Develop Reference

PHP checkbox only showing first value

I am trying to iterate the row data of each message for each value in the database by a checkbox as when clicked you get the string value on this row
the Code:
<div id="Ticket" style="display:none;" class="tabcontent">
<table class="table">
<thead>
<tr>
<th>Ticket ID </th>
<th>username</th>
<th>Data published</th>
<th>Subject</th>
<th>problem</th>
<th>Statues</th>
<th>Solved?</th>
<th>More Details</th>
</tr>
</thead>
<tbody>
<?php
$query=" Select * FROM tickets where resolved=0";
$result_opened = mysqli_query($db, $query);
while($row = mysqli_fetch_array($result_opened)){ ?>
<tr>
<td data-label="id"><?php echo $row['id']?></td>
<td data-label="username"><?php echo $row['username']?></td>
<td data-label="publish"><?php echo $row['published']?></td>
<td data-label="subject"><?php echo $row['subject']?></td>
<td data-label="problem"><?php echo $row['problem']?></td>
<td data-label="">Open</td>
<td> </i> <br/><br/>
</td>
<td><input type="checkbox" id="toggle">
<label for="toggle">see more</label>
<dialog >
<h>Message</h><br><br>
<p>
//Here I am getting only the first value//
<?php echo $row['message'] ?>
</p>
<label for="toggle">close</label>
</dialog></td></tr>
<?php }?>
</tbody>
</table>
</div>
but I keep on getting only the last value in the specific row
image:
I tried many ways to fix it but the main problem is its only getting the first value in the while loop.

The problem arises because you are assigning same id to all checkbox component.
Instead use this -
input type="checkbox" id="toggle-<?=$row['id']?>">

Send Table Row Data via AJAX Based on Checkbox Checked

I have a table with multiple columns (index.php). One column is a checkbox. Whenever the checkbox is checked, it displays another column where you can select a quantity.
I want to then be able to hit a button called "Add to Order" and have it use AJAX to add any selected rows to the index-order.php page. After all selections have been made, I want to be able to click the "Checkout" button and have it take me to the index-order.php page where it should display all of the added selections in a table.
I know how to navigate to the index-order.php page so my main question is how can I add the selected rows to the page while using ajax and staying on the current page when doing so?
Index.php code:
<form name="form1" action="index-order.php">
<section id="checkout-btn">
<button type="submit" id="checkout" name="order">Checkout</button>
</section>
</form>
<form name="form2" method="POST" action="index-order.php">
<section id="addToOrder">
<button type="submit" class="order" id="order" name="order" value="AddToOrder">Add to Order</button>
</section>
<br>
<div id="my-div2" class="ui-widget">
<div class="ui-widget">
<table id="merchTable" cellspacing="5" class="sortable">
<thead>
<tr class="ui-widget-header">
<th class="sorttable_nosort"></th>
<th class="sorttable_nosort">Loc</th>
<th class="merchRow">Report Code</th>
<th class="merchRow">SKU</th>
<th class="merchRow">Special ID</th>
<th class="merchRow">Description</th>
<th class="merchRow">Quantity</th>
<th class="sorttable_nosort">Unit</th>
<th style="display: none;" class="num">Quantity #</th>
</tr>
</thead>
<tbody>
<?php foreach ($dbh->query($query) as $row) {?>
<tr>
<td class="ui-widget-content"><input type="checkbox" class="check" name="check"></td>
<td name="rows[0][0][loc]" class="loc ui-widget-content" id="loc-<?php echo intval ($row['Loc'])?>"><?php echo $row['Loc'];?></td>
<td name="rows[0][0][rp-code]" class="rp-code ui-widget-content" align="center" id="rp-code-<?php echo intval ($row['Rp-Code'])?>"><?php echo $row['Rp-Code'];?></td>
<td name="rows[0][0][sku]" class="sku ui-widget-content" id="sku-<?php echo intval ($row['SKU'])?>"><?php echo $row['SKU'];?></td>
<td name="rows[0][0][special-id]" class="special-id ui-widget-content" align="center" id="special-id-<?php echo intval ($row['Special-ID'])?>"><?php echo $row['Special-ID'];?></td>
<td name="rows[0][0][description]" class="description ui-widget-content" id="description-<?php echo intval ($row['Description'])?>"><?php echo $row['Description'];?></td>
<td name="rows[0][0][quantity]" class="quantity ui-widget-content" data-quantity="<?php echo $row['Quantity'] ?>" align="center" id="quantity-<?php echo intval ($row['Quantity'])?>"><?php echo $row['Quantity'];?></td>
<td name="rows[0][0][unit]" class="unit ui-widget-content" id="unit-<?php echo intval ($row['Unit'])?>"><?php echo $row['Unit'];?></td>
<td name="rows[0][0][quant]" style="display: none;" class="quantity_num ui-widget-content"><input type="textbox" style="width: 100px;" class="spinner" name="value" id="test"></td>
</tr>
<?php } ?>
</tbody>
</table>
</div>
</div>
</form>
Index-order.php:
<?php if(isset($_POST['rows'])): ?>
<table cellspacing="20">
<tr align="center">
<th>Loc</th>
<th>Report Code</th>
<th>SKU</th>
<th>Special ID</th>
<th>Description</th>
<th>Quantity</th>
<th>Unit</th>
<th>Quantity #</th>
</tr>
<?php
foreach($_POST['rows'][0] as $row):
?>
<tr align="center">
<td><?php echo $row['loc']; ?></td>
<td><?php echo $row['rp-code']; ?></td>
<td><?php echo $row['sku']; ?></td>
<td><?php echo $row['special-id']; ?></td>
<td><?php echo $row['description']; ?></td>
<td><?php echo $row['quantity']; ?></td>
<td><?php echo $row['unit']; ?></td>
<td><?php echo $row['quant']; ?></td>
</tr>
<?php
endforeach;
?>
</table>
<?php endif; ?>
JavaScript (obviously needs some work. Posting what I have so far):
$(function () {
$('#form2').on('submit', function (e) {
if($('input.check').is(':checked')) {
$(this).closest('tr');
e.preventDefault();
var request = $.ajax({
type: 'post',
url: 'index-order.php',
data: $('#form2').serialize(),
success: function(){
alert('success');
},
error: function(){
alert('failure');
}
});
}
});
});

