How can I make an element appear and disappear using Jquery. - javascript

I want to do something like this:
$(document).ready(function(){
if($('.undermenu').css('display','block')){
$('#menu').click(function(){
$('.undermenu').css('display','none');
});
}
else{
$('#menu').click(function(){
$('.undermenu').css('display','block');
});
}
});
This code does not work, but is there any Jquery "effect" or whatever that I can use to hide/un-hide.
For example is there and way to check whether or not display is set to none or block?
Thanks.

Just use toggle():
$('#menu').click(function() {
$('.undermenu').toggle();
});
Though the reason your if($('.undermenu').css('display','block')) didn't work is because you set the display property of the element(s) to block, rather than getting the display property and testing it, which would be:
if ($('.undermenu').css('display') =='block')
If you really want to use an if to test the current display, before modifying the presentation, you'd have to do it inside of the click handler (otherwise it will only run once, on DOMReady, rather than every time):
$('#menu').click(function(){
if ($('.undermenu').css('display') == 'block') {
$('.undermenu').hide();
}
else {
$('.undermenu').show();
}
});
Or, if you want to risk the wrath of your colleagues, you can jazz that up a little:
$('#menu').click(function(){
var undermenu = $('.undermenu');
undermenu[undermenu.css('display') == 'block' ? 'hide' : 'show']();
});
References:
css().
toggle().

You use a setter on your condition :
// This line update .undermenu to display it and return true (return $('.undermenu'), so true)
if($('.undermenu').css('display','block')){
But you must get the value, and test
if($('.undermenu').css('display') === 'block'){
And you code conception is bad. If you do that, you test on document are ready if the .undermenu are displayed or not, and you put a function to the click trigger (to display or to hide..) but ! when your .undermenu was change, you already have the same trigger (to display or hide, and he never change)..
So you need to put your trigger for each click and test the value (displayed or not) on the trigger :
$(document).ready(function(){
$('#menu').click(function(){
if($('.undermenu').css('display') === 'block'){
$('.undermenu').hide();
}
else {
$('.undermenu').show();
}
});
});

On jquery exists:
$("#element_id").show();
$("#element_id").hide();
also you can use:
$("#element_id").fadeIn();
$("#element_id").fadeOut();
This show and hide elements with fade effects.
You can query if the element is hidden:
if($("#element_id").is(":hidden")){
$("#element_id").show():
}
else{
$("#element_id").hide();
}

What you're looking for is .toggle()
$("div").click(function () {
$("img").toggle("slow", function () {
// Animation complete.
});
});
Here is a fiddle: http://jsfiddle.net/FQj89/

You can put the if statement in the function so you don't repeat yourself. You can probably also use toggle(); type stuff depending on what you are doing. ---
$('#menu').click(function(){
if ( $('.undermenu').is(':visible') ) {
$('.undermenu').hide();
else {
$('.undermenu').show();
}
});
This is a good way too, depending on what you are doing though, one may be better than the other.
if ( $('.undermenu').css('display') === 'block' ) { // do something }

Related

JQuery not removing active class

I'm trying to make my links slide down over the page when the mobile nav is clicked and the content to disappear so only the links are shown. I have got this basically working but the .displayNone class will not remove when I click the mobilenav again and I'm a bit dumfounded as to why.
$(document).ready(function() {
$('#hamburger').on('click', function(){
$('.links').slideToggle(200);
var status = $('.wrapper').hasClass('.displayNone');
if(status){ $('.wrapper').removeClass('.displayNone'); }
else { $('.wrapper').addClass('displayNone'); }
});
});
Bit of newbie to all this. Anything obvious that anyone can see wrong with this?
Use toggleClass(),
$('.wrapper').toggleClass('displayNone');
And, jQuery's xxxClass() functions expect the name of the class, not the selector, so leave off the . class selector.
When adding/removing classes, just use displayNone, not .displayNone (note the dot!).
Also there's a toggleClass() function which saves you from doing the status thing, which means you just need to do
$('.wrapper').toggleClass('displayNone');
your are doing bit wrong
var status = $('.wrapper').hasClass('.displayNone');
when you use hasClass, addClass or removeClass then you don't need to have '.' dot before class name.
so correct way is
var status = $('.wrapper').hasClass('displayNone');
your code after correction
$(document).ready(function() {
$('#hamburger').on('click', function() {
$('.links').slideToggle(200);
var status = $('.wrapper').hasClass('displayNone');
if (status) {
$('.wrapper').removeClass('displayNone');
} else {
$('.wrapper').addClass('displayNone');
}
});
});
You can use :
$('.wrapper').toggleClass("displayNone");
Final code :
$(document).ready(function(){
$('#hamburger').on('click', function(){
$('.links').slideToggle(200);
$('.wrapper').toggleClass("displayNone");
})
})

how to apply function to each checkbox on page?

