EDIT: So apparently, PI is finite in JavaScript (which makes sense). But that leaves me with a major problem. What's the next best way to calculate the angles I need?
Alright, first, my code:
http://jsfiddle.net/joshlalonde/vtfyj/34/
I'm drawing cubes that open up to a 120 degree angle.
So the coordinates are calculated based on (h)eight and theta (120).
On line 46, I have a for loop that contains a nested for loop used for creating rows/columns.
It's somewhat subtle, but I noticed that the lines aren't matching up exactly. The code for figuring out each cubes position is on line 49. One of the things in the first parameter (my x value) for the origin of the cube is off. Can anyone help figure out what it is?
var cube = new Cube(
origin.x + (j * -w * (Math.PI)) +
(i * w * (Math.PI))
, origin.y + j * (h / 2) +
i * (h / 2) +
(-k*h), h);
Sorry if that's confusing. I,j, and k refer to the variable being incremented by the for loops. So basically, a three dimensional for loop.
I think the problem lies with Math.PI.
The width isn't the problem, or so I believe. I originally used 3.2 (which I somehow guessed and it seemed to line up pretty good. But I have no clue what the magical number is). I'm guessing it has to do with the angle being converted to Radians, but I don't understand why Math.PI/180 isn't the solution. I tried multiple things. 60 (in degrees) * Math.PI/180 doesn't work. What is it for?
EDIT: It might just be a JavaScript related math problem. The math is theoretically correct but can't be calculated correctly. I'll accept the imperfection to spare myself from re-writing code in unorthodox manners. I can tell it would take a lot to circumvent using trig math.
There are 2 problems...
Change line 35 to var w=h*Math.sin(30);. The 30 here matches the this.theta / 4 in the Cube getWidthmethod since this.theta equals 120.
Use the following code to generate the position of your new cube. You don't need Math.Pi. You needed to use both the cube width and height in your calculation.
var cube = new Cube(
origin.x+ -j*w - i*h,
origin.y + -j*w/2 + i*h/2,
h);
Alright I found the solution!
It's really simple - I was using degrees instead of radians.
function Cube(x, y, h) {
this.x = x
this.y = y
this.h = h;
this.theta = 120*Math.PI/180;
this.getWidth = function () {
return (this.h * Math.sin(this.theta / 2));
};
this.width = this.getWidth();
this.getCorner = function () {
return (this.h / 2);
};
this.corner = this.getCorner();
}
So apparently Javascript trig functions use Radians, so that's one problem.
Next fix I made was to the offset of each point in the cube. It doesn't need one! (o.O idk why. But whatever it works. I left the old code just in case I discover why later on).
function draw() {
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
ctx.fillStyle = "#000";
ctx.fillRect(0, 0, canvas.width, canvas.height); // Draw a black canvas
var h = 32;
var width = Math.sin(60*Math.PI/180);
var w = h*width;
var row = 9; // column and row will always be same (to make cube)
var column = row;
var area = row * column;
var height = 1;
row--;
column--;
height--;
var origin = {
x: canvas.width / 2,
y: (canvas.height / 2) - (h * column/2) + height*h
};
var offset = Math.sqrt(3)/2;
offset = 1;
for (var i = 0; i <= row; i++) {
for (var j = 0; j <= column; j++) {
for (var k = 0; k <= height; k++) {
var cube = new Cube(
origin.x + (j * -w * offset) +
(i * w * offset)
, origin.y + (j * (h / 2) * offset) +
(i * (h / 2) * offset) +
(-k*h*offset), h);
var cubes = {};
cubes[i+j+k] = cube; // Store to array
if (j == column) {
drawCube(2, cube);
}
if (i == row) {
drawCube(1, cube);
}
if (k == height) {
drawCube(0,cube);
}
}
}
}
}
See the full Jsfiddle here: http://jsfiddle.net/joshlalonde/vtfyj/41/
Related
The code is from here:
t=0
draw=_=>{t||createCanvas(W = 720,W)
t+=.01
B=blendMode
colorMode(HSB)
B(BLEND)
background(0,.1)
B(ADD)
for(y = 0; y < W; y += 7)
for(x = 0; x < W; x+=7)
dist(x, y, H = 360, H) +
!fill(x * y % 360, W, W,
T=tan(noise(x, y) * 9 + t))
< sin(atan2(y - H, x - H) * 2.5 + 84)**8 * 200 + 130?
