In the following code, an exception is caught by the catch function of the $q promise:
// Fiddle - http://jsfiddle.net/EFpn8/6/
f1().then(function(data) {
console.log("success 1: "+data)
return f2();
})
.then(function(data) {console.log("success 2: "+data)})
.catch(function(data) {console.log("error: "+data)});
function f1() {
var deferred = $q.defer();
// An exception thrown here is not caught in catch
// throw "err";
deferred.resolve("done f1");
return deferred.promise;
}
function f2() {
var deferred = $q.defer();
// An exception thrown here is handled properly
throw "err";
deferred.resolve("done f2");
return deferred.promise;
}
However when I look in the console log output I see the following:
The exception was caught in Angular, but was also caught by the error handling of the browser. This behavior does reproduce with Q library.
Is it a bug? How can I truly catch an exception with $q?
Angular's $q uses a convention where thrown errors are logged regardless of being caught. Instead, if you want to signal a rejection you need to return $q.reject(... as such:
function f2() {
var deferred = $q.defer();
// An exception thrown here is handled properly
return $q.reject(new Error("err"));//throw "err";
deferred.resolve("done f2");
return deferred.promise;
}
This is to distinguish rejections from errors like SyntaxError. Personally, it's a design choice I disagree with but it's understandable since $q is tiny so you can't really build in a reliable unhandled rejection detection mechanism. In stronger libraries like Bluebird, this sort of thing is not required.
As a side note - never, ever throw strings : you miss on stack traces that way.
Is it a bug?
No. Looking in the source for $q reveals that a deliberate try / catch block is created to respond to exceptions thrown in the callback by
Rejecting the promise, as through you had called deferred.reject
Calling the registered Angular exception hander. As can be seen in the $exceptionHandler docs, the default behaviour of this is to log it to the browser console as an error, which is what you have observed.
... was also caught by the error handling of the browser
To clarify, the exception isn't handled directly by the browser, but appears as an error because Angular has called console.error
How can I truly catch an exception with $q?
The callbacks are executed some time later, when the current call stack has cleared, so you won't be able to wrap the outer function in try / catch block. However, you have 2 options:
Put in try/catch block around the code that might throw the exception, within the callback:
f1().then(function(data) {
try {
return f2();
} catch(e) {
// Might want convert exception to rejected promise
return $q.reject(e);
}
})
Change how Angular's $exceptionHandler service behaves, like at How to override $exceptionHandler implementation . You could potentially change it to do absolutely nothing, so there would never be anything in the console's error log, but I don't think I would recommend that.
Fixed with AngularJS version 1.6
The reasoning for this behavior was that an uncaught error is different than a regular rejection, as
it can be caused by a programming error, for example. In practice, this turned out to be confusing
or undesirable for users, since neither native promises nor any other popular promise library
distinguishes thrown errors from regular rejections.
(Note: While this behavior does not go against the Promises/A+ spec, it is not prescribed either.)
$q:
Due to e13eea, an error thrown from a promise's onFulfilled or onRejection handlers is treated exactly the same as a regular rejection. Previously, it would also be passed to the $exceptionHandler() (in addition to rejecting the promise with the error as reason).
The new behavior applies to all services/controllers/filters etc that rely on $q (including built-in services, such as $http and $route). For example, $http's transformRequest/Response functions or a route's redirectTo function as well as functions specified in a route's resolve object, will no longer result in a call to $exceptionHandler() if they throw an error. Other than that, everything will continue to behave in the same way; i.e. the promises will be rejected, route transition will be cancelled, $routeChangeError events will be broadcasted etc.
-- AngularJS Developer Guide - Migrating from V1.5 to V1.6 - $q
The deferred is an outdated and a really terrible way of constructing promises, using the constructor solves this problem and more:
// This function is guaranteed to fulfill the promise contract
// of never throwing a synchronous exception, using deferreds manually
// this is virtually impossible to get right
function f1() {
return new Promise(function(resolve, reject) {
// code
});
}
I don't know if angular promises support the above, if not, you can do this:
function createPromise(fn) {
var d = $q.defer();
try {
fn(d.resolve.bind(d), d.reject.bind(d));
}
catch (e) {
d.reject(e);
}
return d.promise;
}
Usage is same as promise constructor:
function f1() {
return createPromise(function(resolve, reject){
// code
});
}
Here is an sample test that shows the new $q construction function, use of .finally(), rejections, and promise chain propagations:
iit('test',inject(function($q, $timeout){
var finallyCalled = false;
var failValue;
var promise1 = $q.when(true)
.then(function(){
return $q(function(resolve,reject){
// Reject promise1
reject("failed");
});
})
.finally(function(){
// Always called...
