Develop Reference

How to run JavaScript code on Success of Form submit?

I have an Asp.Net MVC web application. I want to run some code on the successful response of the API method which is called on form submit.
I have the below Code.
#using (Html.BeginForm("APIMethod", "Configuration", FormMethod.Post, new { #class = "form-horizontal", id = "formID" }))
{
}
$('#formID').submit(function (e) {
$.validator.unobtrusive.parse("form");
e.preventDefault();
if ($(this).valid()) {
FunctionToBeCalled(); //JS function
}
}
But FunctionToBeCalled() function gets called before the APIMethod(), but I want to run the FunctionToBeCalled() function after the response of APIMethod().
So I made the below changes by referring this link. But now the APIMethod is getting called twice.
$('#formID').submit(function (e) {
$.validator.unobtrusive.parse("form");
e.preventDefault();
if ($(this).valid()) {
//Some custom javasctipt valiadations
$.ajax({
url: $('#formID').attr('action'),
type: 'POST',
data: $('#formID').serialize(),
success: function () {
console.log('form submitted.');
FunctionToBeCalled(); //JS function
}
});
}
}
function FunctionToBeCalled(){alert('hello');}
So I am not able to solve the issue.

If you want to execute some work on success, fail, etc. situation of form submission, then you would need to use Ajax call in your view. As you use ASP.NET MVC, you can try the following approach.
View:
$('form').submit(function (event) {
event.preventDefault();
var formdata = $('#demoForm').serialize();
//If you are uploading files, then you need to use "FormData" instead of "serialize()" method.
//var formdata = new FormData($('#demoForm').get(0));
$.ajax({
type: "POST",
url: "/DemoController/Save",
cache: false,
dataType: "json",
data: formdata,
/* If you are uploading files, then processData and contentType must be set to
false in order for FormData to work (otherwise comment out both of them) */
processData: false, //For posting uploaded files
contentType: false, //For posting uploaded files
//
//Callback Functions (for more information http://api.jquery.com/jquery.ajax/)
beforeSend: function () {
//e.g. show "Loading" indicator
},
error: function (response) {
$("#error_message").html(data);
},
success: function (data, textStatus, XMLHttpRequest) {
$('#result').html(data); //e.g. display message in a div
},
complete: function () {
//e.g. hide "Loading" indicator
},
});
});
Controller:
public JsonResult Save(DemoViewModel model)
{
//...code omitted for brevity
return Json(new { success = true, data = model, message = "Data saved successfully."
}
Update: If SubmitButton calls a JavaScript method or uses AJAX call, the validation should be made in this method instead of button click as shown below. Otherwise, the request is still sent to the Controller without validation.
function save(event) {
//Validate the form before sending the request to the Controller
if (!$("#formID").valid()) {
return false;
}
...
}

Update your function as follows.
$('#formID').submit(function (e) {
e.preventDefault();
try{
$.validator.unobtrusive.parse("form");
if ($(this).valid()) {
$.ajax({
url: $('#formID').attr('action'),
type: 'POST',
data: $('#formID').serialize(),
success: function () {
console.log('form submitted.');
FunctionToBeCalled(); //JS function
}
});
}
}
catch(e){
console.log(e);
}
});
Check the browser console for fetching error. The above code will prevent of submitting the form.
I think line $.validator.unobtrusive.parse("form") were throwing error.
For that use you need to add the following jQuery libraries.
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery-validation-unobtrusive/3.2.11/jquery.validate.unobtrusive.min.js"></script>

I think you should remove razor form tag if you want to post your form using ajax call and add post api URL directly to ajax request instead of getting it from your razor form tag using id:
Here is the revised version of your code :
<form method="post" id="formID">
<!-- Your form fields here -->
<button id="submit">Submit</button>
</form>
Submit your form on button click like:
$('#submit').on('click', function (evt) {
evt.preventDefault();
$.ajax({
url: "/Configuration/APIMethod",
type: 'POST',
dataType : 'json',
data: $('#formID').serialize(),
success: function () {
console.log('form submitted.');
FunctionToBeCalled(); //JS function
}
});
});
function FunctionToBeCalled(){alert('hello');}

You need to use Ajax.BeginForm, this article should help [https://www.c-sharpcorner.com/article/asp-net-mvc-5-ajax-beginform-ajaxoptions-onsuccess-onfailure/ ]

