I have a form that I have two buttons on. One button should take the user to one php script and the other button would take the user two a different php script. However for some reason the buttons aren't doing anything. Here is the code.
<script language="Javascript">
function OnButton1()
{
document.contactform.action = "../scripts/email-info.php"
// document.Form1.target = "_blank"; // Open in a new window
document.contactform.submit(); // Submit the page
return true;
}
function OnButton2()
{
document.contactform.action = "../scripts/email-info2.php"
//document.contactform.target = "_blank"; // Open in a new window
document.contactform.submit(); // Submit the page
return true;
}
</script
Then here is the actual form code:
<form id="contact-form" name="contactform" method="post">
<fieldset>
<div id="holder">
<div id="formLeft">
<div class="txtlabel">Name* </div><div class="input-bg"><input type="text"
name="name" id="name" required></div>
</div>
</div>
<div id="msgbox">
<div class="txtlabel">Tell Us About Your Business Needs</div>
<div class="message-bg">
<textarea name="message" id="message" rows="9" cols="56" required></textarea><input
name="formpage" type="hidden" value="<?=$pagename;?>" />
</div></div><div style="clear:both"></div><br /><br />
<input src="/submitbtn.jpg"
name="submit" value="View Now" class="submit-button" onclick="OnButton1();"/>
<input src="/submitbtn.jpg"
name="submit" value="Download Now" class="submit-button2" onclick="OnButton2();" />
</fieldset>
</form>
I've removed some of the submission fields to make it more easily viewable. But I get nothing when I click either button...Any thoughts??
problem is in input:
<input src="/submitbtn.jpg"
name="submit" value="View Now" class="submit-button" onclick="OnButton1();"/>
When you have a form:
document.contactform.submit
Javascript returns the input with name submit, not the submit function.
You could change the name of the input:
<input src="/submitbtn.jpg"
name="yourName" value="View Now" class="submit-button" onclick="OnButton1();"/>
Also, your inputs are not buttons, check this.
Update
This question mentions HTML5 formaction attribute:
<form action=#">
<buton formaction="script-1.php">submit one</button>
<buton formaction="script-2.php">submit two</button>
</form>
I'm surprised no one mentioned formaction. It is a legal attribute (in HTML5) for the input and button tag in submit/image state and can be used to send form data to a different action page. http://mdn.beonex.com/en/HTML/Element/input.html (it is also valid in button too).
<form action=#">
<buton formaction="script-1.php">submit one</button>
<buton formaction="script-2.php">submit two</button>
</form>
In case you need to support IE9-, you simply can polyfill this, using webshims.
<script src="webshims/polyfiller.js"></script>
<script>
webshims.polyfill('forms');
</script>
<!-- now it also works with IE8/9 and other legacy browsers -->
<form action=#">
<buton formaction="script-1.php">submit one</button>
<buton formaction="script-2.php">submit two</button>
</form>
The reference to your form is
document.forms.contactform
and not
document.contactform
So, for example, the submit button should be:
document.forms.contactform.submit();
// ^^^^^
The same correction should be applied to other references.
Related
I am trying to add more links to this drop down menu, the menu itself works and the links I've provided works as well, the problem is that when I try to add links through a Javascript file using appendChild, nothing seems to be happening. Also the form handling is successful in other codes, the only thing wrong is what is described above.
dropdown.html
<body>
<form id="aform">
URL:<br>
<input type="text" name="URL" id="URL">
<br>
Bookmark Name:<br>
<input type="text" name="bookmarkname" id="bookmarkname">
<br><br>
<input type="submit" id="formsubmit">
</form>
<div class="dropdown">
<button class="dropbtn" id="dropdown">Links</button>
<div id="myDropdown" class="dropdown-content">
Youtube
Amazon
Yahoo
</div>
</div>
<script src="dropdown.js"></script>
dropdown.js
function retrieveFormData() {
var URL = document.getElementById("URL").value;
var Bookmarkname = document.getElementById("bookmarkname").value;
var y = document.getElementById("myDropdown");
var aTag = document.createElement('a');
aTag.appendChild(document.createTextNode(Bookmarkname))
aTag.href = URL;
y.appendChild(aTag);
}
So I try to append new to 'y', but nothing happens in the actual drop down menu, no is added.
That is because you are using a submit button. The submit button tells the browser to send the contents of the form to the server side.
What you want to do is change the submit button to a regular button and add an onclick event.
<body>
<form id="aform">
URL:<br>
<input type="text" name="URL" id="URL">
<br>
Bookmark Name:<br>
<input type="text" name="bookmarkname" id="bookmarkname">
<br><br>
<input type="button" id="formsubmit" onclick="retrieveFormData();" value="Submit">
</form>
<div class="dropdown">
<button class="dropbtn" id="dropdown">Links</button>
<div id="myDropdown" class="dropdown-content">
Youtube
Amazon
Yahoo
</div>
</div>
<script src="forminput.js"></script>
This:
var Bookmarkname = document.getElementById("bookmarkname").value;
...will set Bookmarkname to the string value of #bookmarkname. Then you have this line:
aTag.appendChild(Bookmarkname);
appendChild is for appending a child DOM Node; it won't work for setting text, so you may be getting a link that has no content. You can, however, do aTag.appendChild(document.createTextNode(Bookmarkname)).