finallyCalled = true;
// This will be ignored
return $q.when('passed');
});
var promise2 = $q.when(promise1)
.catch(function(value){
// Catch reject of promise1
failValue = value;
// Continue propagation as resolved
return value+1;
// Or continue propagation as rejected
//return $q.reject(value+2);
});
var updateFailValue = function(val){ failValue = val; };
$q.when(promise2)
.then( updateFailValue )
.catch(updateFailValue );
$timeout.flush();
expect( finallyCalled ).toBe(true);
expect( failValue ).toBe('failed1');
}));
Related
I'm facing a promise rejection that escapes a try catch block. The rejection causes an Uncaught exception which is something I can not comprehend.
If I add a reject handler in the Promise.then or a Promise.catch, the rejection gets captured. But I was hopping try catch will work in this situation.
What is happening here?
class HttpResponse {
json() {
return Promise.reject('parse error')
}
}
function fetch() {
return new HttpResponse();
}
const res = fetch();
try {
res.json().then(json => {
alert(`json: ${json}`);
}
//,reason => {
// alert(`promise.reject ${reason}`);
//}
)
//.catch(reason => {
// alert(`promise.catch ${reason}`);
//})
} catch (e) {
alert(`catch{} from try catch: ${e}`);
}
Promises have their own mechanism of handling errors with the catch() method. A try / catch block can't control what's happening when chaining methods.
function fetch() {
return Promise.reject('parse error');
}
const res = fetch();
res.then(json => {
console.log(`json: ${json}`);
}).catch((e) => {
console.log(`catch{} from chained catch: ${e}`);
});
However, using async / await changes that. There you don't use the methods of a promise but handle errors with a try / catch block.
function fetch() {
return Promise.reject('parse error');
}
(async function() {
try {
const res = await fetch();
} catch (e) {
console.log(`catch{} from try catch: ${e}`);
}
})();
The technical reason behind this behavior is because a JavaScript promise invokes one of two callback functions for success or failure.
A promise does not emit an Error that is required for the try to work. it is not an Error (or more technically accurate) an instance of Error. It emits and event. You are encouraged to emit a new Error() if you need it to emit one. As pointed out here: https:developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
It emits an event that you can set up a handler for: https://developer.mozilla.org/en-US/docs/Web/API/PromiseRejectionEvent –
Finally, await throws and Error as described in the spec: https://tc39.es/ecma262/#await-rejected
Technical reasons behind:
HostPromiseRejectionTracker is an implementation-defined abstract
operation that allows host environments to track promise rejections.
An implementation of HostPromiseRejectionTracker must complete
normally in all cases. The default implementation of
HostPromiseRejectionTracker is to unconditionally return an empty
normal completion.
https://www.ecma-international.org/ecma-262/10.0/index.html#sec-host-promise-rejection-tracker
Basically javascript engines can freely implement this spec. In the case of browsers you don't get the Error captured inside the try/catch because the error is not emitted where you think it should be. But instead it's tracked with this special event that throws the error in the console.
Also on nodejs, this event causes the process to exit if you have node set to exit on unhandled exceptions.
On the other side, if you instead use async/await, the rejection is treated like an 'error' in practical terms. Meaning that the newer async/await feature behaves in a different fashion showing that it is not only syntactic sugar for Promises.
https://tc39.es/ecma262/#sec-throwcompletion
In sum, if you use Promise.then you are forced to provide a reject argument or chain it with .catch to have the rejection captured or else it will reach the console and in case of nodejs to exit the process if configured to do so (I believe new nodejs does this by default).
But if you use the newer async/await syntax you not only have a concise code (which is secondary) but a better rejection handling because it can be properly nested in a try/catch and it will behave like an standard Error.
