So I'm pretty baffled with this issue I have here. I'm almost certain this code is correct yet the list box that I want to appear is not showing up at all after something is selected from the first drop down box. Here is what I have going for the code now
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<link href="css/template.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
function view_private_user_list(){
var i = document.status.private_users.options[document.status.private_users.selectedIndex].value;
if(i == 1){
document.getElementById('private_select_now').style.visibility="visible";
} else{
document.getElementById('private_select_now').style.visibility="visible";
}
}
</script>
</head>
<body>
<div id="show_private_option">
<select id="private_users" onChange="view_private_user_list()">
<option value="0" SELECTED>Select user....</option>
<option value="1">Vincent</option>
</select>
<div id="private_select_now" style="visibility:hidden">
<select size="3">
<option value="">{#template_dlg.select}...</option>
<option value="SOOOOLDmax.htm">SOOOOLDmax</option>
<option value="mike.htm">tester</option>
</select>
</div>
</div>
</body>
</html>
This fiddle should work:
http://jsfiddle.net/3XENR/1/
I think the way you're trying to find out the current value of the dropdown doesn't quite work.
Try this version of the function instead.
function view_private_user_list(){
var selectEl = document.getElementById('private_users');
var i = selectEl.value;
if(i == 1){
document.getElementById('private_select_now').style.visibility="visible";
} else{
document.getElementById('private_select_now').style.visibility="hidden";
}
}
Try:
document.getElementById('private_select_now').style.display ="block";
and
document.getElementById('private_select_now').style.display="none";
instead
instead of visibility, use display
<script type="text/javascript">
function view_private_user_list(){
var i = document.getElementById('private_users').selectedIndex.value
if(i == 1){
document.getElementById('private_select_now').style.display="block";
} else{
document.getElementById('private_select_now').style.display="none";
}
}
</script>
Related
I'm not good at javascript but I tried this...
I'm trying to make an option for a user to switch to another page after searching for an item.
The user for example will searches for a Mercedes under cars section then the options value can change to the Mercedes links page as well as can change to GMC links page is the user searches for gmc. This code seems not to work.
Below is the code:
<div class="all" id="note">
Some content will be posted here...
</div>
<select id="marketing" onChange="window.open(this.value)" multiple>
<option value="1">cars</option>
<option value="2">houses</option>
<option value="3">Promotion</option>
</select>
<script type="text/javascript">
var cars = ['mercedes']
$('#marketing').change(function(){
if($(this).val() == '1'){
if cars[0] ==='mercedes';{
$(this).val() == "http://www.cars.com/mercedes";
}
}
});
<!DOCTYPE html>
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta charset="utf-8" />
<title></title>
<script>
var cars = ['mercedes']
function myFunction() {
var x = document.getElementById("marketing").value;
var companey = document.getElementById('companies').value;
console.log(x + companey);
if (x == 1 && companey == "mercedes") {
var url =
window.open("http://www.cars.com/mercedes" , '_blank');//for new tab
//for same tab
//window.open('http://www.cars.com/mercedes');
}
}
</script>
</head>
<body>
<!this is a working sample hope this will help>
<div class="all" id="note">
Some content will be posted here... <br />
<input type="text" id="companies">mercedes</input>
</div>
<select id="marketing" onchange="myFunction()">
<option value="0"></option>
<option value="1">cars</option>
<option value="2">houses</option>
<option value="3">Promotion</option>
</select>
</body>
</html>
I'm trying to create a webpage where the options in the second dropdown menu depend on the value selected in the first dropdown menu. However, when running the webpage, the options in the second dropdown do not change regardless of what is selected in the first dropdown. The Browser does indicate that it SEES the javascript file, but it just doesn't appear to be actually running it for some reason. Anyone know what's going on?
