We have a responsive image, and there are elements positioned absolutely above the image - The elements positioned above the image need to stay in the exact same position proportionate with the image.
For example: http://jsbin.com/juremuqa/1/edit - I want the red circles on the cat to stay above the eyes. The circles do not have to resize, just cover the eyes no matter height or width of square element. The image should also scale proportionately.
Possible in just CSS? Or would you have to calculate label position with JS?
The positioned elements will be text in the end.
Add this to the Css.
.square .image {
background: url('http://animalkingdomz00.com/images/chartreux-cat-6.jpg');
width: 100%;
height: 100%;
display: block;
background-size: 100% 100%;
}
Try and tell me
If you don't need the red dots to do anything then the easiest solution is to replace the eyes with a transparent background and let the red background color shine through. Otherwise your going to need to play around with image positioning, right now your problem is that your keeping height and width both fixed which means when the image changes size it stretches in ways that change the height to width ratio making your eye percents fail. If you want that then SSS has the right idea.
Related
So I want to have a central div that is full screen, and to make the width and height of the body 150 vw and vh, with a margin of 50% so when you load the page it holds the div central, but you can scroll up, down, left, right, outside of this central div a little bit.
If you do the div 100vw, 100vh, and then the body 200vw, 200vh, it only enables scrolling to the right and downwards.
This is my understanding of how to get towards what I'm trying to do:
HTML:
<div>
centered and full screen div?
</div>
</body>
CSS:
body{
width:150vw;
margin-left:50vw;
height:150vh;
margin-top:50vh;
}
div{
width: 100vw;
height: 100vh;
border: solid;
}
JAVA:
window.scrollTo(50 + 'vw', 50 + 'vh');
https://jsfiddle.net/dsLnzyxw/3/
But this doesnt work as the javascript doesn't accept vw in the scrollTo function.. but just to give a better idea of what I'm trying to do.
Also understand I might be going around on crazy route trying to achieve something that could be done quite simple in css?
How do I achieve this?
Thanks !
In order to get units relative to the viewport width and viewport height (vw and vh) you could do simple calculations:
window.scrollTo(0.5 * window.innerWidth, 0.5*window.innerHeight);
which would set the scroll position to 50% of the window width and 50% of the window height. window.innerWidth returns the width of the window, and this is multiplied by 50% to get 50% of the width of the window in pixels.
The same goes for height. Setting the scroll position is not possible without JavaScript unfortunately.
I have a responsive background image with a smaller image positioned over it. I am trying to keep the smaller image at a specific location when the window is resized.
Both images scale properly, and the left position works so far, but not the top position.
img {
max-width:100%;
}
#dot {
position: absolute;
top: 17%;
left: 66.5%;
width: 10%;
height: 0;
padding-bottom: 10%;
}
I have found some questions with answers that suggest:
Vertical Alignment or Positioning with Javascript
I've also looked into .position() and .offset(), not sure if either would work.
I think my best solution would be to calculate the Y offset using the current window height as a reference but I am not sure what my JS or Jquery code should look like.
Here is my jsfiddle:
http://jsfiddle.net/melissadpelletier/xBu79/21/
I'm not sure exactly what you're trying to do with your images, but you could create a new smaller image (green dot) with the same aspect ratio as your background image, and have the dot placed where it needs to be within that aspect ratio. Then stretch the width of that to be 100% and the two images are basically overlapping, but the top image (smaller image) has a transparent background. Not sure if that all makes sense, but I made a new image and did the fiddle thing, which I'm new to: http://jsfiddle.net/ydack/
img
{
width:100%;
}
#dot
{
width: 100%;
position: absolute;
top:0;
left:0;
}
#dotImg
{
top: 0;
left: 0;
width: 100%;
}
I mistakenly placed the green dot's position based on the black outline, not the full background image, so the dot is slightly up and right of where it needs to be. BUT, the position is maintained while re-sizing the window. Hacky, but it could work!
You are definitely gonna need some javascript for this. What you can do is calculate the height and width of the image whenever you resize your browser window. Then simply use some math to calculate the position of the dot relative to those dimensions.
var height = $('#image').height();
var width = $('#image').width();
/* change the fractions here according to your desired percentages */
$('#dot').css({left: width/2, top: height/2});
$(window).resize(function() {
height = $('#image').height();
width = $('#image').width();
/* change the fractions here according to your desired percentages */
$('#dot').css({left: width/2, top: height/2});
});
Try this code: http://jsfiddle.net/LimitedWard/FFQt2/3/
Note that you will need to also resize the dot according to the height/width of the image if you want it to always fit inside that box.
Edit: after further investigation, it is possible to do this in CSS; however, it's a lot sloppier because the dot doesn't follow the image if the window is too wide. This jQuery solves that problem by using pixel-based positioning.
http://jsfiddle.net/sajrashid/xBu79/24/
plenty of errors mainly not closing tags
<div id='background'>
<img src='http://i.imgur.com/57fZEOt.png'/>
<div id='dot'>
<img src='http://i.imgur.com/yhngPvm.png'/>
</div>
</div>
I have a large image whose height is bigger than the screen height. I have no problem with the width. I need to crop it so that the top 65% of the screen contains this image.