I'm wondering how I can make this work, unfortunately my code doesn't work. I want my form to have two buttons; one goes to the other PHP file, and the other goes to another PHP file.
The first button, SUBMIT, is working fine. But the second button, SEE RANK, is not working, nothing happens after clicking it
<section class="small-section bg-gray-lighter" id="start">
<div class="container relative">
<!-- FORMS -->
<form id="format" class="form align-center" action="Algorithms/article.php" method = "GET">
<form id="rank" class="form align-center" action="Algorithms/Main2.php" method = "GET">
<div class="row">
<div class="col-md-8 align-center col-md-offset-2">
<div class="newsletter-label font-alt">
Type the description of your case below
</div>
<div class="mb-20">
<!-- INPUT TEXT FIELD -->
<input placeholder="Start typing here" name = "caseInput" class="newsletter-field form-control input-md round mb-xs-12" type="text" required/>
</form>
</form>
<!-- BUTTONS -->
<button form="format" type="submit" class="btn btn-mod btn-medium btn-round mb-xs-10">
Submit
</button>
<button form="rank" type="submit" class="btn btn-mod btn-medium btn-round mb-xs-10">
See rank
</button>
<!-- END OF BUTTONS -->
</div>
<div class="form-tip">
<i class="fa fa-info-circle"></i> Ex. "The father killed her daughter."
</div>
<div id="subscribe-result"></div>
</div>
</div>
</div>
</section>
And it looks like this:
First, it doesn't make sense to use <form> inside <form>. There are couple of ways to do this:
Method 1
Use 2 forms instead.
<form method="post" action="php_file_1.php" id="form1">
<!-- Your further HTML Code Goes Here... -->
</form>
<form method="post" action="php_file_2.php" id="form2">
<!-- Your further HTML Code Goes Here... -->
</form>
Method 2
Use a single PHP file. But perform different function on each button click.
<form method="post" action="functions.php" id="form">
<!-- Your further HTML Code Goes Here... -->
<input type="submit" name="action_1" id="button1">
<input type="submit" name="action_2" id="button2">
</form>
Then in your functions.php file:
if(isset($_POST['action_1'])){
action1(); // Your Function Name...
}
elseif(isset($_POST['action_2'])){
action2(); // Your second function
}
You cannot have a form inside a form. (This is why your second buton does not work)
So, your solution will be to have 2 'submit' elements with different names in your form. Then, on form submission, detect and process accordingly depending on which button was pressed.
<!-- BUTTONS -->
<input type="submit" name='submitAction1' class="btn..." value='Submit'>
<input type="submit" name='submitAction2' class="btn..." value='See rank'>
if(isset($_POST['submitAction1'])){
// process form 1
} elseif (isset($_POST['submitAction2'])){
// process form 2
}
From XHTML™ 1.0 The Extensible HyperText Markup Language (Second Edition) - B. Element Prohibitions
form must not contain other form elements
Implementation example with a javascript function which changes the form's action:
<html>
<body>
<script>
function mySubmit(wtf) {
if ('article' == wtf ) {
document.forms['myForm'].action = 'Algorithms/article.php';
} else if ('Main2' == wtf ) {
document.forms['myForm'].action = 'Algorithms/Main2.php';
} else
return false;
document.forms['myForm'].submit();
}
</script>
<form name="myForm">
<input type ="button" value="submit article" class="btn btn-mod btn-medium btn-round mb-xs-10" onClick="mySubmit('article')">
<input type ="button" value="submit Main2" class="btn btn-mod btn-medium btn-round mb-xs-10" onClick="mySubmit('Main2')">
</form>
</body>
</html>
I have a form on my page and want to be able to submit the text box value (partnumber) as a query string in a hyperlink without submitting the form itself ? Is this possible ?
I have done some research and have tried document.getElementById("partnumber").value but am getting the error "Object Required". Code Below.
<form id="form3" name="form3" method="post" action="formpost?rmaid=<%=rmaid%>">
<input name="partnumber" type="text" id="partnumber" size="10" />
<span class="style11">Suggest Link</span>
<input name="invoice" type="text" id="invoice" size="15" />
</form>
I'll set the new page to open in a pop up window and list a series of values in the database but then I need the value selected to come back into the invoice field on the original page. I believe this can be done with JavaScript but I am new to this, can anyone help ?
For those Looking to pass values back I have found this snippet that works...