I am have a problem understanding why rejections are not passed on through a promise chain and I am hoping someone will be able to help me understand why. To me, attaching functionality to a chain of promises implies an intent that I am depending on an original promise to be fulfilled. It's hard to explain, so let me show a code example of my problem first. (Note: this example is using Node and the deferred node module. I tested this with Dojo 1.8.3 and had the same results)
var d = require("deferred");
var d1 = d();
var promise1 = d1.promise.then(
function(wins) { console.log('promise1 resolved'); return wins;},
function(err) { console.log('promise1 rejected'); return err;});
var promise2 = promise1.then(
function(wins) { console.log('promise2 resolved'); return wins;},
function(err) { console.log('promise2 rejected'); return err;});
var promise3 = promise2.then(
function(wins) { console.log('promise3 resolved'); return wins;},
function(err) { console.log('promise3 rejected'); return err;});
d1.reject(new Error());
The results of running this operation is this output:
promise1 rejected
promise2 resolved
promise3 resolved
Okay, to me, this result doesn't make sense. By attaching to this promise chain, each then is implying the intent that it will be dependant upon the successful resolution of d1 and a result being passed down the chain. If the promise in promise1 doesn't receive the wins value, but instead gets an err value in its error handler, how is it possible for the next promise in the chain to have its success function called? There is no way it can pass on a meaningful value to the next promise because it didn't get a value itself.
A different way I can describe what I'm thinking is: There are three people, John, Ginger, and Bob. John owns a widget shop. Ginger comes into his shop and requests a bag of widgets of assorted colours. He doesn't have them in stock, so he sends in a request to his distributor to get them shipped to him. In the mean time, he gives Ginger a rain check stating he owes her the bag of widgets. Bob finds out Ginger is getting the widgets and requests that he get the blue widget when she's done with them. She agrees and gives him a note stating she will. Now, John's distributor can't find any widgets in their supply and the manufacturer doesn't make them any more, so they inform John, who in turn informs Ginger she can't get the widgets. How is Bob able to get a blue widget from Ginger when didn't get any herself?
A third more realistic perspective I have on this issue is this. Say I have two values I want updated to a database. One is dependant on the id of the other, but I can't get the id until I have already inserted it into a database and obtained the result. On top of that, the first insert is dependant on a query from the database. The database calls return promises that I use to chain the two calls into a sequence.
var promise = db.query({parent_id: value});
promise.then(function(query_result) {
var first_value = {
parent_id: query_result[0].parent_id
}
var promise = db.put(first_value);
promise.then(function(first_value_result) {
var second_value = {
reference_to_first_value_id: first_value_result.id
}
var promise = db.put(second_value);
promise.then(function(second_value_result) {
values_successfully_entered();
}, function(err) { return err });
}, function(err) { return err });
}, function(err) { return err });
Now, in this situation, if the db.query failed, it would call the err function of the first then. But then it would call the success function of the next promise. While that promise is expecting the results of the first value, it would instead get the error message from its error handler function.
So, my question is, why would I have an error handing function if I have to test for errors in my success function?
Sorry for the length of this. I just didn't know how to explain it another way.
UPDATE and correction
(Note: I removed a response I had once made to some comments. So if anyone commented on my response, their comments might seem out of context now that I removed it. Sorry for this, I am trying to keep this as short as possible.)
Thank you everybody who replied. I would like to first apologize to everybody for writing out my question so poorly, especially my pseudo code. I was a little too aggressive in trying to keep it short.
Thanks to Bergi's response, I think I found the error in my logic. I think I might have overlooked another issue that was causing the problem I was having. This is possibly causing the promise chain work differently than I thought it should. I am still testing different elements of my code, so I can't even form a proper question to see what I'm doing wrong yet. I did want to update you all though and thank you for your help.
To me, this result doesn't make sense. By attaching to this promise chain, each then is implying the intent that it will be dependant upon the successful resolution of d1 and a result being passed down the chain
No. What you are describing is not a chain, but just attaching all the callbacks to d1. Yet, if you want to chain something with then, the result for promise2 is dependent on the resolution of promise1 and how the then callbacks handled it.
The docs state:
Returns a new promise for the result of the callback(s).
The .then method is usually looked upon in terms of the Promises/A specification (or the even stricter Promsises/A+ one). That means the callbacks shell return promises which will be assimilated to become the resolution of promise2, and if there is no success/error handler the respective result will in case be passed directly to promise2 - so you can simply omit the handler to propagate the error.
