I am trying to get a string from a html page with jquery and this is what I have.
var text = $(this).text();
var key = text.substring(0,1);
if(key == ' ' || key == ' ')
key = text.substring(1,2);
text is this Home
And I want to skip the space and or the keycode above It appears this code does not work either. It only gets the text.substring(0,1); instead of text.substring(1,2); because the if statement is not catching.= and I am not sure why. Any help would be super awesome! Thanks!
There are several problems with the code in the question. First, has no special meaning in JavaScript: it is a string literal with six characters. Second, text.substring(1,2) returns simply the second character of text, not all characters from the second one onwards.
Assuming that you wish to remove one leading SPACE or NO-BREAK SPACE (which is what means in HTML; it is not an Ascii character, by the way), then the following code would work:
var first = text.substring(0, 1);
if(first === ' ' || first === '\u00A0') {
text = text.substring(1, text.length);
}
The notation \u00A0 is a JavaScript escape notation for NO-BREAK SPACE U+00A0.
Should you wish to remove multiple spaces at the start, and perhaps at the end too, some modifications are needed. In that case, using a replace operation with regular expression is probably best.
If you want remove spaces at the beginning (and end) of a string, you can use the trim function
var myvar = " home"
myVar.trim() // --> "home"
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/Trim
Related
So I have a text box on my website and I have coded this to prevent certain words from being used.
window.onload = function() {
var banned = ['MMM', 'XXX'];
document.getElementById('input_1_17').addEventListener('keyup', function(e) {
var text = document.getElementById('input_1_17').value;
for (var x = 0; x < banned.length; x++) {
if (text.toLowerCase().search(banned[x]) !== -1) {
alert(banned[x] + ' is not allowed!');
}
var regExp = new RegExp(banned[x]);
text = text.replace(regExp, '');
}
document.getElementById('input_1_17').value = text;
}, false);
}
The code works perfectly and removes the text from the text box when all the letters typed are lowercase. The problem is when the text contained an uppercase letter it will give the error but the word will not be removed from the text box.
The RegExp is a good direction, just you need some flags (to make it case-insensitive, and global - so replace all occurrences):
var text="Under the xxx\nUnder the XXx\nDarling it's MMM\nDown where it's mmM\nTake it from me";
console.log("Obscene:",text);
var banned=["XXX","MMM"];
banned.forEach(nastiness=>{
text=text.replace(new RegExp(nastiness,"gi"),"");
});
console.log("Okay:",text);
Normally you should use .toLowerCase() with both sides when comparing the strings so they can logically be matched.
But the problem actually comes from the Regex you are using, where you are ignoring case sensitivity, you just need to add the i flag to it:
var regExp = new RegExp(banned[x], 'gi');
text = text.replace(regExp, '');
Note:
Note also that using an alert() in a loop is not recommended, you can change your logic to alert all the matched items in only one alert().
You seem to have been expecting something unreasonable. Lowercase strings will never match strings containing uppercase letters.
Either convert both for comparison or use lowercase banned strings. The former would be more reliable, taking future human error out of the process.
What you can do is actually convert both variables to either all caps or all lowercase.
if (text.toLowerCase().includes(banned[x].toLowerCase())) {
alert(banned[x] + ' is not allowed!');
}
Not tested but it should work. No need to use search since you don't need the index anyway. using includes is cleaner. includes docs
I have a string of text with HTML line breaks. Some of the <br> immediately follow a number between two delimiters «...» and some do not.
Here's the string:
var str = ("«1»<br>«2»some text<br>«3»<br>«4»more text<br>«5»<br>«6»even more text<br>");
I’m looking for a conditional regex that’ll remove the number and delimiters (ex. «1») as well as the line break itself without removing all of the line breaks in the string.
So for instance, at the beginning of my example string, when the script encounters »<br> it’ll remove everything between and including the first « to the left, to »<br> (ex. «1»<br>). However it would not remove «2»some text<br>.
I’ve had some help removing the entire number/delimiters (ex. «1») using the following:
var regex = new RegExp(UsedKeys.join('|'), 'g');
var nextStr = str.replace(/«[^»]*»/g, " ");
I sure hope that makes sense.
Just to be super clear, when the string is rendered in a browser, I’d like to go from this…
«1»
«2»some text
«3»
«4»more text
«5»
«6»even more text
To this…
«2»some text
«4»more text
«6»even more text
Many thanks!
