How is it possible to calculate the total days using interval intitial and final DatePicker. Sorry for my bad english
$(".datepicker").datepicker({
minDate: 0,
numberOfMonths: [3,1],
beforeShowDay: function(date) {
var date1 = $.datepicker.parseDate($.datepicker._defaults.dateFormat, $("#input1").val());
var date2 = $.datepicker.parseDate($.datepicker._defaults.dateFormat, $("#input2").val());
return [true, date1 && ((date.getTime() == date1.getTime()) || (date2 && date >= date1 && date <= date2)) ? "dp-highlight" : ""];
},
onSelect: function(dateText, inst) {
var date1 = $.datepicker.parseDate($.datepicker._defaults.dateFormat, $("#input1").val());
var date2 = $.datepicker.parseDate($.datepicker._defaults.dateFormat, $("#input2").val());
var selectedDate = $.datepicker.parseDate($.datepicker._defaults.dateFormat, dateText);
if (!date1 || date2) {
$("#input1").val(dateText);
$("#input2").val("");
$(this).datepicker();
} else if( selectedDate < date1 ) {
$("#input2").val( $("#input1").val() );
$("#input1").val( dateText );
$(this).datepicker();
} else {
$("#input2").val(dateText);
$(this).datepicker();
}
}
});
http://jsfiddle.net/sWbfk
One way to compute date difference in days is the following:
var t1 = Date.parse($("#input1").val()); // date1.getTime();
var t2 = Date.parse($("#input2").val()); // date2.getTime();
var difference = Math.abs(t2 - t1) / 86400000;
$("#diff").val(difference);
(I tested by putting the code as the last lines of onSelect: function(dateText, inst)).
86400000 is the computed for 24h x 60min x 60s x 1000ms (number of milliseconds in a day)
When you are dealing with dates you should look into moment.js.
You can try something like this:
Moment
moment($("#input1").val()).diff(moment(selectedDate), "days");
Pure JS
var d1 = new Date(date1);
var d2 = new Date(selectedDate);
var secInDays = 24 * 60 * 60 * 1000;
d1.setHours(0, 0, 0, 0);
d2.setHours(0, 0, 0, 0);
console.log((+d2 - +d1) / secInDays)
I'm using the code from JQuery UI Datepicker Disbale Next Day After 12pm to disable weekends, public holidays and next day (if selected after 10am), but I'm stuck on how to only allow Tuesday, Wednesday and Thursday to be selected.
// dates
var dateMin = new Date();
var weekDays = AddWeekDays(1);
dateMin.setDate(dateMin.getDate() + weekDays);
var natDays = [
[1, 1, 'uk'],
[12, 25, 'uk'],
[12, 26, 'uk']
];
function noWeekendsOrHolidays(date) {
var noWeekend = $j.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1 && date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
function AddWeekDays(weekDaysToAdd) {
var mydate = new Date();
if (mydate.getHours()>=10)
var daysToAdd = 1;
else var daysToAdd = 0;
var day = mydate.getDay()
weekDaysToAdd = weekDaysToAdd - (5 - day)
if ((5 - day) < weekDaysToAdd || weekDaysToAdd == 1) {
daysToAdd = (5 - day) + 2 + daysToAdd
} else { // (5-day) >= weekDaysToAdd
daysToAdd = (5 - day) + daysToAdd
}
while (weekDaysToAdd != 0) {
var week = weekDaysToAdd - 5
if (week > 0) {
daysToAdd = 7 + daysToAdd
weekDaysToAdd = weekDaysToAdd - 5
} else { // week < 0
daysToAdd = (5 + week) + daysToAdd
weekDaysToAdd = weekDaysToAdd - (5 + week)
}
}
return daysToAdd;
}
$j('.input-text.addon.addon-custom').datepicker({
beforeShowDay: noWeekendsOrHolidays,
minDate : dateMin,
defaultDate: +1,
firstDay: 1,
changeFirstDay: true,
dateFormat: "DD, dd MM yy"
});
Any help would be very much appreciated.
