Fiddle
i have a jquery which is for that, if the selected value is "<>"(Between) i want to change the style to display:block to an input box .. but here all the selected items css is changed
$(document).ready(function () {
$('.condition-change').change(function () {
if ($('select[name="SearchCondition"]').find('option[value="<>"]').attr("selected", true)) {
$('.second-value').css("display", "block");
}
});
});
Wrong condition
$(document).ready(function () {
$('.condition-change').change(function () {
if($('select[name="SearchCondition"]').find('option[value="<>"]').prop("selected")==true)
{
$('.second-value').css("display", "block");
}
});
});
You simply need to access the selected option value which you can get using val(), so put condition on val(),
Live Demo
$(document).ready(function () {
$('.condition-change').change(function () {
if ($(this).val() == "<>") {
$('.second-value').css("display", "block");
}
});
});
Also using show and hide instead of setting css.
Live Demo
$(document).ready(function () {
$('.condition-change').change(function () {
if ($(this).val() == "<>")
$('.second-value').show();
else
$('.second-value').hide();
});
});
Try,
$('.condition-change').change(function () {
if($(this).val().trim() === '<>') {
$('.second-value').show();
}
});
DEMO
Or
$('.condition-change').change(function () {
$('.second-value').toggle($(this).val().trim() === '<>');
});
DEMO I
// add .is(":checked") function to check whether "<>" value option is selected
$(document).ready(function () {
$('.condition-change').change(function () {
if($('select[name="SearchCondition"]').find('option[value="<>"]').is(":checked"))
{
$('.second-value').css("display", "block");
}
else
{
$('.second-value').css("display", "none");
}
});
});
Related
How to run javascript code if checkbox is checked?
checkbox is defined as
<input type="checkbox" id="Maksja_piiratudes" name="Maksja_piiratudes"
onfocus="if(typeof this.ischanged=='undefined') this.ischanged=false" onblur="summarefresh()" onclick="dataChanged(this)">
I tried
$(function () {
$("#Maksja_piiratudes").on("change", function() {
alert('checkbox is checked');
}); // end on change
}); // end $
But this runs also if checkbox is unchecked.
How to run code only if checkgox is selected ?
Bootstrap 3, jquery, jquery UI are used.
You can use the checked property of an checkbox input.
$(function()
{
$('#Maksja_piiratudes').on('change', function()
{
if (this.checked)
{
alert('checkbox is checked');
}
});
});
Edit:
I prefer the vanilla style more.. so just in case someone needs it:
document.querySelector('#Maksja_piiratudes')
.addEventListener('change', function()
{
if (this.checked)
{
alert('checkbox is checked!');
}
}, false);
Try This
$(function () {
$("#Maksja_piiratudes").on("change", function() {
if ($(this).prop("checked") == true) {
alert('checkbox is checked');
} //end if
}); // end on change
}); // end $
If you want to make it global for all checkboxes use the below:
$(function () {
$("input[type='checkbox']").on("change", function() {
if ($(this).prop("checked") == true) {
alert('checkbox is checked');
} //end if
else {
alert('checkbox is unchecked');
}
}); // end on change
}); // end $
I'm unable to trigger $(this).toggleClass('selected'); for content table. When I debug it just skip this event. How can I make sure its being selected?
$('#contentChangesTable tr')
.filter(':has(:checkbox:checked)')
.addClass('selected')
.end()
.click(function (event) {
$(this).toggleClass('selected');
if (event.target.type !== 'checkbox') {
$(':checkbox', this).attr('checked', function () {
return !this.checked;
});
}
});
You want to use prop and not attr to set checked
JSFiddle: http://jsfiddle.net/TrueBlueAussie/RV46q/
$(function () {
$('#contentChangesTable tr')
.filter(':has(:checkbox:checked)')
.addClass('selected')
.end()
.click(function (event) {
$(this).toggleClass('selected');
if (event.target.type !== 'checkbox') {
$(':checkbox', this).prop('checked', function () {
return !this.checked;
});
}
});
});
I have a question that is quite confusing.
Everytime I check a "checkbox", it gets the closest "div" and add the class "hilight" and "marked" and set an Item to LocalStorage called "marking".
When I switch from div 1 to 2, I remove the class "hilight", but i keep the class "marked".