I am trying to apply a function to every checkbox on a page that shows/hides <div class="selectlist"> depending on if the checkbox is checked, this function makes all the <div class="selectlist"> on the page toggle
$("input[type=checkbox]").live('change', function() {
if ($(this).is(':checked') == false) {
$('#selectlist').hide();
} else {
$('#selectlist').show();
}
});
I tried the jquery each function like this but that doesnt seem to work
$.each($("input[type=checkbox]").live('change', function() {
if ($(this).is(':checked') == false) {
$('#selectlist').hide();
} else {
$('#selectlist').show();
}
}));
I know its possible to this by using a class instead of input[type=checkbox] but I want to avoid doing that
How can I make jquery change the behavior of the checkbox the user clicks?
If you're trying to bind an event handler to all elements verifying input[type=checkbox], simply do
$(document).on('change', "input[type=checkbox]", function() {
if (!this.checked) {
$('#selectlist').hide();
} else {
$('#selectlist').show();
}
});
No need to use each there : most jQuery functions work if the jQuery set contains more than one element.
Note that I use on there instead of live : after having been deprecated for a long time, live has been removed from recent versions of jQuery.
EDIT : discussion in comments below lead to this code :
$(document).on('change', "input[type=checkbox]", function() {
$(this).next().toggle(this.checked);
});
$(document).on('change', 'input[type=checkbox]', function() {
$('#selectlist').toggle(this.checked);
});
ID's are uniqe, and there is no "all the <div id="selectlist"> on the page toggle", there can be only one? Use a class instead, and show us what the markup looks like !

On() and off() - Jquery

Trying to understand Jquery's On() and off() a little better. Not understanding why this is not working. I want to activate and inactivate id TurnON and TurnOff Js.
Javascript
$(document).ready(function(){
$(document).on("click.turnon","#TurnOn",function() {
$(document).off('click.turnon');
alert("Turn Off is now turned off");
});
$(document).on("click.turnoff","#TurnOff",function() {
$(document).on('click.turnon');
alert("Turn Off is now turned back on");
});
});
HTML
<div id="TurnOn">Turn Off</div>
<div id="TurnOff">Turn On</div>
If you want an event handler to only fire once then take a look at .one(): http://api.jquery.com/one
As of jQuery 1.7 it does event delegation.
$(function(){
$(document).one("click.turnon","#TurnOn",function() {
alert("Turn Off is now turned off");
});
$(document).one("click.turnoff","#TurnOff",function() {
alert("Turn Off is now turned back on");
});
});
Here is a demo using .one(): http://jsfiddle.net/9qxfT/1/
Also, your code was just about right but you have a couple typos here:
$(document).on("click.turnoff","#TurnOff",function() {
$(document).on('click.turnon');
alert("Turn Off is now turned back on");
});
$(document).on('click.turnon'); should be: $(document).off('click.turnoff');
Here is a demo of these small changes: http://jsfiddle.net/9qxfT/
Update
You can save the state with a variable:
$(function(){
//declare a variable to save whether or not the `#TurnOn` element is 'on' (true) or 'off' (false)
var isOn = true;
$(document).on("click.turnon","#TurnOn",function() {
//check to see if the flag is set to true, which means the `#TurnOn` element is 'on' already
if (isOn) {
alert("#TurnOn is already turned on");
//otherwise set the `#TurnOn` element to 'on'
} else {
alert("#TurnOn is now turned back on");
isOn = true;
}
});
//set the `#TurnOn` element to `off` when the `#TurnOff` element is clicked
$(document).on("click.turnoff","#TurnOff",function() {
isOn = false;
alert("#TurnOn is now turned off");
});
});​
Here is a demo: http://jsfiddle.net/9qxfT/4/
Your logic is right, but may I suggest better implementation?
Please read this page as well: http://api.jquery.com/off/
Here is what I suggest:
// first put a .click event with a separate "ID" to enable another div "ID".
$('#ButtonForTurnOn').click(function () {
//while body is .on(), the ID, when clicked applies whatever effects
$("body").on("click", "#TurnOn", onlight).find("#TurnOn").addClass("clickable").text("ON switch on");
});
// enable OFF switch
$('#ButtonForTurnOff').click(function () {
$("body").on("click", "#TurnOff", offlight).find("#TurnOff").addClass("clickable").text("OFF switch on");
});
Now, for you to have an effective .off function, YOU MUST have the
"selector string match the one passed to .on() when the event handler
was attached."
For example:
If your $("body").on() is this,
$("body").on("click", "#TurnOff", function({
// stuff here
});
Your $("body").off() should be this,
$("body").off("click", "#TurnOff", function({
// stuff here
});
Try out this jsfiddle
Hope this helps explain things!
Just think of it as disabling something, until its turned back on.