circle(x, y + 30, 4/T) : 0}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/1.5.0/p5.js"></script>
I see that t is increased by 0.01 each iteration, but I am unsure whether for each t value the entire canvas is refreshed, or whether there is an endpoint somewhat set by :0}. Is this correct?
It also seems like there is a Boolean call in the middle basically comparing two distances to determine which circles are filled and how. If the < was instead > the circles would form a complementary pattern on the rendition.
The ! is explained here, as a way of saving space and calling a function as soon as it is declared. I presume it determines how points are filled with a certain variable color scheme depending on the Boolean operation result. The +!fill() is unfamiliar, as well as the ? at the end, and I guess that they amount to: if the x, y location is within the boundary of the star the circles are colored (filled) as such, but the negation in '!' is confusing.
Can I get an English explanation of the main structural points on this code (the loop and the Boolean) to match the syntax?
I have so far gathered that the basic loop is
for(y from 0 to the width of the canvas at increments of 7)
for(x from... )
check if the distance from (x , y) to 360 is less than sin()^8 * 200 + 130
If so fill (or not fill with the ! ????) with these colors
otherwise do nothing :0
This is what it might look like if it were written normally
let t = 0;
const W = 720;
// https://p5js.org/reference/#/p5/draw
// `draw` needs to be in the global scope so p5 can use it
draw = () => {
// create a canvas if this is the first frame
if (!t) createCanvas(W, W);
t += 0.01;
// Use HSB and blending to do the fancy effects
// The black circles are because we're ignoring stroke and so using its defaults
// The blending will eventually hide it anyway
colorMode(HSB);
blendMode(BLEND);
background(0, 0.1);
blendMode(ADD);
// iterate over 7px grid
for(y = 0; y < W; y += 7) {
for(x = 0; x < W; x += 7) {
// center
const H = 360;
// distance from center
const D = dist(x, y, H, H);
// pick an alpha based on location and time
const T = tan(noise(x, y) * 9 + t);
// set fill color
fill(x * y % 360, W, W, T);
// magic to calculate the star's boundary
// sine wave in polar coords, I think
const S = sin(atan2(y - H, x - H) * 2.5 + 84)**8 * 200 + 130;
// draw a circle if we're within the star's area
// circle's color, alpha, and radius depend on location and time
if (D < S) circle(x, y + 30, 4/T);
}
}
};
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/1.5.0/p5.js"></script>
Note that there are some hacks in the original code that are solely to help make it a one-liner or to reduce the number of characters. They don't have any meaningful effect on the results.
The main issue is the +! with ? and :0, which is terribly confusing, but clearly it is equivalent to
t=0
draw=_=>{t||createCanvas(W = 720,W)
t+=.01
B=blendMode
colorMode(HSB)
B(BLEND)
background(0,.1)
B(ADD)
for(y = 0; y < W; y += 7)
for(x = 0; x < W; x+=7)
if(dist(x, y, H = 360, H) < sin(atan2(y - H, x - H) * 2.5 + 84)**8 * 200 + 130){
fill(x * y % 360, W, W,
T=tan(noise(x, y) * 9 + t))
circle(x, y + 30, 4/T)}else{0}}
The Boolean in the ? applies to the dist() part (in absolute values the angle has to be less than sin()... + 130.