Yet, if the error is handled, the resulting promise2 is seen as fixed and will be fulfilled with that value. If you don't want that, you would have to re-throw the error, just like in a try-catch clause. Alternatively you can return a (to-be-)rejected promise from the handler. Not sure what Dojo way to reject is, but:
var d1 = d();
var promise1 = d1.promise.then(
function(wins) { console.log('promise1 resolved'); return wins;},
function(err) { console.log('promise1 rejected'); throw err;});
var promise2 = promise1.then(
function(wins) { console.log('promise2 resolved'); return wins;},
function(err) { console.log('promise2 rejected'); throw err;});
var promise3 = promise2.then(
function(wins) { console.log('promise3 resolved'); return wins;},
function(err) { console.log('promise3 rejected'); throw err;});
d1.reject(new Error());
How is Bob able to get a blue widget from Ginger when didn't get any herself?
He should not be able. If there are no error handlers, he will just perceive the message (((from the distributor) from John) from Ginger) that there are no widgets left. Yet, if Ginger sets up an error handler for that case, she still might fulfill her promise to give Bob a widget by giving him a green one from her own shack if there are no blue ones left at John or his distributor.
To translate your error callbacks into the metapher, return err from the handler would just be like saying "if there are no widgets left, just give him the note that there are no ones left - it's as good as the desired widget".
In the database situation, if the db.query failed, it would call the err function of the first then
…which would mean that the error is handled there. If you don't do that, just omit the error callback. Btw, your success callbacks don't return the promises they are creating, so they seem to be quite useless. Correct would be:
var promise = db.query({parent_id: value});
promise.then(function(query_result) {
var first_value = {
parent_id: query_result[0].parent_id
}
var promise = db.put(first_value);
return promise.then(function(first_value_result) {
var second_value = {
reference_to_first_value_id: first_value_result.id
}
var promise = db.put(second_value);
return promise.then(function(second_value_result) {
return values_successfully_entered();
});
});
});
or, since you don't need the closures to access result values from previous callbacks, even:
db.query({parent_id: value}).then(function(query_result) {
return db.put({
parent_id: query_result[0].parent_id
});
}).then(function(first_value_result) {
return db.put({
reference_to_first_value_id: first_value_result.id
});
}.then(values_successfully_entered);
#Jordan firstly as commenters noted, when using deferred lib, your first example definitely produces result you expect:
promise1 rejected
promise2 rejected
promise3 rejected
Secondly, even if it would produce output you suggest, it wouldn't affect execution flow of your second snippet, which is a bit different, more like:
promise.then(function(first_value) {
console.log('promise1 resolved');
var promise = db.put(first_value);
promise.then(function (second_value) {
console.log('promise2 resolved');
var promise = db.put(second_value);
promise.then(
function (wins) { console.log('promise3 resolved'); },
function (err) { console.log('promise3 rejected'); return err; });
}, function (err) { console.log('promise2 rejected'); return err;});
}, function (err) { console.log('promise1 rejected'); return err});
and that, in case of first promise being rejected will just output:
promise1 rejected
However (getting to the most interesting part) even though deferred library definitely returns 3 x rejected, most of other promise libraries will return 1 x rejected, 2 x resolved (that leads to assumption you got those results by using some other promise library instead).
What's additionally confusing, those other libraries are more correct with their behavior. Let me explain.
In a sync world counterpart of "promise rejection" is throw. So semantically, async deferred.reject(new Error()) in sync equals to throw new Error().
In your example you're not throwing errors in your sync callbacks, you just returning them, therefore you switch to success flow, with an error being a success value. To make sure rejection is passed further, you need to re-throw your errors:
function (err) { console.log('promise1 rejected'); throw err; });
So now question is, why do deferred library took returned error as rejection?
Reason for that, is that rejection in deferred works a bit different. In deferred lib the rule is: promise is rejected when it's resolved with an instance of error, so even if you do deferred.resolve(new Error()) it will act as deferred.reject(new Error()), and if you try to do deferred.reject(notAnError) it will throw an exception saying, that promise can be rejected only with instance of error. That makes clear why error returned from then callback rejects the promise.
There is some valid reasoning behind deferred logic, but still it's not on par with how throw works in JavaScript, and due to that this behavior is scheduled for change with version v0.7 of deferred.
Short summary:
To avoid confusion and unexpected results just follow the good practice rules:
Always reject your promises with an error instances (follow rules of sync world, where throwing value that's not an error is considered a bad practice).
Reject from sync callbacks by throwing errors (returning them doesn't guarantee rejection).