Maybe I'm missing a subtlety here, if so I apologize. But it seems that you can just replace with the regex: /«\d+»<br>/g. This will replace all occurrences of a number between « & » followed by <br>
var str = "«1»<br>«2»some text<br>«3»<br>«4»more text<br>«5»<br>«6»even more text<br>"
var newStr = str.replace(/«\d+»<br>/g, '')
console.log(newStr)
To match letters and digits you can use \w instead of \d
var str = "«a»<br>«b»some text<br>«hel»<br>«4»more text<br>«5»<br>«6»even more text<br>"
var newStr = str.replace(/«\w+?»<br>/g, '')
console.log(newStr)
This snippet assumes that the input within the brackets will always be a number but I think it solves the problem you're trying to solve.
const str = "«1»<br>«2»some text<br>«3»<br>«4»more text<br>«5»<br>«6»even more text<br>";
console.log(str.replace(/(«(\d+)»<br>)/g, ""));
/(«(\d+)»<br>)/g
«(\d+)» Will match any brackets containing 1 or more digits in a row
If you would prefer to match alphanumeric you could use «(\w+)» or for any characters including symbols you could use «([^»]+)»
<br> Will match a line break
//g Matches globally so that it can find every instance of the substring
Basically we are only removing the bracketed numbers if they are immediately followed by a line break.
I was pointed out to this post, which does not seem to follow the criteria I have:
Replace a Regex capture group with uppercase in Javascript
I am trying to make a regex that will:
format a string by adding uppercase for the first letter of each word and lower case for the rest of the characters
ignore HTML markup
Accept swedish characters (åäöÅÄÖ)
Say I've got this string:
<b>app</b>le store östersund
Then I want it to be (changes marked by uppercase characters)
<b>App</b>le Store Östersund
I've been playing around with it and the closest I've got is the following:
(?!([^<])*?>)[åäöÅÄÖ]|\s\b\w
Resulted in
<b>app</b>le Store Östersund
Or this
/(?!([^<])*?>)[åäöÅÄÖ]|\S\b\w/g
Resulted in
<B>App</B>Le store Östersund
Here's a fiddle:
http://refiddle.com/refiddles/598aabef75622d4a531b0000
Any help or advice is much appreciated.
It is not possible to do this with regexp alone, since regexp doesn't understand HTML structure. [*] Instead, we need to process each text node, and carry through our logic for what is the beginning of the word in case a word continues across different text nodes. A character is at start of the word if it is preceded by a whitespace, or if it is at the start of the string and it is either the first text node, or the previous text node ended in whitespace.
function htmlToTitlecase(html, letters) {
let div = document.createElement('div');
let re = new RegExp("(^|\\s)([" + letters + "])", "gi");
div.innerHTML = html;
let treeWalker = document.createTreeWalker(div, NodeFilter.SHOW_TEXT);
let startOfWord = true;
while (treeWalker.nextNode()) {
let node = treeWalker.currentNode;
node.data = node.data.replace(re, function(match, space, letter) {
if (space || startOfWord) {
return space + letter.toUpperCase();
} else {
return match;
}
});
startOfWord = node.data.match(/\s$/);
}
return div.innerHTML;
}
console.log(htmlToTitlecase("<b>app</b>le store östersund", "a-zåäö"));
// <b>App</b>le Store Östersund
[*] Maybe possible, but even if so, it would be horribly ugly, since it would need to cover an awful amount of corner cases. Also might need a stronger RegExp engine than JavaScript's, like Ruby's or Perl's.
EDIT:
Even if just specifying really simple html tags? The only ones I am actually in need of covering is <b> and </b> at the moment.
This was not specified in the question. The solution is general enough to work for any markup (including simple tags). But...
function simpleHtmlToTitlecaseSwedish(html) {
return html.replace(/(^|\s)(<\/?b>|)([a-zåäö])/gi, function(match, space, tag, letter) {
return space + tag + letter.toUpperCase();
});
}
console.log(simpleHtmlToTitlecaseSwedish("<b>app</b>le store östersund", "a-zåäö"));
I have a solution which use almost only regex. It may be not the most intuitive way to do it, but it should be effective and I find it funny :)
You have to append at the end of your string every lowercase character followed by their uppercase counterpart, like this (it must also be preceded by a space for my regex) :
aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZåÅäÄöÖ
(I don't know which letters are missing, I know nothing about swedish alphabet, sorry... I'm counting on you to correct that !)