The + part I still don't understand, and hopefully will be addressed by someone who knows Processing or JS (not me). However, it probably forces the execution to identify and throw out with regards to filling (hence !) values that are too low for the sin(atan2()), which will happen at around 0 and pi.
Because of arctan2() being (here)
the number of spikes in the star will be a multiple of 5 going from 0 to 2 pi. The fact that changing the code to < sin(2 * atan2(...)... doubles the spikes implies that the fill() part is also in Boolean operation of its own.
The result of the Boolean determines whether the colorful fill is applied or not (applied if less than).
The :0 at the end is the else do nothing.
I am currently doing up a mini project on the side as part of my beginner lesson to Javascript. I am hoping to allow an ellipse to appear along points on a few lines in a graph. The coordinates are derived from a css file, using the p5js library.
Following this example, I could only produce multiple ellipses (the amount corresponds to the number of points I have on the line). Is there any way I can somehow 'clear' the ellipses and allow only one to appear each time it travels on the lines?
Would also be great if there are any suggestions as to how I can make ellipses appear on exact coordinates when my mouse hovers over the lines at different points. I'm unable to use map() accurately.
The CSV has its heading with number of days in a month, first column with months and the remaining are data according to days in each month.
Below is a screenshot of what is currently happening, as well as a snippet the said code. Please do kindly correct me if my question wasn't well-asked. Thank you!
var endDay;
var beginX;
var beginY;
var beginY;
var endY;
var distX;
var distY;
var prevStart = null;
for (var i = 0; i < this.data.getRowCount(); i++) {
var a = this.data.getRow(i);
for(var k = 1; k < numDays; k++) {
currEnd = {
'day': this.firstDay + k - 1 ,
'case': a.getNum(k) //get no. of cases by day
}
if(prevStart != null) {
// this.mapDayToWidth, this.mapCaseToHeight are helpers to
// give scaled values
for plotting
beginX = this.mapDayToWidth(prevStart.day);
endX = this.mapDayToWidth(currEnd.day);
beginY = this.mapCaseToHeight(prevStart.case);
endY = this.mapCaseToHeight(currEnd.case);
let new_endX = constrain(mouseX, endX - 20, endX + 20);
distX = endX - beginX;
distY = endY - beginY;
x = beginX + pct * distX;
y = beginY + pct * distY;
pct += 0.00001;
}
prevStart = currEnd;
if(pct < 1.0) {
this.drawEllipses(mouseX, endY, 10);
}
}
}
// how the ellipse is drawn
this.drawEllipse = function(ellipseX, ellipseY, size, begin_X, end_X) {
fill('black');
ellipse(ellipseX, ellipseY, size);
};
// how the line graph was plotted
this.drawLines = function(colr, x1, y1, x2, y2) {
strokeWeight(2);
stroke(colr);
beginShape();
line(x1,
y1,
x2,
y2
);
endShape();
};
For reference, I'm talking about the dark-gray space in the upper left of Discord's Login Page. For anyone who can't access that link, here's a screenshot:
It has a number of effects that are really cool, the dots and (darker shadows) move with the mouse, but I'm more interested in the "wobbly edge" effect, and to a lesser extent the "fast wobble/scale in" on page load (scaling in the canvas on load would give a similar, if not "cheaper" effect).
Unfortunately, I can't produce much in the way of a MCVE, because I'm not really sure where to start. I tried digging through Discord's assets, but I'm not familiar enough to Webpack to be able to determine what's going on.
Everything I've been able to dig up on "animated wave/wobble" is CSS powered SVG or clip-path borders, I'd like to produce something a bit more organic.
Very interesting problem. I've scaled the blob down so it is visible in the preview below.