Fiddle here: http://jsfiddle.net/prydonian/4k4gga6j/
On your datepicker function, add the "beforeShowDay" option like this.
jQuery('#datepicker').datepicker({
minDate: dateMin,
defaultDate: +1,
firstDay: 1,
changeFirstDay: true,
dateFormat: "DD, dd MM yy",
beforeShowDay: function(day){
if (day.getDay()<2 || day.getDay()>4){
return [false, ""];
}
return noWeekendsOrHolidays(day);
}
});
here is the Fiddle updated: http://jsfiddle.net/4k4gga6j/3/
If I understood you right, you need to exclude any day other than Tuesday, Wednesday and Thursday? If the answer is yes, then you should add the following code to your existing noWeekendsOrHolidays method:
($.inArray(date.getDay(), [2, 3, 4]) != -1)
here is updated jsFiddle http://jsfiddle.net/4k4gga6j/4/
I use a datepicker for choosing an appointment day. I already set the date range to be only for the next month. That works fine. I want to exclude Saturdays and Sundays from the available choices. Can this be done? If so, how?
There is the beforeShowDay option, which takes a function to be called for each date, returning true if the date is allowed or false if it is not. From the docs:
beforeShowDay
The function takes a date as a parameter and must return an array with [0] equal to true/false indicating whether or not this date is selectable and 1 equal to a CSS class name(s) or '' for the default presentation. It is called for each day in the datepicker before is it displayed.
Display some national holidays in the datepicker.
$(".selector").datepicker({ beforeShowDay: nationalDays})
natDays = [
[1, 26, 'au'], [2, 6, 'nz'], [3, 17, 'ie'],
[4, 27, 'za'], [5, 25, 'ar'], [6, 6, 'se'],
[7, 4, 'us'], [8, 17, 'id'], [9, 7, 'br'],
[10, 1, 'cn'], [11, 22, 'lb'], [12, 12, 'ke']
];
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1
&& date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
One built in function exists, called noWeekends, that prevents the selection of weekend days.
$(".selector").datepicker({ beforeShowDay: $.datepicker.noWeekends })
To combine the two, you could do something like (assuming the nationalDays function from above):
$(".selector").datepicker({ beforeShowDay: noWeekendsOrHolidays})
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
Update: Note that as of jQuery UI 1.8.19, the beforeShowDay option also accepts an optional third paremeter, a popup tooltip
If you don't want the weekends to appear at all, simply:
CSS
th.ui-datepicker-week-end,
td.ui-datepicker-week-end {
display: none;
}
The datepicker has this functionality built in!
$( "#datepicker" ).datepicker({
beforeShowDay: $.datepicker.noWeekends
});
http://api.jqueryui.com/datepicker/#utility-noWeekends
These answers were very helpful. Thank you.
My contribution below adds an array where multiple days can return false (we're closed every Tuesday, Wednesday and Thursday). And I bundled the specific dates plus years and the no-weekends functions.
If you want weekends off, add [Saturday], [Sunday] to the closedDays array.
$(document).ready(function(){
$("#datepicker").datepicker({
beforeShowDay: nonWorkingDates,
numberOfMonths: 1,
minDate: '05/01/09',
maxDate: '+2M',
firstDay: 1
});
function nonWorkingDates(date){
var day = date.getDay(), Sunday = 0, Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, Saturday = 6;
var closedDates = [[7, 29, 2009], [8, 25, 2010]];
var closedDays = [[Monday], [Tuesday]];
for (var i = 0; i < closedDays.length; i++) {
if (day == closedDays[i][0]) {
return [false];
}
}
for (i = 0; i < closedDates.length; i++) {
if (date.getMonth() == closedDates[i][0] - 1 &&
date.getDate() == closedDates[i][1] &&
date.getFullYear() == closedDates[i][2]) {
return [false];
}
}
return [true];
}
});
The solution here that everyone likes seems to very intense... personally I think it's much easier to do something like this:
var holidays = ["12/24/2012", "12/25/2012", "1/1/2013",
"5/27/2013", "7/4/2013", "9/2/2013", "11/28/2013",
"11/29/2013", "12/24/2013", "12/25/2013"];
$( "#requestShipDate" ).datepicker({
beforeShowDay: function(date){
show = true;
if(date.getDay() == 0 || date.getDay() == 6){show = false;}//No Weekends
for (var i = 0; i < holidays.length; i++) {
if (new Date(holidays[i]).toString() == date.toString()) {show = false;}//No Holidays
}
var display = [show,'',(show)?'':'No Weekends or Holidays'];//With Fancy hover tooltip!
return display;
}
});
This way your dates are human readable. It's not really that different it just makes more sense to me this way.
