I'm dealing with this problem since 2 days and I haven't found a solution.
Here's the tooltip script that I'm using: http://iamceege.github.io/tooltipster/
It works fine, I'm able to show data in HTML format, no problem.
But the problem comes when I want to echo a HTML code from a function that was written by me. The output of the function isn't showed in the tooltip, but outside it.
Here's my function:
public function showProducts($uId, $wid){
$sql1 = "SELECT pids FROM wishlists WHERE uid='$uId' AND id='$wid'";
$q = mysql_query($sql1) or die(mysql_error());
while($data=mysql_fetch_array($q)){
$dbprods = $data['pids'];
$prods = explode(",", $dbprods);
for($i = 0; $i < count($prods); $i++){
$id=$prods[$i];
$q=mysql_query("SELECT * from products where id='$id'");
while($bd = mysql_fetch_array($q)){
echo ''.$bd['name'].'<br />';
}
}
}
}
If I'm typing return $bd['id'];, the tooltip is fine. The problem comes only with that HTML output. The tooltip and function call is this echo '# <a class="tooltip" title="Products <br />'.$this->showProducts($uid, $wid).'">'.$data['name'].'</a><br />';
I have also tried to modify the my function into something like
while($bd = mysql_fetch_array($q)){ ?>
<?php echo $bd['name'];?><br />
<?php }
but still no result. Does anyone helps me out?
Related
I have a strange problem. I am getting the table values using PHP MySQL using a while loop and stored them in a array. Then I am displaying it one after another in a single page.
$sql = "select * from newsfeed order by id DESC";
$result = $db->query($sql);
$posts_array = array(); // Storing the result to an Custom Array
$index = 0;
if($result->num_rows > 0)
{
while($row = $result->fetch_assoc()) {
$posts_array[$index] = $row;
$index++;
}
}
I have successfully set the $post_id of the posts on to the HTML elements using the following code.
<?php
$array_size = sizeof($posts_array);
for($i = 0; $i < $array_size; $i++){
?>
<div class='wrapper' id='wrapper'>
<div class='user'>
<!-- Some Code -->
<?php
$post_id = $posts_array[$i][id];
?>
<input type='image' name='like' id='like' width='40' height='40' src='like_btn.png' value='<?php echo ($post_id);'?> />
<?php } ?>
Now I want to take that value using Jquery and do some Database Work. I have accessed the value using the following code:
<script type="text/javascript">
function justsomething() {
alert($(this).val());
}
</script>
The problem is I am only getting the last post's id as alert() for every post rather than getting different id's .
Please help me. I am confused whether the PHP script is loading every time I click and call the justsomething() function.
Note: I can display the $post_id of every post alone without any problem.
Beacuse the id should be unique to one html element try changing your code to this :
<?php $array_size = sizeof($posts_array); for($i = 0; $i < $array_size; $i++){ ?>
<input type='image' name='like_<?php echo $i ?>' id='like_<?php echo $i ?>' width='40' height='40' src='like_btn.png' value='<?php echo $post_id;?>' onclick='justsomething(this);' />
<?php } ?>
<script>
function justsomething(el) {
var img = el;
alert(img.value);
}
</script>
here is an example
function justsomething(el) {
var img = el;
alert(img.value);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type='image' name='like_1' id='like_1' width='40' height='40' src='like_btn.png' value='15454' onclick='justsomething(this);' />
It works for loop, I hope You can make use of it
$("input[id=like]").each(function(i){
alert($(this).val());
});
It will alert values from every <input id="like"...
Try this code:
onclick='justsomething(this)'
function justsomething(obj) {
alert($(obj).val());
}
I have in my database 2 rows of information so my code create will create positivoNegativo.png twice and the number 10 twice. When I click on the FIRST positivoNegativo.png my number FIRST 10 is incremented (exacly as I wanted to). Now my issue, when I click on the SECOND positivoNegativo.png, the FIRST number is incremented again! I just can't increment the SECOND number by clicking on the SECOND positivoNegativo.png
<html>
<body>
<?php
include_once("./classe/conexao.php");
$busca = $pdo->prepare("select * from anuncios");
$busca->execute();
$linha = $busca->fetchAll(PDO::FETCH_OBJ);
$classe = 0;
foreach ($linha as $lista) {
echo "<p class='demo'>10</p>";
echo "<img src='imagens/positivoNegativo.png'usemap='#mapa'>";
echo "<map name='mapa'>";
echo "<area shape='rect' coords='1,1,73,59' onclick='aumenta($classe)'>";
echo "</map>";
echo "<span>$lista->titulo</span>";
$classe++;
}
?>
<script>
function aumenta(classe) {
var numero = document.getElementsByClassName('demo')[classe].innerHTML;
numero++;
document.getElementsByClassName('demo')[classe].innerHTML = numero;
}
</script>;
</body>
You need to use different map for each image.
foreach ($linha as $lista) {
echo "<p class='demo'>10</p>";
echo "<img src='imagens/positivoNegativo.png'usemap='#mapa$classe'>";
echo "<map name='mapa$classe'>";
echo "<area shape='rect' coords='1,1,73,59' onclick='aumenta($classe)'>";
echo "</map>";
echo "<span>$lista->titulo</span>";
$classe++;
}
Try this:
<?php
include_once("./classe/conexao.php");
$busca = $pdo->prepare("select * from anuncios");
$busca->execute();
$linha = $busca->fetchAll(PDO::FETCH_OBJ);
$classe = 0;
foreach ($linha as $lista) {
echo "<p class='demo".$classe."'>10</p>";
echo "<img src='imagens/positivoNegativo.png' onclick='aumenta($classe)'>";
echo "<span>$lista->titulo</span>";
$classe++;
}
?>
<script>
function aumenta(classe) {
var numero = document.getElementsByClassName('demo'+classe).innerHTML;
numero++;
document.getElementsByClassName('demo'+classe).innerHTML = numero;
}
</script>;
I didn't test the code, but it might give you some hints.