$(document).ready(function() {
$convertfrom = $("select[name='ConvertFrom']");
$convertto = $("select[name='ConvertTo']");
$convertto.change(function() {
if ($(this).val() == "Binary") {
$("select[name='convertto'] option").remove();
$("<option>Decimal</option>").appendTo($convertto);
$("<option>Octal</option>").appendTo($convertto);
$("<option>HexaDecimal</option>").appendTo($convertto);
}
if ($(this).val() == "Decimal") {
$("select[name='convertto'] option").remove();
$("<option>Binary</option>").appendTo($convertto);
$("<option>Octal</option>").appendTo($convertto);
$("<option>HexaDecimal</option>").appendTo($convertto);
}
if ($(this).val() == "Octal") {
$("select[name='convertto'] option").remove();
$("<option>Binary</option>").appendTo($convertto);
$("<option>Decimal</option>").appendTo($convertto);
$("<option>HexaDecimal</option>").appendTo($convertto);
}
if ($(this).val() == "HexaDecimal") {
$("select[name='convertto'] option").remove();
$("<option>Binary</option>").appendTo($convertto);
$("<option>Decimal</option>").appendTo($convertto);
$("<option>Octal</option>").appendTo($convertto);
}
});
});
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<title>Practice</title>
</head>
<body>
<p> Welcome to the Practice Page. On this page, you can randomly generate a problem and see if you can solve it correctly.
Please select a base to convert from below. You'll then be asked to select a base to convert to, and then given a problem to solve. </p>
<form>
<select id="ConvertFrom">
<option value="Select">Select</option>
<option value="Binary">Binary</option>
<option value="Decimal">Decimal</option>
<option value="Octal">Octal</option>
<option value="HexaDecimal">HexaDecimal</option>
</select>
<select id="ConvertTo">
<option value="Convertto">ConvertTo</option>
</select>
</form>
<script src="file:///C:/Users/johnt/Documents/Catan/practice2.js"></script>
</body>
</html>
You made four mistakes.
$convertfrom = $("select[name='ConvertFrom']"); has to be $('#ConvertFrom');
$convertto = $("select[name='ConvertTo']"); has to be $('#ConvertTo');
$convertto.change(function() { has to be $convertfrom.change(function() {
$("select[name='convertto'] option").remove() has to be $convertto.innerHTML = '';
This code works in JSFiddle fine however when I put in in a dreamweaver document or try it in a browser the div never shows. The aim is to get the div 'sreturned' to show when the user selects value '1' from the drop down. I have the code in two seperate files and link them. Any help greatly appreciated.
Here is the HTML
<body>
<script type="text/javascript" src="file:///Macintosh%20HD/Applications/MAMP/htdocs/thesurebettor/Untitled-2.js"></script>
<select id = "typeoption">
<option value="0">Qualifying Bet</option>
<option value="1">Free Bet</option>
<option value="2">Risk Free Bet</option>
</select>
<div style='display:none;' id='sreturned'> Stake Returned
</div>
</body>
Here is the script
$(document).ready(function(){
$('#typeoption').on('change', function() {
if ( this.value == '1')
{
$("#sreturned").show();
}
else
{
$("#sreturned").hide();
}
});
});
EDIT: JSFiddle include jquery in all pages
Do you have add jquery script ? Try this file :
<body>
<script type="text/javascript" src="file:///Macintosh%20HD/Applications/MAMP/htdocs/thesurebettor/Untitled-2.js"></script>
<select id = "typeoption">
<option value="0">Qualifying Bet</option>
<option value="1">Free Bet</option>
<option value="2">Risk Free Bet</option>
</select>
<div style='display:none;' id='sreturned'> Stake Returned
</div>
</body>
<script src="https://code.jquery.com/jquery-1.11.3.js"></script>
<script>
$(document).ready(function(){
$('#typeoption').on('change', function() {
if ( this.value == '1')
{
$("#sreturned").show();
}
else
{
$("#sreturned").hide();
}
});
});
</script>
I am creating a business options form (rough description I know, but here goes). I want the first select that pops up to be to choose an Entity Type (IE: Corporation, LLC, LLP, etc). Once one of these is chosen, I want to .show() the next form. Here is what I've tried so far:
