comparing their lengths.
Using ES6 sets
Thinking ahead to ES6, we could implement include using its sets, which ought to be faster:
function includes(arr1, arr2) {
var set = new Set(arr1);
return arr2.every(Set.prototype.has.bind(set));
}

Checking for duplicate Javascript objects

TL;DR version: I want to avoid adding duplicate Javascript objects to an array of similar objects, some of which might be really big. What's the best approach?
I have an application where I'm loading large amounts of JSON data into a Javascript data structure. While it's a bit more complex than this, assume that I'm loading JSON into an array of Javascript objects from a server through a series of AJAX requests, something like:
var myObjects = [];
function processObject(o) {
myObjects.push(o);
}
for (var x=0; x<1000; x++) {
$.getJSON('/new_object.json', processObject);
}
To complicate matters, the JSON:
is in an unknown schema
is of arbitrary length (probably not enormous, but could be in the 100-200 kb range)
might contain duplicates across different requests
My initial thought is to have an additional object to store a hash of each object (via JSON.stringify?) and check against it on each load, like this:
var myHashMap = {};
function processObject(o) {
var hash = JSON.stringify(o);
// is it in the hashmap?
if (!(myHashMap[hash])) {
myObjects.push(o);
// set the hashmap key for future checks
myHashMap[hash] = true;
}
// else ignore this object
}
but I'm worried about having property names in myHashMap that might be 200 kb in length. So my questions are:
Is there a better approach for this problem than the hashmap idea?
If not, is there a better way to make a hash function for a JSON object of arbitrary length and schema than JSON.stringify?
What are the possible issues with super-long property names in an object?

I'd suggest you create an MD5 hash of the JSON.stringify(o) and store that in your hashmap with a reference to your stored object as the data for the hash. And to make sure that there are no object key order differences in the JSON.stringify(), you have to create a copy of the object that orders the keys.
Then, when each new object comes in, you check it against the hash map. If you find a match in the hash map, then you compare the incoming object with the actual object that you've stored to see if they are truly duplicates (since there can be MD5 hash collisions). That way, you have a manageable hash table (with only MD5 hashes in it).
Here's code to create a canonical string representation of an object (including nested objects or objects within arrays) that handles object keys that might be in a different order if you just called JSON.stringify().
// Code to do a canonical JSON.stringify() that puts object properties
// in a consistent order
// Does not allow circular references (child containing reference to parent)
JSON.stringifyCanonical = function(obj) {
// compatible with either browser or node.js
var Set = typeof window === "object" ? window.Set : global.Set;
// poor man's Set polyfill
if (typeof Set !== "function") {
Set = function(s) {
if (s) {
this.data = s.data.slice();
} else {
this.data = [];
}
};
Set.prototype = {
add: function(item) {
this.data.push(item);
},
has: function(item) {
return this.data.indexOf(item) !== -1;
}
};
}
function orderKeys(obj, parents) {
if (typeof obj !== "object") {
throw new Error("orderKeys() expects object type");
}
var set = new Set(parents);
if (set.has(obj)) {
throw new Error("circular object in stringifyCanonical()");
}
set.add(obj);
var tempObj, item, i;
if (Array.isArray(obj)) {
// no need to re-order an array
// but need to check it for embedded objects that need to be ordered
tempObj = [];
for (i = 0; i < obj.length; i++) {
item = obj[i];
if (typeof item === "object") {
tempObj[i] = orderKeys(item, set);
} else {
tempObj[i] = item;
}
}
} else {
tempObj = {};
// get keys, sort them and build new object
Object.keys(obj).sort().forEach(function(item) {
if (typeof obj[item] === "object") {
tempObj[item] = orderKeys(obj[item], set);
} else {
tempObj[item] = obj[item];
}
});
}
return tempObj;
}
return JSON.stringify(orderKeys(obj));
}
And, the algorithm
var myHashMap = {};
function processObject(o) {
var stringifiedCandidate = JSON.stringifyCanonical(o);
var hash = CreateMD5(stringifiedCandidate);
var list = [], found = false;
// is it in the hashmap?
if (!myHashMap[hash] {
// not in the hash table, so it's a unique object
myObjects.push(o);
list.push(myObjects.length - 1); // put a reference to the object with this hash value in the list
myHashMap[hash] = list; // store the list in the hash table for future comparisons
} else {
// the hash does exist in the hash table, check for an exact object match to see if it's really a duplicate
list = myHashMap[hash]; // get the list of other object indexes with this hash value
// loop through the list
for (var i = 0; i < list.length; i++) {
if (stringifiedCandidate === JSON.stringifyCanonical(myObjects[list[i]])) {
found = true; // found an exact object match
break;
}
}
// if not found, it's not an exact duplicate, even though there was a hash match
if (!found) {
myObjects.push(o);
myHashMap[hash].push(myObjects.length - 1);
}
}
}
Test case for jsonStringifyCanonical() is here: https://jsfiddle.net/jfriend00/zfrtpqcL/