What you can do is get all the siblings of the current checked checkbox and based on that get all the columns and separate the data to finally send it via ajax.
You can do something like this:
$('#form2').on('submit', function (e) {
$checkbox = $(this).find('input.check:checked').parent('td'); //Finds the checked checkbox's column inside #form2
$otherColumns = $checkbox.nextAll(); //Gets all the siblings
});
The above code will get you all the other columns next to the checked checkbox inside your form. What you an do next is travel across $otherColumns and get each individual value using $otherColums.eq(n).html() where n is the number of the column you are trying to get.

Update MySQL data from HTML using Javascript

I'm a beginner in HTML, PHP, JavaScript and MySQL. I've written a HTML code to enter data into a simple table containing columns "Name" and "Email" in MySQL by employing a seperate PHP file. Then I tried fetching the table contents using PHP. But now I need a little help in updating the data. My code is as follows:
enter code here<!DOCTYPE html>
<html>
<script language="javascript" src="update.js"></script>
<?php
$a=mysqli_connect("localhost","root","","test4");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($a,"select * FROM test");
?>
<table border="1" cellspacing="1" cellpadding"1">
<tr>
<th>pkid</th>
<th>Name</th>
<th>Email</th>
<th>Action</th>
</tr>
<?php
for ($i=0; $i<mysqli_num_rows($result); $i++)
{
$row = mysqli_fetch_array($result)
?>
<tr>
<td id="pkid"><?php echo $row['pkid'] ?></td>
<td id="name"><?php echo $row['name'] ?></td>
<td id="email"><?php echo $row['email'] ?></td>
<td><input type=submit onclick="myfunc()" value="View"/></td>
</tr>
<?php
}
?>
</table>
<form action="insert.php" method="post">
<table border="2">
<tr>
<td>Name</td>
<td><input type="text" name="name"></td>
</tr>
<tr>
<td>Email</td>
<td><input type="text" name="email"></td>
</tr>
<tr>
<td>
<input type="submit" value="Add">
</tr>
</table>
</form>
</html>
<?php
mysqli_close($a);
?>

Here is the Code for Update Data to MYSQL :
Html File :
<title>Listing Details for Update</title>
<?php
include ('config.php');
$tbl_name="user"; // Table name
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="400" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
<td></td>
<td></td>
</tr>
<tr>
<td align="center"><strong>pkid</strong></td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Email-Id</strong></td>
<td align="center"><strong>Action</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><? echo $rows['pkid']; ?></td>
<td><? echo $rows['name']; ?></td>
<td><? echo $rows['email']; ?></td>
<td align="center">update</td>
</tr>
<?php
}
?>
</table>
</td>
</tr>
</table>
<?php
mysql_close();
?>
Here you can find the way for Update Single Field, Multiple Field Etc.,
http://php.sysaxiom.com/update_data.php
http://php.sysaxiom.com/update_multiple_data.php

If you need to change the contents of the table to have different rows/row data, (and you want to do it live) you will need to use AJAX. jQuery has fairly straightforward ajax usage, so for actual implementation, I would look to that. You'll also need another PHP file that just returns the raw HTML required to fill in the table. Pseudocode (jquery) below:
$.post("url","dataToPost",function(data){$("#table id where I want to put new data).innerHTML=data});
Basically, the $.post() posts the dataToPost to the url and sets the innerHTML of whatever you select to the resultant data.