You can use noWeekends function to disable the weekend selection
$(function() {
$( "#datepicker" ).datepicker({
beforeShowDay: $.datepicker.noWeekends
});
});
This version of code will make u to get the holiday dates from the sql database and disable the specified date in the UI Datepicker
$(document).ready(function (){
var holiDays = (function () {
var val = null;
$.ajax({
'async': false,
'global': false,
'url': 'getdate.php',
'success': function (data) {
val = data;
}
});
return val;
})();
var natDays = holiDays.split('');
function nationalDays(date) {
var m = date.getMonth();
var d = date.getDate();
var y = date.getFullYear();
for (var i = 0; i ‘ natDays.length-1; i++) {
var myDate = new Date(natDays[i]);
if ((m == (myDate.getMonth())) && (d == (myDate.getDate())) && (y == (myDate.getFullYear())))
{
return [false];
}
}
return [true];
}
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
$(function() {
$("#shipdate").datepicker({
minDate: 0,
dateFormat: 'DD, d MM, yy',
beforeShowDay: noWeekendsOrHolidays,
showOn: 'button',
buttonImage: 'images/calendar.gif',
buttonImageOnly: true
});
});
});
Create a Database in sql and put you holiday dates in MM/DD/YYYY format as Varchar
Put the below contents in a file getdate.php
[php]
$sql="SELECT dates FROM holidaydates";
$result = mysql_query($sql);
$chkdate = $_POST['chkdate'];
$str='';
while($row = mysql_fetch_array($result))
{
$str .=$row[0].'';
}
echo $str;
[/php]
Happy Coding !!!! :-)
$("#selector").datepicker({ beforeShowDay: highlightDays });
...
var dates = [new Date("1/1/2011"), new Date("1/2/2011")];
function highlightDays(date) {
for (var i = 0; i < dates.length; i++) {
if (date - dates[i] == 0) {
return [true,'', 'TOOLTIP'];
}
}
return [false];
}
In this version, month, day, and year determines which days to block on the calendar.
$(document).ready(function (){
var d = new Date();
var natDays = [[1,1,2009],[1,1,2010],[12,31,2010],[1,19,2009]];
function nationalDays(date) {
var m = date.getMonth();
var d = date.getDate();
var y = date.getFullYear();
for (i = 0; i < natDays.length; i++) {
if ((m == natDays[i][0] - 1) && (d == natDays[i][1]) && (y == natDays[i][2]))
{
return [false];
}
}
return [true];
}
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
$(function() {
$(".datepicker").datepicker({
minDate: new Date(d.getFullYear(), 1 - 1, 1),
maxDate: new Date(d.getFullYear()+1, 11, 31),
hideIfNoPrevNext: true,
beforeShowDay: noWeekendsOrHolidays,
});
});
});
In the latest Bootstrap 3 version (bootstrap-datepicker.js) beforeShowDay expects a result in this format:
{ enabled: false, classes: "class-name", tooltip: "Holiday!" }
Alternatively, if you don't care about the CSS and tooltip then simply return a boolean false to make the date unselectable.
Also, there is no $.datepicker.noWeekends, so you need to do something along the lines of this:
var HOLIDAYS = { // Ontario, Canada holidays
2017: {
1: { 1: "New Year's Day"},
2: { 20: "Family Day" },
4: { 17: "Easter Monday" },
5: { 22: "Victoria Day" },
7: { 1: "Canada Day" },
8: { 7: "Civic Holiday" },
9: { 4: "Labour Day" },
10: { 9: "Thanksgiving" },
12: { 25: "Christmas", 26: "Boxing Day"}
}
};
function filterNonWorkingDays(date) {
// Is it a weekend?
if ([ 0, 6 ].indexOf(date.getDay()) >= 0)
return { enabled: false, classes: "weekend" };
// Is it a holiday?
var h = HOLIDAYS;
$.each(
[ date.getYear() + 1900, date.getMonth() + 1, date.getDate() ],
function (i, x) {
h = h[x];
if (typeof h === "undefined")
return false;
}
);
if (h)
return { enabled: false, classes: "holiday", tooltip: h };
// It's a regular work day.
return { enabled: true };
}
$("#datePicker").datepicker({ beforeShowDay: filterNonWorkingDays });
This work for me:
$( "#datepicker" ).datepicker({
beforeShowDay: function( date ) {
var day = date.getDay();
return [ ( day > 0 && day < 6 ), "" ];
}
});
For Saturday and Sunday You can do something like this
$('#orderdate').datepicker({
daysOfWeekDisabled: [0,6]
});
To Disable the Weekends the API has a built-in feature
$('#data_1 .input-group.date').datepicker({
daysOfWeekDisabled: [0,6],
});
0 = Sunday
6 = Sunday
I am calculating the age from jquery datepicker. But this works when only the date is in(mm/dd/yy) format. I need to get this working in dd/mm/yy.