The major thing here is that I didn't use a submit button, I used a link instead and handled the rest in the js file. This way, the form would nver be submitted if the js file is not on the page, and with this js file, it initiates a form submission by itself rather than th form submitting when the submit button is clicked
You can adapt this to your solution as see how it respond. I have somthing like this in production and it works fine.
(function() {
$(function() {
var _$pageSection = $('#ProccessProductId');
var _$formname = _$pageSection.find('form[name=productForm]');
_$formname.find('.buy-product').on('click', function(e) {
e.preventDefault();
if (!_$formname.valid()) {
return;
}
var formData = _$formname.serializeFormToObject();
//set busy animation
$.ajax({
url: 'https://..../', //_$formname.attr('action')
type: 'POST',
data: formData,
success: function(content) {
AnotherProcess(content.Id)
},
error: function(e) {
//notify user of error
}
}).always(function() {
// clear busy animation
});
});
function AnotherProcess(id) {
//Perform your operation
}
}
}
<div class="row" id="ProccessProductId">
#using (Html.BeginForm("APIMethod", "Configuration", FormMethod.Post, new { #class = "form-horizontal", name="productForm" id = "formID" })) {
<li class="buy-product">Save & Proceed</li>
}
</div>

how to turn off reload of page after sending ajax to php and how to fix this code

How to turn off reload of page after sending AJAX to PHP? The page reloads every time when I press submit. Is it possible to send some picture without form?
<script>
$(document).ready(function (e){
$("#uploadForm").on('submit', (function(e){
e.preventDefault();
$.ajax({
url: "/class/pdo/add_new_field.php",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData:false,
success: function(data){
$("#targetLayer").html(data);
},
error: function(){}
});
}));
$('#uploadForm').submit(function () {
return false;
});
});
</script>
<form id="uploadForm" method="POST">
<div style="margin-left: 75px;">
<div class="save_divs">picture<input type="file"></div>
<div class="save_divs">name:</div>
<div class="save_divs">date</div>
<div class="save_divs">short_info</div>
<div class="save_divs">long info<input type="submit"></div>
</div>
</form>
Do i need slash (/) in $.ajax url?

too many event handlers. Remove the second one unless sendContactForm(); is important. If it is, update your question with it.
syntax error in the event handler, remove the ( from before (funtion in the submit and one of the ) from the }));
If class is the top folder in your hierarchy you can use the /class, if it is under the form location, then no. Use "class/..."
like this
<script>
$(function(){
$("#uploadForm").on('submit',function(e){
e.preventDefault();
$.ajax({
url: "/class/pdo/add_new_field.php",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData:false,
success: function(data){
$("#targetLayer").html(data);
},
error: function(){}
});
}); // also a ) too many here
});
</script>

Ok, First problem is : -
You have submit binded twice once with on, once with submit(), use only one.
Now the error is coming due to the second binding,
There is some error in sendContactForm(), due to which it never gets to the line return false and default page is submitted and is reloaded, check for console errors, also, to prevent confusion in future, you could probably use e.preventDefault(); at the start of the function to stop further propogation. (thanks #rory)
$('#uploadForm').submit(function (e) {
e.preventDefault();
sendContactForm();
return false;
});

jquery function not redirecting url

I am working with codeigniter and jquery. I am using ajax to send some info to a codeigniter function to perform a db operation , in order to update the page. After the operation is complete I am trying to refresh the page. However the refresh works inconsistently and usually I have to reload the page manually. I see no errors in firebug:
var message = $('#send_message').val()
if ((searchIDs).length>0){
alert("searchIDs "+searchIDs );
$.ajax({
type: "POST",
url: "AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
success: function(){
alert("OK");
},
complete: function() {
location.href = "pan_controller/my_detail";
}
})
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("OK");
location.href = "pan_controller/my_detail";
});
} else { alert("nothing checked") }
break;
How can I fix this?
addendum: I tried changing to ;
$.ajax({
type: "POST",
url: "AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("REFRESHING..");
location.href = "pan_controller/my_detail";
});
}
})
This is just defaulting to the website homepage. again, no errors in firebug

Add the window object on location.href like this:
window.location.href = "pan_controller/my_detail";

Try to use full path like
$.ajax({a
type: "POST",
url: "YOURBASEPATH/AjaxController/update",
data:{ i : searchIDs, m : message },
dataType: 'json',
.done(function() { // echo url in "/path/to/file" url
// redirecting here if done
alert("REFRESHING..");
location.href = "YOURBASEPATH/pan_controller/my_detail";
});
}
})
BASEPATH should be like this "http://www.example.com"

Try disabling the csrf_enabled (config/config.php) and trying it. If that works, then re-enable the protection and, instead of compiling data yourself, serialize the form; or, at least include the csrf hidden field codeigniter automatically adds. You can also use GET to avoid the CSRF protection, but that's least advisable of of the solutions.

