Develop Reference

unable to parse xml data with AJAX + Wordpress

Ok, I am officially stumped. I have been trying to find why my calls for specific items in a PubMed xml data file are not working... I can execute this one with my current coding:
$test = (string)$id_json->PubmedArticle->MedlineCitation->PMID;
but if I try to get a variable that is in a deeper array, it does not return a value. I have even tested with console.log(data) and I get my PMID returning but not my other, deeper values in the XML file. For example;
$test = (string)$id_json->PubmedArticle->MedlineCitation->Article->Journal->ISSN;
returns nothing for data in console.log(data)
Here is my function in wordpress:
function get_abstract(){
$id = $_POST['abstractid'];
$pubmed_api_call = 'https://eutils.ncbi.nlm.nih.gov/entrez/eutils/efetch.fcgi?db=pubmed&retmode=xml&rettype=abstract&id='.$id;
$id_wpget = wp_remote_get($pubmed_api_call, array('timeout' => 20));
if( is_wp_error( $id_wpget ) ) {
echo "Error Contacting PubMed, please refresh page and try again";
die();
}
$id_xml = wp_remote_retrieve_body($id_wpget);
$id_json = simplexml_load_string($id_xml);
$test = (string)$id_json->PubmedArticle->MedlineCitation->Article->Journal->ISSN;
if($test === ""){
echo "NOTHING";
die();
}
echo $test;
die();
}
and here is my javascript AJAX call:
jQuery(document).ready(function() {
jQuery('.reference_header').click(function(e) {
jQuery(this).find("i").toggleClass("arrow-down arrow-up");
jQuery(this).nextUntil('.reference_header').slideToggle('fast');
var abstractid = jQuery(this).data("id");
e.preventDefault();
jQuery.ajax({
url: get_abstract.ajaxurl,
type: 'POST',
dataType: 'json',
data: {
abstractid: jQuery(this).data("id"),
action: 'get_abstract'
},
success : function(data){
jQuery('.'+abstractid).html("TESTING: "+data);
console.log(data);
}
});
});
});
I cannot find out why it doesnt work... any help is greatly appreciated.

So I figured out the solution to the issue... you need to pass the string text as a json object to AJAX for it to read properly...
working code:
PHP:
echo json_encode(array("result" => "$test"));
die();
AJAX:
success : function(data){
jQuery('.'+abstractid).html("TESTING: "+data.result);
console.log(data.result);
}

Delete post using $.ajax

I am new to $.ajax and don't know so much and i have following button to delete user post by article ID
<button type="button" onclick="submitdata();">Delete</button>
When click this button then following $.ajax process running.
<script>
var post_id="<?php echo $userIdRow['post_id']; ?>";
var datastring='post_id='+post_id;
function submitdata() {
$.ajax({
type:"POST",
url:"delete.php",
data:datastring,
cache:false,
success:function(html) {
alert(html);
}
});
return false;
}
</script>
And delete.php is
<?php
// connect to the database
include 'conn.php';
$dbClass = new Database();
// confirm that the 'post_id' variable has been set
if (isset($_GET['post_id']) && is_numeric($_GET['post_id'])) {
// get the 'post_id' variable from the URL
$post_id = $_GET['post_id'];
// delete record from database
if ($userPostsQuery = $dbClass::Connect()->prepare("DELETE FROM user_posts WHERE post_id = :post_id")) {
$userPostsQuery->bindValue(":post_id", $post_id, PDO::PARAM_INT);
$userPostsQuery->execute();
$userPostsQuery->close();
echo "Deleted success";
} else {
echo "ERROR: could not prepare SQL statement.";
}
}
?>
This code not working post not deleted. Please how do I do?

You likely want to not only match the "GET" you use in your PHP but also add the ID to the button
<button class="del" type="button"
data-id="<?php echo $userIdRow['post_id']; ?>">Delete</button>
using $.get which matches your PHP OR use $.ajax({ "type":"DELETE"
$(function() {
$(".del").on("click", function() {
$.get("delete.php",{"post_id":$(this).data("id")},
function(html) {
alert(html);
}
);
});
});
NOTE: Please clean the var
Do htmlspecialchars and mysql_real_escape_string keep my PHP code safe from injection?
Using ajax DELETE with error handling
$(function() {
$(".del").on("click", function() {
$.ajax({
url: "delete.php",
method: "DELETE", // use "GET" if server does not handle DELETE
data: { "post_id": $(this).data("id") },
dataType: "html"
}).done(function( msg ) {
$( "#log" ).html( msg );
}).fail(function( jqXHR, textStatus ) {
alert( "Request failed: " + textStatus );
});
});
});
In the PHP you can do
if ($_SERVER['REQUEST_METHOD'] === 'DELETE') {
$id = $_REQUEST["post_id"] ....
}

