Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 8 years ago.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
This question appears to be off-topic because it lacks sufficient information to diagnose the problem. Describe your problem in more detail or include a minimal example in the question itself.
Improve this question
I have a div with an id textarea_feedback and a textarea with an id msg.
This is my jQuery code:
$(document).ready(function(){
var text_max = 160;
$('#textarea_feedback').html(text_max + ' characters remaining');
$('#msg').keyup(function(){
var text_length = $('#msg').val().length;
var text_remaining = text_max - text_length;
$('#textarea_feeeback').html(text_remaining + ' characters remaining');
});
});
$('#textarea_feeeback') is a typo.
This is actually a very concrete example of the power of Vanilla JS over jQuery, and of jQuery being too clever for its own good. The Vanilla JS code:
document.getElementById('textarea_feeeback').innerHTML = text_remaining+" characters remaining";
... would have thrown an error saying that it can't set innerHTML of null, which is absolutely correct because textarea_feeeback does not exist. jQuery, however, simply has an object with no elements, and setting the html() of those zero elements is really easy: do nothing.
Unfortunately, "do nothing" is the reason why you can't debug it!
$('#textarea_feeeback').html(text_remaining + ' characters remaining');
^--- typo
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
I am working through Javascript for Kids, which is a surprisingly fun little book for a beginner, but I'm having trouble testing a For Loop example in the text:
var sheepCounted = 0;
for (var sheepCounted = 0; sheepCounted < 10; sheepCounted++) {
console.log(“I have counted” + sheepCounted + “sheep!”);
}
console.log(sheepCounted);
When I use a Javascript tester to test this example I get a syntax error, but I'm not sure why? Can anyone help me out? Thanks.
Change this line which uses “ ”:
console.log(“I have counted” + sheepCounted + “sheep!”);
To this with " ":
console.log("I have counted" + sheepCounted + "sheep!");
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 5 years ago.
Improve this question
I am modifying a code example that I will use (and not very familiar with Javascript)
This is the piece of code
function chk() { cnt++;
var resp=ajax('chk.php', 'POST', 'ordernr='XXXXXX'&r='+((new Date()).getTime()));
if (resp=='3') {
I am posting to this file withe a Querystring-varaible named ordenr
What is the correct syntax to enter the value of Querystring.ordernr instead of XXXXXX
var orderNumber = 1;
var requestParamsStr = 'ordernr=\'' + orderNumber + '\'&r=' + ((new Date()).getTime());
console.log(requestParamsStr);
function chk() {
//cnt++;
var resp = ajax('chk.php', 'POST', encodeURIComponent(requestParamsStr));
//rest of code
}
I think I understand your question. If you need to put quotes around the order number then you must use the escape character / the way I'm doing in the code snippet, so that it doesn't delimit the string (or, alternatively, you could use double quotes within the single quotes). You must also use + to concatenate the the strings.
UPDATE:
I've encoded the request param string as per #ADyson's comment.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 8 years ago.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Improve this question
I want to make a function that has to generate a random number between 2 numbers and you can save it in a variable. I'm using this code:
function rand(ran1, ran2, randVar) {
var randomNumb = Math.floor(Math.random()*(ran2 - ran1)) + ran1;
eval("var " +randVar+ " = "+randomNumb+";");
}
rand(12, 49, rand1)
alert("Your number is: "+rand1)
The error I get is: Can't find variable: rand1
Can anyone help me?
Using eval for this is entirely unnecessary. I'd recommend something like this instead:
function rand(ran1, ran2) {
var randomNumb = Math.floor(Math.random()*(ran2 - ran1)) + ran1;
return randomNumb;
}
var rand1 = rand(12, 49);
alert("Your number is: " + rand1);
Notice that in calling the function, the only real difference is in where you place the identifier, rand1.
Further Reading
Functions
return
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
I'm trying to replace the src of an tag with another path. This works perfectly well:
var tempDocId = 'someId';
$('#documents' + that.ticketId).append('<img id="'+tempDocId+'" src="/img/support/pdf_icon.jpg">');
but the following code gives one of those "image not found" icons ():
var tempDocId = 'someId';
$('#documents' + that.ticketId).append('<img id="'+tempDocId+'" src="/img/support/loading.jpg">');
$('#tempDocId').attr("src", "/img/support/pdf_icon.jpg");
Does anybody know what I'm doing wrong here? All tips are welcome!
because you are looking for id="tempDocId", not the one you generated.
$('#tempDocId').attr("src", "/img/support/pdf_icon.jpg");
needs to be
$('#' + tempDocId).attr("src", "/img/support/pdf_icon.jpg");
so you are not replacing the source. My guess is that your loading image is not valid.
Because $('#tempDocId') doesn't exist. tempDocId is a variable, so try:
$('#' + tempDocId).attr('src', '/img/support/pdf_icon.jpg');
var tempDocId = 'doc' + Math.random().toString().substr(2);
var $img = $('<img id="'+tempDocId+'" src="/img/support/loading.jpg">');
$img.appendTo('#documents' + that.ticketId);
$img.attr('src', '/img/support/pdf_icon.jpg');
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Closed 8 years ago.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Improve this question
How would I write a conditional jquery statement saying value greater than?
This is what I have but i don't think it is correct:
} else if ($('.store_checkbox:checked').val > 63){
$("#hidden_taxon_message").show();
the .val > 63 is what I am having a problem with
Try this:-
} else if ($('.store_checkbox:checked').val() > 63){
$("#hidden_taxon_message").show();
val is a function in JQuery so you have to use ().
The jQuery method is .val() you forgot ()
Try this:
$('.store_checkbox:checked').val() > 63
You have forgot () after val and insert the value inside parseInt to tell to javascrip that is a number not a string
try this:
} else if (parseInt($('.store_checkbox:checked').val()) > 63){
$("#hidden_taxon_message").show();