Obeying to above, you'll get both consistent and expected results in both deferred and other popular promise libraries.
Use can wrap the errors at each level of the Promise. I chained the errors in TraceError:
class TraceError extends Error {
constructor(message, ...causes) {
super(message);
const stack = Object.getOwnPropertyDescriptor(this, 'stack');
Object.defineProperty(this, 'stack', {
get: () => {
const stacktrace = stack.get.call(this);
let causeStacktrace = '';
for (const cause of causes) {
if (cause.sourceStack) { // trigger lookup
causeStacktrace += `\n${cause.sourceStack}`;
} else if (cause instanceof Error) {
causeStacktrace += `\n${cause.stack}`;
} else {
try {
const json = JSON.stringify(cause, null, 2);
causeStacktrace += `\n${json.split('\n').join('\n ')}`;
} catch (e) {
causeStacktrace += `\n${cause}`;
// ignore
}
}
}
causeStacktrace = causeStacktrace.split('\n').join('\n ');
return stacktrace + causeStacktrace;
}
});
// access first error
Object.defineProperty(this, 'cause', {value: () => causes[0], enumerable: false, writable: false});
// untested; access cause stack with error.causes()
Object.defineProperty(this, 'causes', {value: () => causes, enumerable: false, writable: false});
}
}
Usage
throw new TraceError('Could not set status', srcError, ...otherErrors);
Output
Functions
TraceError#cause - first error
TraceError#causes - list of chained errors
a simple explanation from here:
In a regular try..catch we can analyze the error and maybe rethrow it if it can’t be handled. The same thing is possible for promises.
If we throw inside .catch, then the control goes to the next closest error handler. But if we handle the error and finish normally, then it continues to the next closest successful .then handler.
In the example below the .catch successfully handles the error:
new Promise((resolve, reject) => {
throw new Error("Whoops!");
}).catch(function(error) {
alert("The error is handled, continue normally");
}).then(() => alert("Next successful handler runs"));
Here the catch block finishes normally. So the next successful then handler is called.
note that we may have as many .then handlers as we want, and then use a single .catch at the end to handle errors in all of them.
If you have mid catch blocks and you want to break the next chain functions for errors, you shall re-throw the errors inside the catch blocks to signal this error is not handled completely.
new Promise((resolve, reject) => {
throw new Error("Whoops!");
}).catch(function(error) { // (*) first catch
if (error instanceof URIError) { //just as example
// handle it...
} else {
alert("Can't handle such error");
throw error; // throwing this jumps to the next catch
}
}).then(function() {
// our error is other than URIError, so:
// the code doesn't reach here (jump to next catch)
}).catch(error => { // (**) second catch
alert(`The unknown error has occurred: ${error}`);
// don't return anything => execution goes the normal way
});
In the above example we see the first catch (*) will catch the error but can’t handle it (e.g. it only knows how to handle URIError), so it throws it again. The execution jumps from the first catch (*) to the next one (**) down the chain.
I have a nodeJS project where I wish to use asynchronous functions. Namely, I'm using the Q library.
I have a function called someFunction(), that I wish to return a promise. With the then -function, I can then check whether the promise was resolved or rejected like so:
someFunction()
.then(
function(results) {
console.log("Success!");
},
function (error) {
console.log("An error occurred, and I would wish to log it for example");
}
);
What I intuitively expect with the function above is, that the error function would catch all possible errors. So if some exception is raised inside the someFunction, I can rest assured, that the error function will be run (the second function after 'then'). But it seems this is not the case.
For example, let's say the someFunction would be defined as so:
function someFunction() {
var deferred = Q.defer();
throw new Error("Can't bar.");
deferred.resolve("success");
}
Now if I call the function someFunction() like done in the upper code block, it won't run the error function. Why is that? Isn't the partial point of the promise Q.deferred to catch errors? Why should I manually reject every error that happens? I know I could set the whole content of someFunction to try/catch clause, and then reject the deferred, but that feels so wrong! There must be a better way, and I know for sure some of you stackoverflowers know it!
With this information, I began to think about where the deferred.reject and deferred.resolve is even meant to be used? Is it even meant to catch exceptions? Should I really just go through all the error cases manually, and call the deferred.reject on them? I'm interested to hear how this should be handled professionally.
Q has specific function for success and error, so use:
deferred.reject("error");
intead of throwing an Exception.