<body>
<img class="img" src="image.jpg" alt="img">
<p>Description</p>
</body>
If I write a CSS as below, the whole image gets compressed to fit in 65% screen. Moreover, if I resize the screen, the image automatically starts attempting to fit in the top 65%, making the whole screen look disturbed.
body, html { height:100% }
img.img { height:65% }
I want instead, the image to be cropped so that the leftover fits in the 65%, and then it stays that way. That is, if I now resize the window, let the vertical scrollbar appear. How can I achieve this?
(PS: I didn't want to give a fixed height because I want the webpage to be viewed in different devices like mobile phone and iPads too.
I think this is what I need:
Get the maximum height of the device (not the current height of the browser screen as the user might have minimized it for some reason)
Crop the image in such a way that it fits the top 65%, and display it
Keep the image size that way irrespective of the user changing the screen size
But I am not sure how to achieve it.)
Is this what you are seeking: http://jsfiddle.net/JjwMw/1/
body, html {
height: 100%;
margin: 0;
padding: 0;
}
.container {
height: 65%;
width: 100%;
position: relative;
top: -22.75%; /* 65*35/100 */
background-image: url(http://placehold.it/1024x768);
background-size: cover;
background-position: center bottom;
}
Note that the image is now a background-image and is leveraging the background-size property which is not supported in IE8 (...who cares?). If the image cannot be a background image, you scale a div proportionally to fill the width using a padding hack (Proportionally scale a div with CSS based on max-width (similar to img scaling)) and have the inside image set to 100% width and height.
Maybe this can be useful to you:
http://demo.solemone.de/overflow-image-with-vertical-centering-for-responsive-web-design/
Also a search for css cliping property here or in google should bring enough info
I have a background image with height 1400 and width 1000 , if i use any full screen background jquery plugin or code it crops from top or bottom and make it fit the whole screen but what i want is a plugin or code which will make sure the background image is responsive based on width of browser yet the full height of background image should be visible with scroll bar. currently it crops height from top and bottom.
if thats not possible atleast the crop should be only from bottom to maintain aspect ratio.
.background{
width: 100%;
height: 100%;
background-image:url(path/to/image.jpg);
background-position: top center;
background-size: cover;
}
This will only crop the bottom off, but make sure the image 'covers' the entire element.
Demo: http://jsfiddle.net/Rkf6Q/
To show 100% height, and have the width cropped, just set the background-size parameter to auto 100%
Demo: http://jsfiddle.net/Rkf6Q/1/
In my intro page I have a really big image in height and width to fit all the resolutions (more than 4000px in width) and I set it as below:
#source-image {
width: 100%;
position: absolute;
top: 0;
left: 0;
}
Then, I added some text over that image with these style properties:
.description {
position:absolute;
top:510px;
left:23px;
width:340px
}
And it looks properly (and as I want it to be shown) on my 15.6 inch laptop with 1366x768 resolution.
However when my roommate saw it on his high resolution monitor the description was not on the “right” position. Of course, I understand why this is happening.
My question is how can I keep dynamically the proper position of the description text in all resolutions?
Thank you very much.
Set the distance from the bottom, not from the top. Or set it in %.
EDIT: I've adapted one of my experiments into an example: http://dabblet.com/gist/2787061
The position of the description is set relative to the bottom and the left of the image container (the image is filling its entire container).
In the first case, the distances to the left and the bottom of the image container are fixed, in px.
In the second case, they are in % and change on resizing the browser window.
Basically, the rules that do the trick are
figcaption {
bottom: 5px;
left: 23px;
/* more rules here */
}
in the fist case (fixed distances, in px) and
figcaption.perc {
left: 10%;
bottom: 17%;
}
in the second case (percentage).
Also, please note that you don't need position: absolute or to set the top and the left properties for the image.
However, you do need to set position:relative on the parent of the description box.
For the image to fill the screen horizontally, you need to have margin:0; and padding:0; on the body element and width: 100%; and margin: 0; on the figure element. I've edited my example to reflect these changes http://dabblet.com/gist/2787061
For the image to fill the screen both horizontally and vertically, the easiest way is to not even use an img tag, but simply set the image as a background image for the body and set the height for both the html and the body elements to 100% - example http://dabblet.com/gist/2792929
Be careful for two reasons: one, this will really distort the image and can make it look ugly when resizing the browser window and two, if you need some content below the image you will need to give the the outer element position: absolute and set its top: 100%. Both these two aspects can be seen in the example I've linked to. You can simply remove the content below the image if you don't need it.
use position:relative; for the div that wraps the image, and position:absolute; for the text div
please set percentage
check the example- description box set in horizontal center,
first set position relative into wraper div
.description {
position:absolute;
top:510px;
left:50%;
width:340px;
margin:0 0 0 -170px
}