Put this in the child window
<script language="javascript">
function changeParent() {
window.opener.document.getElementById('Invoice').value="Value changed..";
window.close();
}
</script>
<form>
<input type=button onclick="javascript:changeParent()" value="Change opener's textbox's value..">
</form>
For the input field you should add an OnChange to it. This event should call a function which will then set your link's value.
You can see an example of this here (it uses a button press though and not an input OnChange Event): http://www.java2s.com/Code/JavaScript/HTML/ChangeURLandtextofahyperlink.htm
Edit: Added a Stack Snippet illustrating the solution.
function SetSuggestLink() {
var suggest = document.getElementById('partnumber').value;
document.getElementById('innerSpan').innerHTML =
"Suggest Link: suggest.asp?partnumber=" + suggest;
document.getElementById('QueryLink').href =
"suggest.asp?partnumber=" + suggest;
}
.style11 {
color:black;
}
.style2 {
text-decoration:none;
}
<form id="form3" name="form3" method="post" action="formpost?rmaid=SomeValue">
<input name="partnumber" type="text" id="partnumber" size="10"
OnChange="SetSuggestLink()" /> </br>
<a id="QueryLink" class="style2" href="#">
<span id="innerSpan" class="style11">Suggest Link</span>
</a></br>
<input name="invoice" type="text" id="invoice" size="15" />
</form>
I am trying to set-up a form that has 2 buttons, accept and deny. It doesn't seem to be working. Any thoughts on what I should fix?
<form name="iform" method="post" onsubmit="" onreset="" enctype="multipart/form-data" action="formapprovedeny" class="iform">
Form content here.
<input type="button" onclick="submitForm('html_form_approve.php')" class="submit_button" value="Approved" name="Approved" />
<input type="button" class="submit_button" onclick="submitForm('html_form_deny.php')" value="Denied" name="Denied" />
</form>
Here is the script part.
<script>
function submitForm(action)
{
document.getElementById('formapprovedeny').action = action;
document.getElementById('formapprovedeny').submit();
}
</script>
Your Javscript is trying to submit a form with an id of formapprovedeny but your form does not have an id. Try adding id="formapprovedeny" to your form
It should id="formapprovedeny" not action="formapprovedeny"
<form name="iform" method="post" onsubmit="" onreset="" enctype="multipart/form-data" id="formapprovedeny" class="iform">
You have a problem with your naming.
You try to get the form by it's id, but it is not set. It's name is.
You should use either getElementByName or give your form an id.
The type of button must be 'submit' and the value whatever you want, look this:
<input type="submit" class="submit_button" value="Approved" name="Approved" />
<input type="submit" class="submit_button" value="Denied" name="Denied" />
What do you want to achieve using the 2 buttons? What do you expect?
http://jsfiddle.net/xaW5P/
<script>
function submitForm(action)
{
alert('hello submitForm '+action);
document.getElementById('formapprovedeny').action = action;
document.getElementById('formapprovedeny').submit();
}
</script>
if I use your code (added an alert) this seems to work...whatever it should be doing ;)
I'm trying to use javascript (used within another program) to automate the submission of a form with the appropriate textboxes filled in. Using the simple page below, I can successfully fill out the text box using:
javascript:document.getElementsByName('UserIDValue')[0].value = "12345";
but can't seem to get anything to work that will actually submit the form. None of these attempts at solving it work: (By 'work' I mean have the same effect as if I clicked the Log In button.)
document.forms["MFALogInForm"].submit();
document.getElementsByName("LoginButton")[0].submit();
document.getElementById("MFALogInForm").submit();
document.forms[0].submit();
the code for the page I'm working with is below: The link to it is here: https://ppcplus.121fcu.org/Mobile/Features/Auth/MFA/MFALogin.aspx
<html><body>
<form id="MFALogInForm" name="MFALogInForm" method="post" action="MFALogin.aspx?__ufps=981699">
<input type="hidden" name="__EVENTTARGET" value="">
<input type="hidden" name="__EVENTARGUMENT" value="">
<script language=javascript><!--
function __doPostBack(target, argument){
var theform = document.MFALogInForm
theform.__EVENTTARGET.value = target
theform.__EVENTARGUMENT.value = argument
theform.submit()
}
// -->
</script>
<img id="RoofImage" src="/Mobile/Images/Current_HandheldDevice/Universal/1Pixel.gif" alt="Private PC" /><br />
<img id="LogoHeader_LogoImage" src="/Mobile/Images/Current_HandheldDevice/Universal/Logo.gif" /><br />
<font size="+1" color="#006D9B"><b>LOGIN</b></font><br>
<font size="-1"><b>USER ID</b></font><br>
<input name="UserIDValue"/><br>
<input name="LoginButton" type="submit" value="Log In"/><input name="ResetButton" type="submit" value="Reset"/><br>
</form></body></html>
document.forms[0].elements["LoginButton"].click();
worked for me.