since you're sending a post request with ajax so you should use a $_POST iin your script and not a $_GET
here is how it sould be
<?php
// connect to the database
include 'conn.php';
$dbClass = new Database();
// confirm that the 'post_id' variable has been set
if (isset($_POST['post_id']) && is_numeric($_POST['post_id'])) {
// get the 'post_id' variable from the URL
$post_id = $_POST['post_id'];
// delete record from database
if ($userPostsQuery = $dbClass::Connect()->prepare("DELETE FROM user_posts WHERE post_id = :post_id")) {
$userPostsQuery->bindValue(":post_id", $post_id, PDO::PARAM_INT);
$userPostsQuery->execute();
$userPostsQuery->close();
echo "Deleted success";
} else {
echo "ERROR: could not prepare SQL statement.";
}
}
?>
for the JS code
<script>
var post_id="<?php echo $userIdRow['post_id']; ?>";
function submitdata() {
$.ajax({
type:"POST",
url:"delete.php",
data:{"post_id":post_id},
cache:false,
success:function(html) {
alert(html);
}
});
return false;
}
</script>
here i've supposed thqt the give you the real id post you're looking for !!

The reason is pretty simple. You should change your request type to GET/DELETE instead of POST. In PHP you expect GET request but in AJAX you send POST request
Change:
type:"POST",
url:"delete.php",
data:datastring,
to
type:"DELETE",
url:"delete.php?" + datastring,
in PHP
if ($_SERVER['REQUEST_METHOD'] === 'DELETE' && !empty($_REQUEST["post_id") {
$id = $_REQUEST["post_id"];
// perform delete
}
DELETE is actually the only valid method to delete objects. POST should create an object and GET should retrieve it. It may be confusing at first time but it's good practicet specially used in REST APIs. The other one would be UNLINK if you wanted to remove relationship between objects.

Follow #roberts advise and also:
You should have a way to handle errors eg.
to your ajax code add this:
error:function(e){
alert(e.statusText)// if you like alerts
console.log(e.statusText)// If you like console
}
You should also check your error logs. Assuming you use apache2 and linux
execute this in terminal:
tail -f /var/log/apache2/error.log
This gives you a very elaborate way to code. You also eliminate the problem of trial and error.

Script return blank just in jQuery AJAX

I've got very frustrating problem. I send AJAX request to PHP file and when I see Chrome Network Tools, it donť return any JSON. But when I try post the same data via POSTMAN tool in Chrome, it return right. When I open script normally, it return right. Just when I sen request via AJAXm it return nothing.
This is my PHP file: (I know it's functionally useless at this time, i need fix this error before it can do what I need)
$stav = 2;
$ret = array();
$name = query_r("select * from users where username = 'admin'");
$ret['stav']=$stav;
$json = json_encode($ret);
echo $json;
At line 3 must be problem, because when I put it out, it works. But function is 100% exist, 'cause when i put nonsense name of function, it write an error. DB query is also right, i tried it in phpMyAdmin console.
This is my AJAX request:
$("#loginForm").submit(function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "../admin/scripts/login.php",
data: $("#loginForm").serialize(),
dataType: "JSON",
success: function (vysledek){
if(vysledek.stav===1){
window.location.href("../index.php")
}
else if(vysledek.stav===2){
alertify.error('Špatné uživatelské jméno');
}
else if(vysledek.stav===3){
alertify.error('Špatné heslo');
}
},
error: function(vysledek){
alertify.error('Vyskytla se nějaká chyba');
}
});
});
How I wrote, if I open PHP file in browser, it echo {"stav":2}, when I try POSTman, it echo {"stav":2}. But when I run AJAX request, it makes nothing. I really don't know what is wrong.
EDIT
Firebug:
Here

can you please try with the following code
$("#loginForm").submit(function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "../admin/scripts/login.php",
data: $("#loginForm").serialize(),
dataType: "JSON",
success: function (vysledek){
if( parseInt(vysledek.stav) == 1 ){
window.location.href("../index.php")
}
else if( parseInt(vysledek.stav) == 2 ){
alertify.error('Špatné uživatelské jméno');
}
else if( parseInt(vysledek.stav) == 3 ){
alertify.error('Špatné heslo');
}
},
error: function(vysledek){
alertify.error('Vyskytla se nějaká chyba');
}
});
});

<?php
$stav = 2;
$ret = array();
$name = query_r("select * from users where username = 'admin'");
$ret['stav']=$stav;
$json = json_encode($ret);
print_r($json);
?>
Remember to parse JSON to the response
...
success: function (vysledek){
var vysledek = (vysledek);
if(vysledek.stav === 1){
window.location.href("../index.php")
}
...