Maybe. For example if You know what kind object goes by You could write better indexing and searching system than JS objects' keys. But You could only do that with JavaScript and object keys are written in C...
Must Your hashing be lossless or not? If can than try to lose compression (MD5). I guessing You will lose some speed and gain some memory. By the way, do JSON.stringify(o) guarantees same key ordering. Because {foo: 1, bar: 2} and {bar: 2, foo: 1} is equal as objects, but not as strings.
Cost memory
One possible optimization:
Instead of using getJSON use $.get and pass "text" as dataType param. Than You can use result as Your hash and convert to object afterwards.
Actually by writing last sentence I though about another solution:
Collect all results with $.get into array
Sort it with buildin (c speed) Array.sort
Now You can easily spot and remove duplicates with one for
Again different JSON strings can make same JavaScript object.

How to determine if object is in array [duplicate]

This question already has answers here:
How do I check if an array includes a value in JavaScript?
(60 answers)
Closed 29 days ago.
I need to determine if an object already exists in an array in javascript.
eg (dummycode):
var carBrands = [];
var car1 = {name:'ford'};
var car2 = {name:'lexus'};
var car3 = {name:'maserati'};
var car4 = {name:'ford'};
carBrands.push(car1);
carBrands.push(car2);
carBrands.push(car3);
carBrands.push(car4);
now the "carBrands" array contains all instances.
I'm now looking a fast solution to check if an instance of car1, car2, car3 or car4 is already in the carBrands array.
eg:
var contains = carBrands.Contains(car1); //<--- returns bool.
car1 and car4 contain the same data but are different instances they should be tested as not equal.
Do I have add something like a hash to the objects on creation? Or is there a faster way to do this in Javascript.
I am looking for the fastest solution here, if dirty, so it has to be ;) In my app it has to deal with around 10000 instances.
no jquery

Use something like this:
function containsObject(obj, list) {
var i;
for (i = 0; i < list.length; i++) {
if (list[i] === obj) {
return true;
}
}
return false;
}
In this case, containsObject(car4, carBrands) is true. Remove the carBrands.push(car4); call and it will return false instead. If you later expand to using objects to store these other car objects instead of using arrays, you could use something like this instead:
function containsObject(obj, list) {
var x;
for (x in list) {
if (list.hasOwnProperty(x) && list[x] === obj) {
return true;
}
}
return false;
}
This approach will work for arrays too, but when used on arrays it will be a tad slower than the first option.

Why don't you use the indexOf method of javascript arrays?
Check this out: MDN indexOf Arrays
Simply do:
carBrands.indexOf(car1);
It will return you the index (position in the array) of car1. It will return -1 if car1 was not found in the array.
http://jsfiddle.net/Fraximus/r154cd9o
Edit: Note that in the question, the requirements are to check for the same object referenced in the array, and NOT a new object. Even if the new object is identical in content to the object in the array, it is still a different object.
As mentioned in the comments, objects are passed by reference in JS and the same object can exist multiple times in multiple structures.
If you want to create a new object and check if the array contains objects identical to your new one, this answer won't work (Julien's fiddle below), if you want to check for that same object's existence in the array, then this answer will work. Check out the fiddles here and in the comments.

Having been recently bitten by the FP bug reading many wonderful accounts of how neatly the functional paradigm fits with Javascript
I replicate the code for completeness sake and suggest two ways this can be done functionally.
var carBrands = [];
var car1 = {name:'ford'};
var car2 = {name:'lexus'};
var car3 = {name:'maserati'};
var car4 = {name:'ford'};
var car5 = {name:'toyota'};
carBrands.push(car1);
carBrands.push(car2);
carBrands.push(car3);
carBrands.push(car4);
// ES6 approach which uses the includes method (Chrome47+, Firefox43+)
carBrands.includes(car1) // -> true
carBrands.includes(car5) // -> false
If you need to support older browsers use the polyfill, it seems IE9+ and Edge do NOT support it. Located in polyfill section of MSDN page
Alternatively I would like to propose an updated answer to cdhowie
// ES2015 syntax
function containsObject(obj, list) {
return list.some(function(elem) {
return elem === obj
})
}
// or ES6+ syntax with cool fat arrows
function containsObject(obj, list) {
return list.some(elem => elem === obj)
}

try Array.prototype.some()
MDN Array.prototype.some
function isBiggerThan10(element, index, array) {
return element > 10;
}
[2, 5, 8, 1, 4].some(isBiggerThan10); // false
[12, 5, 8, 1, 4].some(isBiggerThan10); // true