Next thing is that someFunction must return promise to be used as You use it:
function someFunction() {
var deferred = Q.defer();
try{
//some Asynchronous code
deferred.resolve("success");
}catch(e){
deferred.reject(e.message);
}
return deffered.promise; //return promise to use then
}
Because Promises ain't magic. They don't somehow magically catch Errors. They catch them, because they wrap the calls to the callbacks in try..catch-blocks, to convert Errors into rejected Promises.
If you want an Error to be handled by the Promise-chain, well put the function-call into a promise-chain: Q.resolve().then(someFunction).then(...).
Now any synchronous Error occuring in someFunction can be handled in the following then's.
Btw: If you use Q.defer(), and you're not dealing with some callback-style API, you're doing it definitely wrong. Search for the Deferred-antipattern.
it won't run the error function. Why is that?
Because you synchronously threw an exception, instead of returning a promise. Which you never should.
Isn't the partial point of the promise Q.deferred to catch errors?
No. then and catch implicitly catch exceptions in their callbacks, defferreds don't - they're just a (deprecated) API to create promises.
Why should I manually reject every error that happens?
Because asynchronous errors are expected to be passed to callbacks anyway, instead of being thrown.
I know I could set the whole content of someFunction to try/catch clause, and then reject the deferred, but that feels so wrong! There must be a better way!
There is: the Q.Promise constructor, the standard (ES6) promise creation API. It has the benefit of being able to catch synchronous exceptions from the executor function:
function someFunction() {
return new Q.Promise(function(resolve) {
throw new Error("Can't bar.");
resolve("success");
});
}
throwing an error will stop the code from executing (and will close node) unless you catch the error in a try/catch block.
handled errors from requests can be passed to the .catch chain by using deferred.reject(error). code errors and custom thrown errors needs to be handled inside try/catch, which is the right way to handle such errors.
function someFunction() {
var deferred = Q.defer();
deferred.reject("Can't bar.");
// or
try {
throw new Error("Can't bar.");
}
catch(err) {
deferred.reject("Can't bar.");
}
deferred.resolve("success");
}
There are many tutorials on how to use "then" and "catch" while programming with JavaScript Promise. However, all these tutorials seem to miss an important point: returning from a then/catch block to break the Promise chain. Let's start with some synchronous code to illustrate this problem:
try {
someFunction();
} catch (err) {
if (!(err instanceof MyCustomError))
return -1;
}
someOtherFunction();
In essence, I am testing a caught error and if it's not the error I expect I will return to the caller otherwise the program continues. However, this logic will not work with Promise:
Promise.resolve(someFunction).then(function() {
console.log('someFunction should throw error');
return -2;
}).catch(function(err) {
if (err instanceof MyCustomError) {
return -1;
}
}).then(someOtherFunction);
This logic is used for some of my unit tests where I want a function to fail in a certain way. Even if I change the catch to a then block I am still not able to break a series of chained Promises because whatever is returned from the then/catch block will become a Promise that propagates along the chain.
I wonder if Promise is able to achieve this logic; if not, why? It's very strange to me that a Promise chain can never be broken. Thanks!
Edit on 08/16/2015:
According to the answers given so far, a rejected Promise returned by the then block will propagate through the Promise chain and skip all subsequent then blocks until is is caught (handled). This behavior is well understood because it simply mimics the following synchronous code (approach 1):
try {
Function1();
Function2();
Function3();
Function4();
} catch (err) {
// Assuming this err is thrown in Function1; Function2, Function3 and Function4 will not be executed
console.log(err);
}
However, what I was asking is the following scenario in synchronous code (approach 2):
try {
Function1();
} catch(err) {
console.log(err); // Function1's error
return -1; // return immediately
}
try {
Function2();
} catch(err) {
console.log(err);
}
try {
Function3();
} catch(err) {
console.log(err);
}
try {
Function4();
} catch(err) {
console.log(err);
}
I would like to deal with errors raised in different functions differently. It's possible that I catch all the errors in one catch block as illustrated in approach 1. But that way I have to make a big switch statement inside the catch block to differentiate different errors; moreover, if the errors thrown by different functions do not have a common switchable attribute I won't be able to use the switch statement at all; under such a situation, I have to use a separate try/catch block for each function call. Approach 2 sometimes is the only option. Does Promise not support this approach with its then/catch statement?
