i have a contact form with jQuery validate method. When the user click on "Reset"-button the hole contact form should be go to the initial state.
This is the button looks like:
<form class="form" method="post" action="" name="contact" id="contact">
<button type="button" id="cancel" class="btn btn-danger btn-lg">Reset</button>
</form>
And the JS-Code in my "$(document).ready-function" is:
$('#cancel').on('click', function () {
$("#contact").validate().resetForm();
$("#contact").removeClass("has-error");
});
Problem: The error Text and the Input-fields will be deleted. But the red border (.has-error) or the green border (.has-success) don't be deleted.
i've created an JSFiddle for you:
http://jsfiddle.net/bBc8c/1/
One Button is clear the input text, the other is delete the error Messages.
I need a Button which reset both (Text, Error Message) and the main problem the red border from the has-* classes.
One Button is declared as type=submit the other is type=button:
<button type="button" id="cancel" class="btn btn-danger btn-lg">Reset 1</button>
<button type="reset" id="cancel2" class="btn btn-danger btn-lg">Reset 2</button>
Your Updated Fiddle
JS Update
$('#cancel').on('click', function () {
$("#contact").validate().resetForm();
$("#contact").find('.has-error').removeClass("has-error");
$("#contact").find('.has-success').removeClass("has-success");
$('#contact').find('.form-control-feedback').remove()
});
For bootstrapvalidator, this might useful when the form being display via bootstrap modal,
$("#editModal").on('hidden.bs.modal', function () {
//Removing the error elements from the from-group
$('.form-group').removeClass('has-error has-feedback');
$('.form-group').find('small.help-block').hide();
$('.form-group').find('i.form-control-feedback').hide();
});
#J Santosh answer worked for Bootstrap 3, great work.
For Bootstrap 4 I have done following changes:
$('#cancel').on('click', function () {
$("#contact").validate().resetForm();
$("#contact").find('.is-invalid').removeClass("is-invalid");
$("#contact").find('.is-valid').removeClass("is-valid");
$("#contact").find('.invalid-feedback').remove();
$("#contact").find('.valid-feedback').remove();
});
Simply have to change the class names. Hope it helps!
I'd reset the form by just using an input[type="reset"] (no jQuery required)
<form class="form" method="post" action="" name="contact" id="contact">
<input type="reset" class="btn btn-danger btn-lg" />
</form>
i've created an JSFiddle for you:
http://jsfiddle.net/bBc8c/1/
One Button is clear the input text, the other is delete the error Messages.
I need a Button which reset both (Text, Error Message) and the main problem the red border from the has-* classes.
One Button is declared as type=submit the other is type=button:
<button type="button" id="cancel" class="btn btn-danger btn-lg">Reset 1</button>
<button type="reset" id="cancel2" class="btn btn-danger btn-lg">Reset 2</button>
Regards
Related
I think I'm going a little mad.
I have a working re-captcha div and submit button:
<div class="g-recaptcha" data-sitekey="LALALALALAL" data-callback="enableBtn"></div>
<br />
<button id="getJSON" type="button" class="btn btn-primary">Save Form</button>
The Save Form button is disabled on page load.
I have the following function:
<script>
function enableBtn(){
var submit = document.getElementById('getJSON');
if (submit.disabled) {
document.getElementById("getJSON").disabled = false;
} else {
document.getElementById("getJSON").disabled = true;
}
}
</script>
The callback works fine for the initial enabling of the button on successful recaptcha response, but when the recaptcha times out the button doesn't get disabled.
As I said, I think I'm going a little mad.
I think that you can use data-expired-callback attribute.
<div class="g-recaptcha" data-sitekey="LALALALALAL" data-callback="enableBtn" data-expired-callback="enableBtn"></div>
<br />
<button id="getJSON" type="button" class="btn btn-primary">Save Form</button>
so I want to get a specific value if a button is clicked in my form, but somehow its listening on all buttons and not only the buttons in my form.
Instead of the javascript example below I also tried calling the class by
$('.modifygap').bind('click', function (e) {
but in this example the value didnt get set correctly.
Here is my html:
<button type="button" id="anotherbutton">Another</button>
<form action="editortoken_information" id="showtoken" method="POST">
<button class="btn btn-outline-secondary" type="submit" name="modifygap" id="modifygap" class="modifygap"
value="14" data-value="test">14</button>
<button class="btn btn-outline-secondary" type="submit" name="modifygap" id="modifygap" class="modifygap"
value="15" data-value="test">15</button>
</form>
And here is my javascript function:
$(document.getElementById("showtoken")).ready(function () {
$("button").click(function (e) {
e.preventDefault();
document.getElementById('tokenindex').value = this.getAttribute("data-value");
})
})
I thought by listening only on the specific id it would only detect button clicks in the form. But for some reason it is listening to all button clicks.
Use event.target.value to get the value of clicked element.
$(document).ready(() => {
$('.modifygap').bind('click', function (e) {
console.log('e', e.target.getAttribute("data-value"))
});
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button type="button" id="anotherbutton">Another</button>
<button class="btn btn-outline-secondary modifygap" type="submit" name="modifygap" id="modifygap"
value="14" data-value="test14">14</button>
<button class="btn btn-outline-secondary modifygap" type="submit" name="modifygap" id="modifygap"
value="15" data-value="test15">15</button>
I have html page that has several button. I want to update my database column when I click a button.
In index.html
<form action="db.php" method="post">
<button type="submit" id="1_y" class="btn btn-success">1.Lambayı Yeşil Yak</button>
<button type="submit" id="1_k" class="btn btn-danger">1.Lambayı Kırmızı Yak</button></form>
And it looks like that
http://prntscr.com/fa5eba
My db table Webtek
http://prntscr.com/fa5ffl
What I want is to update 'birinci_lamba' to 1 when 1_y is clicked and update 'birinci_lamba' again to 0 when 1_k is clicked.