You could use jQuery's grep method:
$.grep(carBrands, function(obj) { return obj.name == "ford"; });
But as you specify no jQuery, you could just make a derivative of the function. From the source code:
function grepArray( elems, callback, inv ) {
var ret = [];
// Go through the array, only saving the items
// that pass the validator function
for ( var i = 0, length = elems.length; i < length; i++ ) {
if ( !inv !== !callback( elems[ i ], i ) ) {
ret.push( elems[ i ] );
}
}
return ret;
}
grepArray(carBrands, function(obj) { return obj.name == "ford"; });

I used underscore javascript library to tweak this issue.
function containsObject(obj, list) {
var res = _.find(list, function(val){ return _.isEqual(obj, val)});
return (_.isObject(res))? true:false;
}
please refer to underscore.js documentation for the underscore functions used in the above example.
note: This is not a pure javascript solution. Shared for educational purposes.

You can just use the equality operator: ==. Objects are checked by reference by default, so you don't even need to use the === operator.
try this, just make sure you're using the correct variable reference in the place of car1:
var i, car, l = cars.length;
for (i = 0; i < l; i++)
{
if ((car = cars[i]) == car1)
{
break;
}
else car = null;
}
Edit to add:
An array extension was mentioned, so here's the code for it:
Array.prototype.contains = Array.prototype.contains || function(obj)
{
var i, l = this.length;
for (i = 0; i < l; i++)
{
if (this[i] == obj) return true;
}
return false;
};
Note that I'm caching the length value, as the Array's length property is actually an accessor, which is marginally slower than an internal variable.

I would use a generic iterator of property/value over the array. No jQuery required.
arr = [{prop1: 'val1', prop2: 'val2'}, {prop1: 'val3', prop2: 'val4'}];
objectPropInArray(arr, 'prop1', 'val3'); // <-- returns true
function objectPropInArray(list, prop, val) {
if (list.length > 0 ) {
for (i in list) {
if (list[i][prop] === val) {
return true;
}
}
}
return false;
}

You could try sorting the array based on a property, like so:
carBrands = carBrands.sort(function(x,y){
return (x == y) ? 0 : (x > y) ? 1 : -1;
});
Then you can use an iterative routine to check whether
carBrands[Math.floor(carBrands.length/2)]
// change carBrands.length to a var that keeps
// getting divided by 2 until result is the target
// or no valid target exists
is greater or lesser than the target, and so on, which will let you go through the array quickly to find whether the object exists or not.

try this ,
You can use the JavaScript some() method to find out if a JavaScript array contains an object.
<script>
// An array of objects
var persons = [{name: "Harry"}, {name: "Alice"}, {name: "Peter"}];
// Find if the array contains an object by comparing the property value
if(persons.some(person => person.name === "Peter")){
alert("Object found inside the array.");
} else{
alert("Object not found.");
}
</script>

EDIT 05/18/2022
The most simple way using ES6:
const arrayContainsObject = <T extends Record<string, unknown>>(array: T[], object: T) => {
return array.some(item => Object.keys(item).every(key => item[key] === object[key]))
}
Use like so:
const arr = [{
prop1: 'value1',
prop2: 'value2'
}]
const obj1 = {
prop1: 'value1',
prop2: 'value2'
}
const obj2 = {
prop2: 'value2',
prop1: 'value1'
}
const obj3 = {
prop0: 'value0',
prop1: 'value1'
}
arrayContainsObject(arr, obj1) // true
arrayContainsObject(arr, obj2) // true, even when props are arranged in different order
arrayContainsObject(arr, obj3) // false
Previous answer, don't use (because the order of props in an object needs to be identical)
const arr = [{
prop: 'value'
}]
const obj = {
prop: 'value'
}
arr.some((e) => Object.entries(e).toString() === Object.entries(obj).toString()) // true

i know this is an old post, but i wanted to provide a JQuery plugin version and my code.
// Find the first occurrence of object in list, Similar to $.grep, but stops searching
function findFirst(a,b){
var i; for (i = 0; i < a.length; ++i) { if (b(a[i], i)) return a[i]; } return undefined;
}
usage:
var product = $.findFirst(arrProducts, function(p) { return p.id == 10 });