Here is a codepen as well at a larger size.
const SCALE = 0.25;
const TWO_PI = Math.PI * 2;
const HALF_PI = Math.PI / 2;
const canvas = document.createElement("canvas");
const c = canvas.getContext("2d");
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
document.body.appendChild(canvas);
class Blob {
constructor() {
this.wobbleIncrement = 0;
// use this to change the size of the blob
this.radius = 500;
// think of this as detail level
// number of conections in the `bezierSkin`
this.segments = 12;
this.step = HALF_PI / this.segments;
this.anchors = [];
this.radii = [];
this.thetaOff = [];
const bumpRadius = 100;
const halfBumpRadius = bumpRadius / 2;
for (let i = 0; i < this.segments + 2; i++) {
this.anchors.push(0, 0);
this.radii.push(Math.random() * bumpRadius - halfBumpRadius);
this.thetaOff.push(Math.random() * TWO_PI);
}
this.theta = 0;
this.thetaRamp = 0;
this.thetaRampDest = 12;
this.rampDamp = 25;
}
update() {
this.thetaRamp += (this.thetaRampDest - this.thetaRamp) / this.rampDamp;
this.theta += 0.03;
this.anchors = [0, this.radius];
for (let i = 0; i <= this.segments + 2; i++) {
const sine = Math.sin(this.thetaOff[i] + this.theta + this.thetaRamp);
const rad = this.radius + this.radii[i] * sine;
const theta = this.step * i;
const x = rad * Math.sin(theta);
const y = rad * Math.cos(theta);
this.anchors.push(x, y);
}
c.save();
c.translate(-10, -10);
c.scale(SCALE, SCALE);
c.fillStyle = "blue";
c.beginPath();
c.moveTo(0, 0);
bezierSkin(this.anchors, false);
c.lineTo(0, 0);
c.fill();
c.restore();
}
}
const blob = new Blob();
function loop() {
c.clearRect(0, 0, canvas.width, canvas.height);
blob.update();
window.requestAnimationFrame(loop);
}
loop();
// array of xy coords, closed boolean
function bezierSkin(bez, closed = true) {
const avg = calcAvgs(bez);
const leng = bez.length;
if (closed) {
c.moveTo(avg[0], avg[1]);
for (let i = 2; i < leng; i += 2) {
let n = i + 1;
c.quadraticCurveTo(bez[i], bez[n], avg[i], avg[n]);
}
c.quadraticCurveTo(bez[0], bez[1], avg[0], avg[1]);
} else {
c.moveTo(bez[0], bez[1]);
c.lineTo(avg[0], avg[1]);
for (let i = 2; i < leng - 2; i += 2) {
let n = i + 1;
c.quadraticCurveTo(bez[i], bez[n], avg[i], avg[n]);
}
c.lineTo(bez[leng - 2], bez[leng - 1]);
}
}
// create anchor points by averaging the control points
function calcAvgs(p) {
const avg = [];
const leng = p.length;
let prev;
for (let i = 2; i < leng; i++) {
prev = i - 2;
avg.push((p[prev] + p[i]) / 2);
}
// close
avg.push((p[0] + p[leng - 2]) / 2, (p[1] + p[leng - 1]) / 2);
return avg;
}
There are lots of things going on here. In order to create this effect you need a good working knowledge of how quadratic bezier curves are defined. Once you have that, there is an old trick that I've used many many times over the years. To generate smooth linked quadratic bezier curves, define a list of points and calculate their averages. Then use the points as control points and the new averaged points as anchor points. See the bezierSkin and calcAvgs functions.
With the ability to draw smooth bezier curves, the rest is about positioning the points in an arc and then animating them. For this we use a little math:
x = radius * sin(theta)
y = radius * cos(theta)
That converts polar to cartesian coordinates. Where theta is the angle on the circumference of a circle [0 - 2pi].
As for the animation, there is a good deal more going on here - I'll see if I have some more time this weekend to update the answer with more details and info, but hopefully this will be helpful.
The animation runs on a canvas and it is a simple bezier curve animation.
For organic feel, you should look at perlin noise, that was introduced when developing original Tron video FX.
You can find a good guide to understand perlin noise here.