I left out the whole <map> thing because it doesn't make sense in your code. There's only an up?
I have the following code which is updating a form on click. When populating title and content, it works fine. When I added startDate nothing populates. Im assuming something in my syntax is wrong but all the logic looks correct to me. Am I missing something?
<script type="text/javascript">
function changeText(title, content, startDate){
window.alert("test");
document.getElementById('startDate').value = document.getElementById(startDate).getAttribute('data-content');
document.getElementById('content').value = document.getElementById(content).getAttribute('data-content');
document.getElementById('title').value = document.getElementById(title).getAttribute('data-content');
}
</script>
<?php
foreach ($announcement as $row){ //Displays title, startDate, endDate from announcement table from database
$tile = ($row["announcementID"] ."t");
$cont = $row["announcementID"];
$startDate = ($row["announcementID"] ."s");
echo "<h2 style=width:auto;padding:8px;margin-top:-30px;font-size:18px;><a style=text-decoration:none;color:#c4572f; >".$row["title"]."</a></h2><br>";
echo "<p style=padding-top:10px;>".$row["content"]."</p><br>";
echo "<p style=font-size:10px;>Posted: ".$row["startDate"]."</p><br>";
echo '<input id="'.$tile.'" data-content="'.$row["title"].'" type=button class=test onclick="changeText(id, '.$cont.', '.$startDate.');" value="Edit">';
echo '<p id="'.$cont.'" data-content="'.$row["content"].'">test</p>';
echo '<p id="'.$startDate.'" data-content="'.$row["startDate"].'">startDate</p>';
echo "<h5 style=line-height:2px;margin-top:-15px;><p>_____________________________________</p></h5><br>";
}
?>
I found the solution after some more testing. JS didnt approve of the variable names with letters attached. After editing that variable names the code worked fine.
I have a problem, trying to create a button with Ajax/Php which is to appear on my main page and is supposed to have a onclick function. To be more specific, I end up in a while loop, which fetches through the rows of my mySQL-table and displays the following:
echo "<table>";
while($result == true && $a <= 15){
$res = $result["uberschrift"];
echo "<tr id='$res'>";
echo "<td>".$a."</td>";
echo "<td>".$res."</td>";
echo "<td>"."<button id='b_löschen' onclick='k_löschen($res)'> löschen </button>"."</td>";
echo "</tr>";
$result = $stmt->fetch();
$a++;
}
echo "</table>";
In fact, this works quite well, and on my main page the string contained in $result["uberschrift"] is displayed properly. However, if I call the function k_löschen with $res as shown above, it will not take the String but a certain
[object HTMLTablerowElement] as input, which naturally causes an Error. Can someone tell me how to change the code so that the function actually takes the string as it's input?
You have issues with your quotes. Also you could tell us what $res typically contained.
I would do this
echo "<tr id=\"".$res."\">";
echo "<td><button id='b_löschen' onclick='k_löschen(\"".$res."\")'>löschen</button></td>";
I have this ajax_update script that updates file.php every 60 seconds..
Now file.php outputs this after updated a table:
<div id='message' style="display: none;">
<span>Hey, <b><? echo $userid; ?></b>, You've got +1 points, you now have <u>
<? echo $n["points"]; ?></u></span>
X
</div>
<script>
$("#message").fadeIn("slow");
</script>
Why will this only work in FF, i mean appear, but not in IE..
What I am trying to do is that after file.php have updated a field in the database(points), there will come up a message like stackoverflow at the top(just like when you earn a badge) saying that you have received 1 point.
This works perfectly in FF but in IE, the message is not showing at all?
Maybe another way to do this? Or a fix, solution?
I tried to put the little JS script in the index.php and remove the ajax update thing, and it works fine in IE.
function addpoints() {
var userid = document.getElementById('user_id_points');
var postFile = 'addpoints.php?userid='+ userid.value;
$.post(postFile, function(data){
$("#message").fadeIn("slow");
$("#points").html(data);
setTimeout(addpoints, 62000);
});
}
function closeNotice() {
$("#message").fadeOut("slow");
}
my ajax script^
<?php
include "tilslut.php";
$userid = $_GET["userid"];
$s = mysql_query("SELECT points, lastpoint FROM member_profile WHERE user_id = '".$userid."'");
$n = mysql_fetch_array($s);
$tid = time();
mysql_query("UPDATE member_profile set points = points+1, lastpoint=$tid WHERE lastpoint<=$tid-60 AND user_id = '".$userid."'");
if(isset($userid)) {
$e = mysql_query("SELECT points FROM member_profile WHERE user_id = '".$userid."'");
$f = mysql_fetch_array($e);
echo $n["points"];
}elseif (mysql_affected_rows() == 1) {
$s = mysql_query("SELECT points FROM member_profile WHERE user_id = '".$userid."'");
$n = mysql_fetch_array($s);
?>
If you receive this text, no problem with php
<div id="message" onclick="closeNotice()">this works
</div>
<?
}else{
?>
This doesnt work at all
<?
}
?>
my php coding, with the
In your ajax update script, call this after the results are in:
$("#message").fadeIn("slow");
Scripts coming back as part of the request are unreliable, putting the logic in your ajax result function is a better approach in this case.
Try this for your ajax call:
function addpoints() {
var postFile = 'addpoints.php?userid='+ $('#user_id_points').val();
$.post(postFile, function(data){
$("#points").html(data).find("#message").fadeIn("slow")
setTimeout(addpoints, 62000);
});
}
Solved this by adding a
header('Content-type: text/html; charset=utf-8');
in the top in addpoints.php