//Code
$('#dob').datepicker({
onSelect: function(value, ui) {
var today = new Date(),
dob = new Date(value),
age = new Date(today - dob).getFullYear() - 1970;
$('#age').text(age);
},
maxDate: '+0d',
yearRange: '1920:2010',
changeMonth: true,
changeYear: true
});
If i try to set dateFormat: 'mm/dd/yy' in the property this wont work.
Any help?
Demo Fiddle mm/dd/yy Demo Fiddle dd/mm/yy
jQuery
onSelect: function (value, ui) {
var today = new Date();
var format = value.split("/");
var dob = new Date(format[2], format[0], format[1]);
var diff = (today - dob);
var age = Math.floor(diff / 31536000000);
$('#age').text(age);
},
Reference
Hope it helps....
Try this:
http://jsfiddle.net/lotusgodkk/GCu2D/120/
Js:
$('#dob').datepicker({
onSelect: function(value, ui) {
console.log(ui.selectedYear)
var today = new Date(),
dob = new Date(value),
age = ui.selectedYear - 1970; //This is the update
$('#age').text(age);
},
maxDate: '+0d',
yearRange: '1920:2010',
changeMonth: true,
changeYear: true,
});
If you inspect the ui object in console, you'll see that it stores year,day,month separately. You can access them like ui.selectedDay or selectedYear . Hope this helps.
this answer will work fine for the all the dates as the month starts from 0 in date function. for date format(dd-mm-yy).
var now= new Date();
var year= now.getFullYear();
$('#dob').datepicker({
onSelect: function (value, ui) {
var today = new Date();
console.log(today.getFullYear());
var format = value.split("-");
console.log(format[2]);
var dob = new Date(format[2], format[1]-1, format[0]);
console.log(dob);
var diff = (today - dob);
var age = Math.floor(diff / 31536000000);
$('#age').text(age);
},
dateFormat: 'dd-mm-yy',
maxDate: '+0d',
yearRange: '1920:'+year,
changeMonth: true,
changeYear: true
});
$("#dob").datepicker({
onSelect: function (value, ui) {
debugger
var today = new Date();
var year = today.getFullYear() - ui.selectedYear;
var month = today.getMonth() - ui.selectedMonth;
var date = today.getDate() - ui.selectedDay;
if ((year == 0 && month == 0 && date < 0) || (year == 0 && month < 0) || (year < 0)) {
$("#lbl6").show();
$("#age").val("");
} else if ((year == 0) || (year > 0 && month == 0 && date >= 0) || (year > 0 && month > 0)) {
$("#age").val(year);
} else if ((year > 0 && month == 0 && date < 0) || (year > 0 && month < 0)) {
$("#age").val(year - 1);
}
},
dateFormat: 'dd M y',
changeMonth: true,
changeYear: true,
yearRange: '1900:2020'
});
I wonder how to set next month with showing only mondays active:
i tried to do smth like that but it wont work
function onlyMondaysNextMonth(date){
var day = date.getDay();
var mDate = date.getMonth() + 1;
return {
minDate: mDate,
}
return [(day == 1),''];
}
Thank you.
Use the following code to enable only Mondays starting from next month
var minDate = null;
var now = new Date();
if (now.getMonth() == 11) {
minDate = new Date(now.getFullYear() + 1, 0, 1);
} else {
minDate = new Date(now.getFullYear(), now.getMonth() + 1, 1);
}
/* create datepicker */
jQuery(document).ready(function () {
jQuery('#datepicker').datepicker({
minDate: minDate,
constrainInput: true,
beforeShowDay: beforeShowDay
});
});
function beforeShowDay(date) {
var day = date.getDay();
if (day == 1)
return [true]
return [false];
}
The working sample is hosted in http://elangovanr.com/samples/jquery/datepickermonday.html for your reference.