Submit unresponsive after ajax call + fadeIn()

Good day, fellow programmers.
There's this index.php that does an Ajax call to login.php and appends the DOM elements and some javascript from inside this into the body of the index. This login.php consists out of a a single div that contains a form and a submit button, which fadeIn() as soon as it is all appended.
However: the submit button is unresponsive!
I did find, after a while, that this does not happen when you directly access login.php via URL (.../.../login.php) instead. This means it's the fact that the index appends the whole, which makes them unresponsive.
(Also: in light of this, I've added a $(document).ready(function(){ ... }); around the entire script in the login.php, but that did not seem to help at all. Instead it caused all functions to return errors...)
I'm out of ideas. Perhaps some of you might have had any experience with these matters?
As always, thank you for the time!
Here's the (simplified) code:
index.php
$('#logInButton').click(function(){
loadContent('/login/login.php', 'body');
});
loadContent();
function loadContent(url, appendDiv, optionalData, cb) {
if (appendDiv == '#contentCenter') {
// vanity code
}
if (cb) {
$.ajax({
url: url,
cache: false,
type: 'post',
data: optionalData,
success: function(html){
$(appendDiv).append(html);
},
complete: function(){
cb();
}
});
}
else {
$.ajax({
url: url,
cache: false,
type: 'post',
data: optionalData,
success: function(html){
$(appendDiv).append(html);
}
});
}
}
login.php (deleted some styling. If you want some specific info, just ask!)
<style>
// some styling
</style>
<div id="loginBlack">
<div class="login" style="z-index:9999;">
<form id="myform1" name="myform1">
<div>
<img src="images/inputEmail.png" />
<div id="emailOverlay">
<input id="email" type="text"/>
</div>
</div>
<input id="iets" name="iets" type="submit"/>
</form>
</div>
</div>
<script type="text/javascript">
// $(document).ready(function(){ // <-- been trying this out.
$('#loginBlack').fadeIn(t)
// some functions pertaining to logging in and registering
// });
</script>

Use jquery on() instead of click()
$('body').on('click', '#logInButton' ,function(){
loadContent('/login/login.php', 'body');
});
That should make the elements behave properly
Note: you can also replace body selector with something nearer to the click button ( its nearest parent )
EDIT::
With this you can have the styling in your normal css file. Put it outside of the login.php
And your js goes into into the success handlers. So just leave the php with the actual html
function loadContent(url, appendDiv, optionalData, cb) {
if (appendDiv == '#contentCenter') {
// vanity code
}
if (cb) {
$.ajax({
url: url,
cache: false,
type: 'post',
data: optionalData,
success: function(html){
$(html).hide().appendTo(appendDiv).fadeIn('slow');
},
complete: function(){
cb();
}
});
}
else {
$.ajax({
url: url,
cache: false,
type: 'post',
data: optionalData,
success: function(html){
$(html).hide().appendTo(appendDiv).fadeIn('slow');
}
});
}
}

passing variable back from the server to ajax success

User fills input texts, presses the button Submit. The data sends to the server to be stored and result returned back. Fancybox window with result appears. My question is: how to display the result $res1 in the fancybox?
$.ajax({
type:"POST",
url:"index/success",
async:false,
data:{ name:name, password:password},
success:function ()
{
var html='$res1 from the server should be here instead of this string';//var html=$res1.
$.fancybox(
{
content: html,//fancybox with content will be displayed on success resul of ajax
padding:15,
}
);
}
});
=========================
OK, still doesn't work (returns in the fancybox the whole page+ the word "hello" on top instead of the message "hello"). Below is my update regarding the answers below, that doesn't work properly:
PHP:
<?php
$res1="hello";... // handle logic here
echo $res1; // print $res1 value. I want to display "hello" in the fancybox.
?>
AJAX
$.ajax({
type: "POST",
url: "index/success",
async: false,
data: {
name: name,
password: password
},
success: function (html) {
$.fancybox(
{
content: html,//returns hello+page in the fancybox
//if I use the string below instead of the upper one, the fancybox shows "The requested content cannot be loaded. Please try again later."
// content: console.log(html)
padding:15,
}
});
=============
New update:
Fixed!!! The problem was the data ( "hello" in the example above) was sent to the template in the framework, and template was displayed.
That's why.
Fixed.
Thank you.
Everybody.

Assuming you're using PHP:
PHP:
<?php
... // handle logic here
echo $res1; // print $res1 value
?>
AJAX:
$.ajax({
type: "POST",
url: "index/success",
async: false,
data: {
name: name,
password: password
},
success: function (html) {
// given that you print $res1 in the backend file,
// html will contain $res1, so use var html to handle
// your fancybox operation
console.log(html);
}
});
Enjoy and good luck!

$.ajax({
type:"POST",
url:"index/success",
async:false,
data:{ name:name, password:password},
success:function(html){ // <------- you need an argument for this function
// html will contain all data returned from your backend.
console.log(html);
}
});