I need a little help with changing the following regex to allow negative numbers. It needs to allow decimal numbers of up to a maximum of 4 decimal places, which it already does.
/^\d+(\.\d{1,4})?$/
Can anyone help?
Thanks
Just put -? before the first digit - "optionally match a minus sign"
Add the - in the character class with optional(?)
/^[-+]?\d+(\.\d{1,4})?$/
The following allows for integer numbers (123), integer with 1 to 4 fractional part (123.1234) and only 1 to 4 fractional part (.1234), that's usually accepted as a valid number. All options can be prefixed by plus or minus signs:
/^[-+]?(?:\d+|\d*(?:\.\d{1,4})?)$/
The (?:xxx) construction is preferred to (xxx) when we're not interested to capture the matches, because it requires less resources.
Related
I am trying to only allow numeric values, along with a possible negative symbol at the front of the string, and a single decimal, using Regex in JavaScript. This input value will only allow for a possible 10 digits also.
Currently, when a user inputs text, I have this logic that will only allow numbers, negative signs, and decimals. However, I want to limit the number of the negative sign to one, and only allow this at the front of the string. Also, I want to limit the number of decimals to one.
input.slice(0, 10).replace(/[^0-9.\-]/, '');
Can anyone please help me figure this out?
You can do:
input.slice(0, 10).match(/([-]?)([0-9]+)([.]?)([0-9]?)/);
Short n sweet.
/^-?\d{0,10}(\.\d{0,3})?$/
optional negative char. at the start
allows max of 10 digits next
again optional decimal group with at most 3 decimal places
These barriers can be modified accordingly.
Numerical input should not exceed 8 digits ( counting numbers on both the side of the decimal). Example: 123456.78 or 0.12 or 1.23
Numerical values should be able to accept negative numbers. Example: -0.8 , or -1.23
Max of 2 decimal number allowed
Numerical value should not accept any alpahbets in the input box
I tried Creating the following regular expression but i am not able to figure it out quite efficiently
^-?[0-9]\d*(\.\d+)?[,8]$
Regular exp
To match the required number of digits and no more, lookahead at the beginning of the pattern for (?:\d\.?) 1 to 8 times, and then match \d*(?:\.\d{1,2})?$ to match a number which, if containing decimals, contains at maximum 2 decimal characters:
^-?(?=(?:\d\.?){1,8}$)\d*(?:\.\d{1,2})?$
https://regex101.com/r/rQMRVX/5
(unless you need to capture the decimal part, it can be a non-capturing group like above)
You can try this
^-?\d{1,8}.?\d{1,2}$
Link : https://regex101.com/r/x7yw5M/2
I am trying to build regex that can validate number or range input.
Allowed values are
Any number between 1 and 1816
A range consisting of 2 numbers separated by -. Each number must be between 1 and 1816. E.g. "1-1816", "3-100", "1815-1816"
Invalid values include
"0"
negative numbers (like "-13")
numbers with leading zeros (like "01")
numbers out of range 1-1816 (alone or as part of range)
Any regex will be fine JavaScript or C#.
So far I figured out just
(?<=\s|^)\d+(?=\s|$)
The problem with your regex is that you are accepting all digits via \d and not limiting it to suit your accepted range.
Use this:
^(?:181[0-6]|180\d|1[0-7]\d{2}|[1-9]|\d{2,3})(?:-(?:181[0-6]|180\d|1[0-7]\d{2}|[1-9]|\d{2,3}))?$
This regex limits the numbers to be in the range 1-1816, while supporting either individual numbers or a range via a hyphen separator as specified.
Demo
This regex should do the trick:
^([1-9][0-9]{0,2}|1[0-7][0-9]{2}|180[0-9]|181[0-6])(-([1-9][0-9]{0,2}|1[0-7][0-9]{2}|180[0-9]|181[0-6]))?$
Basically it allows
A number with leading 1 and 0 to 2 more digits
A number with leading 1, followed by 0-7 and twice any number
A number with leading 180 followed by one more number
A number with leading 181 followed by one number 0-6
This optionally once more repeated after -
But generally regexes are not good to work with numbers (and hard to update whne the number changes). If you have such option I'd rather just validate the number by much simpler regex, like
^[1-9][0-9]{0,3}(-([1-9][0-9]{0,3}))?$
and than programmatically split it by - (if present) and parse the individual segments as integer and validate their numeric value against the range.
That would additionally allow you to check for invalid ranges like 100-1, 1800-1800 etc.
how to validate numbers between 0 to 99999.99 using regex?
basically it should accept the values like 0.01, 0000.01, .01 and 9999.99
also it should have only two values after dot(.)
I tried something like the below but it did not work for me.
/^[0-9]{1,5}.[0-9]{2}$/
decimal is optional
Could someone help pls.
The . character has special meaning in a regex, so you need to escape it.
Anyway, let me see if I got the rules straight:
Decimal point is optional
If decimal point not given:
Between 1 and 5 digits
If decimal point is present:
Between 0 and 5 digits before decimal point
Between 1 and 2 digits after decimal point
Since the number of digits depends on the presence of the decimal point, you make the regex have two choices, separated by |.
Choice 1 (no decimal point): [0-9]{1,5}
Choice 2 (decimal point): [0-9]{0,5}\.[0-9]{1,2}
Since you want anchors (^$), you can either put them in both choices, or surround the choice set with parenthesis. To make it non-capturing, use (?:xxx).
Final regex is one of these:
/^[0-9]{1,5}$|^[0-9]{0,5}\.[0-9]{1,2}$/
/^(?:[0-9]{1,5}|[0-9]{0,5}\.[0-9]{1,2})$/
You can see the second one in effect on regex101.
If javascript then below regex would work:
^\d{0,5}(((\.){0})|((\.){1}\d{1,2}))$
All the above mentioned cases are satisfying.
Thank you and ^(?:\d{1,5}(?:\.\d{1,2})?|\.\d{1,2})$ is what i was trying to get and this serves my purpose.
Javascript regex:
/^\d{1,5}(\.\d{1,2})?$/
Javascript demo
I have this code to test if a value entered in a INPUT is numeric:
$("#price").val().match(/^\d+$/);
I need some help rewriting this function to allow decimal places either with colon or dot meaning for example 230.00 is allowed and 230,00 is allowed too. Also the decimal places could be four or less. Any?
Regex: $("#price").val().match(/^\d+([,\.]\d{1,4})?$/);
Regex n2 with negative values: $("#price").val().match(/^-?\d+([,\.]\d{1,4})?$/);
If you need help parsing values related to some culture in specific, take a loot at this https://github.com/jquery/globalize. It's a library about globalization and localization.
Hope it helps!
$("#price").val().match(/^\d+((\.|,)\d+)?$/);
the above won't limit the number of decimal places to four, though.
By the way, that's a comma and not a "colon"
To match decimal places up to 4 only, use this
$("#price").val().match(/^\d+((\.|,)\d{1,4})?$/);
should match 1 to four numbers after . or ,