In the example I've used https://github.com/josephg/noisejs
var c = $('canvas').get(0).getContext('2d');
var simplex = new SimplexNoise();
var t = 0;
function init() {
window.requestAnimationFrame(draw);
}
function draw() {
c.clearRect(0, 0, 600, 300);
c.strokeStyle="blue";
c.moveTo(100,100);
c.lineTo(300,100);
c.stroke();
// Draw a Bézier curve by using the same line cooridinates.
c.beginPath();
c.lineWidth="3";
c.strokeStyle="black";
c.moveTo(100,100);
c.bezierCurveTo((simplex.noise2D(t,t)+1)*200,(simplex.noise2D(t,t)+1)*200,(simplex.noise2D(t,t)+1)*200,0,300,100);
c.stroke();
// draw reference points
c.fillRect(100-5,100-5,10,10);
c.fillRect(200-5,200-5,10,10);
c.fillRect(200-5,0-5,10,10);
c.fillRect(300-5,100-5,10,10);
t+=0.001;
window.requestAnimationFrame(draw);
}
init();
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/simplex-noise/2.4.0/simplex-noise.js"></script>
<canvas width="600" height="300"></canvas>
Note: further investigation on Discord source code, I've pointed out that's is using https://www.npm.red/~epistemex libraries. Epistemex NPM packages are still online, while GitHub repos and profile does not exists anymore.
Note 2: Another approach could be relying on physics libraries like this demo, but it can be an overkill, if you just need a single effect.
I was working on a fun project that implicates creating "imperfect" circles by drawing them with lines and animate their points to generate a pleasing effect.
The points should alternate between moving away and closer to the center of the circle, to illustrate:
I think I was able to accomplish that, the problem is when I try to render it in a canvas half the render jitters like crazy, you can see it in this demo.
You can see how it renders for me in this video. If you pay close attention the bottom right half of the render runs smoothly while the top left just..doesn't.
This is how I create the points:
for (var i = 0; i < q; i++) {
var a = toRad(aDiv * i);
var e = rand(this.e, 1);
var x = Math.cos(a) * (this.r * e) + this.x;
var y = Math.sin(a) * (this.r * e) + this.y;
this.points.push({
x: x,
y: y,
initX: x,
initY: y,
reverseX: false,
reverseY: false,
finalX: x + 5 * Math.cos(a),
finalY: y + 5 * Math.sin(a)
});
}
Each point in the imperfect circle is calculated using an angle and a random distance that it's not particularly relevant (it relies on a few parameters).
I think it's starts to mess up when I assign the final values (finalX,finalY), the animation is supposed to alternate between those and their initial values, but only half of the render accomplishes it.
Is the math wrong? Is the code wrong? Or is it just that my computer can't handle the rendering?
I can't figure it out, thanks in advance!
Is the math wrong? Is the code wrong? Or is it just that my computer can't handle the rendering?
I Think that your animation function has not care about the elapsed time. Simply the animation occurs very fast. The number of requestAnimationFrame callbacks is usually 60 times per second, So Happens just what is expected to happen.
I made some fixes in this fiddle. This animate function take care about timestamp. Also I made a gradient in the animation to alternate between their final and initial positions smoothly.
ImperfectCircle.prototype.animate = function (timestamp) {
var factor = 4;
var stepTime = 400;
for (var i = 0, l = this.points.length; i < l; i++) {
var point = this.points[i];
var direction = Math.floor(timestamp/stepTime)%2;
var stepProgress = timestamp % stepTime * 100 / stepTime;
stepProgress = (direction == 0 ? stepProgress: 100 -stepProgress);
point.x = point.initX + (Math.cos(point.angle) * stepProgress/100 * factor);
point.y = point.initY + (Math.sin(point.angle) * stepProgress/100 * factor);
}
}
Step by Step:
based on comments
// 1. Calculates the steps as int: Math.floor(timestamp/stepTime)
// 2. Modulo to know if even step or odd step: %2
var direction = Math.floor(timestamp/stepTime)%2;
// 1. Calculates the step progress: timestamp % stepTime
// 2. Convert it to a percentage: * 100 / stepTime
var stepProgress = timestamp % stepTime * 100 / stepTime;
// if odd invert the percentage.