Setting element visiblity with jQuery

Using jQuery, is there some property on an element that I can set to true/false to control the visibility of that element?
Basically, I need something like this:
$(this).visible(someCondition);
toggle() won't work because I need to be able to tell it whether or not it will be shown.
show() and hide() work, but I have to do this:
if (someCondition) {
$(this).show();
}
else {
$(this).hide();
}
Which, as you can see, is not nearly as elegant as the solution I'm looking for.
toggle(someCondition) will work.
It takes an optional boolean parameter.
As SLak suggested, toggle() works. If you are using classes that have visibility states set (i.e., display: none or visibility:hidden), you can also use toggleClass().
jQuery.fn.visibleCond = function( cond ) {
if ( cond ) {
return this.show();
} else {
return this.hide();
};
};
Then:
$(this).visibleCond(someCondition);
And fiddle: http://jsfiddle.net/C3daq/

jQuery .load() How to prevent double loading from double clicking

I am using jQuery load() function to load some pages into container. Here is the code:
$('div.next a').live('click',function() {
$('.content').load('page/3/ #info','',function(){
//do something
});
return false;
});
Everything works just fine but the problem is when I quickly double click the div.next link, from console I see that it loads the page twice because I did a quick double click. I could even make it 3 clicks and it will load it 3 times and show in console smth like that:
GET http://site/page/3/ 200 OK 270ms
GET http://site/page/3/ 200 OK 260ms
My question is how to prevent such double clicking and not to let load the target page more then once no matter how many times it was clicked.
Thank you.
Whatever happened to good ol' JavaScript? Why are you all trying to figure it out with pure jQuery?
var hasBeenClicked = false;
$('div.next a').live('click',function() {
if(!hasBeenClicked){
hasBeenClicked = true;
$('.content').load('page/3/ #info','',function(){
//do something
//If you want it clickable AFTER it loads just uncomment the next line
//hasBeenClicked = false;
});
}
return false;
});
As a side note, never never never use .live(). Use .delegate instead like:
var hasBeenClicked = false;
$('div.next').delegate('a','click',function() {
if(!hasBeenClicked){
hasBeenClicked = true;
$('.content').load('page/3/ #info','',function(){
//do something
//If you want it clickable AFTER it loads just uncomment the next line
//hasBeenClicked = false;
});
}
return false;
});
Why? Paul Irish explains: http://paulirish.com/2010/on-jquery-live/
To answer your comment...
This could happen if you have your delegate function nested inside your AJAX call (.load(), .get(), etc). The div.next has to be on the page for this to work. If div.next isn't on the page, and this isn't nested, just do this:
$('#wrapper').delegate('div.next a','click',function() {
http://api.jquery.com/delegate/
Delegate needs the selector to be the parent of the dynamically added element. Then, the first parameter of delegate (div.next a in the last example) is the element to look for within the selected element (#wrapper). The wrapper could also be body if it's not wrapped in any element.
You could try using the jquery one method:
$("a.button").one("click", function() {
$('.content').load('page/3/ #info','',function(){
//do something
});
});
You could unbind the click event with die():
$(this).die('click').click(function() { return False; });
Or you could give the element a .clicked class once it is clicked:
$(this).addClass('clicked');
And check if that class exists when performing your logic:
$('div.next a').live('click',function() {
if (!$(this).is('.clicked')) {
$(this).addClass('clicked');
$('.content').load('page/3/ #info','',function(){
//do something
});
}
return false;
});
Store whether you're waiting for the load in a variable.
(function() {
var waitingToLoad = false;
$('div.next a').live('click',function() {
if (!waitingToLoad) {
waitingToLoad = true;
$('.content').load('page/3/ #info','',function(){
waitingToLoad = false;
//do something
});
}
return false;
});
})()

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