This can't be achieved with features of the language. However, pattern-based solutions are available.
Here are two solutions.
Rethrow previous error
This pattern is basically sound ...
Promise.resolve()
.then(Function1).catch(errorHandler1)
.then(Function2).catch(errorHandler2)
.then(Function3).catch(errorHandler3)
.then(Function4).catch(errorHandler4)
.catch(finalErrorHandler);
Promise.resolve() is not strictly necessary but allows all the .then().catch() lines to be of the same pattern, and the whole expression is easier on the eye.
... but :
if an errorHandler returns a result, then the chain will progress to the next line's success handler.
if an errorHandler throws, then the chain will progress to the next line's error handler.
The desired jump out of the chain won't happen unless the error handlers are written such that they can distinguish between a previously thrown error and a freshly thrown error. For example :
function errorHandler1(error) {
if (error instanceof MyCustomError) { // <<<<<<< test for previously thrown error
throw error;
} else {
// do errorHandler1 stuff then
// return a result or
// throw new MyCustomError() or
// throw new Error(), new RangeError() etc. or some other type of custom error.
}
}
Now :
if an errorHandler returns a result, then the chain will progress to the next FunctionN.
if an errorHandler throws a MyCustomError, then it will be repeatedly rethrown down the chain and caught by the first error handler that does not conform to the if(error instanceof MyCustomError) protocol (eg a final .catch()).
if an errorHandler throws any other type of error, then the chain will progress to the next catch.
This pattern would be useful if you need the flexibility to skip to end of chain or not, depending on the type of error thrown. Rare circumstances I expect.
DEMO
Insulated Catches
Another solution is to introduce a mechanism to keep each .catch(errorHandlerN) "insulated" such that it will catch only errors arising from its corresponding FunctionN, not from any preceding errors.
This can be achieved by having in the main chain only success handlers, each comprising an anonymous function containing a subchain.
Promise.resolve()
.then(function() { return Function1().catch(errorHandler1); })
.then(function() { return Function2().catch(errorHandler2); })
.then(function() { return Function3().catch(errorHandler3); })
.then(function() { return Function4().catch(errorHandler4); })
.catch(finalErrorHandler);
Here Promise.resolve() plays an important role. Without it, Function1().catch(errorHandler1) would be in the main chain the catch() would not be insulated from the main chain.
Now,
if an errorHandler returns a result, then the chain will progress to the next line.
if an errorHandler throws anything it likes, then the chain will progress directly to the finalErrorHandler.
Use this pattern if you want always to skip to the end of chain regardless of the type of error thrown. A custom error constructor is not required and the error handlers do not need to be written in a special way.
DEMO
Usage cases
Which pattern to choose will determined by the considerations already given but also possibly by the nature of your project team.
One-person team - you write everything and understand the issues - if you are free to choose, then run with your personal preference.
Multi-person team - one person writes the master chain and various others write the functions and their error handlers - if you can, opt for Insulated Catches - with everything under control of the master chain, you don't need to enforce the discipline of writing the error handlers in that certain way.
First off, I see a common mistake in this section of code that could be completely confusing you. This is your sample code block:
Promise.resolve(someFunction()).then(function() {
console.log('someFunction should throw error');
return -2;
}).catch(function(err) {
if (err instanceof MyCustomError) {
return -1;
}
}).then(someOtherFunction()); // <== Issue here
You need pass function references to a .then() handler, not actually call the function and pass their return result. So, this above code should probably be this:
Promise.resolve(someFunction()).then(function() {
console.log('someFunction should throw error');
return -2;
}).catch(function(err) {
if (err instanceof MyCustomError) {
// returning a normal value here will take care of the rejection
// and continue subsequent processing
return -1;
}
}).then(someOtherFunction); // just pass function reference here
Note that I've removed () after the functions in the .then() handler so you are just passing the function reference, not immediately calling the function. This will allow the promise infrastructure to decide whether to call the promise in the future or not. If you were making this mistake, it will totally throw you off for how the promises are working because things will get called regardless.
Three simple rules about catching rejections.
If nobody catches the rejection, it stops the promise chain immediately and the original rejection becomes the final state of the promise. No subsequent handlers are invoked.