This function is to check for a unique field.
Arg 1: the array with selected data
Arg 2: key to check
Arg 3: value that must be "validated"
function objectUnique( array, field, value )
{
var unique = true;
array.forEach(function ( entry )
{
if ( entry[field] == value )
{
unique = false;
}
});
return unique;
}

you can use Array.find().
in your case is going to look like this
carBrands.find(function(car){
let result = car.name === 'ford'
if (result == null){
return false;
} else {
return true
}
});
if car is not null it will return the javaScript Object which contains the string 'ford'

The issue with many of the answers here is that they will NOT find an object in an array that is equal to another object. They will only search for an EXISTING object that has a pointer to it in an array.
Quick fix using lodash to see if ANY equal object is in an array:
import _ from 'lodash';
_.find(carBrands, car1); //returns object if true, undefined if false
Working Plunker using this method: https://plnkr.co/edit/y2YX9o7zkQa2r7lJ

if its possible to use es6
carBrands.filter(carBrand => carBrand.name === carX.name).length > 0
if it's true there is a similarity

You can convert both the JSON objects to string and simply check if the bigger json contains the smaller json.
console.log(JSON.stringify(carBrands).includes(JSON.stringify(car1))); // true
console.log(JSON.stringify(carBrands).includes(JSON.stringify(car5))); // false

You could also a the findIndex
var carBrands = [];
var car1 = {name:'ford'};
var car2 = {name:'lexus'};
carBrands.push(car1);
if (carBrands.findIndex(f => f.name === car1.name) === -1) {
console.log('not contain')
} else {
console.log('contain')
}
if (carBrands.findIndex(f => f.name === car2.name) === -1) {
console.log('not contain')
} else {
console.log('contain')
}

In Javascript, given value, find name from Object literal

I'm new JavaScript and trying to find out an easier way to find name given a value from object literal.
e.g.
var cars ={ Toyata: ['Camry','Prius','Highlander'],
Honda: ['Accord', 'Civic', 'Pilot'],
Nissan: ['Altima', 'Sentra', 'Quest']};
Given 'Accord', I want to get Honda from the object Cars.

You would need to loop through, like this:
function getManufacturer(carName) {
for(var key in cars) {
if(cars.hasOwnProperty(key)) {
for(var i=0; i<cars[key].length; i++) {
if(cars[key][i] == carName) return key;
}
}
}
return "Not found";
}
You can test it out here, for the same of working cross-browser, this ignores the existence of .indexOf() since IE doesn't have it...that version would look like this:
function getManufacturer(carName) {
for(var key in cars) {
if(cars.hasOwnProperty(key) && cars[key].indexOf(carName) != -1) {
return key;
}
}
return "Not found";
}

If you're going to be doing this once, then use a function like the one given by Bobby. If you're going to be doing this multiple times then I'd suggest creating a reverse mapping of cars to manufacturers:
var manufacturers = {};
// create a map of car models to manufacturers:
for (var manf in cars) {
/* see note below */
for (var i=0; i<cars[manf].length; i++) {
manufacturers[cars[manf][i]] = manf;
}
}
// Now referencing the manufacturers is
// a very fast hash table lookup away:
var model = 'Accord';
alert(manufacturers[model]);
note for those with itchy downvoting fingers: For objects that don't inherit anything as given in the OP a hasOwnProperty check here is unnecessary. For objects that do inherit it depends on the programmer. If you want composability via inheritance then a hasOwnProperty check is exactly what you DONT want. If you don't care about inheritance then use a hasOwnProperty check but if so you would not be inheriting in the first place which would make a hasOwnProperty check unnecessary. In the rare case where you are forced to create the object via inheritance but don't want to check the parent's attributes then you should do a hasOwnProperty check. Of course, if you use a library like Prototype.js that insists on modifying the Object object then I feel sorry for you because you are forced to do a hasOwnProperty check.

Maintain a separate mapping of models to manufacturers.
var cars ={ Toyata: ['Camry','Prius','Highlander'],
Honda: ['Accord', 'Civic', 'Pilot'],
Nissan: ['Altima', 'Sentra', 'Quest']};
var models = {};
var hasOwnProperty = Object.prototype.hasOwnProperty;
for (key in cars) {
if (hasOwnProperty.call(cars, key)) {
var i=0,l=cars[key].length,manufacturer=cars[key];
while (i<l) {
if ( ! hasOwnProperty.call(models, manufacturer)) {
models[manufacturer] = key;
} else {
// Throw an error, or change the value to an array of values
}
i++;
}
}
}