HTML FILE
<head>
<link rel="stylesheet" type="text/css" href="hide.css">
<script src="//code.jquery.com/jquery-1.10.2.js">
function getEntityType(sel) {
var openingEntityType = sel.value;
$("#basicOpeningEntityInformation").show();
}
</script>
</head>
<body>
<select id="oet" onchange="getEntityType(this)">
<option value="">Select an Option</option>
<option value="inc">Corporation</option>
<option value="llc">Limited Liability Company</option>
<option value="llp">Limited Liability Partnership</option>
<option value="lp">Limited Partnership</option>
<option value="gp">General Partnership</option>
<option value="jv">Joint Venture</option>
<option value="dba">Sole Proprietorship</option>
</select>
<br/>
<br/>
<form id="basicOpeningEntityInformation">
Entity Name:
<input type="text" id="openingEntityName">
<br/>
</form>
</body>
CSS FILE:
#basicOpeningEntityInformation {
display: none;
}
When the page loads, #basicOpeningEntityInformation is hidden. I want it to be unhide when a select from above is chosen. I tested my console and the select is passing it's value to var openingEntityType as it should; however, it is not making the other form visible. I tired with both .basicOpeningEntityInformation and #basicOpeningEntityInformation and neither seem to work (both in the CSS and the Script.
Thank you!
You need to check if the selected value is one of the required values:
$('#oet').on('change', function() {
var selectedItem = $(this).val();
if (selectedItem == 'inc' || selectedItem == 'llc' || selectedItem == 'llp') {
$('#basicOpeningEntityInformation').show();
} else {
$('#basicOpeningEntityInformation').hide();
}
});
Demo: https://jsfiddle.net/tusharj/L4b0wpts/1/
Try adding this..it will work
<head>
<link rel="stylesheet" type="text/css" href="hide.css">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.js"> </script>
<script>
function getEntityType(sel) {
var openingEntityType = sel.value;
jQuery("#basicOpeningEntityInformation").show();
}
</script>
</head>
you are using $(".basicOpeningEntityInformation").show();
so change the
id="basicOpeningEntityInformation" to class="basicOpeningEntityInformation"
OR
$(".basicOpeningEntityInformation").show(); to $("#basicOpeningEntityInformation").show();
am trying to select a multi select combo box. There i have to customize the property that when mouse over a value the color has to change. I tried few steps i know nut its not working. Suggest me the way how should i handle it. Here is the code.
<html>
<head>
<style type="text/css" >
</style>
<script type="text/javascript">
var a="hidden";
function doset()
{
if(a=="hidden")
a="visible";
else
a="hidden";
document.getElementById("myitems").style.visibility = a;
}
function dochange(a)
{
document.getElementById(a).style.background-color= 0xff00ff;
}
</script>
</head>
<body>
<label>ajay</label>
<input type=button value="v" onClick="doset(); return false;"/>
<div id=myitems style='visibility:hidden'>
<select multiple="multiple" >
<option id= prav1 onMouseover="dochange(this.id); return true;">ajay</option>
<option id= prav2 onMouseover="dochange(this.id); return true;">musthafa</option>
<option id= prav3 onMouseover="dochange(this.id); return true;">praveen</option>
<option id= prav4 onMouseover="dochange(this.id); return true;">shruthy</option>
<option id= prav5 onMouseover="dochange(this.id); return true;">vasanth sir</option>
</select>
</div>
</body>
</html>
It is backgroundColor instead of background-color
document.getElementById(a).style.backgroundColor= "#ff00ff";
SEE A WORKING DEMO
document.getElementById(a).style.background= "#ff00ff";
function dochange(a)
{
document.getElementById(a).style.backgroundColor = "#ff00ff";
}
"document.getElementById(a).style.background-color" is wrong
Have to be: "document.getElementById(a).style.backgroundColor"