If the promise rejection is caught and either nothing is returned or any normal value is returned from the reject handler, then the reject is considered handled and the promise chain continues and subsequent handlers are invoked. Whatever you return from the reject handler becomes the current value of the promise and it as if the reject never happened (except this level of resolve handler was not called - the reject handler was called instead).
If the promise reject is caught and you either throw an error from the reject handler or you return a rejected promise, then all resolve handlers are skipped until the next reject handler in the chain. If there are no reject handlers, then the promise chain is stopped and the newly minted error becomes the final state of the promise.
You can see a couple examples in this jsFiddle where it shows three situations:
Returning a regular value from a reject handler, causes the next .then() resolve handler to be called (e.g. normal processing continues),
Throwing in a reject handler causes normal resolve processing to stop and all resolve handlers are skipped until you get to a reject handler or the end of the chain. This is effective way to stop the chain if an unexpected error is found in a resolve handler (which I think is your question).
Not having a reject handler present causes normal resolve processing to stop and all resolve handlers are skipped until you get to a reject handler or the end of the chain.
There is no built-in functionality to skip the entirety of the remaining chain as you're requesting. However, you could imitate this behavior by throwing a certain error through each catch:
doSomething()
.then(func1).catch(handleError)
.then(func2).catch(handleError)
.then(func3).catch(handleError);
function handleError(reason) {
if (reason instanceof criticalError) {
throw reason;
}
console.info(reason);
}
If any of the catch blocks caught a criticalError they would skip straight to the end and throw the error. Any other error would be console logged and before continuing to the next .then block.
If you can use the newer async await this is pretty simple to implement:
async function myfunc() {
try {
return await anotherAsyncFunction();
} catch {
//do error handling
// can be async or not.
return errorObjct();
}
}
let alwaysGetAValue = await myfunc();
Depending on what technology your using you may need some kind of high level wrapper function to allow for the top level await.
Consider the following code:
// Fiddle - http://jsfiddle.net/EFpn8/3/
f1().then(function(data) {
console.log("success 1: "+data)
return f2();
})
.then(function(data) {console.log("success 2: "+data)})
.catch(function(data) {console.log("error: "+data)});
function f1() {
var deferred = $q.defer();
// An exception thrown here is not caught in catch
// throw "err";
deferred.resolve("done f1");
return deferred.promise;
}
function f2() {
var deferred = $q.defer();
// An exception thrown here is handled properly
// throw "err";
deferred.resolve("done f2");
return deferred.promise;
}
If the following code runs with an exception in f2, then the catch function is called correctly. However, in case there is an exception in f1 then the catch code never executes and only a standard JS exception occurs.
In the original Q library, this could be handled by this code:
// Fiddle - http://jsfiddle.net/FEPc7/
Q.fcall(f1).then(function(data) {
console.log("success 1: "+data)
return f2();
})
.then(function(data) {console.log("success 2: "+data)})
.catch(function(data) {console.log("error: "+data)});
Using fcall the f1 function is safely guarded and an exception in it will trigger the catch function as expected.
Since it seems to be that the same behavior from all members of a promise chain would be helpful and natural to the developer, I made the following function for AngularJS:
// Fiddle - http://jsfiddle.net/EFpn8/5/
function promise(work) {
var deferred = $q.defer();
try {
deferred.resolve(work());
} catch(err) {
deferred.reject(err);
throw err;
}
return deferred.promise;
}
Which can be used like so:
promise(f1).then(function(data) {
console.log("success 1: "+data)
return f2();
})
.then(function(data) {console.log("success 2: "+data)})
.catch(function(data) {console.log("error: "+data)});
This works fine, however, it seems rather a hack. Is there something inherit in Angular to do that instead? Or is it unnecessary for some reason?
The first call of the chain is synchronous, so at first glance it seems unusual for exceptions raised in it to be then passed to $q to then call the error callbacks, which are for the asynchronous promise rejections (or indeed exceptions)
To quote from the $q docs
Q has many more features than $q
So the lack of fCall function sounds like one of the things the team decided could be removed. It looks like you do have to roll your own, like you have. You might want to use a technique like from https://gist.github.com/leon/8800809 to decorate $q with a fCall method, so you then use it like:
$q.fCall(f1).then(function()...
I know this is an older question, but I hit the same thing today and found this answer but didn't think I should need to add fCall() to get this to work.
After a little digging I found this can be done in Angular v1.5 today (not sure at what point this became valid):
$q.when().then(() => f1)...