I'm trying to get the LocalStorage, and add class "hilight" again to divs that has "marked"
JS Fiddle: http://jsfiddle.net/b4KgV/
HTML
1
2
<button class="1st">show 1st</button>
<button class="2nd">show 2nd</button>
JS
localStorage.clear();
$(document).on('click', ':checkbox', function () {
if ($(this).is(':checked')) {
$(this).closest("div").addClass('hilight marked');
localStorage.setItem("marking","yes");
}
else {
$(this).closest("div").removeClass('hilight marked');
}
});
$(".1st").on('click', function() {
$(".second").css('display','none');
$(".second").removeClass('hilight');
$(".first").css('display','block');
});
$(".2nd").on('click', function() {
$(".first").css('display','none');
$(".first").removeClass('hilight');
$(".second").css('display','block');
});
if (localStorage.getItem("marking")) {
$(".marked").closest("div").addClass('hilight');
};
Thx.
Localstorage goes by key:value as you know, I tried to keep them separate.
Try this fiddle
http://jsfiddle.net/b4KgV/11/
$(document).on('click', ':checkbox', function () {
var div = $(this).closest("div").attr("id")
if ($(this).is(':checked')) {
$(this).closest("div").addClass('hilight marked');
localStorage.setItem(div, true);
} else {
$(this).closest("div").removeClass('hilight marked');
localStorage.setItem(div, false);
}
});
$(".1st").on('click', function () {
console.log("test")
if (localStorage.getItem("firstDiv") == "true") {
$(".first").closest("div").addClass('hilight');
};
$(".second").css('display', 'none');
$(".second").removeClass('hilight');
$(".first").css('display', 'block');
});
I have this code:
<script>
(function ($) {
$(document).ready(function () {
$("#thisclick, #thisclick2").click(function () {
if ($('.example').is(":hidden")) {
$(this).html($(this).html().replace(/Hide/, 'Show'));
} else {
$(this).html($(this).html().replace(/Show/, 'Hide'));
}
// Do it afterwards as the operation is async
$(".example").hide();
});
});
})(jQuery);
</script>
The way the current code works is that if #thisclick is clicked it hides #example. Which is what I require but when #thisclick is clicked again i want it to show #example. Using the above code, it won't work. What must I do to achieve this?
You should be able to change your code to as follows to get it to work:
(function ($) {
$(document).ready(function() {
$("#thisclick").click(function () {
$("#example").slideToggle("slow");
});
});
})(jQuery);
Here is a link to a quick sample:
http://jsfiddle.net/andyjmeyers/szmXp/
Are you expecting like
<button>This click</button>
<p style="display: none">Example</p>
<script>
$("button").click(function () {
$("p").toggle();
});
</script>
Please check it on http://jsfiddle.net/X5r8r/1107/
<script>
(function ($) {
$(document).ready(function() {
$("#thisclick").click(function () {
if ($('#example').is(":hidden")) {
$(this).html($(this).html().replace(/Hide/, 'Show'));
} else {
$(this).html($(this).html().replace(/Show/, 'Hide'));
}
// Do it afterwards as the operation is async
$("#thisclick").slideToggle("slow");
if($("#example").attr("isHidden") == "1")
$("#example").slideToggle("slow");
$("#example").attr("isHidden","1");
});
});
})(jQuery);
</script>
You can do this:
$("#thisclick").click(function () {
if ($('#example').hasClass("hidden"))
{
$('#example').removeClass("hidden");
$('#example').show();
}
else
{
$('#example').addClass("hidden");
}
}
or more easily:
$("#thisclick").click(function () {
$('#example').toggleClass("hidden");
}
define style":
.hidden
{ display:none;}
I've searched but can't find how to do this. I'm trying to make the elements with comment-modbox inside this hide and show:
$('.comment-wrapper').each(function (index) {
$(this, '.comment-modbox').mouseover(function () {
$('.comment-modbox').show();
});
$(this, '.comment-modbox').mouseout(function () {
$('.comment-modbox').hide();
});
});
This code just hides and shows all comment-modbox regardless as to if they are contained within this.
Thanks for any help!
Answer:
$('.comment-wrapper').each(function (index) {
$(this).mouseover(function () {
$('.comment-modbox', this).show();
});
$(this).mouseout(function () {
$('.comment-modbox', this).hide();
});
});
try this (jQuery("selector", context)...)
$('.comment-wrapper').each(function (index) {
$('.comment-modbox', this).mouseover(function () {
$(this).show();
});
$('.comment-modbox', this).mouseout(function () {
$(this).hide();
});
});
Second choice:
$('.comment-wrapper').each(function (index) {
var wrapper = this;
$('.comment-modbox', wrapper)
.mouseover(function () {
$(this).show();
})
.mouseout(function () {
$(this).hide();
});
});