EDIT: add an identifier to a dynamically generated row

I'm pulling down two tables from the db. There's a Javascript function that adds a row from Table2 into the Table1. What i've been trying to do is get the data from Table1 on the confirm_trade.php page so I can put it into the db but can't figure out how to pull that row(item_id). I thought putting the table in a form would allow me to access them through the $_POST but that's not working. How to add an identifier to the jquery row so I can grab on the confirm page?
The appended rows coming from the jQuery function are the rows I need the item_id from.
function addto(obj)
{
var $row = $(obj).parents("tr");
var $table = $("#tradee");
var item_id = $row.find(".item-id").text();
var item_name = $row.find(".item-name").text();
var item_desc = $row.find(".item-desc").text();
var newTR = $("<tr><td>"+item_id+"</td><td>"+item_name+
"</td><td>"+item_desc+"</td></tr>");
$table.append(newTR);
}
Table2:
<div id='fixedDiv'>
<form action="confirm.php" method="post">
<table align="center" id="Table2">
<tr><td>Other Item</td></tr>
<?php while($rowi =$item->fetch_assoc())
{?>
<tr>
<td>
<?php echo $rowi['item_id']; ?>
</td>
<td>
<?php echo $rowi['item_name']; ?>
</td>
<td><?php echo $rowi['item_description'];?></td>
</tr>
<?php } ?>
<tr>
<td><input type="submit" name="submit" value="Continue"/></td>
</tr>
</table>
</form>
</div>
<br>
Table 1:
<table align="center" id="Table1">
<tr><th>item_id</th>
<th>Cat_id</th>
<th>Name</th>
<th>Description</th>
</tr>
<?php while($row =$item_results->fetch_assoc())
{?>
<tr></tr>
<tr>
<td class="item-id"> <?php echo $row['item_id']; ?> </td>
<td><?php echo $cat_id = $row['cat_id']; ?> </td>
<td class="item-name"><?php echo $item_id = $row['item_name'];?></td>
<td class="item-desc"><?php echo $item_descrip = $row['item_description'];?>
</td>
<td><input type="button" class="added" onclick="addto(this)"
value="Add" />
<td><input type="button" class="removed" onclick="remove()"
value="Remove" >
</td>
</tr>
<?php } ?>
</table>

Judging by your code, you can use <input type="hidden" name="some_hidden_data" value="field-value">. be sure that you also wrap your table with <form method="post"></form>
the hidden field will be then included as $_POST['hidden_field_name'];

PHP - UPDATE a row in a dynamic HTML table

I have a dynamic table that I created in HTML:
<table id="rounded-corner" width="51%" border="1" align="center" cellpadding="2" cellspacing="0">
<tr>
<th width="19%">Job Type</th>
<th width="24%">Job Description</th>
<th width="19%">Type of Piping</th>
<th width="19%">Scheduled Start Time</th>
<th width="19%">Scheduled End Time</th>
</tr>
<?php do { ?>
<tr>
<td nowrap><?php echo $row_selectJobs['JobType']; ?></td>
<td><?php echo $row_selectJobs['JobDesc']; ?></td>
<td><?php echo $row_selectJobs['PipeType']; ?></td>
<td align="center"><?php echo substr($row_selectJobs['TimeStart'],0,-3); ?></td>
<td align="center"><?php echo substr($row_selectJobs['TimeEnd'],0,-3); ?></td>
</tr>
<?php } while ($row_selectJobs = mysql_fetch_assoc($selectJobs)); ?>
</table>
I was wondering if there is a way to add a button to each row so that you can modify the contents of that row. Remember, it's a dynamic table. I'm new to PHP and I really just stole this code from Dreamweaver and modified it for my own needs.

jQuery would be pretty simple to do this for. In your do loop just add another TD and use echo to output something like
<input type='button' class='changeRow' value='Edit' />
For each of the other TD's you will first want to output the values inside a span with a classname something like
<span class="labelValue">..What your PHP actually outputs..</span>
Then a hidden textbox, or something like that depending on how you want to actually do the editing. Each with a className relating to that row. so
<input type='text' class='editInput' value='' style='display: none;'/> etc...
Then using jQuery you can link it all together to make it editable like
$(document).ready(function(){
$('.changeRow').click(function(){
var tb = $(this).parents('tr').find('input.editInput');
var label = $(this).parents('tr').find('span.labelValue');
if($(this).val() == 'Edit'){
tb.val(label.html());
label.hide();
tb.show();
$(this).val('Save');
}
else{
label.html(tb.val());
tb.hide();
label.show();
$(this).val('Edit');
}
});
});
So when your HTML is output, it would look something like this
<td> <!-- The extra td for your edit button -->
<input type="button" class="changeRow" value="Edit">Some Job Type</span>
</td>
<td nowrap>
<span class="labelValue">Some Job Type</span>
<input type="text" class="editInput" value="" style="display: none;" />
</td>