stepProgress = (direction == 0 ? stepProgress: 100 -stepProgress);
// recompute position based on step percentage
// factor is for fine adjustment.
point.x = point.initX + (Math.cos(point.angle) * stepProgress/100 * factor);
point.y = point.initY + (Math.sin(point.angle) * stepProgress/100 * factor);
jsfiddle here: http://jsfiddle.net/yw0w18m3/2/
I'm using paper.js to make a background image that looks somthing like this:
Basically, I'm creating a couple thousand triangles over a loop and rotating them on every other iteration.
function Tri(x, y, rotate) {
var tri = new Path([
new Point((x - 42), (y - 48)),
new Point((x - 42), y),
new Point(x, (y - 24)),
new Point((x - 42), (y - 48))
]);
tri.fillColor = {
hue: Math.random() * 360,
saturation: 0,
brightness: ( (( Math.random() ) * .95) + .3 )
};
if(rotate) { tri.rotate(180); }
}
for (var i = 0; i < 2000; i++) {
rotate = false;
if( i % 2 ) {
rotate = true;
}
new Tri(x, y, rotate);
x = x + 42;
if( x > (winWidth + 42) ) {
x = 0 ;
y = y + 24;
}
}
There seems to be a brief 1-2 second pause/freeze though while the shapes are being drawn. Is there a more efficient way to draw all the shapes first (or push to an array) then add that to the canvas all at once?
I based my code off of the example here: http://paperjs.org/examples/candy-crash/ (click "source" in the upper right corner).
Any help is much appreciated.
Thanks!
I would end up creating two triangles, one rotated, so they don't have to be built from new points each time. Then choose the correct triangle based on the rotation variable and clone it, as opposed to create points and a triangle from scratch each time. Finally, just change the position of the cloned triangle.
Last, I would correct the maxTri so it doesn't do more than it needs to. The paren should follow the 48, not the 24. You're doing an order of magnitude more triangles than needed.
Here's a link to the sketch.paperjs.org solution I created based on your code. I find sketch easier to use than jsfiddle for paper examples.
proto1 = new Path([
new Point(0, -24),
new Point(0, 24),
new Point(42, 0)
]);
proto1.closed = true;
proto2 = proto1.clone();
proto2.rotate(180);
function putTriangle(pos, rotate) {
var tri = (rotate ? proto2 : proto1).clone();
tri.position = pos;
tri.position = tri.position.subtract([21, 0])
tri.fillColor = {
hue: Math.random() * 360,
saturation: 0,
brightness: Math.random() * 0.5 + 0.5
}
}
var tris = [],
x = 42,
y = 24,
rotate,
winWidth = paper.view.size.width,
winHeight = paper.view.size.height,
rows = (winHeight + 48) / 24,
cols = (winWidth + 42) / 42,
numTri = rows * cols,
numTriOrig = (winWidth + 42) / 42 * (winHeight + 48 / 24);
//console.log(numTri, numTriOrig);
x = 0;
y = 0;
for (var row = 0; row < rows; row++) {
rowrotate = row % 2;
for (var col = 0; col <= cols; col++) {
rotate = rowrotate ^ col % 2;
putTriangle([x,y], rotate);
x += 42;
}
x = 0;
y = y + 24;
}
Two thoughts:
I see you use rotate to transform you triangles into place. This is an expensive operation. You could replace the rotate with a less geometric & more arithmetic calculation of the triangles orientation.
Also, I see is that the fill color is being changed with each triangle and state changes (like fill) are modestly expensive. You could group all the similarly colored triangles and draw them in a single batch.