Then you can use the following regex :
(?![^<]*>)(\s<[^/]*?>|\s|^)([\wåäö])(?=.*\2(.)\S*$)|[\wåÅäÄöÖ]+$
Replace by :
$1$3
Test it here
Here is a working javascript code :
// Initialization
var regex = /(?![^<]*>)(\s<[^/]*?>|\s|^)([\wåäö])(?=.*\2(.)\S*$)|[\wåÅäÄöÖ]+$/g;
var string = "test <b when=\"2>1\">ap<i>p</i></b>le store östersund";
// Processing
result = string + " aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZåÅäÄöÖ";
result = result.replace(regex, "$1$3");
// Display result
console.log(result);
Edit : I forgot to handle first word of the string, it's corrected :)
I am trying to toggle a hidden input element when the select element has a certain option. When I am alerted of variable q, q has no input but variable put does I am quite confused as to why .replace() removes the entire string.
function hiddeninput(choice, put) {
var q = put.replace(/./g, "").replace(/#/g, "");
alert(put + "," + q);//alerts .other,
if (choice === q) {
$(put).show();
} else {
$(put).hide();
}
}
Any help would be appreciated. JSfiddle has been quite buggy these past few days some of my previous working fiddles have stopped working, maybe that could be the reason.
Do you realize that . is to match any character?
You need to escape it with a \ so it will match just the . and not any character.
var q = put.replace(/\./g, "").replace(/#/g, "");
And instead of doing two replacements you can just do one
var q = put.replace(/[.#]/g,"");
In regex "." will match any character. You've got: put.replace(/./g, "");. This means you're replacing each match of any character with nothing, which will result in nothing.
If you want to match a dot, you need to escape the special character using a backslash: put.replace(/\./g, "");.
I'm not sure if this'll entirely solve your problem, but to me it seems like something unintended.
I'm trying to remove the whitespaces from a textarea . The below code is not appending the text i'm selecting from two dropdowns. Can somebody tell me where i'd gone wrong? I'm trying to remove multiple spaces within the string as well, will that work with the same? Dont know regular expressions much. Please help.
function addToExpressionPreview() {
var reqColumnName = $('#ddlColumnNames')[0].value;
var reqOperator = $('#ddOperator')[0].value;
var expressionTextArea = document.getElementById("expressionPreview");
var txt = document.createTextNode(reqColumnName + reqOperator.toString());
if (expressionTextArea.value.match(/^\s+$/) != null)
{
expressionTextArea.value = (expressionTextArea.value.replace(/^\W+/, '')).replace(/\W+$/, '');
}
expressionTextArea.appendChild(txt);
}
> function addToExpressionPreview() {
> var reqColumnName = $('#ddlColumnNames')[0].value;
> var reqOperator = $('#ddOperator')[0].value;
You might as well use document.getElementById() for each of the above.
> var expressionTextArea = document.getElementById("expressionPreview");
> var txt = document.createTextNode(reqColumnName + reqOperator.toString());
reqOperator is already a string, and in any case, the use of the + operator will coerce it to String unless all expressions or identifiers involved are Numbers.
> if (expressionTextArea.value.match(/^\s+$/) != null) {
There is no need for match here. I seems like you are trying to see if the value is all whitespace, so you can use:
if (/^\s*$/.test(expressionTextArea.value)) {
// value is empty or all whitespace
Since you re-use expressionTextArea.value several times, it would be much more convenient to store it an a variable, preferably with a short name.
> expressionTextArea.value = (expressionTextArea.value.replace(/^\W+/,
> '')).replace(/\W+$/, '');
That will replace one or more non-word characters at the end of the string with nothing. If you want to replace multiple white space characters anywhere in the string with one, then (note wrapping for posting here):
expressionTextArea.value = expressionTextArea.value.
replace(/^\s+/,'').
replace(/\s+$/, '').
replace(/\s+/g,' ');
Note that \s does not match the same range of 'whitespace' characters in all browsers. However, for simple use for form element values it is probably sufficient.
Whitespace is matched by \s, so
expressionTextArea.value.replace(/\s/g, "");
should do the trick for you.
In your sample, ^\W+ will only match leading characters that are not a word character, and ^\s+$ will only match if the entire string is whitespace. To do a global replace(not just the first match) you need to use the g modifier.
Refer this link, you can get some idea. Try .replace(/ /g,"UrReplacement");
Edit: or .split(' ').join('UrReplacement') if you have an aversion to REs