So, what should be my db.php page ? Or any other advise to do that ?
You use a from-tag, so you should use <input.. instead of <button... You seem to use bootstrap and <input class="btn btn-danger" /> should also work.
Then, you need to give your inputs a name attribute:
<form action="db.php" method="post">
<input type="submit" name="1_y" id="1_y" class="btn btn-success">1.Lambayı Yeşil Yak />
<input type="submit" name="1_k" id="1_k" class="btn btn-danger">1.Lambayı Kırmızı Yak /></form>
Your db.php file could look like that:
<?php
if(isset($_POST['1_k'])){
mysql_query("..."); //your update-query
} elseif(isset($_POST['1_y']){
mysql_query("..."); //your other update-query
}
I am building angular2 form and I would like to have multiple buttons to submit the form, e.g "Save" and "Save and close".
I have tried to use simple buttons with click action on them, but I didn't find anyway to manually mark form as submitted to force form validation.
<form #ticketForm="ngForm" novalidate>
<input type="text" id="customerName" required
name="customerName" [(ngModel)]="ticket.customerName"
#customerName="ngModel">
<div class="tj-form-input-errors"
*ngIf="customerName.errors && (customerName.dirty ||
customerName.touched || ticketForm.submitted)">
<small [hidden]="!customerName.errors.required">
Customer name is required
</small>
</div>
<button type="button" (click)="save(ticketForm)">Save</button>
<button type="button" (click)="saveAndClose(ticketForm)">Save and close</button>
</form>
Assign different id to each button. Then you can obtain the id of the button which triggered submit using document.activeElement.id. like the following :
In your Html :
<form #form="ngForm" (submit)="firstSave(form,$event)">
...
<div class="form-group">
<input type="submit" id="submit-1" value="Submit 1" class="btn btn-sm btn-primary"/>
<input type="submit" id="submit-2" value="Submit 2" class="btn btn-sm btn-success"/>
</div>
</form>
Then in your typescript :
firstSave(form: NgForm, $event: Event) {
var activeButton = document.activeElement.id; // document.activeElement?.id
if (activeButton == "submit-1") {
alert("you have clicked on submit 1");
}
if (activeButton == "submit-2") {
alert("you have clicked on submit 2");
}
}
StackBlitz Here.
You can subscribe to form changes, which I think will fire form validation.
I do something like this:
this.physicalForm.valueChanges
.map((value) => {
return value;
})
.filter((value) => this.physicalForm.valid)
.subscribe((value) => {
do what you need with the values here...
});
Then in your click handler for each button, if this.physicalForm.valid you save or save&update.
i ran into the same situation. In my case i have 2 submit 'Save','Save and Allocate'
Solution
You can simply set the the type of submit button in the payload and do the action accordingly in the backend code.
Sample code
//here formData is my payload for the API call eg: formData.name,formData.email
<button type="submit" class="btn btn-primary md" (click)="formData.save_type='save'">Save</button>
<button type="submit" class="btn btn-primary md" (click)="formData.save_type='allocate'">Save And Allocate</button>
Trying to wrap my head around some Angular items and working thru a tutorial to edit and learn.
Clicking the below button shows the below form. How do I reverse this once the form is submitted? Meaning hiding the form on submit until the button is clicked once more.
<button ng-click="addNewClicked=!addNewClicked;" class="btn btn-sm btn-primary">
<i class="fa fa-plus"></i>Add Task
</button>
Basically, the form appears, I enter something and submit, but would like the form to dissapear upon submit? Thinking something to do with ng-hide, but can I do this using only Angular? Or do I need to do something with javascript/css?
<div id="addForm" class="margin-full-5">
<form ng-init="addNewClicked=false; " ng-if="addNewClicked" id="newTaskForm" class="add-task">
<div class="form-actions">
<div class="input-group">
<input type="text" class="form-control" name="comment" ng-model="taskInput" placeholder="Add New Task" ng-focus="addNewClicked">
<div class="input-group-btn">
<button class="btn btn-default" type="submit" ng-click="addTask(taskInput)">
<i class="fa fa-plus"></i> Add Task
</button>
</div>
</div>
</div>
</form>
You can also achieve this using a combination of Angular form's attribute $submitted, ng-hide and ng-submit
<form name="myForm" ng-hide="myForm.$submitted" ng-submit="submit()">
<button>Submit</button>
</form>
Read about it here: https://docs.angularjs.org/api/ng/type/form.FormController
Somewhere in your view.
<button ng-click="showTheForm = !showTheForm">Add a Task</button>
<form ng-show="showTheForm" ng-submit="processForm()">
<button>Submit</button>
<button type="button" ng-click="showTheForm = false">Cancel</button>
</form>
Somewhere in your controller
$scope.processForm = function() {
// execute something
$scope.showTheForm = false;
}
Your form is displaying IF the addNewClicked value evaluates to true, which occurs when you click the add task button. If you want the form to disappear on submit, you just need to make the onClick to that button change your addNewClicked to false.
AngularJS Docs for Ng-If
You can do that by using ng-show/ng-hide as per example below :
<form ng-init="addNewClicked=false; " ng-if="addNewClicked" ng-hide="hideform" id="newTaskForm" class="add-task">
and modify the submit method to make the hideform = true;
$scope.addTask = function(input){
... your things
$scope.hideform = true;
}
You can also do the same using jQuery :
$("#newTaskForm").hide();
This should do the trick:
$scope.addTask = function(taskInput) {
...
$scope.addNewClicked = false;
}
You could use ng-show as you can see in this jsfiddle
This will show and hide the div element based on clicking the button. When the button is clicked it will toggle the boolean, hence acting as an on/off switch for ng-show