AJAX take data from POST with PHP

i have a little problem with my script.
I want to give data to a php file with AJAX (POST).
I dont get any errors, but the php file doesn't show a change after AJAX "runs" it.
Here is my jquery / js code:
(#changeRank is a select box, I want to pass the value of the selected )
$(function(){
$("#changeRank").change(function() {
var rankId = this.value;
//alert(rankId);
//$.ajax({url: "/profile/parts/changeRank.php", type: "post", data: {"mapza": mapza}});
//$("body").load("/lib/tools/popups/content/ban.php");
$.ajax({
type: "POST",
async: true,
url: '/profile/parts/changeRank.php',
data: { 'direction': 'up' },
success: function (msg)
{ alert('success') },
error: function (err)
{ alert(err.responseText)}
});
});
});
PHP:
require_once('head.php');
require_once('../../lib/permissions.php');
session_start();
$user = "test";
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
$_SESSION["user"] = $user;
header('Location:/user/'.$user);
die();
When i run the script, javascript comes up with an alert "success" which means to me, that there aren't any problems.
I know, the post request for my data is missing, but this is only a test, so im planning to add this later...
I hope, you can help me,
Greets :)

$(function(){
$("#changeRank").change(function() {
var rankId = this.value;
//alert(rankId);
//$.ajax({url: "/profile/parts/changeRank.php", type: "post", data: {"mapza": mapza}});
//$("body").load("/lib/tools/popups/content/ban.php");
$.ajax({
type: "POST",
async: true,
url: '/profile/parts/changeRank.php',
data: { 'direction': 'up' },
success: function (msg)
{ alert('success: ' + JSON.stringify(msg)) },
error: function (err)
{ alert(err.responseText)}
});
});
});
require_once('head.php');
require_once('../../lib/permissions.php');
session_start();
$user = "test";
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
$_SESSION["user"] = $user;
echo json_encode($user);
This sample code will let echo the username back to the page. The alert should show this.

well your js is fine, but because you're not actually echoing out anything to your php script, you wont see any changes except your success alert. maybe var_dump your post variable to check if your data was passed from your js file correctly...

Just return 0 or 1 from your php like this
Your PHP :
if($_SESSION["user"] != $user && checkPermission("staff.fakeLogin", $_SESSION["user"], $mhost, $muser, $mpass, $mdb))
{
$_SESSION["user"] = $user;
echo '1'; // success case
}
else
{
echo '0'; // failure case
}
Then in your script
success: function (msg)
if(msg==1)
{
window.location = "home.php"; // or your success action
}
else
{
alert('error);
}
So that you can get what you expect

If you want to see a result, in the current page, using data from your PHP then you need to do two things:
Actually send some from the PHP. Your current PHP redirects to another URL which might send data. You could use that or remove the Location header and echo some content out instead.
Write some JavaScript that does something with that data. The data will be put into the first argument of the success function (which you have named msg). If you want that data to appear in the page, then you have to put it somewhere in the page (e.g. with $('body').text(msg).

Header wont redirect when passedthrough ajax

Not sure if this is possible but I have a page that submits a form with AJAX and if it meets certain conditions it should automatically take the user to another page. NOTHING is outputted before the header tag its just a bunch of conditions.
Problem: Header redirect not working...
AJAX
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: '_ajax/add.php',
data: $('form').serialize(),
success: function (data) {
$("input").val('Company Name');
$("form").hide();
getInfo();
}
});
});
add.php
$row = mysqli_fetch_array($result);
$id = $row['id'];
header("Location: http://localhost/manage/card.php?id=$id");

Headers can only be modified before any body is sent to the browser (hence the names header/body). Since you have AJAX sent to the browser, you can't modify the headers any more. However, you can have the add.php script called via AJAX return the $id parameter. Then that parameter can be used in JavaScript to redirect the page: window.location = 'http://localhost/manage/card.php?id=' + id.
More info on PHP header(): http://www.php.net/manual/en/function.header.php
AJAX
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: '_ajax/add.php',
data: $('form').serialize(),
success: function (data) {
window.location = 'http://localhost/manage/card.php?id=' + data;
}
});
});
add.php
$row = mysqli_fetch_array($result);
$id = $row['id'];
echo $id;
exit;

You indicate in the question that under certain conditions, you want a redirect.
To do that, you would want to alter your javascript to contain an if condition, and to watch for certain responses.
I would recommend modifying your responses to be json, so that you can pass back different information (such as a success status, as well as a redirect url, or other information you might want).
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: '_ajax/add.php',
data: $('form').serialize(),
success: function (data) {
var response = $.parseJSON(data);
if (response.redirect) {
window.location = response.redirect_url;
} else {
$("input").val('Company Name');
$("form").hide();
getInfo();
}
}
});
});
As for your add.php file, you'll want to change this to be something more like so:
$json = array(
'redirect' => 0,
'url' => '',
}
if (...condition for redirect...) {
$row = mysqli_fetch_array($result);
$id = $row['id'];
$json['redirect'] = 1;
$json['redirect_url'] = "Location: http://localhost/manage/card.php?id=$id";
}
echo json_encode($json);
die();

You seem to have a miss understanding of how AJAX works. Introduction to Ajax.
The reason why your redirect appears not to working is because an Ajax call doesn't directly affect your browser. It's a behind the scenes call.
To get the data out from the AJAX call you need to do something with the returned data.
success: function (data) {
$("input").val('Company Name');
$("form").hide();
//You need to do something with data here.
$("#myDiv").html(data); //This would update a div with the id myDiv with the response from the ajax call.
getInfo();
}